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Operational Amplifier• Operational amplifier is an amplifier whose output voltage is
proportional to the negative of its input voltage and that boosts the amplitude of an input signal, many times, i.e., has a very high gain.High-gain amplifiers.
• They were developed to be used in synthesizing mathematical operations in early analog computers, hence their name.
• Typified by the series 741 (The integrated circuit contains 8-pin mini-DIP, 20 transistors and 11 resistors).
• Used for amplifications, as switches, as filters, as rectifiers, and in digital circuits.
• Take advantage of large open-loop gain.• It is usually connected so that part of the output is fed back to the
input.• Can be used with positive feedback to produce oscillation.
2
Figure 8.2, 8.3
A Voltage Amplifier Simple Voltage Amplifier Model
inLSinSLout
L
inS
inL
Lout
LinLS
inS
inin
AvvvvvRR
RRR
RAv
RRRAvvv
RRRv
=≈
++
=
+=
+=
;;
;
3
The Operational Amplifier• The integrated circuit operational amplifier evolved soon after
development of the first bipolar integrated circuit.• The µA-709 was introduced by Fairchild Semiconductor in 1965.• Since then, a vast array of op-amps with improved characteristics,
using both bipolar and MOS technologies, have been designed.• Most op amps are inexpensive (less than a dollar) and available from a
wide range of suppliers.• There are usually 20 to 30 transistors that make up an op-amp circuit.• From a signal point of view, the op-amp has two input terminals and
one output terminal as shown in the following figures.• The ideal op-amp senses the difference between two input signals and
amplifies the difference to produce an output signal.• Ideally, the input impedance is infinite, which means that the input
current is zero. The output impedance is zero.
4
Figure 8.4
Operational Amplifier Model Symbols and Circuit Diagram
5
The Ideal and Real Op-Amp
Ideal Amplifier:• Two Inputs:
– Inverting.– Non-inverting.
• Vo = A (V+ - V-)• Gain A is large (∞).• Vo = 0, when V+ = V-
• Infinite input resistance, which produces no currents at the inputs.
• The output resistance is zero, so it does not affect the output of the amplifier by loading.
• The gain A is independent of the frequency.
Real Amplifier:• Gain (105 - 109).• Input resistance
– 106 for BJTs– 109 - 1012
• Output resistance: 100-1000 Ω.
6
Figure 8.5
Inverting Amplifier
SvSRFR
outv
FRvAoutv
FRoutv
SRvAoutv
SRSv
vviniFiSi
iniFR
voutvFi
SRvSv
Si
iniFiSi
−=
−−=+
+=−=−=
=−−
=−−
=
=+
;0;
0;;
7
Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp is driven by a sinusoidal soorce, vs= 0.1 sin ωt volts, which has a source resistance of Rsr = 1 kΩ and which supply a maximum current of 5 µA. Assume that the frequency is low.
Ω=×=+=
−=+
−=Ω
=−×
==+=
+=
+==
k 100205)1(52y Accordingl
.51
2 and k 19 be should 1
kΩ 206105
1.0(max)(max)
(min)1 write then weA,5 max)( If
1Therefore .resistance source therepresents
.1 :sresistance twomeans example in this (
RsrRRRsrR
RvAR
sisv
srRRsi
RsrRsv
sisrR
srRRsRsRsRsv
si
µ
8
To Solve Ideal Op-Amp Circuit• If the noninverting terminal of the op-amp is at ground potential, then
the inverting terminal is at virtual ground. Sum currents at this point, assuming zero current enters the op-amp itself.
• If the noninverting terminal of the op-amp is not at ground potential, then the inverting terminal voltage is equal to that at the noninvertingterminal. Sum currents at the inverting terminal node, assuming zero current enters the op-amp itself.
• For an ideal op-amp circuit, the output voltage is determined from either step 1 or step 2 above and is independent of any load connected to the output terminal.
9
Amplifier with a T-Network
R1
R2 R3
vx
R4
0
0-+
vo
i1
i2 i3
i4
vs
)23
431(
12
get weequations above theCombing342
;342
)12(220
RR
RR
RR
svov
vA
Rovxv
Rxv
Rxv
iii
RR
svRixv
++−==
−=−−=+
−=−=
10
Design Example: An op-amp with a T-network is to be used as a preamplifier for a microphone. The maximum microphone output voltage is 12 mV (rms) and the
microphone has an output resistance of 1 kΩ. The op-amp circuit is to be designed such that the maximum output voltage is 1.2 V (rms). The input amplifier resistance
should be fairly large but all resistance values should be less than 500 kΩ.
Ω=Ω==
ΩΩ=Ω=
=−+−=−
==
−+−=
==
k 1.384R and k 40032
k 50 be will)effective 1( resistance total then thek 1 sr and k 49 1set weIfncalculatio in the resistance source theof value theinclude should We
5.1043;8)
431(8100
813
12 choose weIf
13)
431(
12
100012.02.1
RRRRR
RR
RR
RR
RR
RR
RR
RR
vA
vA
11
A Practical Application: Why Feedback
• Self-balancing mechanism, which allows the amplifier to preserve zero potential difference between its input terminals.
• A practical example that illustrates a common application of negative feedback is the thermostat. This simple temperature control system operates by comparing the desired ambient temperature and the temperature measured by the thermometer and turning a heat source on and off to maintain the difference between actual and desired temperature as close to zero as possible.
12
Figure 8.7
Summing Amplifier
∑=
−=
=
==
−=+++
N
nS
S
Fout
F
outF
S
Sn
FN
n
n
n
n
vRRv
Rvi
NnRv
i
iiii
1
21
,...2,1......
...
13
Figure
8.8, 8.9
Noninverting Amplifier Voltage Follower
S
F
S
out
RR
vv
+=1 outS vv =
14
Design Example: Design a noninverting amplifier with a closed loop gain of Av = 5. The output voltage is limited to -10 V ≤ vo ≤ +10 V and the
maximum current in any resistor is limited to 50 µAAnswer: R1 = 40 kΩ, R2 = 160 kΩ
15
Figure 8.10
Differential Amplifier
( )121
2 vvRRvout −=
16
Figure 8.14, 8.15
Instrumentation Amplifier Input (a) and output (b) stages of Instrumentation amplifier
+=
−=
1
2
21
21RR
RR
vvvA Fout
V
17
Figure 8.20
Op-amp Circuits Employing Complex Impedances
S
F
S
out
S
F
S
out
ZZj
VV
ZZj
VV
+=
−=
1)(
)(
ω
ω
18
Figure 8.21, 8.23
Active Low-Pass Filter
Normalized Response of Active Low-pass Filter
19
Figure 8.24, 8.25
Active High-Pass Filter
Normalized Response of Active High-pass Filter
20
Figure 8.26, 8.27
Active Band-Pass Filter
Normalized Amplitude Response of Active Band-pass Filter
21
Figure 8.30
Op-amp Integrator
∫∞−
−=t
SFS
out dttvCR
tv )(1)(
22
Figure 8.35
Op-amp Differentiator
dttdvCRtv S
SFout)()( −=