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International Indian School, Dammam Upper Primary Sections

2020-2021

Class V Mathematics Class work and Home work to be done in Mathematics Notebook

C.W. 5.4.2020 Addition of Large numbers

Addition of large numbers is the same as for smaller numbers. The numbers we add are

called addends and the answer in addition is called the sum or the total.

The properties of addition of large numbers are also the same as for smaller numbers.

We can add numbers in any order and still the sum will be the same. Eg. 3,092 + 1,200 = 1,200 + 3,092

Zero added to any number gives the same number as the sum. Eg. 7,689 + 0 = 7,689

Example 1: Add 61,327 and 39,855

L TTh Th H T O 1 1 1 6 1 3 2 7

+ 3 9 8 5 5

1 0 1 1 8 2 Answer: Sum = 1,01,182

H.W. of 5.4.2020

Arrange in columns and add: A. 5,087 + 26,542 B. 65,875 + 75,842

C. 45,735 + 69046 D. 93,485 + 48,294 E. 2,87,635 + 26,542

Answers for H.W of 5.4.2020:

A. 5,087 + 26,542 = 31,629 B. 65,875 + 75,842 = 1,41,717

C. 45,735 + 69,046 = 1,14,781 D. 93,485 +48294 = 1,41,779

E. 2,87,635 + 26,542 = 3,14,177

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C.W. 6.4.2020 Addition of Large numbers

Example 1: Add 2,753+ 26,932 + 1, 47,841 Example 2: Add 54,567 + 45,765 + 12,636

L TTh Th H T O L TTh Th H T O 1 2 1 1 1 1 1 2 7 5 3 5 4 5 6 7

2 6 9 3 2 4 5 7 6 5

+ 1 4 7 8 4 1 + 1 2 6 3 6

1 7 7 5 2 6 1 1 2 9 6 8 _ Answer: Sum = 1,77,526 Answer: Sum = 1,12,968

H.W. of 6.4.2020

Arrange in columns and add: A. 51,487 + 456 + 2, 39,601

B. 1,11,321 + 56,789 + 45,987 C. 1,08,162 + 59,346 + 18,882

Answers for H.W of 6.4.20:

A. 51,487 + 456 + 2,39, 601 = 2,91,544

B. 1,11,321 + 56,789 + 45,987 = 2,14,097

C. 1, 08,162 + 59,346 + 18,882 = 1,86,390

C.W. 7.4.2020 Subtraction of Large numbers

Recalling what is subtraction and the related terms:

Terms like take away and find the difference imply subtraction. To answer questions like how many left, how many more, how many less, we do subtraction. Terms used in subtraction are minuend, subtrahend and the difference.

The number we subtract from is called the minuend. The number we subtract is called the subtrahend. The answer in subtraction is called the difference. 7 3 9 5 Minuend

- 3 2 8 2 Subtrahend

4 1 1 3 Difference

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Example 1: Find the difference: 48,259 – 37,146 and check your answer with addition.

TTh Th H T O Check: 1 1 1 1 3

4 8 2 5 9 + 3 7 1 4 6

- 3 7 1 4 6 4 8 2 5 9 Minuend

1 1 1 1 3

Answer: Difference = 1 1, 1 1 3

H.W of 7.4.2020 Subtract and check your answer with addition:

a) 93,542 – 78,645

b) 9, 38,743 – 78,243

c) 85290 – 74,882

Properties of Subtraction

A number subtracted from itself is equal to zero. 852 - 852 = 0 Zero subtracted from a number is equal to the number itself. 852 – 0 = 852 The properties of subtraction and the method of subtraction of large numbers are the same as they are for smaller numbers.

Example 3:

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Answers for H.W of 7.4.2020:

Solution: Check:

b) 9,38,743 – 78,243

Solution: Check:

c) 85,290 – 74,882

Solution: Check:

T Th Th H T O

1 1 1 1

1 4 8 9 7

+ 7 8 6 4 5

9 3 5 4 2

T Th Th H T O

8 12 14 13

9 3 5 4 12

- 7 8 6 4 5

1 4 8 9 7

Ans:

L T Th Th H T O

8

9 13 8 7 4 3

- 7 8 2 4 3

8 6 0 5 0 0

Ans:

L T Th Th H T O

1

8 6 0 5 0 0

+ 7 8 2 4 3

9 3 8 7 4 3

T Th Th H T O

4 8

8 5 12 9 10

- 7 4 8 8 2

1 0 4 0 8

Ans:

T Th Th H T O

1 1

1 0 4 0 8

+ 7 4 8 8 2

8 5 2 9 0

Minuend

Difference: 8,60,500

Minuend

Difference: 10, 408

Minuend

Difference: 14,897

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C.W 8.4.2020 Subtraction of Large numbers (Continued)

Example 1: Find the difference: 4, 39,235 - 1, 45,987 and check your answer with addition.

