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Painting game on graphs
Xuding Zhu
Zhejiang Normal University
2014.05.28
8th Shanghai Conference on Combinatorics
There are six teams, each needs to competewith all the others.
Each team can play one game per day
How many days are needed to scheduleall the games?
Answer: 5 days
A scheduling problem:
1st day
2nd day
3rd day
4th day
5th day
5)(' 6 K
12)(' 2 nK n
This is an edge colouring problem.
Each day is a colour.
There are six teams, each needs to competewith all the others.
Each team can play one game per day
How many days are needed to scheduleall the games?
Answer: 5 days
Each team can choose one day off
7 days are enough
A scheduling problem:
7 days are needed
Each edge misses at most 2 colours
There are 7 colours
Each edge has 5 permissible colours
5)('ch 6 K
I do not know any easy proof
List colouring conjecture:
)(')('ch GG For any graph G,
However, the conjecture remains open for nK2
Haggkvist-Janssen (1997) nKn )('ch
n)ch'(K)'(Kn- nn 212 22
There are six teams, each needs to competewith all the others.
Each team can play one game per day
How many days are needed to scheduleall the games?
Answer: 5 days
Each team can choose one day off
7 days are enough
The choices are madebefore the scheduling
A scheduling problem
There are six teams, each needs to competewith all the others.
Each team can play one game per day
How many days are needed to scheduleall the games?
7 days are enough
Each team can choose one day off
A scheduling problem
is allowed not to show up for one day
On each day, we know which teams haven’t shown up today
but we do not know which teams will not show up tomorrow
We need to schedule the games for today
On-line list colouring of graphs
We start colouring the graph
before having the full information of the list
f-painting game (on-line list colouring game) on G
,2,1,0)( : GVf
is the number of permissible colours for x)(xf
Two Players:
Lister Painter
Each vertex v is given f(v) tokens.
Each token represents a permissible colour.
But we do not know yet what is the colour.
Reveal the list Colour vertices
At round i
is the set of vertices which has colour i asa permissible colour.iV
Painter chooses an independent subset of iI iV
vertices in are coloured by colour i.iI
Lister choose a set of uncoloured vertices, removesone token from each vertex of
iV
iV
If at the end of some round, there is an uncoloredvertex with no tokens left, then Lister wins.
If all vertices are coloured thenPainter wins the game.
G is f-paintable if Painter has a winning strategy for the f-painting game.
G is k-paintable if G is f-paintable for f(x)=k for every x.
The paint number of G is the minimum k for which G is k-paintable.
)(chp G
choice number choosable- is :min)(ch kGkG
)(ch)(chp GG
Painter start colouring the graph
after having the full information of the list
List colouring:On-line list colouring:
before
4,2,2
Theorem [Erdos-Rubin-Taylor (1979)]
n2,2,2 is 2-choosable.
4,2,2 is not 2-paintable
4,2,2
1
12
2 3
334
4 5
5Lister wins the game
4,2,2 is not 2-paintable
Theorem [Erdos-Rubin-Taylor,1979]
A connected graph G is 2-choosable if and only if its core is
1K ornC2 p2,2,2or
p2,2,2However, if p>1, then is not 2-paintable.
Theorem [Zhu,2009]
A connected graph G is 2-paintable if and only if its core is
1K ornC2 2,2,2or
A recursive definition of f-paintable
Assume . Then G is f-paintable, if ,2,1,0)( : GVf
(1) )(GV or
(2).paintable is
, set tindependen ),(
)(f-δG-I
XI GVX
X
XX of function sticcharacteri :
For any question about list colouring,we can ask the same question for on-line list colouring
Planar graphs and locally planar graphs
Chromatic-paintable graphs
Partial painting game
Complete bipartite graphs
b-tuple painting game and fractional paint number
For any result about list colouring,we can ask whether it holds for on-line list colouring
Some upper bounds for are automatically upper bounds for
)(chG)(chp G
Theorem [Galvin,1995] If G is bipartite, then )()(' GGp
Upper bounds for ch(G) proved by kernel method are also upperbounds for )(chp G
Upper bounds for ch(G) proved by Combinatorial Nullstellensatz are also upper bounds for
paintable1 is then
,
whichfor norientatio an has If
2009] [Schauz, Theorem
)(dG
|OE(D)| |EE(D)|
DG
D
)(chp G
Brooks’ Theorem
choosable is then, , If 12 G CKG knpaintable
[Hladky-Kral-Schauz,2010]
Upper bounds for ch(G) proved by induction
Theorem [Thomassen, 1995] Every planar graph is 5-choosable
Planar graphs
[ Schauz,2009 ] paintable
Thomassen proves a stronger result:
),,,(C
cycle boundary withgraph planar a is Assume
21 kvvv
G
,)( for 5)( and
,3 for 3)( ,1)()(v If 21
CGVvvf
kivfvff i
choosable.- is then fG paintable
Basically, Thomassen’s proof works for f-paintable.
