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  •  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y =...
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 · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log

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Page 1:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 2:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 3:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 4:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 5:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 6:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 7:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 8:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 9:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log

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© T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

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