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1 Operational Amplifier Operational amplifier is an amplifier whose output voltage is proportional to the negative of its input voltage and that boosts the amplitude of an input signal, many times, i.e., has a very high gain.High-gain amplifiers. They were developed to be used in synthesizing mathematical operations in early analog computers, hence their name. Typified by the series 741 (The integrated circuit contains 8-pin mini- DIP, 20 transistors and 11 resistors). Used for amplifications, as switches, as filters, as rectifiers, and in digital circuits. Take advantage of large open-loop gain. It is usually connected so that part of the output is fed back to the input. Can be used with positive feedback to produce oscillation.

Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

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Page 1: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

1

Operational Amplifier• Operational amplifier is an amplifier whose output voltage is

proportional to the negative of its input voltage and that boosts the amplitude of an input signal, many times, i.e., has a very high gain.High-gain amplifiers.

• They were developed to be used in synthesizing mathematical operations in early analog computers, hence their name.

• Typified by the series 741 (The integrated circuit contains 8-pin mini-DIP, 20 transistors and 11 resistors).

• Used for amplifications, as switches, as filters, as rectifiers, and in digital circuits.

• Take advantage of large open-loop gain.• It is usually connected so that part of the output is fed back to the

input.• Can be used with positive feedback to produce oscillation.

Page 2: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

2

Figure 8.2, 8.3

A Voltage Amplifier Simple Voltage Amplifier Model

inLSinSLout

L

inS

inL

Lout

LinLS

inS

inin

AvvvvvRR

RRR

RAv

RRRAvvv

RRRv

=≈

++

=

+=

+=

;;

;

Page 3: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

3

The Operational Amplifier• The integrated circuit operational amplifier evolved soon after

development of the first bipolar integrated circuit.• The µA-709 was introduced by Fairchild Semiconductor in 1965.• Since then, a vast array of op-amps with improved characteristics,

using both bipolar and MOS technologies, have been designed.• Most op amps are inexpensive (less than a dollar) and available from a

wide range of suppliers.• There are usually 20 to 30 transistors that make up an op-amp circuit.• From a signal point of view, the op-amp has two input terminals and

one output terminal as shown in the following figures.• The ideal op-amp senses the difference between two input signals and

amplifies the difference to produce an output signal.• Ideally, the input impedance is infinite, which means that the input

current is zero. The output impedance is zero.

Page 4: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

4

Figure 8.4

Operational Amplifier Model Symbols and Circuit Diagram

Page 5: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

5

The Ideal and Real Op-Amp

Ideal Amplifier:• Two Inputs:

– Inverting.– Non-inverting.

• Vo = A (V+ - V-)• Gain A is large (∞).• Vo = 0, when V+ = V-

• Infinite input resistance, which produces no currents at the inputs.

• The output resistance is zero, so it does not affect the output of the amplifier by loading.

• The gain A is independent of the frequency.

Real Amplifier:• Gain (105 - 109).• Input resistance

– 106 for BJTs– 109 - 1012

• Output resistance: 100-1000 Ω.

Page 6: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

6

Figure 8.5

Inverting Amplifier

SvSRFR

outv

FRvAoutv

FRoutv

SRvAoutv

SRSv

vviniFiSi

iniFR

voutvFi

SRvSv

Si

iniFiSi

−=

−−=+

+=−=−=

=−−

=−−

=

=+

;0;

0;;

Page 7: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

7

Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp is driven by a sinusoidal soorce, vs= 0.1 sin ωt volts, which has a source resistance of Rsr = 1 kΩ and which supply a maximum current of 5 µA. Assume that the frequency is low.

Ω=×=+=

−=+

−=Ω

=−×

==+=

+=

+==

k 100205)1(52y Accordingl

.51

2 and k 19 be should 1

kΩ 206105

1.0(max)(max)

(min)1 write then weA,5 max)( If

1Therefore .resistance source therepresents

.1 :sresistance twomeans example in this (

RsrRRRsrR

RvAR

sisv

srRRsi

RsrRsv

sisrR

srRRsRsRsRsv

si

µ

Page 8: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

8

To Solve Ideal Op-Amp Circuit• If the noninverting terminal of the op-amp is at ground potential, then

the inverting terminal is at virtual ground. Sum currents at this point, assuming zero current enters the op-amp itself.

