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Differentiation
Calculus Chapter 2
The Derivative and the Tangent Line Problem
Calculus 2.1
Calculus chapter 2 3
A tangent line…
• Circles – is perpendicular to the radial line at a point
• Curves• Touches but does not cross?• Touches or intersects at only one point?• Has a slope equal to the slope of the curve
at that point
Calculus chapter 2 4
Slope of secant line
• As point Q approaches point P, the slope of the secant line approaches the slope of the tangent line.
• slope of the tangent line is said to be the limit of the slope of the secant line
sec
f c x f cm
x
Calculus chapter 2 5
Slope of tangent line
• f must be defined on an open interval containing c
• The limit must exist
0
limx
f c x f cm
x
Calculus chapter 2 6
Linear functions
• Have the same slope at any point• Slope of tangent line agrees with slope
of line using “rise over run” definition.
Calculus chapter 2 7
Example
• Find the slope of the graph of the following function at any point.
5 6f x x
Calculus chapter 2 8
Nonlinear functions
• The slope of the tangent line changes
Calculus chapter 2 9
Example
• Find the slope of the graph of the following function at any point.
21f x x
Calculus chapter 2 10
Vertical tangent lines
• If f is continuous on [a, b], and c is in the interval [a, b], each of the following gives a vertical tangent line
0
limx
f c x f c
x
0limx
f a x f a
x
0
limx
f b x f b
x
Calculus chapter 2 11
Definition of the Derivative of a Function
• The limit must exist
0
limx
f x x f xf x
x
Calculus chapter 2 12
Denoting the derivative
x
f x
dy
dxy
df x
dxD y
Calculus chapter 2 13
Example
• Find the derivative of
2 2 3f x x x
Calculus chapter 2 14
Example
• Find the slope of the graph of the following function at the points (1, 1), (4, 2), and (0,0).
f x x
Calculus chapter 2 15
Alternative form of derivative
• Useful for finding the derivative at one point (not in general)
limx c
f x f cf c
x c
Calculus chapter 2 16
Example
• Find the derivative at c = 1
2 2f x x x
Calculus chapter 2 17
Differentiability implies continuity
• If a function is differentiable at c, then it is continuous at c
• The reverse is not true• A continuous function might have
• A sharp point• A vertical tangent line
• See page 111
Basic Differentiation Rules and Rates of Change
Calculus 2.2
Calculus chapter 2 19
Differentiation Rules
• Allow you to find derivatives without the direct use of the limit definition.
• Can be proven using the limit definition.
Calculus chapter 2 20
Constant Rule
• The derivative of a constant function is 0.
• The slope of a horizontal line is 0.
0dc
dx
Calculus chapter 2 21
The Power Rule
1n ndx nx
dx
3
23
f x x
f x x
2
2
f x x
f x x
0
1
f x x
f x x
f x
Calculus chapter 2 22
The Constant Multiple Rule d
cf x cf xdx
3
2
2
3
3 3
9
f x x
f x x
f x x
1
2
1
2
2
3
2
3
2 1
3 2
1
3
f x x
f x x
f x x
f xx
Calculus chapter 2 23
The Sum and Difference Rules
df x g x f x g x
dx
Calculus chapter 2 24
Examples
• Find the derivatives
2 2 3y t t
3 22 3f x x x x
2 23f s s s
s
Calculus chapter 2 25
Derivatives of sine and cosine functions
• Can be proven using the special trig limits
sin cosd
x xdx
cos sind
x xdx
Calculus chapter 2 26
Examples
• Find the derivatives
siny x x
2cos4sin
3
tf t t
Calculus chapter 2 27
Nonexample
• Can’t pull the two out of the sine function
• A composite function• Need the chain rule – section 2.4
sin 2 2cosd
x xdx
Calculus chapter 2 28
Rates of change
• Derivatives can determine the rate of change of one variable with respect to another
Calculus chapter 2 29
Example
• The area of a circle with a radius r is A = pr2. Find the rate of change of the area with respect to r when r = 2 m.
Calculus chapter 2 30
Position function
• Gives the position of an object as a function of time
s t
Calculus chapter 2 31
Average velocity
distancerate
time
Calculus chapter 2 32
Instantaneous velocity
• Or just velocity• Derivative of the position function
v t s t
Calculus chapter 2 33
Speed
• Absolute value of velocity
Calculus chapter 2 34
Position of free-falling object
• s0 is initial height• v0 is initial velocity• g is acceleration due to gravity
• –32 ft/s2
• –9.8 m/s2
20 0
1
2s t gt v t s
Calculus chapter 2 35
Example
• A ball is thrown straight down from the top of a 220-ft building with an initial velocity of –22 ft/s. What is its velocity after 3 seconds? What is its velocity after falling 108 feet?
