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UNIVERSIDAD NACIONAL ABIERTA Y A DISTANCIAESCUELA DE CIENCIAS BÁSICAS, TECNOLOGÍA E INGENIERÍAANALISIS DE CIRCUITOS AC2016 - Semestre I

UNIVERSIDAD NACIONAL ABIERTA Y A DISTANCIA UNAD

ANALISIS DE CIRCUITOS AC

TRABAJO COLABORATIVO 1

INTEGRANTES:

RUBEN DARIO PENCUE PUENTES

1.079.606.725

CARLOS ANDRES LONDOÑO

9.725.611

EDINSON FERNANDO RIVERA

14.27.00

GRUPO: 20142!25

TUTOR:

PABLO ANDRES GUERRA GON"ALE"

ABRIL 2016


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CONTENIDO

INTRODUCCION.......................................................................................................3

OBJETIVOS...............................................................................................................4

DESARROLLO TRABAJO PRÁCTICO ANÁLISIS DE CIRCUITOS AC...................5

PROCEDIIENTO 1!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!"

PROCEDIIENTO 2!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1#

PROCEDIIENTO #!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!21

PROCEDIIENTO $!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!2%

PROCEDIIENTO "!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!#"

PROCEDIIENTO 6!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!$6

PROCEDIIENTO &!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!""

CONCLUSIONES!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!6#

BIBLIOGRA'IA!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!6"


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INTRODUCCION

L(s )*r)+*t(s e )(rr*ete ./ter. . s*( (r m+)( t*em( e/ s+stet( *.r*( e /.*e*er3. e/4)tr*). 5 e/e)tr*). e /. *str*7+)* e eer3., */+m*.)*, r(+)t(s e )(s+m( 5 s*stem.s *+str*./es! Aem8s, /. )(mres* e /(s)()et(s e /(s )*r)+*t(s e )(rr*ete ./ter. es + rerre9+*s*t( ese)*./ .r. m*/ese tem.s 9+e :. ese *s(s*t*:(s e/e)tr*)(s 5 /. m.9+*.r*. r(t.t(r*. .st. e/)(tr(/ .+t(m8t*)(, /.s )(m+*).)*(es 5 e/ r()es.m*et( e se;./es! P(r /( t.t(,+estr( est+*( e /(s )*r)+*t(s e )(rr*ete ./ter. t*ee t.t( ./*).)*(es*me*.t.s )(m( s+7se)+etes! E e/ es.rr(//( e est. .)t*:*. se :er8 re


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OBJETIVOS

Ver*


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DESARROLLO TRABAJO PR#CTICO AN#LISIS DE CIRCUITOS AC

UNIDAD 1

PROCEDI$IENTO 1

O7=et*:(s

1! Ver*er*met(s 9+e /. *me.)*., , e + )*r)+*t( RL ser*e

est8 .. (r /.


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I+)t(res

• 1 e $& m

• 1 e 100 m

1! *. /(s *+)t(res e $& m 5 100 m .r. :er*


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J! Re*t. /(s .s(s e/ 2 ./ &K re*stre t((s /(s :./(res e e/ re/ e 100 m e /. t.7/.1!

10! E>.m*e /. t.7/. 2! C( /(s :./(res e /. *me.)*. H)./)+/.(s . .rt*r e VL IL e/. t.7/. 1, )./)+/e e/ 8+/( e


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V R=V ∗ R

Z

V R=5∗33003615.3

V R=4.56 V

V(/t.=e e e/ *+)t(r!

V L=V ∗ X L

Z

V L=5∗1476.63615.3

V L=2.4 V

C(rr*ete )./)+/..!

I =

V R

R

I = 4.56

3300

I =1.38 mA

Re.)t.)*. *+)t*:.

X l=V R

R

X l= 2.04

0.00138


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X l=1478.3

Ime.)*. e/ )*r)+*t(

Impedanciadel circuito=V t

I t Impedanciadel circuito=

5

0.00138

Impedanciadel circuito=3623

Ime.)*. e/ )*r)+*t(

Impedanciadel circuito= R− X L

Impedanciadel circuito=3300−1476.6

Impedanciadel circuito=1823.4

Re.)t.)*. *+)t*:.

