Total Effectiveness Equipment Performance (TEEP)

Sajin Calvin S11MF08

IntroductionTEEP measures the overall equipment effectiveness relative to every minute of the clock, or calendar time.

Exposes Hidden factory Should be used with financial information

Hidden Factory Reduce planned maintenance downtime Use pre-assembled equipment modules to “swap

out”, reducing replacement time Execute only statistically designed experiments

(minimize guessing) Staff work areas appropriately to cover lunches,

breaks, week end, and holidays Train and educate workers offline Hold multiple meetings to communicate with

employees before or after shifts Improve reliability of delivery Improve transition to new equipment

modifications

Formulas Loading Time = Total Time – All Planned Downtime

(Excluded Time)

= Schedule Time

Operating Time = Loading Time – (Non Operating Time)

=Run Time= Uptime= Equipment making product time

Operating Time = Loading Time – (All Downtime + All Stop Time)

Availability = = =

Availability = Loading Time – (DT+ ST)Loading Time

Formulas (Conti..) Actual Cycle Time = Runtime Actual Amount Produced

Theoretical Cycle Time = Ideal Speed (Equipment Capacity as Designed)

= Highest Accredited Speed Rate ( if Higher than design rate)

Operating Speed Rate =

Operating Speed Rate =

Net Operating Rate =

Formulas (Conti..) Net Operating Time =

Performance Efficiency = Net Operating Rate X Operating Speed Rate

Performance Efficiency = 1.0 X Operating Speed Rate

Performance Efficiency =

OEE = Availability X Performance Efficiency X Quality Rate

OEE =

Asset Utilization = =

TEEP = Asset Utilization X Speed Rate X Quality Rate

TEEP =

Formulas (Conti..)

Problem Given Data Total Clock Time = 2400min Excluded time = 570min Run Time@100% = 1000min (Includes 40min

for waste) Run Time@50% = 340min ST Operations = 170min 7freq ST Included = 60min 6freq DT Technical = 150min 6freq DT Operations = 30min 6freq

Problem (Conti..)Given Data DT Operations = 30min 2freq DT Quality = 80min 4freq Total ST & DT = 490min 21freq Assume Normal waste @ 3.5% and 4Units/min

Solution Total Time = 240 blocks X 10 min/block = 2400 min

Ideal (Theoretical) Rate = 4 units/min (15sec cycle time)

Then, Actual Units Produced =

Given that 160 units were contaminated and, therefore, designated as

No Good (NG), Number of Good Units Produced = (4680 – 160 ) X 0.965 = 4362

Good Units

Quality Rate = = = 0.932

Solution (Conti..)Method 1 : OEE using Nakajima Formulas Loading Time = Total Time – Excluded Time = 2400 min – 570 min

= 1830 min

Availability = = = 73.2%

From above, Total Units Produced = 4680

Actual Cycle Time =

= = 17.18 sec

Operating Speed Rate = = 15 sec /17.18 sec = 0.873

Solution (Conti..)Method 1 : OEE using Nakajima Formulas

Performance Efficiency = 1 X Operating Speed Rate =1 X 0.873 = 0.873

OEE = Availability X Performance Efficiency X Quality Rate

=73.2 percent X 0.873 X 0.932 = 59.6 percent

Solution (Conti..)Method 2 : OEE using Event Time Records Scheduled Time = Total Time – Excluded Time = 2400 – 570

= 1830 min – Runtime = 1000+340 = 1340 min

Operating Speed Rate = [(100 min X 1.0)+(340min X 0.5)] /1340

= 1170 /1340 = 0.873

Availability = = 1340 /1830 = 0.732 = 73.2 percent

OEE = Availability X Speed Rate X Quality Rate

= 73.2 percent X 0.873 X 0.932 = 59.6 percent

Solution (Conti..)Method 2 : OEE using Event Time Records

Asset Utilization = = 1340 / 2400 = 0.558 = 55.8 percent

TEEP = Asset Utilization X Speed Rate X Quality Rate

= 55.8 percent X 0.873 X 0.932 = 45.4 percent

Solution (Conti..)Method 3 : OEE based on Good Units Transferred

Theoretical Runtime = (4362 units) / (4 units/min) = 1090.5 min

OEE = Theoretical Runtime / Scheduled Time

= 1090.5/1830 = 0.5959 = 59.6 percent

TEEP = Theoretical Time/Total Time

= 1090.5/2400 = 0.4544 = 45.5 percent

Thank You