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ANALISIS BALOK TTULANGAN TUNGGAL
Section Properties :
Mutu Beton fc' = 27.92 MPa= 4000 psi
Mutu Baja fy = 418.8 MPa= 60000 psi
Tebal Pelat hf = 63.4518 mm= 2.50 in
Tinggi Balok h = 507.614 mm= 20.00 in
Lebar Balok bw = 253.807 mm= 10.00 in
Lebar eff Balok beff = 1015.23 mm= 40.00 in
Tebal Selimut d' = 50.7614 mm= 2.00 in
Tinggi Efektif Ba d = 456.853 mm= 18.00 in
Jml. Tul Dia. A A
(buah) (mm)As 2 22 760.571 1.18
= 0.0285ρf = 0.85*fc'*(beff-bw)*hf/(fy*bw*d) = 0.0236
= 0.0130= 0.0098= 0.0033
= 0.0066 > ρmin (OK)= 0.0016 < ρmax (OK)
Cek penampang :
ϖ = (As/(beff*d))*(fy/fc') = 0.0246= 0.61 in < hf
Sehingga balok dianalisis dengan persegi:
Balok Persegi :
a = As*fy/(0.85*fc'*beff) = 0.5209 inMn = As*fy*(d-a/2) = 1,256,685 lb-in
= ### lb-in
(mm2) (in2)
Cek ρmax < 0.75 ρb
ρb = (0.85*ß1*fc'/fy)*(87000/(87000+fy))
ρb = bw/b*(ρb+ρf)ρmax = 0.75*ρbρmin = 200/fy
ρw = As/bw*dρ = As/beff*d
c = 1.18*ϖ*d/ß1
Mu = Ø*Mn
bw
d
d'
hf
beff
c
As
Asf
h
ANALISIS BALOK TTULANGAN TUNGGAL
Section Properties :
Mutu Beton fc' = 27.92 MPa= 4000 psi
Mutu Baja fy = 418.8 MPa= 60000 psi
Tebal Pelat hf = 63.4518 mm= 2.50 in
Tinggi Balok h = 507.614 mm= 20.00 in
Lebar Balok bw = 253.807 mm= 10.00 in
Lebar eff Balok beff = 1015.23 mm= 40.00 in
Tebal Selimut d' = 50.7614 mm= 2.00 in
Tinggi Efektif Ba d = 456.853 mm= 18.00 in
Jml. Tul Dia. A A
(buah) (mm)As 10 22 3802.86 5.90
= 0.0285ρf = 0.85*fc'*(beff-bw)*hf/(fy*bw*d) = 0.0236
= 0.0130= 0.0098= 0.0033
= 0.0328 > ρmin (OK)= 0.0082 < ρmax (OK)
Cek penampang :
ϖ = (As/(beff*d))*(fy/fc') = 0.1230= 3.07 in > hf
Sehingga balok dianalisis dengan T :
Balok T :
Asf = 0.85*fc'*(beff-bw)*hf/fy = 4.25a = (As-Asf)*fy/(0.85*fc'*bw) = 2.92 inMn1 = (As-Asf)*fy*(d-a/2) = 1,640,948 lb-inMn2 = Asf*fy*(d-hf/2) = 4,271,250 lb-inMn = Mn1+Mn2 = 5,912,198 lb-in
= ### lb-in
(mm2) (in2)
Cek ρmax < 0.75 ρb
ρb = (0.85*ß1*fc'/fy)*(87000/(87000+fy))
ρb = bw/b*(ρb+ρf)ρmax = 0.75*ρbρmin = 200/fy
ρw = As/bw*dρ = As/beff*d
c = 1.18*ϖ*d/ß1
in2
Mu = Ø*(Mn)
bw
d
d'
hf
beff
c
As
Asf
h
ANALISIS BALOK TTULANGAN DOBEL
Section Properties :
Mutu Beton fc' = 27.92 MPa= 4000 psi
Mutu Baja fy = 418.8 MPa= 60000 psi
Modulus Elastisit Es = 200000 MPa= 3E+07 psi
Tebal Pelat hf = 63.4518 mm= 2.50 in
Tinggi Balok h = 507.614 mm= 20.00 in
