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REVIEW LECTURE #1KNOWLEDGE BASE REQUIRED:
STRENGTH OF MATERIALSSTEEL DESIGNTIMBER DESIGNSOIL MECHANICS
WE COVERED:AREA AND CENTER OF GRAVITYItotxx = Ixx + Ay2
RADIUS OF GYRATION SECTION MODULUS
SOLVED ONE PROBLEM
MECHANICS OF MATERIAL BEHAVIOR:
DEFLECTION COMPUTATIONS
SOLVED DEFLECTION PROBLEM• DUE TO LOAD• DUE TO THERMAL EXPANSION
WE REVIEWED STATICS:
WE REVIEWED FLEXURE:
SM
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REVIEW OF STATICS (CONT’D)
MOMENT -SHEAR DIAGRAMS
SAMPLE PROBLEM
2' 6 ' 4 '
16000# 14000#
12000# 18000#
4000LB
-14000LB
32000FT-LB
56000 FT-LB
SOLUTION
SIMPLE SUPPORT
CANTILEVER
OVERHANGING
CONTINUOUS
IN FORMING AND BRACING DESIGN MANY OF THE MEMBERS HAVE MULTIPLE SUPPORTS.
WHAT IS THE DIFFERENCE BETWEEN A CONTINOUS MEMBER AND A SIMPLE SPAN??
Will the Moments be higher for the simple span or the continuous span??
Will the Shear be higher for the simple span or the continuous span??
Will the loads be higher for the simple span or the continuous span??
IN FORMING AND BRACING DESIGN MANY OF THE MEMBERS HAVE MULTIPLE SUPPORTS.
A B C D
w l
ASSUME A SPAN OF 10 FT. AT 1K/FT:
A=5k B=10k C D
w =1k/ft
.5w l
Vm ax=.5w l=5K
.5w l .5w l
M m ax=12.5 K -FT
SIMPLE SPAN SOLUTION
CONTINUOUS BEAMS - THREE SPANS
A=4k B=11k C D
w =1k/ft
.4w l
Vm ax=.6w l=6K
.5w l
.4w l.4w l
.6w l
M m ax=10K-FT
CONTINUOUS SPAN SOLUTION
CONCLUSION:
NOTE:• A Continuous Span will have: 10% more load on its interior
supports than a simple span20% less load on the exterior
support than a simple span
• Shear is greater in the continuous span solution 6K > 5K
• The maximum moment is greater in the simple span solution 12.5 k-ft > 10 k-ft
CONCLUSION CONTINUED:
• The length of the Wood member would have to span over all of the supports of the beam as one piece, because it is difficult to splice different member together effectively to achieve continuity!!
• Steel members would have to be the length of the full member because you can splice the pieces together, but welds and bolts are not sufficient enough to prevent stress concentrations across the connections!!