Download xlsx - BALOK-T

ANALISIS BALOK TTULANGAN TUNGGAL

Section Properties :

Mutu Beton fc' = 27.92 MPa= 4000 psi

Mutu Baja fy = 418.8 MPa= 60000 psi

Tebal Pelat hf = 63.4518 mm= 2.50 in

Tinggi Balok h = 507.614 mm= 20.00 in

Lebar Balok bw = 253.807 mm= 10.00 in

Lebar eff Balok beff = 1015.23 mm= 40.00 in

Tebal Selimut d' = 50.7614 mm= 2.00 in

Tinggi Efektif Ba d = 456.853 mm= 18.00 in

Jml. Tul Dia. A A

(buah) (mm)As 2 22 760.571 1.18

= 0.0285ρf = 0.85*fc'*(beff-bw)*hf/(fy*bw*d) = 0.0236

= 0.0130= 0.0098= 0.0033

= 0.0066 > ρmin (OK)= 0.0016 < ρmax (OK)

Cek penampang :

ϖ = (As/(beff*d))*(fy/fc') = 0.0246= 0.61 in < hf

Sehingga balok dianalisis dengan persegi:

Balok Persegi :

a = As*fy/(0.85*fc'*beff) = 0.5209 inMn = As*fy*(d-a/2) = 1,256,685 lb-in

= ### lb-in

(mm2) (in2)

Cek ρmax < 0.75 ρb

ρb = (0.85*ß1*fc'/fy)*(87000/(87000+fy))

ρb = bw/b*(ρb+ρf)ρmax = 0.75*ρbρmin = 200/fy

ρw = As/bw*dρ = As/beff*d

c = 1.18*ϖ*d/ß1

Mu = Ø*Mn

bw

d

d'

hf

beff

c

As

Asf

h

ANALISIS BALOK TTULANGAN TUNGGAL










Jml. Tul Dia. A A

(buah) (mm)As 10 22 3802.86 5.90


= 0.0130= 0.0098= 0.0033

= 0.0328 > ρmin (OK)= 0.0082 < ρmax (OK)

Cek penampang :

ϖ = (As/(beff*d))*(fy/fc') = 0.1230= 3.07 in > hf

Sehingga balok dianalisis dengan T :

Balok T :

Asf = 0.85*fc'*(beff-bw)*hf/fy = 4.25a = (As-Asf)*fy/(0.85*fc'*bw) = 2.92 inMn1 = (As-Asf)*fy*(d-a/2) = 1,640,948 lb-inMn2 = Asf*fy*(d-hf/2) = 4,271,250 lb-inMn = Mn1+Mn2 = 5,912,198 lb-in

= ### lb-in

(mm2) (in2)


ρb = (0.85*ß1*fc'/fy)*(87000/(87000+fy))



c = 1.18*ϖ*d/ß1

in2

Mu = Ø*(Mn)

bw

d

d'

hf

beff

c

As

Asf

h

ANALISIS BALOK TTULANGAN DOBEL




Modulus Elastisit Es = 200000 MPa= 3E+07 psi







Jml. Tul Dia. A A

(buah) (mm)As' 2 12 226.286 0.35As 2 22 760.571 1.18


= 0.0130= 0.0098= 0.0033

= 0.0066 > ρmin (OK)= 0.0016 < ρmax (OK)

Cek penampang :

ϖ = (As/(beff*d))*(fy/fc') = 0.0246= 0.61 in < hf

Sehingga balok dianalisis dengan persegi:

Kontrol Tulangan :

fy/Es = 0.0021= 0.0068 > fy/Es

fs' = 60000.00 psi

(mm2) (in2)


ρb = (0.85*ß1*fc'/fy)*(87000/(87000+fy))



c = 1.18*ϖ*d/ß1

εs' = 0.003*(c-d')/c

bw

d

d'

hf

beff

c

As

Asf

h


= 0.0849 > fy/Esfs = 60000.00 psi

Balok Persegi :

a = (As*fs-As'*fs')/(0.85*fc'*beff) = 0.3659 inMn = (As*fs-As'*fs')*(d-a/2)+As'*fs'*(d-d') = 1,223,877 lb-in

= ### lb-in

εs = 0.003*(d-c)/c

Mu = Ø*Mn





Modulus Elastisit Es = 200000 MPa= 3E+07 psi







Jml. Tul Dia. A A

(buah) (mm)As' 2 12 226.286 0.35As 10 22 3802.86 5.90


= 0.0130= 0.0098= 0.0033

= 0.0328 > ρmin (OK)= 0.0082 < ρmax (OK)

Cek penampang :

ϖ = (As/(beff*d))*(fy/fc') = 0.1230= 3.07 in > hf

Sehingga balok dianalisis dengan T :

Kontrol Tulangan :

fy/Es = 0.0021= 0.0010 < fy/Es

fs' = 30019.04 psi

(mm2) (in2)


ρb = (0.85*ß1*fc'/fy)*(87000/(87000+fy))



c = 1.18*ϖ*d/ß1

εs' = 0.003*(c-d')/c

bw

d

d'

hf

beff

c

As

Asf

h


= 0.0146 > fy/Esfs = 60000.00 psi

Balok T :

a = (As*fs-As'*fs'-0.85*fc'*hf*(beff-bw))/(0.85*fc'*bw)= 2.61 in

Asf = 0.85*fc'*(beff-bw)*hf/fy = 4.25Mn1 = 0.85*fc'*a*bw*(d-a/2) = 1,480,271 lb-inMn2 = Asf*fy*(d-hf/2) = 4,271,250 lb-inMn3 = As'*fs'*(d-d') = 168,720 lb-inMn = Mn1+Mn2 +Mn3 = 5,920,241 lb-in

= ### lb-in

εs = 0.003*(d-c)/c

in2

Mu = Ø*(Mn)