11
Physics Letters B 614 (2005) 67–77 www.elsevier.com/locate/physletb Muon anomalous magnetic moment in a supersymmetric U(1) model Vernon Barger a , Chung Kao b , Paul Langacker c , Hye-Sung Lee a a Department of Physics, University of Wisconsin, Madison, WI 53706, USA b Department of Physics and Astronomy, University of Oklahoma, Norman, OK 73019, USA c Department of Physics and Astronomy, University of Pennsylvania, Philadelphia, PA 19104, USA Received 25 January 2005; received in revised form 7 March 2005; accepted 8 March 2005 Available online 29 March 2005 Editor: M. Cvetiˇ c Abstract We study the muon anomalous magnetic moment a µ = (g µ 2)/2 in a supersymmetric U(1) model. The neutralino sector has extra components from the superpartners of the U(1) gauge boson and the extra Higgs singlets that break the U(1) symme- try. The theoretical maximum bound on the lightest neutralino mass is much smaller than that of the Minimal Supersymmetric Standard Model (MSSM) because of the mixing pattern of the extra components. In a U(1) model where the U(1) symmetry is broken by a secluded sector (the S -model), tan β is required to be 3 to have realistic electroweak symmetry breaking. These facts suggest that the a µ prediction may be meaningfully different from that of the MSSM. We evaluate and compare the muon anomalous magnetic moment in this model and the MSSM and discuss the constraints on tan β and relevant soft breaking terms. There are regions of the parameter space that can explain the experimental deviation of a µ from the Standard Model calculation and yield an acceptable cold dark matter relic density without conflict with collider experimental constraints. 2005 Elsevier B.V. All rights reserved. 1. Introduction The anomalous magnetic moment of the muon a µ = (g 2) µ /2 is one of the most precisely measured physical quantities. Its current value from the Brookhaven National Laboratory E821 experiment is [1,2] (1) a µ (exp) = (11 659 208 ± 6) × 10 10 , which is a 2.4σ deviation from the Standard Model (SM) prediction (2) a µ a µ (exp) a µ (SM) = (23.9 ± 10.0) × 10 10 , E-mail address: [email protected] (H.-S. Lee). 0370-2693/$ – see front matter 2005 Elsevier B.V. All rights reserved. doi:10.1016/j.physletb.2005.03.042

Muon anomalous magnetic moment in a supersymmetric model

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Page 1: Muon anomalous magnetic moment in a supersymmetric model

b

r

mmetric

esemuons.n

ical

Physics Letters B 614 (2005) 67–77

www.elsevier.com/locate/physlet

Muon anomalous magnetic moment in a supersymmetricU(1)′ model

Vernon Bargera, Chung Kaob, Paul Langackerc, Hye-Sung Leea

a Department of Physics, University of Wisconsin, Madison, WI 53706, USAb Department of Physics and Astronomy, University of Oklahoma, Norman, OK 73019, USA

c Department of Physics and Astronomy, University of Pennsylvania, Philadelphia, PA 19104, USA

Received 25 January 2005; received in revised form 7 March 2005; accepted 8 March 2005

Available online 29 March 2005

Editor: M. Cvetic

Abstract

We study the muon anomalous magnetic momentaµ = (gµ − 2)/2 in a supersymmetricU(1)′ model. The neutralino sectohas extra components from the superpartners of theU(1)′ gauge boson and the extra Higgs singlets that break theU(1)′ symme-try. The theoretical maximum bound on the lightest neutralino mass is much smaller than that of the Minimal SupersyStandard Model (MSSM) because of the mixing pattern of the extra components. In aU(1)′ model where theU(1)′ symmetryis broken by a secluded sector (theS-model), tanβ is required to be 3 to have realistic electroweak symmetry breaking. Thfacts suggest that theaµ prediction may be meaningfully different from that of the MSSM. We evaluate and compare theanomalous magnetic moment in this model and the MSSM and discuss the constraints on tanβ and relevant soft breaking termThere are regions of the parameter space that can explain the experimental deviation ofaµ from the Standard Model calculatioand yield an acceptable cold dark matter relic density without conflict with collider experimental constraints. 2005 Elsevier B.V. All rights reserved.

