Solving Absolute Value Equations and Inequalities
By Ellie Silverman
Solving Absolute Value Equations
2x + 3 = 7
2x + 3 = 7
This equation means the absolute value of 2x+3 is 7.
Absolute value is a number’s distance from zero. For example, the absolute value of 4 is 4 and the absolute value of -4 is 4 because they are both
four ‘spots’ away from zero.
These are absolute value signs
4-2 0-1 1 2 3-4 -3
1 2 3 4 1 2 3 4
2x + 3 = 7To solve this equation you have to get rid of the absolute value signs. To do this you have to set
2x+3 equal to 7 and -7.
2x + 3 = 7 2x + 3 = -7
2x + 3 = 7
Now that you set 2x+3 equal to 7 and -7, you solve.
2x + 3 = -7
2x = 4 2x = -102 2 22x = 2 x = -5
-3 -3 -3 -3
Solving Absolute Value Inequalities
2x + 3 < 72x + 3 ≤ 7
2x + 3 > 72x + 3 ≥ 7
Some things to remember when solving inequalities:
* < or > = open dot on number line
* Always remember to flip the sign if you divide by a negative
* Less than means you put and between your solutions and shade between them on the number
line* Greater means you put or between your solutions and shade outwards on the number line
* ≤ or ≥ = closed dot on number line
2x + 3 < 7
To solve this inequality you have to get rid of the absolute value signs. To do this you have to set
2x+3 less than 7 and greater than -7
Less thand
2x + 3 < 7
2x + 3 > -7an
d
Now that you set 2x+3 less than 7 and -7, you solve.
2x + 3 < 7
and
2x + 3 > -7-3 -3 -3 -3
2x < 4 2x > -10
x < 2 x > -52 2 2 2
4-2 0-1 1 2 3-4 -3
Now it’s time to graph your solutions!
5-5-6
X < 2 AND X > -5
If the answer looked like this:
X ≤ 2 AND X ≥ -5 Then the circles on the graph would be closed
2x + 3 > 7
To solve this inequality you have to get rid of the absolute value signs. To do this you have to set
2x+3 greater than 7 and less than -7
greator
2x + 3 > 7
2x + 3 < -7or
Now that you set 2x+3 greater than 7 and less than -7, you solve.
2x + 3 > 7
and
2x + 3 < -7-3 -3 -3 -3
2x > 4 2x < -10
x > 2 x < -52 2 2 2
4-2 0-1 1 2 3-4 -3
Now it’s time to graph your solutions!
X > 2 OR x < -5
5-5-6
If the answer looked like this:
Then the circles on the graph would be closed
X ≥ 2 OR x ≤ -5
More PracticeSolve and graph each inequality:
1.) 8b + 9 < 63
4.) -8x - 10 < 58
2.) 4 + 5x > 24
3.) 5 - 8x < 43
5.) -7r ≤ 7
6.) 8b + 9 < 63
7.) -5p ≥ 20
3.) 1 + x < 8
Just a Funny Math Video
http://www.youtube.com/watch?v=6cAs1YBELmA