X l=w . L

w=2π . f

w=2 π .5000 Hz

w=3141.6 rad/seg

D(e LM


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X l=3141.6rad

seg∗0,047 H

X l=1476.6Ω

A+/( e


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PROCEDI$IENTO 1 CON INDUCTOR DE 100 $

V(/t.=e e e/ res*st(r

V R=V ∗ R

Z

V R=5∗33004556.3

V R=3.62V

V(/t.=e e e/ *+)t(r!

V L=

V ∗ X LZ

V L=5∗3141.6

4556.3

V L=3.44 V


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C(rr*ete )./)+/..

I =V R

R

I = 3.62

3300

I =1.09mA

Re.)t.)*. *+)t*:.

Reactanciainductia=V L

I L

Reactanciainductia= 3.44

0.00109

Reactanciainductia=3156

Ime.)*. e/ )*r)+*t(

Impedanciadel circuito=V t

I t Impedanciadel circuito=

5

0.00109

Impedancia del circuito=4587

Ime.)*. e/ )*r)+*t(

Impedanciadel circuito= R− X L

Impedanciadel circuito=3300−3141.6

Impedanciadel circuito=158,4

Re.)t.)*. *+)t*:.


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X l=w . L

w=2 π . f

w=2π .5000 Hz

w=3141.6 rad /seg

D(e LM

X l=3141.6 rad

seg∗0,1 H

X l=3141.6Ω

A+/( e


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PROCEDI$IENTO 2

O7=et*:(s

1! e*r e/ 8+/( e


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• Geer.(r e


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6! C( e/ se/e)t(r e ODO HODE :ert*)./ +est( e DUAL-ALT m*. e/es


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Res*ste)*., R, A)( e /.(. se(*./D, *:*s*(es

D*st.)*.etre +t(s

)er( ,*:*s*(es

A+/( e


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V L=10∗3141.54556.2

V L=6.89 V

C(rr*ete )./)+/..

I =V R

R

I = 7.24

3300

I =2.19 mA

Re.)t.)*. *+)t*:.

X l=w . L

w=2π . f

w=

2 π .5000 Hz

w=31415.9 rad /seg

D(e LM

X l=31415.9rad

seg∗0,1 H

X l=3141.5Ω

Ime.)*. e/ )*r)+*t(


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Z =2

√ R2+ X L

2

Z =2

√ 3300 2+3141.52

Z =√ 20759022.25

Z =4556.2Ω

A+/( e


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PROCEDI$IENTO 2.2 >RESISTENCIA 1?@:

V(/t.=e e e/ res*st(r

V R=V ∗ R

Z

V R=10∗10004556.2

V R=3.03V

V(/t.=e e e/ *+)t(r

V L=

V ∗ X LZ

V L=10∗3141.53296.82

V L=9.52 V


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C(rr*ete )./)+/..

I =V R

R

I = 3.03

1000

I =3.03 mA

Re.)t.)*. *+)t*:.

X l=w . L

w=2π . f

w=2 π .5000 Hz

w=31415.9 rad /seg

D(e LM

X l=31415.9rad

seg∗0,1 H

X l=3141.5Ω

Ime.)*. e/ )*r)+*t(

Z =2

√ R2+ X L

2

Z =2

√ 1000 2+3141.52

Z =√ 1086022.25


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Z =3296.8Ω

A+/( e


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PROCEDI$IENTO

1! C( + ../*?.(r e )..)*t(res*+)t(res ( + me*(r LCR m*. /(s

)..)*t(res e 0!0## ' 5 0!1 ' .r. :er*


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#! E)*e. e/ eer.(r e


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T%&'% 5. D(3()*( '% *(/%,*% ( ,*),*3 R, ( S()*(

V./(r e/)..)*t(r, '

Vet,V

V(/t.=e ee/res*st(r VR

V(/t.=ee e/)..)*t(r VC

C(rr*ete)./)+/..VRR mA

Re.)t.)*.)..)*t*:.H)./)+/..),

Re.)t.)*.)..)*t*:.H)./)+/..V)I),

Ime.)*. e/)*r)+*t(H)./)+/.. Le5e OmVTIT,

Ime.)*. e/)*r)+*t(H)./)+/..R+) ,

N(m*.