1. Introduction

The anomalous magnetic moment of the muonaµ = (g − 2)µ/2 is one of the most precisely measured physquantities. Its current value from the Brookhaven National Laboratory E821 experiment is[1,2]

(1)aµ(exp) = (11 659 208± 6) × 10−10,

which is a 2.4σ deviation from the Standard Model (SM) prediction

(2)aµ ≡ aµ(exp) − aµ(SM) = (23.9± 10.0) × 10−10,

E-mail address: [email protected](H.-S. Lee).

0370-2693/$ – see front matter 2005 Elsevier B.V. All rights reserved.doi:10.1016/j.physletb.2005.03.042

Page 2: Muon anomalous magnetic moment in a supersymmetric model

68 V. Barger et al. / Physics Letters B 614 (2005) 67–77

ic

te altions

gs mass

n

arm-e

ecalcula-d if. Thess of a

-

y of itsls.ns,sns to

V-ies the

in

ew

ove the

when the hadronic vacuum polarization information is taken directly from the annihilation ofe+e− to hadrons[3]measured at CMD-2[4]. The uncertainties involved in Eq.(2) are 7.2 × 10−10 from the leading-order hadroncontribution[5], 3.5×10−10 from the hadronic light-by-light scattering[6], and 6×10−10 from theaµ experiment.The indirect hadronic information from the hadronicτ decay gives a higher SM value that does not indicasignificant discrepancy with the SM (only a 0.9σ deviation).1 Recently released KLOE data[8] show an overalagreement with the CMD-2 data[4], confirming that there is a discrepancy between the hadronic contribufrom thee+e− data and theτ data obtained from ALEPH, CLEO and OPAL[9].

New physics is expected to exist at the TeV-scale to resolve various theoretical problems, including Higstabilization, and new physics could give a significant contribution toaµ to explain the above deviation[10]. Therehave been extensive studies ofaµ in supersymmetric (SUSY) models[11], which show that supersymmetry canaturally explain the deviation of Eq.(2).

Theaµ data constrains the SUSY parameters, including the sign ofµ [12] and upper limits on relevant scaland fermion superpartner masses[13]. In the minimal supergravity model (mSUGRA) or the Minimal Supersymetric Standard Model (MSSM), the dominant additional contribution toaµ comes from the first-order radiativcorrections of the chargino–sneutrino and the neutralino–smuon loops; it is

(3)aµ(SUSY) ∼ 13× 10−10 tanβ sign(µ)

(MSUSY/100 GeV)2

in the limit that all the supersymmetric masses are degenerate atMSUSY [14]. The 2-loop corrections involvsfermion subloops or chargino/neutralino subloops and are at about the few percent level, although fulltions are not yet complete[15]. The discrepancy in Eq.(2) shows that a supersymmetry solution can be founsign(µ) > 0 andMSUSY 700 GeV for tanβ 50, in the limit that supersymmetric masses are degeneratedeviation ofaµ similarly gives constraints on the parameters of other new physics models including the masecond generation leptoquark[16], the mass of the heavy photon in the little Higgs model[17] and the compactification scale of an extra dimension[18].