Locally planar
embedded in a surface G
contractible
non-contractible
edge-width of G
length of shortest non-contractible cycle
edge-width is large torus :
Theorem [Thomassen, 1993] For any surface , there is a constant , any G embedded in with edge-width > is 5-colourable.
w w
Locally planar
embedded in a surface G
contractible
non-contractible
edge-width of G
length of shortest non-contractible cycle
edge-width is large torus :
Theorem [Thomassen, 1993] For any surface , there is a constant , any G embedded in with edge-width > is 5-colourable.
w w
DeVos-Kawarabayashi-Mohor 2008
choosable
Han-Zhu 2014+
paintable
Find a subgraph H
G-H is planar Each piece in H is planar
Apply strategy for planar graphs on the pieces of H and on G-H, one by one
+ some other nice properties
Chromatic-paintable graphs
A graph G is chromatic choosable if )()(ch GG
Conjecture: Line graphs are chromatic choosable.
Conjecture: Claw-free graphs are chromatic choosable.
Conjecture: Total graphs are chromatic choosable.
Ohba Conjecture: Graphs G with are chromatic choosable.
1)(2|)(| GGV Theorem [Noel-Reed-Wu,2013]
paintable )()( GGchp
paintable
paintable
paintable
Conjecture: Graph squares are chromatic choosable. [Kim-Park,2013]
paintable
A graph G is chromatic choosable if )()(ch GG
Conjecture: Line graphs are chromatic choosable.
Conjecture: Claw-free graphs are chromatic choosable.
Conjecture: Total graphs are chromatic choosable.
Ohba Conjecture: Graphs G with are chromatic choosable.
1)(2|)(| GGV
paintable )()( GGchp
paintable
paintable
paintable
Conjecture: Graph squares are chromatic choosable. [Kim-Park,2013]
paintableNO! Question
3,2,2K is not 3-paintable.
33
33
333
Lister
33
33
333
Lister
323233
Painter
232333
33
33
333
Lister
323233
Painter
232333
Lister
33
33
333
Lister
323233
Painter
232333
Lister
33
33
333
Lister
323233
Painter
232333
Lister
Painter
13222
23222
31322
33
33
333
Lister
323233
Painter
232333
Lister
Painter
13222
23222
31322
Lister
33
33
333
Lister
323233
Painter
232333
Lister
Painter
13222
23222
31322
Lister
3111
Painter Lose
2112
Painter Lose
2311
Painter Lose
3,2,2K
is not 3-paintable
{123}
{1}{2}{3}
Theorem [Kim-Kwon-Liu-Zhu,2012]
For k>1, is not (k+1)-paintable.3,2 kK
Ohba Conjecture: Graphs G with are chromatic choosable.
1)(2|)(| GGV paintable
On-line version Huang-Wong-Zhu 2011
To prove this conjecture, we only need to considercomplete multipartite graphs.
1v 2v
3v 4v
12 nv nv2
Theorem [Huang-Wong-Zhu,2011]
nK 2 is n-paintable
The first proof is by usingCombinatorial Nullstellensatz
A second proof gives a simple winning strategy for Painter
The proof uses induction.
Theorem [Kozik-Micek-Zhu,2014]
On-line Ohba conjecture is true for graphswith independence number at most 3.
The key in proving this theorem is to find a “good” technical statement that can be proved by induction.
1 size of parts
2 size of parts
3 size of parts
Partition of the partsinto four classes
2or 1 size of parts
ordered
ordered
1 size of parts
2 size of parts
3 size of parts
2or 1 size of parts
ordered
ordered
1A
2A
1kA
1S
2S
sS
2k
3k
iB
iC
||)(1
ij
jS Siv
vAi For ikkvf 32)(
vuBi ,For 32)( kkvf
|)(|)()( GVufvf
iSvFor )(2)( 321 ivkkkvf S
wvuCi ,,For 32)( kkvf
1|)(|)()( GVufvf
3211|)(|)()()( kkkGVwfufvf
G is f-paintable
Theorem [Kozik-Micek-Zhu,2014]
On-line Ohba conjecture is true for graphswith independence number at most 3.
Theorem [Chang-Chen-Guo-Huang,2014+]
)(432
|| ,)( If2
2
Gmmmm
VmG
paintable- chromatic is thenG
paintable)(47
||,4)( GVg
Theorem [Erdos,1964] then,n vertices has and bipartite isG If
Theorem[Zhu,2009]
If G is bipartite and has n vertices, then
1log)( 2 nGchp
1log)(ch 2 nG
Complete bipartite graphs
probabilistic proof
Painter colours , double the weight of each vertex in
iVAiVB
A
B
Initially, each vertex x has weight w(x)=1
Assume Lister has given set iV
If )()( ii VBwVAw
If x has permissible colours, Painter will be able to colour it.
1log2 n
A
B
The total weight of uncoloured vertices is not increased.
If a vertex is given a permissible colour but is not coloured by that colour, then its weight doubles.
