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Fault Tree Analysis
Failures in Process Industries
• Single Component Failure
– Data for failure rates are compiled by industry
– Single component or single action
• Multiple Component Failure
– Failures resulting from several failures and/or
actions
– Failure rates determined using FTA
Instrument Faults/year
Controller 0.29
Control valve 0.60
Flow measurements (fluids) 1.14
Flow measurements (solids) 3.75
Flow switch 1.12
Gas – liquid chromatograph 30.6
Hand valve 0.13
Indicator lamp 0.044
Level measurements (liquids) 1.70
Level measurements (solids) 6.86
Failure Rates Data
Instrument Faults/year
Oxygen analyser 5.65
pH meter 5.88
Pressure measurement 1.41
Pressure relief valve 0.022
Pressure switch 0.14
Solenoid valve 0.42
Stepper motor 0.044
Strip chart recorder 0.22
Thermocouple temperature meas. 0.52
Thermometer temperature meas. 0.027
Valve positioner 0.44
Failure Rates Data
Failure Rates Data
Component
Failure Frequency
(hr-1) Component
Failure Frequency
(hr-1)
Gasket Failure (leak) 1.00 x 10-06 Pump Seal Failure 8.00 x 10-07
Gasket Failure (total) 1.00 x 10-07 Alarm Failure 1.00 x 10-05
Pipe Rupture (> 3 in) 1.00 x 10-10 Operator Error 2.00 x 10-05
Pipe Rupture (< 3 in) 1.00 x 10-09 Hose Rupture 2.00 x 10-05
Valve Rupture 1.00 x 10-08
• Some data are per hour
Frequency, Reliability and Probability
p = 1- e-mt
where p is the annual probability of occurrence, m is the annual frequency and t is time period (i.e., 1 year).
Component Failure Rate m(faults/year)
Reliability R=e(-mt)
Failure Probability
P=1-R
Control Valve 0.6 0.55 0.45
Controller 0.29 0.75 0.25
DP Cell 1.41 0.24 0.76
Conversion is important in OR gate (dimensional homogeneity)
Frequency and Probability - Example
taking the case of gasket failure and assumingthat we have 10 gaskets, the annual probability ofoccurrence is:
137-
year 10 x 8.7210
year
hr 8760
hr
10 x 1exp1p
What is Fault Tree Analysis
• Fault Tree is a method by which a particular
undesired system failure mode can be
expressed in terms of component failure
modes and operator actions.
• The system failure mode to be considered is
termed the “top event” and fault tree is
developed in branches below this event
showing it causes.
• Fault tree analysis is typically carried out by
a group or people or an individual.
• These individuals must have knowledge on
the process so that causes of undesirable
events can be understood
• The following information is important
• process and equipment description and
specification
• process flow diagram, process instrumentation
diagram and design information
• plant operation, human factors and
environmental factors
Fault Tree Analysis
Two basic Element
• The two mostly used gate symbol are “and” &
“or” gates.
– “And” gate is used to indicate that output event
occurs if all input event occurs simultaneously.
– “Or” gate is used when output event occurs if any
one of the input event occurs.
• Event symbol mostly used is “Rectangle” to
show any event. Signify the TOP EVENT by a
double box.
FTA Procedure
1. Define top event
2. Choose events identified by hazard identification
method (i.e HAZOP) which can lead to this top
event.
3. Decide on the hierarchical construction of fault
tree
4. Construct fault tree. All inputs to a particular gate
should be completely defined before further
analysis of one of them is undertaken.
5. Quantify the base events
6. Quantify the top event
FTA Procedure
7. Analyze results to determine the
significance of particular base events or
combination events
8. Carry out sensitivity analysis to test the
following factors:
– uncertainty of basic data
– effect of improving reliability of plant and
control systems
– effect of varying method of operation on the
plant
– effect of plant modernization
– effect of improved training of operators
Underlying Principles
• Causes of undesirable events can only be
understood with knowledge on how the system
functions through:
– chemical/physical processes in the plant
– specific information on the whole process
– data on hazardous properties of materials
– process flow diagram and process instrumentation
diagram
– equipment specification
– plant operation
– human factors and environmental factors
Example: Pump
• A system to pump acetic acid from the supply tank
to the process is illustrated in figure.
