Ppt Karan Gmg14190

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    INDUSTRIAL TRAINING PRESENTATION

    MULTI-PURPOSE OP-AMPS

    Submitted by: Karan Gogna

    College Roll No:14190Electronics and Communication Engineering(IIIrd year)

    Dronacharya College of Engineering,Gurgaon

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    Presentation Outline

    Company Profile

    Op-Amps

    Single Ended-Input Distortions

    Op-Amp Operations

    Conclusion References

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    Company Profile

    The company I did my Summer Training Cum

    Internship from GMG Engineers and

    Contractors Pvt. Ltd, is a private Electronics

    and Electrical based firm that specializes in

    Transformers, manufacture of ICs and PCB

    Designing. All the various projects undertaken

    by the firm aim at power factor improvementtechniques by promoting energy and fuel

    conservation.

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    MY PROFILE

    TRAINEEWork Fields

    Op-Amps

    PCBs

    Transformers Other linear electric circuits

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    Op-Amps

    Introduction

    Types

    Applications

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    Single-Ended Input

    +

    Vo

    ~Vi

    +

    Vo

    ~Vi

    + terminal : Source

    terminal : Ground

    0o phase change

    + terminal : Ground

    terminal : Source

    180o phase change

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    Distortion

    Vd

    +

    Vo

    +Vcc=+5V

    Vcc=5V0

    +5V

    5V

    The output voltage never excess the DC voltage

    supply of the Op-Amp

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    Common-Mode Operation

    +

    Vo

    Vi ~

    Same voltage source is applied

    at both terminals

    Ideally, two input are equally

    amplified

    Output voltage is ideally zerodue to differential voltage is

    zero

    Practically, a small output

    signal can still be measuredNote for differential circuits:

    Opposite inputs : highly amplified

    Common inputs : slightly amplified

    Common-Mode Rejection

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    Operational Amplifier

    Noninverting Amplifier

    (1) Kirchhoff node equation at V+yields,

    (2) Kirchhoff node equation at V

    yields,

    (3) Setting V+ = V yields

    or

    +VinVo

    Ra Rf

    iVV

    00

    f

    o

    a R

    VV

    R

    V

    0

    f

    oi

    a

    i

    R

    VV

    R

    V

    a

    f

    i

    o

    R

    R

    V

    V1

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    Operational Amplifier

    +

    vi

    Ra

    vov-

    v+

    Rf

    +

    vi

    Ra

    vov-

    v+

    Rf

    R2R1

    +

    vivo

    v-

    v+

    Rf

    +

    vivo

    v-

    v+

    Rf

    R2R1

    Noninverting amplifier Noninverting input with voltage divider

    i

    a

    f

    o v

    RR

    R

    R

    Rv ))(1(

    21

    2

    Voltage follower

    io vv

    i

    a

    f

    o v

    R

    Rv )1(

    Less than unity gain

    io vRR

    Rv

    21

    2

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    Operational Amplifier

    Inverting Amplifier

    (1) Kirchhoff node equation at V+yields,

    (2) Kirchhoff node equation at V

    yields,

    (3) Setting V+ = V yields

    0

    V

    0_

    f

    o

    a

    in

    R

    VV

    R

    VV

    a

    f

    in

    o

    R

    R

    V

    V

    Notice: The closed-loop gainVo/Vin is

    dependent upon the ratio of two resistors,and is independent of the open-loop gain.

    This is caused by the use of feedback

    output voltage to subtract from the input

    voltage.

    +

    ~

    Rf

    Ra

    VinVo

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    Operational Amplifier

    Multiple Inputs

    (1) Kirchhoff node equation at V+yields,

    (2) Kirchhoff node equation at V

    yields,

    (3) Setting V+ = V yields

    0V

    0_

    c

    c

    b

    b

    a

    a

    f

    o

    R

    VV

    R

    VV

    R

    VV

    R

    VV

    c

    aj j

    j

    f

    c

    c

    b

    b

    a

    afo

    R

    VR

    R

    V

    R

    V

    R

    VRV

    +

    Rf

    Va

    VoRb

    Ra

    RcVb

    Vc

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    Operational Amplifier

    Inverting IntegratorNow replace resistors Ra and Rfby complex

    componentsZa

    andZf, respectively,

    therefore

    Supposing

    (i) The feedback component is a capacitor C,

    i.e.,

    (ii) The input component is a resistor R,Za = R

    Therefore, the closed-loop gain (Vo/Vin) become:

    where

    What happens ifZa = 1/jCwhereas,Zf= R?

    Inverting differentiator

    in

    a

    f

    o VZ

    ZV

    CjZf

    1

    dttvRC

    tv io )(1

    )(

    tjii eVtv

    )(

    +

    ~

    Zf

    Za

    VinVo

    +

    ~

    R

    VinVo

    C

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    Ref:080114HKN Operational Amplifier

    Op-Amp IntegratorExample:

    (a) Determine the rate of change

    of the output voltage.

    (b) Draw the output waveform.

    Solution:

    +

    RVoVi

    0+5V

    10 k

    0.01FC

    Vo(max)=10 V

    100s

    (a) Rate of change of the output voltage

    smV/

    Fk

    V

    50

    )01.0)(10(

    5

    RC

    V

    t

    V io

    (b) In 100 s, the voltage decrease

    VssmV/ 5)100)(50( oV

    0

    +5V

    0-5V

    -10V

    Vi

    Vo

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    Operational Amplifier

    Op-Amp Differentiator

    RCdt

    dVv io

    +

    R

    C

    Vo

    Vi

    0to t1 t2

    0

    to t1 t2

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    Conclusion

    In the end I would like to conlude by saying

    this Summer training cum Internship that I got

    to do helped me gain a lot of knowledge and

    practical experience as well as exposure invarious conceps in electronics, what I believe

    would play a very imperative role in the

    subjects and concepts that I will be studying inthe subsequent semester too.

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    References

    I would like to thank the staff @GMG Engineers and

    Contractors for their keen support and guidance in every

    milestone of my internship experience.

    Following websites were referred for the compilation of

    the presentation:-

    1. en.wikipedia.org/wiki/Operational_Amplifiers

    2. Op-AMP_Guide Vol 2010, 11, 12, 133.https://www.google.co.in/?gws_rd=cr&ei=TN5HUp_BHMqE

    rgeh_IHQDg#q=op+amp+ppt&safe=off

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