If x has been given k permissible colours, but remains uncoloured,then
kxw 2)( nxw k 2)( nk 2log
Theorem [Carraher-Loeb-Mahoney-Puleo-Tsai-West]
rkK ,
XY
rYXk ||||
k
,...,2,1: Vf
k
k
kt
2t1t
k
ii
rk
tr
K
1
,
iff
paintable-f is
3-choosable complete bipartite graphs
Theorem
iff q)(p choosable-3 is , qpK
26,3 qp
18,4 qp
8,5 qp
7,6 qp
Mahadev-Roberts-Santhanakrishnan, 1991
Furedi-Shende-Tesman, 1995
O-Donnel,1997
3-paintable complete bipartite graphs
Theorem [Chang-Zhu,2013]
iff q)(p paintable-3 is , qpK
26,3 qp
11,4 qp
8,5 qp
7,6 qp
Theorem [Erdos, 1964]
noK nn 2, log))1(1()(ch
noKch nn 2,p log))1(1()(
)( ,p nnKch)( ,nnKch and
Theorem [Zhu, 2010]
Erdos-Lovasz Conjecture
nonK nn 222, loglog))1(1(log)(ch
Maybe
?loglog)1(log)( 222,p nonKch nn
nonKnon nn 222,222 loglog))1(21
(log)(chloglog))1(2(log
2log)(chloglogloglogloglog 2,p222222 nKnnn nn
Theorem [RadhaKrishnan-Srinivasan,2000]
nonK nn 222, loglog)1(21
log)(ch
Probabilistic mothed.
)( ,p nnKch)( ,nnKch and
Theorem [Duray-Gutowksi-Kozik,2014+]
nnKch nn 222,p logloglog)(
Theorem [Gerbner-Vizer, 2014+]
nnnKch nn 222222,p loglogloglogloglog)(
1c constant some for logloglog)( 222,p ncnKch nn ?
b-tuple list colouring
b-tuple on-line list colouring
G is (a,b)-choosable
if |L(v)|=a for each vertex v, then there is a b-tuple L-colouring.
If each vertex has a tokens, then Painter has a strategy to colour each vertex a set of b colours.
(a,b)-choosable
Conjecture [Erdos-Rubin-Taylor]
(am,bm)-choosable
On-line version
(a,b)-paintable (am,bm)-paintable
Theorem [Tuza-Voigt, 1996]
2-choosable (2m,m)-choosable
Theorem [Mahoney-Meng-Zhu, 2014]
2-paintable (2m,m)-paintable
colourable-b)(a, is G :inf)(ba
Gf
choosable-b)(a, is G :inf)(ba
Gchf
paintable-b)(a, is G :inf)(ba
Gchfp
)()( GchG ff
Theorem
)()( GchG fPf
[Alon-Tuza-Voigt, 1997] [Gutowski, 2011]
Infimum attained Infimum not attained
)()( GchG ff
Theorem
)()( GchG fPf
[Alon-Tuza-Voigt, 1997] [Gutowski, 2011]
Infimum attained Infimum not attained
Every bipartite graph is (2m,m)-choosable for some m
Theorem [Mahoney-Meng-Zhu,2014]
For any m, a connected graph G is (2m,m)-paintable if and only if its core is
1K or nC2 2,2,2or
Partial painting game
Partial f-painting game on G
same as the f-painting game, except that Painter’s goal is not to colour all the vertices, but to colour as many vertices as possible.
Fact:
least at colour
can one colours, kk' using then ,)( If kG
V kk'
vertices.
Conjecture [Albertson]:
least at colour can one colours,
epermissibl kk' has vertex each ,)(h If kGc
V kk'
vertices.
Conjecture [Zhu, 2009]:
least at colour to strategy a has Painter then
tokens kk' has vertex each ,)(h If P kGc
V kk'
vertices.
Conjecture [Zhu, 2009]:
least at colour to strategy a has Painter then
tokens kk' has vertex each ,)(h If P kGc
V kk'
vertices.
Theorem [Wong-Zhu,2013]
76
Question: Can the difference be arbitrarily large ?
)(ch)(p GGch
Nine Dragon TreeNine Dragon Tree
Thank you
An easy but useful lemma:
Corollary: If G is k-degenerate, then G is (k+1)-paintable
If f(v) >d(v), then G is f-paintable iff G-v is f-paintable.
Painter uses his winning strategy on G-v.
Colour v only if v is marked (i.e., the current colour is permissible for v), and none of its neighbours used the current colour.
v will be coloured when all its tokens are used gone, if not earlier.
2v
kv1v
Case 1
u
w
2v
kv1v
1G2G
iV
)( 11 GVVV ii
Painter apply his winning strategy on with 1G
, obtain independent set 11ii VI
Case 1
wuGVVwuIV iii ,)(, 212
Then Painter apply his winning strategy on with 2G
obtain independent set 22ii VI
u
w
221 in , of
role the play ,
Gvv
wu
21iii III
2v
kv1v
Case 2
iV
'iV defined as follows:
kiii vVVVv ' then , If 1
][' then , and If 1 kGiiiki vNVVVvVv
ii VV ' Otherwise
Painter apply his winning strategy on with input kvG 'iV
obtains 'iI add if possible. kv