V=A (base) •h

10=(x )(2x )( y )

10=2x2 y

y= 5

x2

D ( x , y )=3 (2 x2 )+2 [2 ( xy ) ]+2[2(2 xy )]

D ( x , y )=6x2+4 xy+8 xy

D ( x )=6 x2+ 40x2 x2

+ 80x2 x2

D ( x )=6 x2+ 20x

+ 40x

D ( x )=6 x2+ 60x

D' (x)=12x−60x2

12 x−60x2

=0

−60=−12x (x2)

60=−12x3

6012

=x3

3√5= 3√x3

x=1.70

D' ' ( x )=12+ 120 xx4

D' ' (1.70 )=12+ 120(1.70)(1.70)4

D' ' (1.70 )>0→D ( x )Tiene unMIN en x=1.70

y= 5

(1.70 )2=1.70 Por lo tanto , paraque el costo seaminimo x=1.70 y=1.70