/

N(m*

./

e*

(

0!0## s*m+/.(r

# 1.95 5 0.95 4822! 5263! 5263.1 6822!

0!1 s*m+/.(r

# .91 5 1.95 1589 ! 2564 ! 2564.1 2564 !

$! *. /(s :./(res e BP e e/ res*st(r 5 e/ )..)*t(r! Re)+ere 9+e .r. me*r e

C1 e e/ (s)*/(s)(*( e7e +s.r e/ m(( ADD 5 e/ 7(t INVERT! Re*streest(s :./(res e /. t.7/. "!

P%)% 0.0F

V pp" 1=5 #V ppR1=1.95


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P%)% 0.1F

V pp" 2=5 #V ppR 2=3.91

"! C( e/ :(/t.=e me*( e R1 5 e/ :./(r e s+ res*ste)*., )./)+/e 5 re*stre /.)(rr*ete (r e/ )*r)+*t( e ser*e! D.( 9+e e/ res*st(r 5 e/ )..)*t(r est8 eser*e, /. )(rr*ete )./)+/.. .r. R1 es /. m*sm. 9+e .r. C1!

P%)% 0.0F


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I c1=V r

R #=

1.95 ❑2000 !

=0.95 mA

P%)% 0.1F

I c2=V r

R #=

3.91 ❑2000 !

=1.95 mA

6! C./)+/e 5 re*stre e/ :./(r e /. re.)t.)*. )..)*t*:. e C1 me*.te /.


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X c 2=V c

I c2#=

5 ❑0.00195 A

=2564!

I$PEDANCIA DEL C*),*3

P%)% 0.0F

Z c 1= V &

I &c1#=

5❑0.00095 A

=5263!

P%)% 0.1F

Z c 2= V &

I &c2#=

5❑0.00195 A

=2564!

&! Des+4s +t*/*)e /. /e5 e Om 5 /. e)+.)* e /. re.)t.)*. e ser*e Ht.7/. "

.r. )./)+/.r /. *me.)*. e/ )*r)+*t(! Re*stre .m7(s :./(res e /. t.7/. "!

C (' C1 Z t =Z R+Z " =2000 !+4822 !=6822!

C (' C2 Z t =Z R+Z " =2000 !+1589 !=3589 !

%! S+st*t+5. e/ )..)*t(r e 0!0## )


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J! Re*t. /(s .s(s e/ # ./ & 5 .(te t((s /(s :./(res e e/ re/ rese)t*:( e0!1 )

P%)% 0.0F

&an'=4822

2000=2.41 #'=arctan 2.41=1.17

rad

s #lo pasamosa grados

(rados=180

π ∗rad #

180

3.1416∗1.17=67.5 o∴'=67.5o )la impedancia Z =

R

cos'

Z =2000

cos'=

2000

0.38=5220 Ω

P%)% 0.1F

&an'=1589

2000=0.79 #'=arctan 0.79=0.67

rad

s # lo pasamosa grados

(rados=180

π ∗rad #

180

3.1416∗0.67=38.5o∴'=38.5o )la impedancia Z =

R

cos'

Z =2000

cos'

=2000

0.78

=2554Ω

T%&'% 6. D(3()*%,*- /(' ' /( +%( 8 '% *(/%,*% /( ,*),*3 RC ( ()*(


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V%') /(' ,%%,*3)F

R(%,3%,*%,%%,*3*/( '% 3%&'%5@

3% C

R

A'/(

+%( ;)%/

I(/%,*%

">RCOS @N*%' $(/*/

0!0## s*m+/.( 4822! 2.41 67.5

o5220Ω

0!1 s*m+/.( 1589! 0.79 38.5

o2554Ω

11! E e/ es.)*( 7.=( /. t.7/. 6 tr.)e /(s *.r.m.s


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2! C( e/ eer.(r e


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$! P.r. /. etr.. e *s.r( e7e se/e))*(.rse e/ )../ 2! E + )*r)+*t( e ser*e /.

