Simultaneous Diophantine Approximation with Excluded Primes László Babai Daniel Štefankovič

Simultaneous Diophantine Approximation with Excluded Primes

László BabaiDaniel Štefankovič

Dirichlet (1842) Simultaneous Diophantine Approximation

1 2, ,..., ,n Q

1,..., nr r

Given reals

integers

1/ 2i iQ p trivial

for all i

and

q Q

q

1/ ni iq r Q

such that and

Simultaneous Diophantine Approximationwith an excluded prime

1 2, ,..., n

1,..., nr r

Given reals

integers

i iq r for all i

and q

gcd( , ) 1p q

prime p

?such that and

Simultaneous diophantine -approximationexcluding

1 1/ 3

1 1 1| | | / 3 | 1/ 3q r q r

p

Not always possible

Example 3p

If

then


1 1| |q r

p

obstacle with 2 variables

1 22 1/ p

1 2 1 23 | ( 2 ) ( 2 ) | 1/q r r p

2 2| |q r

If

then


p

general obstacle

1 1 2 2 ... 1/n nb b b p t

| | 1/ib p

If

then


p

Theorem:

If there is no -approximationexcluding p then there exists an obstacle with

3/ 2| | /ib n Kronecker’s theorem ():

Arbitrarily good approximation excluding possible IFF no obstacle.

p


p

obstacle with 3/ 2| | /ib n

3/ 2pn

pnecessary to prevent -approximation

excluding

psufficient to prevent -approximation

excluding

Motivating example

Shrinking by stretching

Motivating example

set

stretching by

/A m Z Z

gcd( , ) 1x m

moda ax m{ | }Ax ax a A

x

arc length of A

max | (mod ) |a A

a m

Example of the motivating example

A = 11-th roots of unity mod 11177

Example of the motivating example

168

A = 11-th roots of unity mod 11177

m a prime

thenIf

every small set can be shrunk

Shrinking modulo a prime

m a prime

1 ,..., da a

m m

proof:

; 0q q Q 1/

1i i n

q pQ

Dirichlet: 1Q m

:x q

| |d A

1 1/ dm there exists such thatx

arc-length of Ax

Shrinking modulo a prime

Shrinking modulo any number

m a prime every small set canbe shrunk

?

Shrinking modulo any number


gcd( , ) 1x m

2km 1{1,1 2 }kA

If

then the arc-length of Ax22k

1 ,..., da a

m m

proof:

; 0q q Q 1/

1i i n

q pQ

Dirichlet: 1Q m

:x q

Where does the proof break?

2km

1 ,..., da a

m m

proof:

; 0q q Q 1/

1i i n

q pQ

Dirichlet: 1Q m

:x q

Where does the proof break?

2km

approximation excluding 2

need:

Shrinking cyclotomic classes


set of interest – cyclotomic class(i.e. the set of r-th roots of unity mod m)

•locally testable codes•diameter of Cayley graphs•Warring problem mod p•intersection conditions modulo p k

k


cyclotomic class

can be shrunk


cyclotomic class

can be shrunk

Show that there is no small obstacle!

Theorem:

If there is no -approximationexcluding p then there exists an obstacle with

3/ 2| | /ib n

Lattice

1,...,n

nv v R1v

2vlinearly independent

Lattice

1,...,n

nv v R

1 ... nv v Z Z

Lattice

1,...,n

nv v R

1 ... nv v Z Z

Dual lattice

* { |( ) }TL u v L v u Z

Banasczyk’s technique (1992)

2|| ||( ) x

x A

A e

gaussian weight of a set

( ) ( ) / ( )L x L x L mass displacement function of lattice


( ) ( ) / ( )L x L x L mass displacement function of lattice

0 ( ) 1L x

dist( , ) ( ) 1/ 4Lx L n x

properties:


( ) ( ) / ( )L A L A L discrete measure

*( ) ( )LL

x x

21( ) exp( || || ) exp(2 )

( )T

L

y L

x y iy xL

relationship between the discrete measure and the mass displacement function of the dual


( ) ( ) / ( )L A L A L discrete measure defined by the lattice

*( ) ( )LL

x x

21( ) exp( || || ) exp(2 )

( )T

L

y L

x y iy xL

|| ||

1*

( ) x sL

|| ||

1*

( ) x sL


1

2

3

1 0 0

0 1 0/

0 0 1

0 0 0

n

1 2 3, ,

there is no short vectorwith coefficient of thelast column

w L

0(mod )p

Banasczyk’s technique (1992)there is no short vectorwith coefficient of thelast column

w L

0(mod )p

( ) 1/ 2L u 1: nu ep n

* ( ) 1/ 2Lu *dist( , )u L n

obstacleQED

Lovász (1982) Simultaneous Diophantine Approximation

1 2, ,..., ,n Q

1,..., 0<np p q Q

Given rationals

integers

2

1/

2ni i n

q pQ

for all i

can find in polynomial time

Factoring polynomials with rational coefficients.


p - algorithmic

1 2, ,..., n Given rationals

can find in polynomial time

,prime p

12 nC p -approximation excluding p

where is smallest such that thereexists -approximation excluding p

/ 24 2nnC n

Exluding prime and bounding denominator

If there is no -approximationexcluding pthen there exists an

approximate obstacle with 3/ 2| | /ib n

with q Q

1 1 2 2 ... 1/n nb b b p t | | /n Q

Exluding prime and bounding denominator

necessary to prevent -approximationexcluding p with q Q

the obstacle

sufficient to prevent3/ 2/(2 )n p -approximation

excluding p with /(2 )q Q pn

Exluding several primes

If there is no -approximationexcluding 1,..., kp pthen there exists

obstacle with 1/ 2| | (max( , )) /ib n n k

1 [ ]

1/n

i i ji j A k

b p t


m=7k

m*

primitive 3-rd root of unity

10 1 7 , gcd( ,7) 1kc c t t

obstacle

know21 0 (mod 7 )k


10 1 7 , gcd( ,7) 1kc c t t

21 0 (mod 7 )k

20 1Res(1 , )x x c c x

0divisible by 17k

2 20 12( )c c

( 1) / 2

4

7 k

There is g with all 3-rd roots

1/ 2 1/ 2[ (4 7) ,(4 7) ]m m

Dual lattice

1 2 3

1 0 0 0

0 1 0 0/0 0 1 0

1

n

Algebraic integers?

possible that a small integer combination with small coefficients is doubly exponentially close to 1/p

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Simultaneous Diophantine Approximation with Excluded Primes László Babai Daniel Štefankovič