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Over Lesson 10–2 A. A B. B C. C D. D 114

Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

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Page 1: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Over Lesson 10–2

A. A

B. B

C. C

D. D

114

Page 2: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Over Lesson 10–2

A. A

B. B

C. C

D. D

66

Page 3: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Over Lesson 10–2

A. A

B. B

C. C

D. D

125

Page 4: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Over Lesson 10–2

A. A

B. B

C. C

D. D

150

Page 5: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Over Lesson 10–2

A. A

B. B

C. C

D. D

210

Page 6: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

• Recognize and use relationships between arcs and chords.

• Recognize and use relationships between arcs, chords, and diameters.

Page 9: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Use Congruent Chords to Find Arc Measure

Jewelry A circular piece of jade is hung from a

chain by two wires around the stone.

JM KL and = 90. Find .

Page 10: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Use Congruent Chords to Find Arc Measure

Page 11: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

A. A

B. B

C. C

D. D

85

Page 12: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Use Congruent Arcs to Find Chord Lengths

Page 13: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Use Congruent Arcs to Find Chord Lengths

WX = YZ Definition of congruent segments

7x – 2 = 5x + 6 Substitution

2x = 8 Add 2 to each side.

x = 4 Divide each side by 2.

So, WX = 7x – 2 = 7(4) – 2 or 26.

Answer: WX = 26

Page 14: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

A. A

B. B

C. C

D. D

13

Page 16: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Use a Radius Perpendicular to a Chord

Answer:

Page 17: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

A. A

B. B

C. C

D. D

80

Page 18: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Use a Diameter Perpendicular to a Chord

CERAMIC TILE In the ceramic stepping stone

below, diameter AB is 18 inches long and chord EF

is 8 inches long. Find CD.

Page 19: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Use a Diameter Perpendicular to a Chord

Step 1 Draw radius CE.

This forms right ΔCDE.

Page 20: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Use a Diameter Perpendicular to a Chord

Step 2 Find CE and DE.

Since AB = 18 inches, CB = 9 inches. All

radii of a circle are congruent, so

CE = 9 inches.

Since diameter AB is perpendicular to EF,

AB bisects chord EF by Theorem 10.3. So,

DE = (8) or 4 inches.__12

Page 21: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Use a Diameter Perpendicular to a Chord

Step 3 Use the Pythagorean Theorem to find CD.

CD2 + DE2 = CE2 Pythagorean

Theorem

CD2 + 42 = 92 Substitution

CD2 + 16 = 81 Simplify.

CD2 = 65 Subtract 16 from each

side.Take the positive

square root.

Answer:

Page 22: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

A. A

B. B

C. C

D. D

4.90

In the circle below, diameter QS is 14 inches long and chord RT is 10 inches long. Find VU to the nearest hundredth.

Page 24: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Chords Equidistant from Center

Since chords EF and GH are congruent, they are

equidistant from P. So, PQ = PR.

Page 25: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

Chords Equidistant from Center

PQ = PR

4x – 3 = 2x + 3 Substitution

x = 3 Simplify.

So, PQ = 4(3) – 3 or 9

Answer: PQ = 9

Page 26: Over Lesson 10–2 A.A B.B C.C D.D 5-Minute Check 1 114

A. A

B. B

C. C

D. D

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