• The system function automatically.
• When the regulator is energized, one of the pumps
is started and acid passes through the feed pipes; if
no acid is detected in the feed pipe the second
pump is started.
• Construct a fault tree with the top event “no flow to
the process”.
• To make your life easier, consider failure modes
listed here.
• Is there any other notable failures not listed should
be considered?
P1M
S
P2
F1
F2
E
C1 C2
R
E : ELECTRICITY
F1,F2 : FEED PIPES
M : MANIFOLD
P1,P2 : PUMPS
R : REGULATOR
S : SUPPLY TANK
Example: Pump
C1, C2 : CABLES
Component Symbol Failure Mode
Cables C1 + C2 short-circuit
Electricity supply E power cut
Feed pipes F1 + F2 rupture of pipe
Manifold M rupture
Pumps P1 + P2 fail to start
Regulator R fail to open on Supply
tank S level too low
Failure Modes to Consider
PROBLEM 1 - SIMPLIFIED SYSTEM
NO FLOW TO PROCESS
GENERAL PROBLEMS
PROBLEMS WITH PUMPS
Regulator fails
Tanks level
too low
Power cut
Manifold M
fails
PUMP P1 PROBLEMS PUMP P2 PROBLEMS
Pipe P1 ruptures
Pump P1 fails to start
Cable C1 short circuits
Pipe P2 ruptures
Pumps P2 fails to start
Cable C2 short circuits
Fault Tree
Frequency (failure/year) = probability of failure per operation × number of operation per year
AND GATE rules :
can multiply P and P = unit of probability
can multiply P and F = unit of F
cannot multiply F and F = unit F2 (for example failure/yr2)
OR GATE rules :
can add P and P = unit of P
can add F and F = unit F
cannot add F and P =different unit
RULES for AND GATES
P(A.B) = PA.PB F(AB) = FA.PB
Unit on Fault Tree and Rules
Boolean Rules
Differences to numerical manipulation
Indempotent A+A=A
A.A=A
Absorption A+A.B=A
A.(A+B)=A
For example :
(M+W) . (M+Z)
= M.M + M.Z +W.M +W.Z
= M + M.Z +W.M +W.Z
= (M + M.Z +M.W) + W.Z
= M+ W.Z
A CUT SET = combination of basic events which will produce TOP EVENT
In the example :
M, M.Z, W.M, W.Z are all cut set
But
Minimal CUT SET is a CUT SET if any basic event is removed the TOP EVENT will not occur
Therefore MINIMAL CUT SET is M and W.Z
……can redraw the FAULT TREE…..
Boolean Algebra and Minimal Cut Set
PROBLEM 1 - SIMPLIFIED SYSTEM
PUMP FAIL
PUMP A FAILS PUMP B FAILS
Failure of Power Supply
Pump A Mechanical Failure
Failure of Power Supply
Pump B Mechanical Failure
M W M Z
Example – Minimal Cut Set
Unit on FTA
• Quantify Fault Tree
• Electrical supply failure, P = 0.1
• Single pump failure, P = 0.25
• Referring to Fault Tree :
– Before minimal cut set, Probability of pump fail =
0.1225
– After minimal cut set, Probability of pump fail =
0.1625
PROBLEM 1 - SIMPLIFIED SYSTEM
PUMP FAIL
FAILURE OF
POWER SUPPLYMECHANICAL FAILURE OF
PUMPS
Pump A
Mechanical
Failure
Pump B
Mechanical
Failure
M
W Z
Example -Minimum Cut Set
TOP EVENT
A B
DC E C
D E
Boolean Algebra-Minimum Cut Set
(A + B) . [ (C + D) . (E + C) + (D.E) ]
= (A + B) . (C.E + D.E + C.C + D.C + D.E )
= (A + B) . (C.E + D.E + C + D.C + D.E )
= (A + B) . (C + C.E + D.E + D.C + D.E )
= (A + B) . (C + C.D + C.E + D.E + D.E )
INDEMPOTENT LAW
= (A + B) . (C + C.D + C.E + D.E)
ABSORPTION LAW
= (A + B) . (C + D.E )
Boolean Algebra-Minimum Cut Set
TOP EVENT
A BC
D E
Boolean Algebra-Minimum Cut Set