Given thataµ has been a powerful tool for constraining the new physics models, due to the accuracmeasurement and the SM evaluation, it is interesting to pursue whataµ can tell about recently emerging modeThe recent idea of split supersymmetry assumes large masses (e.g., 1010 GeV) for scalar superpartners (sleptosquarks) while keeping fermionic superpartners (gauginos, higgsinos) at the TeV-scale[19]. The large masseof the smuon and sneutrino would make the chargino–sneutrino and neutralino–smuon loop contributioaµ

negligible; the split supersymmetry model would be rejected if the deviation ofaµ is in fact real.Another interesting TeV-scale new physics model is the supersymmetricU(1)′ model[20,21]. It has a structure

similar to the MSSM but has an extraU(1) gauge symmetry(U(1)′), which is spontaneously broken at the Tescale by one or multiple Higgs singlets. This model can provide natural solutions to some of the difficultMSSM faces, including the explanation of the electroweak scale of theµ parameter (µ-problem[22]) and thelack2 of a sufficiently strong first-order phase transition for electroweak baryogenesis (EWBG)[24]. The Next-to-Minimal Supersymmetric Standard Model (NMSSM)[25] can also resolve theµ-problem but its discreteZ3symmetry invokes a cosmological domain wall problem[26]; a variant which avoids this problem is discussedRefs.[27,28].

Besides the bottom-up reasons to introduce an additionalU(1) symmetry to supplement the MSSM, many nphysics models, including grand unified theories (GUTs), extra dimensions[29], superstrings[30], little Higgs[31],dynamical symmetry breaking[32] and Stueckelberg mechanism models[33] predict extraU(1) symmetries or

1 For a recent review of the various SM predictions and theaµ discrepancies, see Ref.[7].2 The required strong first-order phase transition for EWBG is allowed in the MSSM only if the light Higgs mass is only slightly ab

LEP experimental bound and the light stop mass is smaller than the top mass[23].

Page 3: Muon anomalous magnetic moment in a supersymmetric model

V. Barger et al. / Physics Letters B 614 (2005) 67–77 69

di-

.roups ord

at

ak)

l values

eds

e

oftences

sion

lly

gauge bosons. The newly introduced particles such as theU(1)′ gauge boson(Z′) and theU(1)′ breaking Higgssinglet(S) and their superpartnersZ′-ino (Z′) and singlino(S), alter the Higgs and neutralino spectra. The mofied Higgs spectrum[34] and the neutralino relic density[35] have been recently studied in theU(1)′ model witha secludedU(1)′ symmetry breaking sector[21], and the difference in the predictions from the MSSM detailed

There have been studies of the muon anomalous magnetic moment in models with additional gauge gE6 GUT [36–38]. They mostly concentrated on the loops including theZ′ or the exotic quarks in the model antheir superpartners, and constraints were obtained on their masses or couplings. To explain theaµ deviation, theZ′ masses should be typically smaller than the experimental limits ofMZ′ 500–800 GeV from direct searchesthe Tevatron[39,40].

In this Letter we quantitatively study a supersymmetricU(1)′ model with a secludedU(1)′ symmetry breakingsector (theS-model)[21] to see how the extended neutralino sector contribution toaµ is different from the MSSMprediction. The superpotential in this model is

(4)W = hsSH1H2 + λsS1S2S3,

wherehs andλs are dimensionless parameters. Theµ-problem is solved by replacing theµ term by an effectiveµparameter

(5)µeff = hss/√

2,

wheres/√

2 is the vacuum expectation value (VEV) of the Higgs singletS that acquires a VEV at the electroweor TeV scale. TheZ′ has a large mass generated by the Higgs singlet fieldsS1,2,3, which acquire large (TeV scaleVEVs for smallλs because of an almostF andD flat direction. The extra Higgs singlets allowµeff to be at theelectroweak scale while keeping theZ′ heavier than the experimental limit.

The electroweak symmetry breaking is driven by electroweak scale trilinear soft terms, leading to smalfor tanβ ≡ v2/v1 (tanβ ∼ 1 to 3), while solutions without unwanted global minima at〈H 0

i 〉 = 0 typically have〈S〉 1.5〈H 0

i 〉 [21]. A small tanβ implies a problem in the MSSM; for example, the light Higgs mass nelarge tanβ (for reasonable superpartner masses) to satisfy the LEP bound ofmh > 115 GeV. The mixing of theHiggs doublets and singlets in theS-model, however, lowers the LEPmh bound significantly[34]. Furthermore,the maximum theoretical value formh for a given tanβ is increased, both byF -terms (similar to effects in thNMSSM [25,34]) and byD-terms[41]. As a result, tanβ ∼ 1–3 is experimentally allowed in theS-model.