• If the noninverting terminal of the op-amp is not at ground potential, then the inverting terminal voltage is equal to that at the noninvertingterminal. Sum currents at the inverting terminal node, assuming zero current enters the op-amp itself.

• For an ideal op-amp circuit, the output voltage is determined from either step 1 or step 2 above and is independent of any load connected to the output terminal.

Page 9: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

9

Amplifier with a T-Network

R1

R2 R3

vx

R4

0

0-+

vo

i1

i2 i3

i4

vs

)23

431(

12

get weequations above theCombing342

;342

)12(220

RR

RR

RR

svov

vA

Rovxv

Rxv

Rxv

iii

RR

svRixv

++−==

−=−−=+

−=−=

Page 10: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

10

Design Example: An op-amp with a T-network is to be used as a preamplifier for a microphone. The maximum microphone output voltage is 12 mV (rms) and the

microphone has an output resistance of 1 kΩ. The op-amp circuit is to be designed such that the maximum output voltage is 1.2 V (rms). The input amplifier resistance

should be fairly large but all resistance values should be less than 500 kΩ.

Ω=Ω==

ΩΩ=Ω=

=−+−=−

==

−+−=

==

k 1.384R and k 40032

k 50 be will)effective 1( resistance total then thek 1 sr and k 49 1set weIfncalculatio in the resistance source theof value theinclude should We

5.1043;8)

431(8100

813

12 choose weIf

13)

431(

12

100012.02.1

RRRRR

RR

RR

RR

RR

RR

RR

RR

vA

vA

Page 11: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

11

A Practical Application: Why Feedback

• Self-balancing mechanism, which allows the amplifier to preserve zero potential difference between its input terminals.

• A practical example that illustrates a common application of negative feedback is the thermostat. This simple temperature control system operates by comparing the desired ambient temperature and the temperature measured by the thermometer and turning a heat source on and off to maintain the difference between actual and desired temperature as close to zero as possible.

Page 12: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

12

Figure 8.7

Summing Amplifier

∑=

−=

=

==

−=+++

N

nS

S

Fout

F

outF

S

Sn

FN

n

n

n

n

vRRv

Rvi

NnRv

i

iiii

1

21

,...2,1......

...

Page 13: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

13

Figure

8.8, 8.9

Noninverting Amplifier Voltage Follower

S

F

S

out

RR

vv

+=1 outS vv =

Page 14: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

14

Design Example: Design a noninverting amplifier with a closed loop gain of Av = 5. The output voltage is limited to -10 V ≤ vo ≤ +10 V and the

maximum current in any resistor is limited to 50 µAAnswer: R1 = 40 kΩ, R2 = 160 kΩ

Page 15: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

15

Figure 8.10

Differential Amplifier

( )121

2 vvRRvout −=

Page 16: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

16

Figure 8.14, 8.15

Instrumentation Amplifier Input (a) and output (b) stages of Instrumentation amplifier

+=

−=

1

2

21

21RR

RR

vvvA Fout

V

Page 17: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

17

Figure 8.20

Op-amp Circuits Employing Complex Impedances

S

F

S

out

S

F

S

out

ZZj

VV

ZZj

VV

+=

−=

1)(

)(

ω

ω

Page 18: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

18

Figure 8.21, 8.23

Active Low-Pass Filter

Normalized Response of Active Low-pass Filter

Page 19: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

19

Figure 8.24, 8.25

Active High-Pass Filter

Normalized Response of Active High-pass Filter

Page 20: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

20

Figure 8.26, 8.27

Active Band-Pass Filter

Normalized Amplitude Response of Active Band-pass Filter

Page 21: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

21

Figure 8.30

Op-amp Integrator

∫∞−

−=t

SFS

out dttvCR

tv )(1)(

Page 22: Operational Amplifier - Engineeringrhabash/ELG3331L01.pdf · 2006. 9. 14. · 7 Design Example: Design an inverting amplifier with a closed loop voltage of Av = -5. Assume the op-amp

22

Figure 8.35

Op-amp Differentiator

dttdvCRtv S

SFout)()( −=