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2.6SolvingAbsoluteValueInequalitiesThinkingBack: ! = 5meansthedistancebetweenxand0is5units.CoreConcepts:paycloseattentiontoyoursigns!$! + & < (means$! + & < ( AND $! + & > −($! + & > (means$! + & > ( OR $! + & < −(Example1:SolvingAbsoluteValueInequalitiesSolveeachinequality.Grapheachsolution,ifpossible.
a) ! + 7 < 2 b) 8! − 11 < 0 Example2:SolvingAbsoluteValueInequalitiesSolveeachinequality.
a) ( − 1 ≥ 5 b) 10 −1 ≥ −2 c)4 2! − 5 + 1 > 21