L TTh Th H T O

4 3 9 2 3 5

- 1 4 5 9 8 7

2 9 3 2 4 8

Answer: Difference = 2, 93,248

Example 2: Find the difference: 30,000 - 18,603 and check your answer with addition

TTh Th H T O

3 0 0 0 0

- 1 8 6 0 3

1 1 3 9 7

Answer: Difference = 11,397

Example 3: Find the difference: 40,001 - 27,505 and check your answer with addition.

TTh Th H T O

4 0 0 0 1

- 2 7 5 0 5

1 2 4 9 6

Answer: Difference = 12,496 H.W of 8.4.2020

Subtract and check your answer with addition

a) 21,976 – 8,756 b) 50,001 – 39,846 c) 20,106 – 15,302 d) 81,065 – 21,952

Check: 2 9 3 2 4 8

+ 1 4 5 9 8 7

4 3 9 2 3 5 Minuend

Check: 1 1 3 9 7

+ 1 8 6 0 3

3 0 0 0 0 Minuend

Check: 1 2 4 9 6

+ 2 7 5 0 5

4 0 0 0 1 Minuend

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Solutions / Answers for H.W of 8.4.2020

Subtract and check your answer with addition:

a) 21,976 – 8,756

Check:

b) 50,001 – 39,846

Check:

c) 20,106 – 15,302 Check:

d) 81,065 – 21,952 Check:

T Th Th H T O

1

2 11 9 7 6

- 8 7 5 6

1 3 2 2 0

Ans:

T Th Th H T O

1

1 3 2 2 0

+ 8 7 5 6

2 1 9 7 6

T Th Th H T O

4 9 9 9

5 10 0 0 11

- 3 9 8 4 6

1 0 1 5 5

Ans:

T Th Th H T O

1 1 1 1

1 0 1 5 5

+ 3 9 8 4 6

5 0 0 0 1

T Th Th H T O

1 1

4 8 0 4

+ 1 5 3 0 2

2 0 1 0 6

T Th Th H T O

1 9 8

2 10 11 0 6

- 1 5 3 0 2

0 4 8 0 4

Ans:

T Th Th H T O

7 10

8 1 10 6 5

- 2 1 9 5 2

5 9 1 1 3

Ans:

T Th Th H T O

1 1

5 9 1 1 3

+ 2 1 9 5 2

8 1 0 6 5

Difference: 10, 155

Minuend

Difference: 13,220

Minuend

Minuend

Difference: 4, 804

Difference: 59,113

Minuend

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9.4.2020 C.W. Problem Solving in Addition and Subtraction

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Solution for H.W given on 9.4.2020

No. of motorbikes produced by a factory in the year 2015 = 28,900 No. of motorbikes not sold in the year 2015 = 4,795 No. of motorbikes sold in the year 2015 = 24,105 (28,900 – 4,795) Answer: No. of motor bikes sold in 2015 were = 24,105

C.W. 12.4.2020 Problem Solving (Continued)

a) Sushil’s car travelled 25,384 km in one year and Suraj’s car travelled 30,001 km in the

same year. How many kilometres less did Sushil’s car run?

Solution

Distance Sushil’s car travelled in a year = 25,384 km 3 0 0 10 1 Distance Suraj’s car travelled in that year = 30,001 km Distance Sushil’s car travelled less by = 4,617 km (30,001 km – 25,384 km) Answer: Sushil’s car ran less by 4,617 km

H.W of 9.4.2020

Write Correct Statements and solve the following in your Math Notebook.

1) A factory produced 28,900 motorbikes in the year 2015. Out of these 4,795 motorbikes were not sold. Find out how many motorbikes were sold in 2015.

