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NUCLEAR MAGNETIC RESONANCE SPECTROSCOPY
PRINCIPLE AND APPLICATION IN STRUCTURE ELUCIDATION
Second order spectra
Professor S. SANKARARAMAN
Department of Chemistry
Indian Institute of Technology Madras
Chennai – 600 036
Second order spectra:
When the chemical shift values are very close and
the difference in chemical shifts are comparable to J values
one finds second order effects in the NMR spectra
Typically when (∆δ∆δ∆δ∆δ)/J is less than 10, second order effects
are seen in the spectra
Unusual intensities of multiplets
More than expected number of lines in multiplets
Number of lines ( frequency and intensities) can be theoretically
calculated
These are characteristic features of a second order spectrum
Examples of spin systems that show second order effects:
Hm
Ha Hx
R
mutually coupled amx spin system
δa, δm, δx, Jam, Jax, Jmx
Ha
Hb
X
Y
R
Rmutually coupled ab spin system
δa, δb, Jab
X
R
Ha
Hb
Y Z
Ha'
Hb'Hb
Ha
X
Y
X
YHa Ha'
Hb Hb'
mutually coupled aa'bb' spin system
δa, δb, six different coupling constants
Note: Ha and Ha' are chemicallyequivalent but magnetically non-equivalent protons. similarlyHb and Hb' are.
AB spin system – second order spin system
Has 4 lines, but line spacing and intensities depend on ∆δ∆δ∆δ∆δ/J ratio
The multiplet consists of two chemical shift values (δδδδA and δδδδB)
and one coupling constant (JAB)
First order quartet
Second order
AB quartet
First order quartet AB quartet
All 4 lines equally spaced and the
spacing between any adjacent
lines is J value.
Spacing between lines 2 and 3 varies
considerably. Spacing between 1 and 2 or 3
and 4 is J value. Spacing between 2 and 3 is
not J value.
Intensity ratio always 1:3:3:1 Intensity ratios varies widely
Contains only one δ and one J Contains two δ values and one J
Spectral pattern is symmetical
with respect to center of the
multiplet
Pattern does not depend on
spectrometer frequency.
Spectral pattern is symmetical with respect to
center of the multiplet
Pattern dependents on spectrometer
frequency. Multiplet can look like AB or AM or
AX system depending on spectrometer
frequency
First order simple quartet
second order AB quartet
( 4 - 1)( 3 - 2)
a = (c -
b = (c +
Jab =( 4 - 3) = ( 2 - 1)
Calculation of δδδδ and J values from a AB spectrum
( 4 - 1)( 3 - 2)
( - )( - )
( )( ) = 18 Hz
c = (20.5 + 28.0)/2 = 24.25
a = (c -
b = (c +
= 24.25 - 9 = 15.25 Hz= 24.25 + 9 = 33.25 Hz
Jab = ( 4 - 3) = ( 2 - 1) = 10.5 Hz
S
COOHH
H
Jab = 14 Hz
Ha
Ha
Hb
HbHa and Hb are
diastereomeric protons
ABC, ABX and AMX type 3 spin systems – examples
Computer simulated 3 spin system
F1 = 528.5 Hz, F2 = 594.5 Hz
F3 = 626.1 Hz, J1,2 = 10.54 Hz
J1,3 = 1.59 Hz, J2,3 = 17.28 Hz
AB
X
AB portion X portion
Dependence of ABX system on ∆δAB
JAB = 15.7 Hz, JAX = 0 Hz, JBX = 7.7 Hz
∆δAB =56.7 Hz
∆δAB =18.7 Hz
∆δAB =5.0 Hz
AB portion of the 60 MHz 1H NMR spectrum of
100 MHz 1H NMR of (olefinic region)
HaHb
Hc
100 MHz 1H NMR spectrum (aromatic region) of
60 MHz 1H NMR spectrum of
HaHx Hm
AA’BB’ and AA’XX’ type 4 spin systems – examples
Cl
Cl
Ha
Hb
Hb'
Ha'
Cl
OH
Hb
Ha Ha'
Hb'
NH2
Hb Hb'
OH
Ha'Ha
S
Hb Hb'
Ha Ha'Spectral pattern is complex, but
Symmetric with respect to mid-point
Of the multiplet
Pattern recognition is easy for AA’BB’ system
although extraction of δδδδ and J values from
The spectrum is not easy
4 spin spectrum can be simulated
Dependence of AA’BB’ spectrum on ∆δ
> 30 Hz
30 Hz
20 Hz
15 Hz
10 Hz
5 Hz
(J = 8.2 Hz, J’ = 1.5 Hz, Ja = 7.5 Hz, Jb = 3.0 Hz)
THANK YOU