)(rr*ete es /. m*sm. e t(( e/ )*r)+*t(! P(r t.t(, e + )*r)+*t( e ser*e /.

)(rr*ete se +s.r8 )(m( /3e. e re


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R3%: E' /(+%( ()+. 2 )+.r(s .r(> es e)*r 2W1%M 6

6! C( e/ se/e)t(r e ODO HODE :ert*)./ +est( e DUAL-ALT, m*. e/

es es e)*r 2W1%M 6

&! Re*t. /(s .s(s e/ 2 ./ 6 )( e/ res*st(r e 6!% %! N( ..+e e/ eer.(r e


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RM6!%X RM2X

RM6!%X RM2X

J! C./)+/e /. )(rr*ete e e/ )*r)+*t( .r. ).. :./(r e V me*.te /. /e5 e Om )(

/(s :./(res me*(s e VR 5 R! Re*stre s+s res+est.s e /. t.7/. $"-2 .r. e/

res*st(r e 6!% %!

P%)% 2?

I c1=V r

R #=

1.95 ❑2000 !

=0.975 mA


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P%)% 6.H?

I c2=V r

R #=

4.10 ❑6800 !

=0.603 mA

10! C./)+/e /. re.)t.)*. )..)*t*:., C e/ )..)*t(r )( /. /e5 e Om .r.

)..)*t(res )( e/ :./(r me*( e VC 5 e/ :./(r )./)+/.( e I! Re*stre s+s

res+est.s e /. t.7/. % .r. e/ res*st(r e 6!% %!

P%)% R 12?

X c 1=V medido

I R 1#=

3.19 ❑0.00095 A

=3271 !

P%)% R 2 6.H?

X c 2=V medido

I R 2#=

3.54 ❑0.00195 A

=5804 !

11! A .rt*r e /(s :./(res )./)+/.(s e C e e/ .s( 10 5 e/ :./(r me*( e R,)./)+/e e/ 8+/( e


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P%)% R 2 6.H?

&an'=5804

2000=0.85 # '=arctan 0.85=0.70 rad

s # lo pasamosa grados

(rados=180

π ∗rad #

180

3.1416∗0.70=40.5o∴'=40.5 o) laimpedancia Z =

R

cos'

Z =2000

cos'=

2000

0.76=2630 Ω

12! E)*e. e/ eer.(r e


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Res*ste

)*.

H:./(r

(m*.

, /

C..)*t.

)*. H:./(r

(m*./

C,'

V(/t.=e

./*).

(

V,V

V(/t.=e

e e/

res*st(r

VR,V

V(/t.

=e

ee/)

..)*

t(r

VC

V

C(rr*ete

H)./)+/..

I,mA

Re.)t.

)*.

)..)*t

*:.

H)./)+/

..

C,

A+/( e


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PROCEDI$IENTO 5A! e*)* e /. (te)*. (r e/ m4t(( e :(/t.=e-)(rr*ete

A1! C( + metr( m*. /. res*ste)*. e/ res*st(r e 100 5 .(te e/ :./(r e /.

t.7/. J!

A2! C( S1 .7*ert(, .rme e/ )*r)+*t( e /.


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VR e I e s+s )8/)+/(s! Re*stre /.s res+est.s e /. t.7/. J e e/ re/ "'!

A"! C( S1 .7*ert( 5 /.


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B2! C*erre S1! A+mete /. s./*. e /.


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re/ e " '! T.m7*4 m*. /. *st.)*., D, e 0 . #60 e /. (. se(*./ e

:(/t.=e! Re*stre e/ :./(r e /. t.7/. 10 .r. e/ res*st(r e 100 ! A.+e e/

(s)*/(s)(*(K .7r. S1K es)(e)te e/ )..)*t(r e " '!

B"! C( /.