1 1

2 8 9 0 0 - 4 7 9 5 2 4 1 0 5 Check: 4795 + 24105

28900

1

9 2

1

9 9

1

30001 - 25384 4617 Check: 4617 + 25384

30001

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b) Mr. Shenoy had Rs. 3, 25,765. He borrowed Rs.1, 12,700 to buy a new car. How much did

the car cost?

Solution

Amount Mr.Shenoy had = Rs. 3, 25,765 Amount he borrowed to buy a car = Rs. 1, 12,700 The cost of the car = Rs. 4, 38,465 (Rs. 3,25,765 + Rs. 1,12,700)

Answer: The cost of the car = Rs.4, 38,465

H.W of 12.4.2020

Write correct statements and solve the following :

1) In an examination 3, 59,089 boys and 4, 23, 085 girls participated. Find the number of students participated in the examination. 2) The population of a town in the year 1995 was 6, 80,301 and it increased by 1,52,028 in the year 2000. Find the population in the year 2000.

Solution for H.W of 12.4.2020

1) In an examination 3, 59,089 boys and 4, 23, 085 girls participated. Find the number of students participated in the examination. No. of boys participated in an examination = 3,59,089 No. of girls participated in the examination = 4, 23,085 Total No. of students participated = 7, 82,174 (3,59,089 + 4,23,085) Answer: No. of students participated in the exam = 7, 82,174 2) The population of a town in the year 1995 was 6, 80,301 and it increased by 1, 52,028 in the year 2000. Find the population in the year 2000.

Solution The population of a town in 1995 = 6, 80,301 Increase of the population in 2000 = 1, 52,028 The population in 2000 = 8, 32,329 (6,80,301 + 1,52,028) Answer: The population of the town in 2000 = 8,32,329

1

325765

+ 112700

438465

3,59,089 + 4,23,085 7,82,174

6 8 0 3 0 1

+ 1 5 2 0 2 8

8 3 2 3 2 9

680301 + 152028 832329

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C.W 13.4.2020 Missing Addend

Missing Addend = Sum – Given Addend Solve:-

Example 1: A pen drive can hold 530 songs. So far 391 songs have been copied on to it. How many more songs can be copied on to the pen drive?

Example 2: What must you add to 7,328 to make it 14,095?

7,328 + ___________ = 14,095

Missing Addend = Sum - Given Addend

= 14,095 - 7,328

= 6,767

Answer: 6,767 must be added to 7,328 to make it 14,095.

Example 3:

Solve :- 7,394 + _________ = 12,642

Missing Addend = Sum - Given Addend

= 12,642 - 7,394

= 5,248

Answer: 7,394 + 5,248 = 12,642

H.W of 13.4.2020

Solve following questions in your note book:-

a) 612 + _______ = 948 b) What must you add to 18,345 to make it 19,624? c) The sum of two numbers is 40,132. If one number is 29,184, find the other number.

Total number of songs a pen drive can hold

530

391 + ______ = 530

Number of songs already copied

391 530

- 391

Number of songs yet to be copied(530 – 391)

139 139

Answer: 139 more songs can be copied on to the pen drive.

14095 - 7328 6767

12642 - 7394 5248

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Solutions for H.W of 13.4.2020

a) 612 + _______ = 948

Solution:

Missing Addend = Sum - Given Addend 948 = 948 - 612 -612 = 336 336 Ans:- 612 + 336 = 948 b) What must you add to 18,345 to make it 19,624? Solution:-

Given Addend = 18,345 19624

Sum = 19,624 -18345

Missing Addend = Sum – Given Addend 01279 = 19,624 – 18,345

= 1,279

Ans:- 1,279 must be added to 18,345 to make it 19,624

c) The sum of two numbers is 40,132. If one number is 29,184, find the other number.

Solution:-

Sum of 2 numbers = 40,132 Given number = 29,184 40132 Missing Addend = Sum - Given Addend -29184 10948 = 40,132 – 29,184

= 10,948 Answer:- 29,184 + 10,948 = 40,132

C.W 14.4.2020 Missing Minuend

Missing Minuend = Subtrahend + Difference Solve:- a) _______ - 847 = 1,238

Solution:-

Missing Minuend = Subtrahend + Difference = 847 + 1,238 1238 = 2,085 + 847 Answer:- 2,085 - 847 = 1,238 2085

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b) If you subtract 23,146 from a number, you are left with 35,906. Find the number.

