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© T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

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Page 1: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

Page 2: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

6 m

8 m

Finding the hypotenuse

x

62 + 82 = x2

36 + 64 = x2

100 = x2

100 = x

= x10 x = 10

ÛÛÛÛÛ

12 m

13 m

Finding one of the shorter sides

x

122 + x2 = 132

144 + x2 = 169

x2 = 169

= 25

= 25

x x = 5

ÛÛÛÛÛ

– 144

x2

Page 3: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

10 m

12

mFinding the hypotenuse

x

102 + 122 = x2

100 + 144 = x2

244 = x2

244 = x

= x15.62 x ≈ 15.62

ÛÛÛÛÛ

11 m

15 m

Finding one of the shorter sides

x

112 + x2 = 152

121 + x2 = 225

x2 = 225

104=

= 104

x x ≈ 10.20

ÛÛÛÛÛ

– 121

x2

Page 4: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

5 cm

5 c

m

12 c

mx

a

25 + 25 a= 2 Û25 +25 a= 2 Û

50 a= 2 Û

50 a= Û

a .» 7 07 cm

a2 x+ 2 = 212 Û

( )2

50 x+ 2 =144 Û

50 x+ 2 =144 Û

x 2 =144 - 50 Ûx 2

94=

Ûx

= 94

Find x

.9 70 cm»

Double application Pythagoras theorem

Page 5: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

5 mx

Find the perimeter of this triangle

20 m

13 m

Two applications of Pythagoras Theorem to find x

h

25 2+h = 213 Û25 2+h =169 Ûh2 = -169 25 Ûh2 =144 Ûh =12 m

x 2 2+h = 220 Ûx 2+144 = 400 Ûx 2 = -400 144 Ûx 2 = 256 Ûx =16 m

The perimeter ofthis triangle is 54 m

Page 6: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

Page 7: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

15

8 17

10

6 11.7

24

7

25

12

35 37

5

15

15.8

8

8

11.3

Calculate the hypotenuse of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate.

all measurements in cm

Page 8: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

12

9 15

14

6 15.2

12

5

13

20

21 29

6

20

20.9

9

9

12.7

Calculate the hypotenuse of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate.

all measurements in cm

Page 9: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

17.9

9 20

15

13.220

45

28

53

20

21 29

11

60

61

9.4

9

13

Calculate the missing side of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate.

all measurements in cm

Page 10: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

16.1

8 18

20

1525

10.4

6

12

17.3

22 28

10

24

26

6

8

10

Calculate the missing side of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate.

all measurements in cm

Page 11: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

30

16 34

36

1539

13

6

14.3

17.0

21 27

18

80

82

7.5

8

11

Calculate the missing side of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate.

all measurements in cm

Page 12: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas

28

21 35

31

23.739

13

6

14.3

20

21 29

14

48

50

2.8

4.5

5.3

Calculate the missing side of these right-angled triangles, giving your answer correct to 1 d.p. where appropriate.

all measurements in cm

Page 13: © T Madas. 6 m 8 m Finding the hypotenuse x 6262 + 8 2 = x2= x2 36 + 64 = x2= x2 100 = x2= x2 = x= x = x= x 10 x = 10 12 m 13 m Finding one of the shorter

© T Madas