The neutralinos in theS-model have extra components of theZ′-ino and singlinos. The lightest neutralinotheU(1)′ model is often very light because of the mixing pattern of the extra components. Eq.(3) suggests thaaµ in this model may be significantly different from that of the MSSM. We numerically investigate the differand obtain constraints on tanβ and the relevant soft breaking terms. We do not includeZ′ loops since theZ′ massbounds from direct searches at colliders imply negligible effects.

In Section2 we describe the formalism to compute the chargino and neutralino contributions in theS-model. InSection3, we give the numerical analysis ofaµ and make comparisons to the MSSM results, before the concluin Section4.

2. Supersymmetric contributions to aµ with U(1)′ symmetry

In this section we describe the neutralino and chargino contributions toaµ in the S-model (seeFig. 1). Theformalism is similar to the MSSM with a straightforward extension. We assume that the VEVs of theS1,2,3 arelarge compared to the VEVs of other Higgs fields (H 0

1 , H 02 andS) and that their singlino components essentia

decouple[21,34].

Page 4: Muon anomalous magnetic moment in a supersymmetric model

70 V. Barger et al. / Physics Letters B 614 (2005) 67–77

ted

e

stse

Fig. 1. Supersymmetric contributions toaµ involving charginos and neutralinos.

2.1. Neutralino contribution

Ignoring theS1,2,3 singlinos, the neutralino mass matrix in the basisB, W3, H01 , H 0

2 , S, Z′ is given by

(6)Mχ0 =

M1 0 −g1v1/2 g1v2/2 0 00 M2 g2v1/2 −g2v2/2 0 0

−g1v1/2 g2v1/2 0 −hss/√

2 −hsv2/√

2 gZ′Q′(H 01 )v1

g1v2/2 −g2v2/2 −hss/√

2 0 −hsv1/√

2 gZ′Q′(H 02 )v2

0 0 −hsv2/√

2 −hsv1/√

2 0 gZ′Q′(S)s

0 0 gZ′Q′(H 01 )v1 gZ′Q′(H 0

2 )v2 gZ′Q′(S)s M1′

,

wheree = g1 cosθW = g2 sinθW ; gZ′ is theU(1)′ gauge coupling constant, for which we take the GUT motivavalue ofgZ′ = √

5/3g1. Q′ is theU(1)′ charge, and the anomaly-free charge assignments based onE6 GUT canbe found in Ref.[42].

The VEVs of the Higgs doublets are〈H 0i 〉 ≡ vi/

√2 with

√v2

1 + v22 246 GeV. The diagonalization of th

mass matrix can be accomplished using a unitary matrixN ,

(7)NT Mχ0N = Diag(Mχ0

1,Mχ0

2,Mχ0

3,Mχ0

4,Mχ0

5,Mχ0

6

).

The first 4×4 (5×5) submatrix of Eq.(6) is the MSSM (NMSSM) limit. Due to the singlino addition, there exia kind of see-saw mechanism that makes the lightest neutralino very light[28,43], less than 100 GeV in the casof M1′ M1 (where theZ′ practically decouples and the mass matrix becomes the NMSSM limit)[35]. We will

consider both this limit and that in which the gaugino mass unification relation,M1′ = M1 = 53

g21

g22M2 0.5M2, is

satisfied.The smuon mass-squared matrix is given by

(8)M2µ =

(M2

LL M2LR

M2RL M2

RR

),

(9)M2LL = m2

L+ m2

µ + (T3µ − Qµ sin2 θW

)M2

Z cos2β,

(10)M2RR = m2

E+ m2

µ + (Qµ sin2 θW

)M2

Z cos2β,

(11)M2LR = mµ

(A∗

µ − µeff tanβ),

(12)M2RL = (

M2LR

)∗.