Solution:-

Number subtracted (Subtrahend) 23,146 ______ - 23,146 = 35,906

Number left (Difference) 35,906

Missing Minuend

Subtrahend + Difference = 23,146 + 35,906 = 59,052

23146 +35906 59052

Answer:- 59,052 - 23,146 = 35,906

c) A large library has lent out 1,785 books. It has 7,816 books left. How many books does the library have in all?

Solution:-

Number of books lent out (Subtrahend)

1,785

____ - 1,785 = 7,816

Number of books left (Difference)

7,816

1785 +7816 9601

Total number of books in the library (Minuend)

Subtrahend + Difference = 1,785 + 7,816 = 9,601

Answer: The library has 9,601 books in all

H.W of 14.4.2020

Solve:-

a) _________ - 9,162 = 1,811

Solution for the H.W of 14.04.2020

Solve:-

a) _________ - 9,162 = 1,811

Solution:- 9162

Missing Minuend = Subtrahend + Difference +1811

= 9,162 + 1,811 10973

= 10,973

Answer:- 10,973 - 9,162 = 1,811

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C.W 15.4.2020 Missing Subtrahend

Missing subtrahend = Minuend - Difference

Solve:-

a) 9,408 - __________ = 1,138

Solution:- 9408

Missing Subtrahend = Minuend - Difference -1138

= 9,408 - 1,138 8270

= 8,270

b) Find the number which must be subtracted from 83,196 to leave 11,422

Solution:-

Minuend

83,196

83196 - ______ = 11422

Difference

11,422

Subtrahend

Minuend – Difference

= 83,196 - 11,422 = 71,774

83196 - 11422 71774

Ans:- 71,774 must be subtracted from 83,196 to leave 11,422

c) An art exhibition had 915 pieces of art on show. Some of them got sold but there

were 211 unsold pieces. How many pieces were sold?

Total number of pieces of art on show (Minuend)

915

915 - _____ = 211

Number of unsold pieces (Difference)

211

Number of sold pieces (Subtrahend)

Minuend - Difference = 915 - 211 = 704

915 -211 704

Answer:- 704 pieces of art were sold.

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H.W of 15.4.2020

Solve :- 1) 49,584 - __________ = 23175

Solution for H.W of 15.04.2020

Solve:-

1) 49,584 - __________ = 23,175 49584 Solution:- -23175

Missing Subtrahend = Minuend - Difference 26409 = 49,584 - 23175 = 26,409

Ans:- 49,584 - 26,409 = 23,175

C.W 16.04.2020 Solve:-

a) Harshita’s stamp album can hold 1,500 stamps. So far she has pasted 785 stamps in it. How many more stamps can she paste in it?

No. of stamps Harshita’s stamp album can hold

1,500

1500 = 785+ _____

No of stamps she pasted 785

No. of more stamps she can paste = 1,500 - 785 = 715

1500 -785 715

Ans:- Harshita can paste 715 more stamps .

b) 1,328 people were waiting to enter an exhibition. At noon 737 people were still waiting to enter, how many people had already entered?

Total number of people waiting to enter an exhibition

1,328 1328 - _____ = 737

Number of people still waiting to enter 737

Number of people had already entered

= 1,328 - 737 = 591

1328 -737 591

Answer:- 591 people had already entered .

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c) A truck was carrying a load of mangoes. It deposited 302 kg at the first market. It is still carrying 942 kg. How many kilograms of mangoes did it have in the beginning?

Weight of mangoes deposited at the first market

302 kg

____ - 302kg = 942kg

Weight of mangoes the truck is still carrying (left in the truck)

942 kg

Weight of mangoes the truck had in the beginning

= 302 kg+ 942 kg = 1,244 kg

302 +942 1244

Answer:- The truck had 1,244 kg of mangoes in the beginning.

H.W of 16.4.2020

Write statements and solve the following:

a) Khalid wants to buy a board game that costs ₹ 501. He has ₹ 479. How much more money does he need?

Solution for H.W of 16.04.2020

Ans :- Khalid need ₹22 more to buy the board game

Cost of a board game that Khalid wants to buy

₹501

₹ 501 = ₹ 479 + _____

Money he has

₹479

Money he needs more

= ₹ 501 - ₹ 479

= ₹ 22

501 -479 022