42/69


VA F100 10 \' 6,26 \' 1%,J V 1%,J V 2",0 mA $&2," VA$&2,# F 0,JJJ 'P

B%! Re*t. e/ .s( B" .r. e/ )*r)+*t( ser*e e 10 ' 5 100 !

"'

Re.)t.)*. C..)*t*:. ) .r. "'

X c= 1

2 πf"

X c= 1

2∗3,14∗60∗5 $%

)M "#0,"

Ime.)*. e/ )*r)+*t( .r. )..)*t(r e "'

z=√

R

2

+ Xc2

z=√ 1002+530,52

M "#J,%$

C(rr*ete e )(es.(r "'

I M V )

I M "0V "#0,"

IM J$,2mA

V(/t.=es e e/ res*st(r VR )*r)+*t( " '

VR M I W R


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VR M J$,2mA W 100

Vr M J,$2:

P(te)*. ..rete e/ )*r)+*t( .r. "'!

S M V W I HVA

SM "0V W J$,2mA!

SM $,&1 VA

P(te)*. re./ e/ )*r)+*t( .r. "'! He*(

P M I W V W C(s HF

PM J2,%mA W "0V W 0,1%"#

PM 0,%"F

'.)t(r e (te)*. 'P H)(s .r. "'

C(s M P S

C(s M 0,%"F $,&1VA

C(s M 0,1%

10'

Re.)t.)*. C..)*t*:. ) .r. 10'

X c= 1

2 πf"

X c= 12∗3,14∗60∗10 $%

) M 26",2"

Ime.)*. e/ )*r)+*t( .r. )..)*t(r e 10'


44/69


z=√ R2+ Xc2

z=√ 1002+265,252

M 2%#,$

C(rr*ete e )(es.(r 10'

I M V )

I M 2"V 26",2"

IM J$,2mA

V(/t.=es e e/ res*st(r VR )*r)+*t( 10 '

VR M I W R

VR M J$,2mA W 100

Vr M J,$2:

P(te)*. ..rete e/ )*r)+*t( .r. 10'!

S M VW I HVASM 2"V W J$,2mA!

SM 2,#" VA

P(te)*. re./ e/ )*r)+*t( .r. 10'! He*(

P M I! V! C(s HF

PM J0,JmA W 2"V W 0, #6#"

PM 0,%2F

'.)t(r e (te)*. 'P H)(s .r. 10'

C(s M P S

C(s M 0,%2F 2,#"VA

C(s M 0,#$


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T.7/. 10! Determ*.)* e/


46/69


A+/( e


47/69



48/69


A+/( e


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PROCEDI$IENTO 6

1! C( e/ eer.(r e


50/69


res+est. e e/ re/ QRL e /. t.7/. 11!

6! C./)+/e /. *me.)*. t(t./ e/ )*r)+*t( )( (s m4t((s /. /e5 e Om H)( e/

:./(r )./)+/.( e I 5 e/ :(/t.=e ./*).(, VAB 5 /.


51/69


10! C./)+/e /. *me.)*. , e/ )*r)+*t( )( (s m4t((s /. /e5 e Om Hme*.te

VAB e I 5 /.


52/69


re/ QRC e /. t.7/. 11!

T.7/. 11! Determ*.)* e /. *me.)*. e + )*r)+*t( RLC ser*e!

)*r)+*

t(

C(m(ete V(/t.=e

A/*).

(

VAB

V-

V(/t.

=e e

e/

res*st

(r

VR

V-

V(/t.=

e e e/

*+)t

(r

VL

V-

V(/t.=e

e e/

)..)*t

(r

VC

V-

C(rr*e

te

I, mA

Re.)t.)*.

R,

L,

m

C,

+'

I,

L

C.,

C

RL 2

X

10

0

0,02

2

10 ",$ %,6 2,6% #1$1

,6

RLC 2

X

10

0

0,02

2

10 &,6 1,2 ",$ #,%1 #1$1

,6

1$$6

,%RC 2

X

0,02

2

10 % ",% $ 1$$6

,%

C8/)+/(s .r. )*r)+*t(s RL


53/69


Re.)t.)*. I+)t*:. L


54/69


L M 2_!