The Product and Quotient Rules and Higher-Order Derivatives
Calculus 2.3
Calculus chapter 2 37
Product Rule
• Take the first function times the derivative of the second plus the second function times the derivative of the first.
df x g x f x g x g x f x
dx
Calculus chapter 2 38
Product rule with more than two functions
• Take the derivative of each function times the other functions and add all products
df x g x h x
dx
f x g x h x f x g x h x f x g x h x
Calculus chapter 2 39
Examples
• Find the derivatives using the product rule.
2 32 1 1f x x x x
sinf x x x
5 4 2 3f x x x x
Calculus chapter 2 40
The quotient rule
• Take the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator divided by the square of the denominator.
Calculus chapter 2 41
The quotient rule
2
f x g x f x f x g xd
dx g x g x
LOdHI HIdLO
LOLO
Calculus chapter 2 42
Examples
• Find the derivatives using the quotient rule
3
2
3 2
1
x xf x
x
2 1
3
x xf x
x
Calculus chapter 2 43
Avoiding the quotient rule
• See example 6 on page 130
Calculus chapter 2 44
Derivatives of trig functions
• Can be proven using the quotient rule
2tan secd
x xdx
2cot cscd
x xdx
sec sec tand
x x xdx
csc csc cotd
x x xdx
Calculus chapter 2 45
Higher order derivatives
• Second derivative of the function is the derivative of the first derivative
• Third derivative of the function is the derivative of the second derivative
• Etc.• See page 133
Calculus chapter 2 46
Acceleration
• The derivative of velocity.• The second derivative of position.• Example: find the acceleration of an
object in free fall if the position function is
20 0
1
2s t gt v t s
The Chain Rule
Calculus 2.4
Calculus chapter 2 48
The Chain rule
• One of the most powerful differentiation rules
• Used for composite functions
df g x f g x g x
dx
Calculus chapter 2 49
The Chain Rule
• Differentiate the “outside” function, leaving the inside function alone
• Then multiply it by the derivative of the inside function
• Example:
sin 3y x
Calculus chapter 2 50
Examples
• Differentiate
tan 1y x
2 1y x
32 2 1y x x
Calculus chapter 2 51
General Power Rule
1n ndf x n f x f x
dx
Calculus chapter 2 52
Examples
• Differentiate
2
1
3 1s t
t t
322 1f x x
2
1
2g t
t
Calculus chapter 2 53
Examples
• Differentiate
y x x
33 9f x x x
3 5cosy x x
Implicit Differentiation
Calculus 2.5
Calculus chapter 2 55
Explicit functions
• y is an explicit function of x• Solved for y, or easy to solve for y
3 2y x
12xy
Calculus chapter 2 56
Implicit functions
• Can’t be easily solved for y
22 3 4 2x y y xy
2 9y x
Calculus chapter 2 57
Implicit differentiation
• Used to differentiate implicit functions• To differentiate with respect to x
• For each term that involves x alone, proceed as normal
• For each term that involves y, apply the chain rule
Calculus chapter 2 58
Examples
3dx
dx 3d
ydx
3dx y
dx 2d
xydx
Calculus chapter 2 59
Guidelines
1. Differentiate both sides with respect to x
2. Collect all terms with dy/dx on the left and all other terms on the right.
3. Factor out dy/dx.
4. Solve for dy/dx.
Calculus chapter 2 60
Examples
2 2 2x y y x
cos y x y
Calculus chapter 2 61
Representing a Graph by differentiable functions
2 2 4x y
2 1x y
Calculus chapter 2 62
Example
• Find the slope of the tangent line to the graph at the indicated point
2 3 0 , 1,1x y
Calculus chapter 2 63
Finding the second derivative
• Find the second derivative with respect to x in terms of x and y.
2 2 2 3x y x
Related rates
Calculus 2.6
Calculus chapter 2 65
Finding related rates
• Use the chain rule to find the rates of change of two or more related variables that are changing with respect to time.
Calculus chapter 2 66
Example
• Differentiate with respect to t• Insert known values
2 3
Find when 3 if 2
y x x
dy dxx
dt dt
Calculus chapter 2 67
Example
• The radius r of a sphere is increasing at a rate of 2 inches per minute. Find the rate of change of the volume of the sphere when r = 6 inches.
Calculus chapter 2 68
Example
• A conical tank (with vertex down) is 10 feet across the top and 12 feet deep. If water is flowing into the tank at the rate of 10 cubic feet per minute, find the rate of change of the depth of the water the instant it is 8 feet deep.
Calculus chapter 2 69
More examples
• Pages 153 – 157