5
/4 [email protected] Discretised relaxation path sampling (DRPS) 1 Rate constants: from Sinai billiards to protein folding Wales group Department of Chemistry University of Cambridge Boris Fačkovec Alumni festival 26th September 2014

Rate constants: from Sinai billiards to protein folding

Embed Size (px)

Citation preview

/4 [email protected] relaxation path sampling (DRPS) 1

Rate constants: from Sinai billiards to protein folding

Wales group Department of Chemistry University of Cambridge

Boris Fačkovec

Alumni festival 26th September 2014

/4 [email protected] relaxation path sampling (DRPS)

• large separation of smallest and largest time scales

2

molecular vibration (~1 fs)

folding (~1 ms)

Rare events

AB

J

I

H

G

E

F

CD

A C

B D

J H E

I G F

kAB / exp(��E)

/4 [email protected] relaxation path sampling (DRPS) 3

Transition state theory

position

pote

ntia

l

prob

abilit

y de

nsity

position

relaxation

kTSTAB =

eq.flux

eq.population

• cell-to-cell rate constant in DRPS is based on relaxation:

/4 [email protected] relaxation path sampling (DRPS) 4

peptide dynamicspolymer reversal polymer translocation

where the unnecessary constant terms are ignored. kB is theBoltzmann constant and T is the absolute temperature. !1!and !2! are the values of !! in regions I and II, respectively.Fm exhibits a free energy barrier as a function of m. Thenature of the free energy barrier depends on "i# conforma-tional statistics on both regions, and "ii# value of the chemi-cal potential mismatch $% relative to the entropic part &firsttwo terms on the right-hand side of Eq. "2#'. The results areillustrated in Figs. 2 and 3. When $%!0, the barrier is sym-metric in f!m/N if the size exponent is the same in bothregions. For (1)(2 , the barrier becomes asymmetric. Thefree energy minima are downhill from I to II if the chain ismore compact in II than in I. This is illustrated in Fig. 2 bytaking !1!!0.9, !2!!0.5, and N$%/kBT!"3.0. On theother hand, the free energy minima are uphill if the chain ismore compact in I. This is illustrated in Fig. 2 by taking!1!!0.5, !2!!0.9, and N$%/kBT!3.0. By keeping the samevalue of ( in both regions, the free energy barrier can bemade asymmetric if $%)0, as illustrated in Fig. 3 with !1!!0.69!!2! .

Following the usual arguments of the nucleationtheory,13 the transport of the chain through the barrier isdescribed by

*

*t Wm" t #!km"1Wm"1" t #"km!Wm" t #"kmWm" t #

#km#1! Wm#1" t #, "3#

where Wm is the probability of finding a nucleus of m seg-ments in region II. km is the rate constant for the formationof a nucleus with m#1 segments from a nucleus with msegments. km! is the rate constant for the decay of a nucleuswith m segments into a nucleus of m"1 segments. Using thedetailed balance to express km#1! in terms of km and adoptingm to be a continuous variable, we get

*

*t Wm" t #!!"*

*m D "1 #"m ##*2

$*m2 km"Wm" t #, "4#

where

D "1 #"m #!"km*

*mFm

kBT#

*

*m km . "5#

As mentioned above, we assume that the rate constant km isindependent of m "because we deal here with only ho-mopolymers#, and is dictated by the ratchet potential arisingfrom the details of the pore. Under this condition, valid forthe experimental problem addressed in this paper, km is takento be a nonuniversal constant k0 independent of N. ThereforeWm is given by

*

*t Wm" t #!*

*m ! k0kBT *Fm

*m Wm" t ##k0*

*m Wm" t #" , "6#

It follows14 from Eq. "6# that the mean first passage time +for the process described by Eq. "6#, i.e., the average timerequired by the chain, having already placed at least onesegment in region II, to go from region I to region II is

+!1k0#0

Ndm1 exp$ Fm1

kBT% #

0

m1dm2 exp$ "

Fm2

kBT% . "7#

The limits 0 and N are actually 1 and N"1, respectively, andN in the following formulas should be replaced by (N"2) ifone is interested in small values of N. Substituting Eq. "2# inEq. "7#, the general results are given in Fig. 4, where + "in

FIG. 1. Polymer escape in transition.

FIG. 2. Plot of Fm in units of kBT against f. Curves represent: solid line,N$%/kBT!0, !1!!0.5!!2! ; long-dashed line, N$%/kBT!"3, !1!!0.9,!2!!0.5; dashed line, N$%/kBT!"3, !1!!0.5, !2!!0.9.

FIG. 3. Plot of Fm in units of kBT against f for !1!!0.69!!2! . Curvesrepresent: solid line, N$%/kBT!0; long-dashed line, N$%/kBT!"1;dashed line, N$%/kBT!"1.

10372 J. Chem. Phys., Vol. 111, No. 22, 8 December 1999 M. Muthukumar

This article is copyrighted as indicated in the article. Reuse of AIP content is subject to the terms at: http://scitation.aip.org/termsconditions. Downloaded to IP:131.111.184.86 On: Thu, 19 Jun 2014 00:33:12

0 10 20 30 40 50

0

10

20

30

Stationary PointPote

ntial

Ene

rgy D

iffere

nce

(kca

l/mol)

A

Misfolded

Unfolded

Native

0 10 20 30 40 50

0

10

20

30

Stationary PointPote

ntial

Ene

rgy D

iffere

nce

(kca

l/mol)

B

Native

Unfolded

biomolecular folding

010

2030

4050

0102030

Stat

ionar

y Poin

t

Potential Energy Difference (kcal/mol)

A

Misf

olde

d

Unfo

lded

Nativ

e

010

2030

4050

0102030

Stat

ionar

y Poin

t

Potential Energy Difference (kcal/mol)

B

Nativ

e

Unfo

lded

A B

Sinai billiards

-11.40 -11.48

-12.54-11.50

-11.04

43

2

1

-10.77

Cluster rearrangement

From Sinai billiards to folding

QUESTIONS?