LM 2W#!1$16W"X?W 100m

L M #1$1,6

Ime.)*. )*r)+*t( RL

z=√ R2+ Xl2

z=√ 2 -!2+3141,6 !2

M #&2$,2

C(rr*ete )*r)+*t( RL

IL M VT

IL M H10V- #&2$,2

IL M 2,6%mA

Ime.)*. (r /e5 e O .r. )*r)+*t( RL

M V I

M H10V - 2,6%mA

M #,#

C8/)+/(s .r. )*r)+*t(s RC


55/69


Re.)t.)*. C..)*t*:. )

C M 1 2_!


56/69


CM 1 H2W#,1$16W "X?W 0,022'

C M 1$$6,%"

Ime.)*. )*r)+*t( RC

z=√ R2+ Xc2

z=√ 2 -!2+1446,852

M 2$6%!$

C(rr*ete )*r)+*t( RC

IC M VT

IC M H10V- 2$6%!$

IC M $mA

Ime.)*. (r /e5 e O .r. )*r)+*t( RC

M V I

M H10V - H$ mA

M 2"00

C8/)+/(s .r. )*r)+*t(s RLC


57/69


58/69


z=√ 2 *!2+(3141,6−1446,85)2

M 2621,$%

C(rr*etes )*r)+*t( RLC

IT M VT

IT M H10V- 2621,$%IT M #,%1mA

Ime.)*. (r /e5 e O .r. )*r)+*t( RLC

M V I

M H10V - H#,%1mA

M 262$!6&

PROCEDI$IENTO 7


59/69


1! C( e/ eer.(r e


60/69


T.7/. 12! Determ*.)* e /. *me.)*. e + )*r)+*t( RLC e .r./e/(

V(/t.=e

./*).( V,

V-

C(rr*ete 5


61/69


C./)+/( e )(rr*ete

VM I!RIM HJ,J": - 2010IM $,J"mAP.r. e


62/69


C./)+/( e )(rr*eteILM HV- LILM H10V- H#1$1!6E/ :./(r e L se e)+etr. e /. t.7/. 11!ILM#!1%mAC8/)+/( e


63/69


C./)+/( e )(rr*ete

I) M HV- )I) M H10V- 1$$6,%I) M 6!J1mA

C./)+/( e


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C./)+/( e )(rr*ete res*st(r 5 )..)*t(r

IRC M √ IR2+ I" 2

IRC M √ 5 mA2+6,91mA 2

IRC M %,"2mA

A+/(

MƟ tan−1[ ( I" ) IR ]

MƟ tan−1[

(6,91mA )5 mA

]

M "$,11 M "$6^#JƟ

C./)+/( e )(rr*ete res*st(r 5 e e/ *+)t(r

IRL M √ IR2+ IL2

IRC M √ 5 mA2+3,18 mA2

IRC M ",J2mA

A+/(

MƟ tan−1[

( IL ) IR

]

MƟ tan−1[

(3,18 mA )5 mA

]

M #2,$" M #22&^22Ɵ

C(rr*ete t(t./ e/ )*r)+*t(


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IT M √ IR2+( I" − IL)2

IT M √ 5mA2+(6,91mA−3,18mA)2

IT M √ 5mA2+3,73mA 2

IT M 6,2#mA

A+/( e


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MƟ tan−1[

( I" − IL) IR

]

MƟ tan−1[ (6,91mA−3,18 mA )5 mA ]

MƟ tan−1[0,746]

M #6,&2 M #6$#^22Ɵ

IT .e/.t. . VT

C8/)+/( e


67/69


CONCLUSIONES

C( /. /e5 e Om 5 /. e)+.)* e re.)t.)*.s e ser*e, se (7t+:( /. *me.)*. e/

)*r)+*t( e/ e=er)*)*( mer( 1 5 ./ )./)+/.r e/ 8+/( e


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L.s *:ers.s re/.)*(es etre /(s )()et(s .9+3 est+*.(s erm*te *


69/69