Its diagonalization can be accomplished through the unitary matrixD as

(13)D†M2µD = Diag

(M2

µ1,M2

µ2

).

Page 5: Muon anomalous magnetic moment in a supersymmetric model

V. Barger et al. / Physics Letters B 614 (2005) 67–77 71

d. We

hehe loop

d

The LEP2 SUSY Working Group analysis foundmµR 95 GeV fromµ → µχ0

1,2 searches[44]. Sincemµ

is small compared to supersymmetric parameters, the off-diagonal terms of Eq.(11) and Eq.(12) are small andhence the mixing is small. For tanβ 1, bothm2

L, m2

E (95 GeV)2 are required to givemµ1 95 GeV from the

tree-level mass matrix of Eq.(8), while for tanβ 1, somewhat larger values of these parameters are requirerequire bothm2

Landm2

Eto be larger than(100 GeV)2 and takeAµ = 0 in our numerical analysis.

The neutralino contribution toaµ is then[11]

(14)aµ

(χ0) = a1

µ

(χ0) + a2

µ

(χ0),

where

(15)a1µ

(χ0) =

6∑j=1

2∑k=1

8π2Mχ0j

Re[LjkR

∗jk

]F1

(M2

µk/M2

χ0j

),

(16)a2µ

(χ0) =

6∑j=1

2∑k=1

m2µ

16π2M2χ0

j

(|Ljk|2 + |Rjk|2)F2

(M2

µk/M2

χ0j

),

with the followingµ–µ–χ0 chiral coupling:

(17)Ljk = 1√2

(g1YµL

N∗1j − g2N

∗2j + gZ′Q′(µL)N∗

6j

)D1k +

√2mµ

v1N∗

3jD2k,

(18)Rjk = 1√2

(g1YµR

N1j + gZ′Q′(µR)N6j

)D2k +

√2mµ

v1N3jD1k.

YµL= −1, YµR

= 2 are hypercharges and the terms withgZ′ coupling are the additional contributions from tU(1)′. Sincemµ is small compared to the supersymmetric masses, we can approximate it as zero in tintegral functions to obtain

(19)F1(x) = 1

2

1

(x − 1)3

(1− x2 + 2x lnx

),

(20)F2(x) = 1

6

1

(x − 1)4

(−x3 + 6x2 − 3x − 2− 6x lnx).

2.2. Chargino contribution

The chargino mass matrix is given by

(21)Mχ± =(

M2√

2MW sinβ√2MW cosβ hss/

√2

).

It is essentially the same as in the MSSM except thatµ is replaced byµeff = hss/√

2. Mχ± can be diagonalizeby two unitary matricesU andV as

(22)U∗Mχ±V −1 = Diag(Mχ±

1,Mχ±

2

).

The LEP light chargino mass limitMχ− 104 GeV[45] gives constraints onM2 andµeff for a fixed value oftanβ. The sneutrino mass-squared is given by

(23)M2νµ

= m2L

+ T3νM2Z cos2β.

As in the MSSM calculations, we do not include the right-handed neutrino or its superpartner.

Page 6: Muon anomalous magnetic moment in a supersymmetric model

72 V. Barger et al. / Physics Letters B 614 (2005) 67–77

alues

it

both the

r

nsity in

mass

too

The chargino loop contribution toaµ is [11]

(24)aµ(χ−) = a1µ(χ−) + a2

µ(χ−),

where

(25)a1µ(χ−) =

2∑j=1

1∑k=1

8π2Mχ−j

Re[LjkR

∗jk

]F3

(M2

νµ/M2

χ−j

),

(26)a2µ(χ−) = −

2∑j=1

1∑k=1

m2µ

16π2M2χ−

j

(|Ljk|2 + |Rjk|2)F4

(M2

νµ/M2

χ−j

),

with the chiralµ–νµ–χ− couplings

(27)Lj1 =√

2mµ

v1U∗

j2, Rj1 = −g2Vj1.

