4
Section 3.2 Graphing Systems of Linear Inequalities in Two Variables Procedure for Graphing Linear Inequalities: 1. Draw the graph of the equation obtained for the given inequality by replacing the inequality sign with an equal sign. Use a dashed line if the problem involves a strict inequality, < or >. Otherwise, use a solid line to indicate that the line itself constitutes part of the solution. 2. Pick a test point, (a, b), lying in one of the half-planes determined by the line sketched in Step 1 and substitute the numbers a and b for the values of x and y in the given inequality. For simplicity, use the origin, (0, 0), whenever possible. 3. If the inequality is satisfied (True), the graph of the solution to the inequality is the half-plane containing the test point (Shade the region containing the test point). Otherwise (if the inequality is False), the solution is the half-plane not containing the test point (Shade the region that does not contain the test point). 1. Find the graphical solution of the inequality. Does the solution exist on the line 10x +4y = -8? 10x +4y -8 2. Find the graphical solution of the inequality. Does the solution exist on the line 2x +5y = -10? 2x +5y> -10 F- - ¥ " # = - - Find x. y intercepts T x - int :L so ) ; y - int : to , - E ) n the FILITTI . TIE 'The the true is soled . ÷÷÷÷÷÷÷÷÷÷ . X Find x , y - intercepts o . 2x t 5 y = 's LO x - int e . ( If , o ) , ( o , - ¥ ) n The Solution does NOT east on the ÷ :÷÷÷÷÷ " s Shade towards COO ) ( Right )

Section 3.2 Graphing Systems of Linear Inequalities in Two ...mayaj/m140_Chapter3_Sec... · Section 3.2 Graphing Systems of Linear Inequalities in Two Variables Procedure for Graphing

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Page 1: Section 3.2 Graphing Systems of Linear Inequalities in Two ...mayaj/m140_Chapter3_Sec... · Section 3.2 Graphing Systems of Linear Inequalities in Two Variables Procedure for Graphing

Section 3.2 Graphing Systems of Linear Inequalities in Two Variables

Procedure for Graphing Linear Inequalities:

1. Draw the graph of the equation obtained for the given inequality by replacing the inequality

sign with an equal sign. Use a dashed line if the problem involves a strict inequality, < or >.

Otherwise, use a solid line to indicate that the line itself constitutes part of the solution.

2. Pick a test point, (a, b), lying in one of the half-planes determined by the line sketched in Step

1 and substitute the numbers a and b for the values of x and y in the given inequality. For

simplicity, use the origin, (0, 0), whenever possible.

3. If the inequality is satisfied (True), the graph of the solution to the inequality is the half-plane

containing the test point (Shade the region containing the test point). Otherwise (if the inequality

is False), the solution is the half-plane not containing the test point (Shade the region that does

not contain the test point).

1. Find the graphical solution of the inequality. Does the solution exist on the line 10x+ 4y = �8?

10x+ 4y �8

2. Find the graphical solution of the inequality. Does the solution exist on the line 2x+ 5y = �10?

2x+ 5y > �10

F-

-

¥" #=

-

-

Find x. y intercepts Tx - int :L so ) ; y

- int : to ,- E ) n theFILITTI

.TIE'The

the true is soled.

÷÷÷÷÷÷÷÷÷÷.

XFind x , y - intercepts o

.2x t 5

y= 's LO

x - int e. ( - If , o ) , ( o

,- ¥ )

nThe Solution does

NOT east on the

÷:÷÷÷÷÷

" s

Shade towards COO ) ( Right )

Page 2: Section 3.2 Graphing Systems of Linear Inequalities in Two ...mayaj/m140_Chapter3_Sec... · Section 3.2 Graphing Systems of Linear Inequalities in Two Variables Procedure for Graphing

3. Write a system of linear inequalities that describes the shaded region.

5x+ 2y 30

x+ 2y 12

x 0

y 0

Bounded vs Unbounded A solution set S is bounded if the solution has a boundary that

fully encloses the solution set.

A solution set S is unbounded if the solution DOES NOT have a boundary that fully encloses

the solution set.

4. Determine graphically the solution set for the system of inequalities. Indicate whether the solution

set is bounded or unbounded.

3x� 2y > �17

�x+ 2y > 7

2 Fall 2019, Maya Johnson

LI E ¥¥ ( 6,02 , C 0,15 )

L2 E - ( 12,02 , ( 0,6 )

ZTest Logo ) Ll '

a

{ I 5 Lost 267 ? 30

• ? 30 True

•⇒ O E 30 V

Test Coco ) L2 :

① +26 > ? 12

o ? 12 True

←Bounded? oeizr¥#o→•

22

LI

-

-

- -

unbounded!

¥¥ios , Coi ' I )

⇒La

- ( - 17,02 , co , Zz ) a

n r

.

Test Locos Ll :

aIT

• a - i > True I

,,

I u

- 9 -

shade to Loso ) ( Right )i ~ ,

s*÷÷÷÷f*Ea -

C.

- '

-'

-

Test LOO ) L2 :,

' ¥077 False

L' t

Shade awayfrom Loso ) -

( Left ) I

Page 3: Section 3.2 Graphing Systems of Linear Inequalities in Two ...mayaj/m140_Chapter3_Sec... · Section 3.2 Graphing Systems of Linear Inequalities in Two Variables Procedure for Graphing

5. Determine graphically the solution set for the system of inequalities. Indicate whether the solution

set is bounded or unbounded.

3x� 4y 12

4x+ 5y 20

x � 0

y � 0

6. Determine graphically the solution set for the system of inequalities. Indicate whether the solution

set is bounded or unbounded.

2x+ 2y � 20

6x+ 6y 30

3 Fall 2019, Maya Johnson

L I

i¥p#C 4202 , ( o

, -3 )

L2A

- ( 5,02 , C 0,4 ) -

<3

g- ( 0202 i ( 011 ) d

§I

ep

g,

Bounded!

L 4 - ( 1,0 ) , ( 010 ),

'

:÷÷÷÷÷:c . . .ciii%¥¥÷:÷÷¥"Test Locos L2 :-

A S

L2

O 420 True -

Shade to Logo ) ( Lett ) ¢23 e! 24 -7 Stay in 1st Quadrant

-

L

c I-i¥f¥C 10,07 , ( o

, 10 )L2 ( I-7 ( 5,07

,C 0,5 )

p aTest Coco ) Ll :

µ£\0220' False

-

→A-shade away from Co ,59

÷÷¥:÷: c

shade to loco ) ( Left ) - ¢

Jasmin I

Page 4: Section 3.2 Graphing Systems of Linear Inequalities in Two ...mayaj/m140_Chapter3_Sec... · Section 3.2 Graphing Systems of Linear Inequalities in Two Variables Procedure for Graphing

7. Determine graphically the solution set for the system of inequalities. Indicate whether the solution

set is bounded or unbounded.

x+ y 5

2x+ y 8

2x� y � �1

x � 0

y � 0

4 Fall 2019, Maya Johnson

in ( 5,0 ) , Cos 5)

- ( 4,0 ) ,co , 8)

- C- Iso ) ,Co , D

① toftadret^

got23

-7

-6

¥¥z

- *#I-•#

← Ed-I I

tuI I I

1 2 3 4 5

Test Logo ) L 18 Test logo ) L 38

① E5 TrueO z - 1 True

Shade towards ( Left )shade towards k.Rrg.tt)

Test Lo ,o ) L2 :

O I 8 True

Shade towards ( theft )