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SOLVING TWO VARIABLE LINEAR INEQUALITIES INCLUDING ABSOLUTE VALUE INEQUALITIES

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Text of SOLVING TWO VARIABLE LINEAR INEQUALITIES INCLUDING ABSOLUTE VALUE INEQUALITIES

  • Slide 1
  • SOLVING TWO VARIABLE LINEAR INEQUALITIES INCLUDING ABSOLUTE VALUE INEQUALITIES
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  • Summary of Inequality Signs > < > < Continuous line Dashed line Shade above the line Shade below the line
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  • Graphing Linear Inequalities The graph of a linear inequality is a region of the coordinate plane that is bounded by a line. This region represents the SOLUTION to the inequality.
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  • A linear inequality is an inequality in two variables whose graph is a region of the coordinate plane that is bounded by a line.
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  • Graph the following inequality: x > 2 Boundary is:x = 2 We shaded at the right of the line because x is more than 2. The line is dashed because it is not equal or less than x, so the line which is the boundary is not included in the solution.
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  • Graph the following inequality: y < 6 Boundary: y = 0x + 6m= 0y- intercept = (0,6) We shaded below the line because y is less than 6. The line is dashed because it is not equal or less than y, so the line which is the boundary is not included in the solution.
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  • Example
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  • 1.The boundary line is dashed.
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  • 2.Substitute (0, 0) into the inequality to decide where to shade. So the graph is shaded away from (0, 0).
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  • Graph the following inequality: 4x + 2y < 10 Solve for y y < -2x + 5 Boundary is: y = -2x + 5m= -2 y- intercept = (0,5) We shaded below the line because y is less than the expression -2x + 5. The line is dashed because it is not equal or less than y, so the line which is the boundary is not included.
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  • Graph the following inequality: -9x + 3y< 3 Solve for y y < 3x + 1 Boundary is: y = 3x + 1 m= 3y- intercept = (0, 1) We shaded below the line because y is less than the expression 3x +1. The line is dashed because it is not equal or less than y, so the line which is the boundary is not included.
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  • Graph the following inequality: y 2 > (x 4) Solve for y y > x 3 Boundary is: y = x 3 m = y-intercept = (0, -3) We shaded above because y is greater or equal than the expression and the line is continuous because the word equal in greater or equal indicates that the boundary is included in the solution.
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  • EXAMPLE
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  • Problem, cont
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  • Graph the following absolute value equation: y = |x| For x 0 y = -x y = x Now lets shift it two units up: y = |x| + 2 Now lets shift it three units to the right: y = |x - 3| + 2 Now lets graph it upside down y = |x-3| + 2 Now lets make it skinner y = 6|x-3| + 2
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  • So, thats how the different parameters in an absolute value equation affect our graph. Now lets graph absolute value inequalities.
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  • Absolute Value Inequalities Graph the absolute value function then shade above OR below Solid liney Dashed liney Shade above y>, y> Shade belowy
  • Absolute Value Inequalities Graph y + 1 < -2|x + 2| -y < -2|x + 2| - 1 y > 2|x + 2| + 1 -y so CHANGE the direction of the inequality
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  • Absolute Value Inequalities y > 2|x + 2| + 1 Vertex = (-2, 1) Slope = 2 Solid line Shade above
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  • Absolute Value Inequalities y > 2|x + 2| + 1
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  • Absolute Value Inequalities y > 2|x + 2| + 1
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  • Absolute Value Inequalities y > 2|x + 2| + 1
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  • Absolute Value Inequalities y > 2|x + 2| + 1
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  • Absolute Value Inequalities Write an equation for the graph below.
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  • Graph the following inequality: y > |x| Finding the boundary: For x 0 y = -x y = x There are two regions: Testing point (0,2) 2 > | 0| 2 > 0 true Therefore, the region where (0,2) lies is the solution region and we shade it..
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  • Finding the boundary: For x + 1 0 y = -(x+1) 3 y = x+1 3 y = - x 1 -3y = - x 4 y = x 2 There are two regions: Testing point (0,0) 0 < | 0+1| 3 0 < -2 false So the region where (0,0) lies is not in the solution region, therefore we shade the region below. Graph the following inequality: y < |x+1| 3.
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  • Steps: 1.Decide if the boundary graph is solid or dashed. 2.Graph the absolute value function as the boundary. 3.Use the point (0, 0), if it is not on the boundary graph, to decide how to shade.
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  • Graph y 2|x 3| + 2
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  • Graph y 2|x 3| + 2 1.The boundary graph is solid.
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  • 2.y 2|x 3| + 2 0 2|0 3| + 2 0 2|-3| + 2 0 6 + 2 0 8 False So shade away from (0, 0).
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  • 1.The boundary graph is dashed.
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  • Your Turn! 8. Graph 9. Graph
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  • 8. 9.
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  • Example 10
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  • y |x+4| - 3y 2x+5