The loop integral functions are

(28)F3(x) = −1

2

1

(x − 1)3

(3x2 − 4x + 1− 2x2 lnx

),

(29)F4(x) = −1

6

1

(x − 1)4

(2x3 + 3x2 − 6x + 1− 6x2 lnx

).

3. Analysis

The MSSM can explain the 2.4σ deviation between the E821 experiment and the SM prediction for most vof tanβ. In this section, we compare predictions from the MSSM with those of theS-model.

Fig. 2(a) showsaµ in theM2–s (alsoM2–µ) plane for the MSSM (filled circles), theS-model and its NMSSMlimit (dark shading), with tanβ = 2.5 andmsmuon≡ m

L= m

E= 100 GeV. The comparison is made forµ = µeff.

The corresponding plot for theS-model withM1′ = M1 is hardly distinguishable from that of the NMSSM limso it is not shown in the figure. The plots are the parameter spaces that can give valuesaµ × 1010 = 13.9–33.9favored by Eq.(2). The parameter space excluded by the LEP chargino mass limit ofMχ− > 104 GeV is shownas the lightly shaded area outlined by solid curves. Throughout the following analysis (Figs. 3 and 4), we donot include the parameter points that violate the LEP chargino mass constraint. This figure shows thatMSSM3 and theS-model (including the NMSSM limit) can explain theaµ data with small tanβ while satisfyingmsmuon 100 GeV from the experimental bound on the scalar muon mass. TheS-model gives only a slightly largearea in the parameter space than the MSSM. For theS-model,hs = 0.75, and theE6 motivatedη-model4 chargeassignments are assumed[42].

It is interesting to note that in theM1′ M2 case5 (NMSSM limit), a sizable part of theaµ 2.4σ deviationsolution area overlaps the solution area which reproduces the observed cold dark matter (CDM) relic dethe same framework and limit[35] as shown inFig. 2(b). The filled squares have the WMAP 3σ allowed range of0.09< Ωχ0h2 < 0.15, the open circles haveΩχ0h2 < 0.09 and the crosses have 0.15< Ωχ0h2 < 1.0. In the eventthat theaµ deviation from the SM is real, this CDM result enhances the viability of the model. The chargino

3 It should be emphasized that the MSSM cannot accept this small tanβ if we consider other constraints: the light Higgs mass would besmall to be compatible with the LEP Higgs mass bound ofmh > 115 GeV.

4 Theη-model is aU(1)′ model that is produced with a unique set of charge assignments whenE6 is broken to a rank-5 group.5 The CDM expectations for smallerM have not yet been examined.

1′
Page 7: Muon anomalous magnetic moment in a supersymmetric model

V. Barger et al. / Physics Letters B 614 (2005) 67–77 73

n hast-

rhave

islimit, a

ydensity.

is

.llrict

it

alue

r muon

Fig. 2. (a) aµ in the MSSM (filled circles) and the NMSSM limit(M1′ M2) of the S-model (dark shading) for tanβ = 2.5and msmuon= 100 GeV. For theS-model, hs = 0.75 andη-model charges are assumed. The region outside the NMSSM regioaµ × 1010 < 13.9, while the island inside the NMSSM region (aroundM2 ∼ 100 GeV) hasaµ × 1010 > 33.9. The lightly shaded area oulined by solid curves is excluded by the LEP chargino mass limitMχ− > 104 GeV. Theaµ have values 13.9 aµ × 1010 33.9 favoredby Eq.(2). The models give similaraµ results and all the models allow small tanβ for msmuonsmall(∼ 100 GeV). (b) The solution space fothe acceptable neutralino relic density[35] and the(g − 2)µ deviation are shown together for the same NMSSM limit. The filled squaresthe WMAP 3σ allowed range of 0.09< Ω

χ0h2 < 0.15, the open circles haveΩχ0h2 < 0.09 and the crosses have 0.15< Ω

χ0h2 < 1.0.

allowed by both theaµ deviation and the relic density is 104 GeV Mχ± 220 GeV, where the lower boundthe present experimental limit. Since the chargino mass could be only slightly larger than the present LEPsearch for the SUSY trilepton signal at the Tevatron Run II will be very interesting[46]. It should be noted that onltheZ-pole annihilation channel was considered to show this model could reproduce the acceptable relicThere could be a larger solution space when more channels are considered.