Lebar Balok bw = 253.807 mm= 10.00 in
Lebar eff Balok beff = 1015.23 mm= 40.00 in
Tebal Selimut d' = 50.7614 mm= 2.00 in
Tinggi Efektif Ba d = 456.853 mm= 18.00 in
Jml. Tul Dia. A A
(buah) (mm)As' 2 12 226.286 0.35As 2 22 760.571 1.18
= 0.0285ρf = 0.85*fc'*(beff-bw)*hf/(fy*bw*d) = 0.0236
= 0.0130= 0.0098= 0.0033
= 0.0066 > ρmin (OK)= 0.0016 < ρmax (OK)
Cek penampang :
ϖ = (As/(beff*d))*(fy/fc') = 0.0246= 0.61 in < hf
Sehingga balok dianalisis dengan persegi:
Kontrol Tulangan :
fy/Es = 0.0021= 0.0068 > fy/Es
fs' = 60000.00 psi
(mm2) (in2)
Cek ρmax < 0.75 ρb
ρb = (0.85*ß1*fc'/fy)*(87000/(87000+fy))
ρb = bw/b*(ρb+ρf)ρmax = 0.75*ρbρmin = 200/fy
ρw = As/bw*dρ = As/beff*d
c = 1.18*ϖ*d/ß1
εs' = 0.003*(c-d')/c
bw
d
d'
hf
beff
c
As
Asf
h
ANALISIS BALOK TTULANGAN DOBEL
= 0.0849 > fy/Esfs = 60000.00 psi
Balok Persegi :
a = (As*fs-As'*fs')/(0.85*fc'*beff) = 0.3659 inMn = (As*fs-As'*fs')*(d-a/2)+As'*fs'*(d-d') = 1,223,877 lb-in
= ### lb-in
εs = 0.003*(d-c)/c
Mu = Ø*Mn
ANALISIS BALOK TTULANGAN DOBEL
Section Properties :
Mutu Beton fc' = 27.92 MPa= 4000 psi
Mutu Baja fy = 418.8 MPa= 60000 psi
Modulus Elastisit Es = 200000 MPa= 3E+07 psi
Tebal Pelat hf = 63.4518 mm= 2.50 in
Tinggi Balok h = 507.614 mm= 20.00 in
Lebar Balok bw = 253.807 mm= 10.00 in
Lebar eff Balok beff = 1015.23 mm= 40.00 in
Tebal Selimut d' = 50.7614 mm= 2.00 in
Tinggi Efektif Ba d = 456.853 mm= 18.00 in
Jml. Tul Dia. A A
(buah) (mm)As' 2 12 226.286 0.35As 10 22 3802.86 5.90
= 0.0285ρf = 0.85*fc'*(beff-bw)*hf/(fy*bw*d) = 0.0236
= 0.0130= 0.0098= 0.0033
= 0.0328 > ρmin (OK)= 0.0082 < ρmax (OK)
Cek penampang :
ϖ = (As/(beff*d))*(fy/fc') = 0.1230= 3.07 in > hf
Sehingga balok dianalisis dengan T :
Kontrol Tulangan :
fy/Es = 0.0021= 0.0010 < fy/Es
fs' = 30019.04 psi
(mm2) (in2)
Cek ρmax < 0.75 ρb
ρb = (0.85*ß1*fc'/fy)*(87000/(87000+fy))
ρb = bw/b*(ρb+ρf)ρmax = 0.75*ρbρmin = 200/fy
ρw = As/bw*dρ = As/beff*d
c = 1.18*ϖ*d/ß1
εs' = 0.003*(c-d')/c
bw
d
d'
hf
beff
c
As
Asf
h
ANALISIS BALOK TTULANGAN DOBEL
= 0.0146 > fy/Esfs = 60000.00 psi
Balok T :
a = (As*fs-As'*fs'-0.85*fc'*hf*(beff-bw))/(0.85*fc'*bw)= 2.61 in
Asf = 0.85*fc'*(beff-bw)*hf/fy = 4.25Mn1 = 0.85*fc'*a*bw*(d-a/2) = 1,480,271 lb-inMn2 = Asf*fy*(d-hf/2) = 4,271,250 lb-inMn3 = As'*fs'*(d-d') = 168,720 lb-inMn = Mn1+Mn2 +Mn3 = 5,920,241 lb-in
= ### lb-in
εs = 0.003*(d-c)/c
in2
Mu = Ø*(Mn)
