Upload
meg-majumder
View
231
Download
0
Embed Size (px)
Citation preview
8/12/2019 21 Tangent, Slope and Derivative
1/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Do Now: What is the equation of the linetangent to the circle at point (7, 8)?
Aim: What do slope, tangent and the
derivative have to do with each other?
5 10
10
8
6
4
2
-2
8/12/2019 21 Tangent, Slope and Derivative
2/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Tangents & Secants
A tangent to a circle is a line in the plane of
the circle that intersects the circle in exactly
one point.
O
A
A secant of a circle is a line that intersects the
circle in two points.
B
C
8/12/2019 21 Tangent, Slope and Derivative
3/22
Aim: The Tangent Problem & the Derivative Course: Calculus
-1
Tany
x1-1
1radius = 1
center at (0,0)(x,y)
cos , sin
cos
tan lengthof theleg oppositelength of the leg adjacent to
x
y
cos
sintan
1
slope
8/12/2019 21 Tangent, Slope and Derivative
4/22
Aim: The Tangent Problem & the Derivative Course: Calculus
slope is
steep!
slope islevel:
m= 0
Tangents to a Graph
(x1, y1)
(x2, y2)
(x
3,y
3)
(x4, y4)slope is
falling:
mis (-)
3
2
1
-1
2A
Unlike a tangent to a circle,
tangent lines of curves can
intersect the graph at more than
one point.
3
2
1
-1
2A
8/12/2019 21 Tangent, Slope and Derivative
5/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Finding the Slope (tangent) of a Graph at a Point
10
8
6
4
2
5
h x = x2
1
2
21
2 x
y
mslope
This is an approximation. How can we be
sure this line is really tangent to f(x) at (1, 1)?
(1, 1)
8/12/2019 21 Tangent, Slope and Derivative
6/22
8/12/2019 21 Tangent, Slope and Derivative
7/22
Aim: The Tangent Problem & the Derivative Course: Calculus
3
2.5
2
1.5
1
0.5
1
Slope and the Limit Process
x, f(x)
h
f(x + h)f(x)
x
ymslope
sec
(x + h, f(x + h))
h is the change in x
f(x+ h)f(x)is thechange in y
As (x + h, f(x + h))
moves down the curve
and gets closer to
(x, f(x)), the slope of
the secant moreapproximates the
slope of the tangent at
(x, f(x).
8/12/2019 21 Tangent, Slope and Derivative
8/22
Aim: The Tangent Problem & the Derivative Course: Calculus
3
2.5
2
1.5
1
0.5
1
Slope and the Limit Process
x, f(x)
h
f(x + h)f(x)
(x + h, f(x + h))
What is happening to
h, the change in x?
Its approaching 0,
or its limit at x as h
approaches 0.
x
ymslope
sec
h is the change in x
f(x+ h)f(x)is thechange in y
8/12/2019 21 Tangent, Slope and Derivative
9/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Slope and the Limit Process
3
2.5
2
1.5
1
0.5
1
As h 0, the slope of the
secant, which
approximates the slope
of the tangent at (x, f(x))
more closely as (x + h, f(x+ h)) moved down the
curve. At reaching its
limit, the slope of thesecant equaled the slope
of the tangent at (x, f(x)).
sec0
tan lim mmslopeh
h
xfhxfmslope
)()(sec
8/12/2019 21 Tangent, Slope and Derivative
10/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Definition of slope of a Graph
3
2.5
2
1.5
1
0.5
1
The slopem
of the graphof fat the point (x, f(x)) ,
is equal to the slope of its
tangent line at (x, f(x)),
and is given by
provided this limit exists.
sec0
tan lim mmslopeh
h
xfhxf
m h
)()(
lim0
difference quotient
8/12/2019 21 Tangent, Slope and Derivative
11/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Model Problem
Find the slope of the graph f(x) = x2at the
point (-2, 4).
h
xfhxfm
h
)()(lim
0
h
fhfm
h
)2()2(lim
0
set up difference
quotient
h
hm
h
22
0
)2()2(lim
Use f(x) = x2
h
hh
m h
444
lim
2
0
Expand
h
hhm
h
2
0
4lim
Simplify
h
hhm
h
)4(lim
0
Factor and divide out
Simplify)4(lim0
hmh
4)4(lim0
hm h Evaluate the limit
8
6
4
2
Slope ED = -4.00
D: (-2 .00, 4.00)
q x = x2
E
D
8/12/2019 21 Tangent, Slope and Derivative
12/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Slope at Specific Point vs. Formula
h
xfhxf
m h
)()(
lim)1( 0
h
cfhcfm
h
)()(lim)2(
0
What is the difference between thefollowing two versions of the difference
quotient?