We now consider the limits on tanβ and msmuon that allow the favored range ofaµ. Fig. 3(a) shows themaximumaµ as a function of tanβ in theS-model (withM1′ = M1). The MSSM curve is nearly the same, asthe NMSSM limit(M1′ M2) of theS-model.M2 is scanned from 100 GeV to 1000 GeV,µ (µeff) from 100 GeVto 1000 GeV (negativeµ is nearly irrelevant for producing positiveaµ), andmsmuonfrom 100 GeV to 500 GeVThis figure demonstrates the almost linear dependence on tanβ, as in Eq.(3), and shows that even with smatanβ, both models are able to produce the favored values ofaµ. Smaller tanβ, however, has less supersymmetparameter space that explains the deviation. The maximum values ofaµ havemsmuon∼ 100 GeV (the lowesscan value).

Since the chargino contribution is the same in the MSSM and theS-model, the dominant difference inaµ wouldcome from the lightest neutralino (χ0

1 ) contribution. The mass and the coupling ofχ01 in theS-model is similar to

that of the MSSM. In the NMSSM limit(M1′ M1), χ01 is often significantly lighter than that of the MSSM but

is mostly singlino-like which couples to the muon only through mixing;χ02 is mostly similar toχ0

1 of the MSSM.Fig. 3(b) shows the maximumaµ as a function ofmsmuonin theS-model; the MSSM curve is nearly identic

when tanβ is scanned only from 1 to 3. The maximum points have tanβ ∼ 3 (the highest scan value). A large valof tanβ, as more generalU(1)′ models allow, would always ensure a sufficiently large maximumaµ for a givenmsmuon. This figure demonstrates the roughly inverse-squared dependence onmsmuonas in Eq.(3). It also showsthat, for small tanβ, the scalar muon should be light(100 GeV Mµ 180 GeV) to explain theaµ deviation.This could in principle lead to a concern for the neutralino cold dark matter candidate, since the scala

Page 8: Muon anomalous magnetic moment in a supersymmetric model

74 V. Barger et al. / Physics Letters B 614 (2005) 67–77

re

es

ith the.g.,ameterwill beCollider

Fig. 3. Maximumaµ versus (a) tanβ and (b)msmuonin theS-model withM1′ = M1. The MSSM result and the NMSSM limit(M1′ M2)

are nearly indistinguishable from theM1′ = M1 curve and are not plotted.M2 is scanned from 100 GeV to 1000 GeV, andµ (µeff) from100 GeV to 1000 GeV.msmuonis scanned from 100 GeV to 500 GeV for (a), and tanβ from 1 to 3 for (b). Horizontal dashed-dot lines aboundaries of the measured deviationaµ × 1010 = 13.9–33.9 of Eq.(2).

Fig. 4. Maximumaµ versusM2 in (a) the MSSM and (b) theS-model. The dotted curves takeM1 as a free parameter while the solid onfollow the gaugino mass unification relation(M1′ = M1 0.5M2). µ (µeff) is scanned from 100 GeV to 1000 GeV,M1 (for dotted curves)from 50 GeV to 1000 GeV, tanβ from 1 to 3, andmsmuon from 100 GeV to 500 GeV. WhenM1 is a free parameter, we takeM1′ M2(NMSSM limit) for theS-model (dotted curve). In both models, the maximum values ofaµ occur forM1 ∼ 50 GeV whenM1 is taken as afree parameter.

could be light enough to be the lightest supersymmetric particle (LSP). A charged LSP would conflict wobservational absence of exotic isotopes. In theS-model, however, the lightest neutralino is usually very light, eMχ0

1 100 GeV, while it produces the acceptable range of the relic density for a wide range of the par

space[35]. One can therefore have a light slepton with an even lighter neutralino as the LSP. A light sleptonobservable in future accelerators such as the CERN Large Hadron Collider (LHC) and International Linear(ILC). Light sleptons could be detected easily at a linear collider of a moderate energy of 500 GeV.