(1) Produces a formula for finding the
slope of any point on the function.
(2) Finds the slope of the graph for the
specific coordinate (c, f(c)).
8/12/2019 21 Tangent, Slope and Derivative
13/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Definition of the Derivative
The derivative of fat xis
h
xfhxfxf
h
)()(lim)('
0
provided this limit exists.
The derivative f(x) is a formula for the
slope of the tangent line to the graph offat the point (x,f(x)).
The function found by evaluating the limit of
the difference quotient is called thederivative of fat x. It is denoted by f (x),
which is read f pr ime of x.
8/12/2019 21 Tangent, Slope and Derivative
14/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Finding a Derivative
Find the derivative of f(x) = 3x22x.
0
( ) ( )'( ) lim
h
f x h f x f x
h
h
xxhxhxxf h
)23()](2)(3[lim)('
22
0
h
xxhxhxhxxf
h
2322363lim)('
222
0
h
hhxhxf
h
236lim)('
2
0
h
hxh
xf h
)236(
lim)(' 0
factor out h
)236(lim)('0
hxxfh
26x
8/12/2019 21 Tangent, Slope and Derivative
15/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Do Now:
Find the equation of the line tangent to
Aim: What is the connection between
differentiability and continuity?
( ) 2Find the slope of tangent at = 9f x x
x
8/12/2019 21 Tangent, Slope and Derivative
16/22
Aim: The Tangent Problem & the Derivative Course: Calculus
6
5
4
3
2
1
0.5 1 1.5 2 2.5
f(x) is a continuous function
Differentiability and Continuity
What is the relationship, if any, between
differentiability and continuity?
(c, f(c))
(x, f(x))
f(x)f(c)
xc
xc
Is there a limit as x
approachesc? YES
x c
f x f c f c
x c
( ) ( )'( ) lim
alternative
form of
derivative
8/12/2019 21 Tangent, Slope and Derivative
17/22
8/12/2019 21 Tangent, Slope and Derivative
18/22
8/12/2019 21 Tangent, Slope and Derivative
19/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Graphs with Sharp TurnsDifferentiable?
2.5
2
1.5
1
0.5
-0.5
1 2 3 4 5
f(x) = |x2|
Is this function continuous at 2?
m= 1m= -1
x
x2
lim | 2 | ?
x
x2
lim | 2 | ?
YES
One-sided limits are not equal, fis therefore notdifferentiable at 2. There is no tangent line at (2, 0)
2 2
2 0( ) (2)lim lim 1
2 2x x
xf x f
x x
x c
f x f c
f c x c
( ) ( )
'( ) lim
alternative
form of
derivative
2 2
2 0( ) (2)lim lim 1
2 2x x
xf x f
x x
Is this function differentiable at 2?
8/12/2019 21 Tangent, Slope and Derivative
20/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Graph with a Vertical Tangent Line1.2
1
0.8
0.6
0.4
0.2
-0.2
-0.4
-0.6
-0.8
-1
-1 1
f(x) = x1/3
Is f continuous at 0?
YES
x
f x f
x0
( ) (0)lim
0
x
x
x
1
3
0
0lim
x
x
20 3
1lim UND
x
x
13
0
lim ?
Does a limit exist at 0?
NO
fis not differentiable at 0; slope
of vertical line is undefined.
8/12/2019 21 Tangent, Slope and Derivative
21/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Differentiability Implies Continuity
a b c d
fis not
continuous at a
therefore not
differentiable
f is
continuous at
b& c, but not
differentiable
corner
vertical
tangent
fis continuous at
dand
differentiable
8/12/2019 21 Tangent, Slope and Derivative
22/22
Aim: The Tangent Problem & the Derivative Course: Calculus
Summary