Page 9: Muon anomalous magnetic moment in a supersymmetric model

V. Barger et al. / Physics Letters B 614 (2005) 67–77 75

ose.

the

muon isarkable

duceshesolutionic

tralinoixing;o mass

ofareg

R40896,iscon-

Fig. 4 shows the maximumaµ as a function ofM2 in both models. For the dotted curves, we do not impthe gaugino mass unification assumption ofM1′ = M1 0.5M2, and we scanM1 from 50 GeV to 1000 GeVThis figure shows that independentM1 can make quite a difference for a fixedM2 whenM2 is large. ForFig. 3, arelaxation of gaugino mass unification would not make much difference since the maximumaµ mostly happensfor small M2.6 In the S-model we do not relaxM1′ as a free parameter for the dotted curve, but rather takeNMSSM limit (M1′ M2) and relax onlyM1. UnlessM1′ is very small (smaller than theM1 scan limit of 50 GeV),it would not increase the maximumaµ significantly. For a wide range ofM2 (and practically for anyM2 in thecase thatM1 is a free parameter), both models can produce the favoredaµ. The maximumaµ have tanβ ∼ 3,msmuon∼ 100 GeV (andM1 ∼ 50 GeV for the dotted curves).

4. Conclusion

Unlike the MSSM, the electroweak symmetry breaking condition in theS-model requires small tanβ. Moreover,the LEP smuon mass bound requires slepton masses above about 100 GeV. On the other hand, the 2.4σ deviationof the muon anomalous magnetic moment favors large tanβ and small slepton soft terms. Theaµ determinationgives the most severe constraint on tanβ and slepton masses in theS-model; nonetheless, theS-model can stillexplain the deviation while satisfying the chargino and smuon mass limits. Since the mass of the light sconstrained to be less than 180 GeV, it would be easily observable at the next generation colliders. It is remthat the parameter space that explains theaµ deviation has a sizable overlap with the parameter space that proan acceptable cold dark matter relic density even when only theZ-pole annihilation channel is considered. Tcommon solution space implies a lighter chargino upper mass bound of 220 GeV, though the commonspace would increase when annihilation channels in addition to theZ-pole are included for the neutralino reldensity calculation. More generalU(1)′ models that do not require small tanβ could explain theaµ deviation in awider range of the parameter space.

Even though the lightest neutralino in theS-model is often very light, the difference of theaµ predictions ofthe MSSM and theU(1)′ models for comparable parameters is not large. This is because the lightest neuis mostly singlino-like when it is lighter than that of the MSSM, and it couples to the muon only through mthe properties of the other neutralinos are quite similar to those of the MSSM. The relaxation of gauginunification makes a sizable difference in both models.

The contribution of theZ′-loop is suppressed by the largeZ′ mass, which is constrained by the CDF limitMZ′ 500–800 GeV, with the limit depending on the model[39]. In the case that the right-handed neutrinosU(1)′ charged and form Dirac particles, more severe constraints ofMZ′ multi-TeV are deduced from Big BanNucleosynthesis (BBN)[47]. Other possibilities for neutrino mass in these models are discussed in Ref.[48].

Acknowledgements

This research was supported in part by the US Department of Energy under Grants No. DE-FG02-95ENo. DE-FG02-04ER41305, No. DE-FG02-03ER46040, and No. DOE-EY-76-02-3071, and in part by the Wsin Alumni Research Foundation.

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