Lecture 7 Energy Release Rate

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    CEE 770 Meeting 7

    Objectives of This Meeting

    Learn Generalized Stiffness Derivative Technique (akaGeneralized Virtual Crack Extension techniques) for:

    Computing G, and its derivatives

    Using these values to predict single crack tip stability

    Using these values to predict multiple crack tip stability

    Using these values to predict shape evolution of a 3D

    crack

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    Review Pages 72-74, VCE/Stiffness

    Derivative Methods

    Recall from your studies of LEFM theory that energy release rate (aka crackdriving force) for a single 2D crack tip, in FEM context, is defined as:

    fK uuuT =2

    1 (43, p.72)

    aaaG

    +

    =

    fK TT

    uuu21 (44, page 73, from Parks, 1975)

    Where a is the length of crack, u is the nodal displacement vector,Kis the global

    stiffness matrix,fthe global force vector, and nonzero contributions to

    and occur only over elements adjacent to the crack front.aK / af /

    137

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    Typical Near-Tip Meshing for a

    Virtual Crack Extension, a

    138

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    Energy Release Rate and Its Rates

    aaaG

    +

    =

    fK TT

    uuu21 (44, page 73, from Parks, 1975)

    This is OK for a single, 2D crack tip, BUT for more general, multiple crack2D case, and always for 3D:

    i

    T

    i

    T

    i

    i

    aaa

    G

    fKuuu +=

    2

    1

    Ti

    Sd

    Tip 1

    1

    2

    3

    4

    3

    4

    5

    6

    5

    6

    2D Multiple Crack System

    2

    3D crack front

    1

    2

    3

    45

    6

    (69)

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    Energy Release Rate and Its Rates: Key Issues

    How to compute the derivatives in

    accurately?

    What is the meaning ofa for 3D crack?

    How to compute higher order derivatives? And whycompute them?

    i

    T

    i

    T

    i

    iaaaG

    fKuuu +=

    2

    1

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    When Can a 2D Crack Propagate?

    When Can a 3D Crack Change Shape?

    For a 2D system with a single crack, the necessary and sufficientconditions for crack extension are:

    G = Gc, and

    G/a 0

    where,G = - /a =Potential energy of the system

    G/a = - 2 /a2

    Therefore, one needs to be able to calculate both G and G/aaccurately.

    Moreover, in many 2D situations it is possible that the system willhave multiple cracks!

    Why????(70)

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    The Sufficiency Condition of LEFM

    GIc

    G

    aa0

    a0

    P0

    P0

    P0

    P0

    P1

    P1

    P1

    P2

    P2

    P2

    P3

    P3

    P3

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    The Generalized Virtual Crack Extension MethodHwang, Wawrzynek, Tayebi, Ingraffea, "On the Virtual Crack Extension Method for Calculation of the Rates of Energy Release Rate,

    Engineering Fracture Mechanics, 59, 521-542, 1998

    Provides Gi and Gi/ai for multiple crack systems.

    subjected to arbitrary thermal loading, crack-face loading,

    body forces, in 2D/3D/axisymmetric problems, from a single FEA.

    ji

    T

    i

    T

    jji

    T

    ji

    T

    j

    i

    aaaaaaaaa

    G

    ffKK 22

    2

    1u

    uuu

    uu ++=

    Non-Zero for these

    loadings

    Null for 2D

    Non-Zero for 3Dwhen i = j

    i

    T

    i

    T

    i

    i aaaG

    fK

    uuu +=

    21

    (71)

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    How to Compute The Derivatives

    Analytically and Accurately

    Gi

    aj = uT K

    aiK

    1 f

    aj K

    aju

    +f

    aj K

    aju

    T

    K1T f

    ai

    i j

    i = j

    For a multiply cracked system, the following expressions are the rates of energyrelease rate for crack tip i. They are the analytical and generalized version of thestiffness derivative technique (Parks, 1975). Even more general expressions whichaccount for mixed-mode are also available in Hwang et al.,1998:

    Gi

    ai= uT

    K

    aiK1

    f

    ai

    K

    aiu

    1

    2 uT

    2K

    ai2 u +

    f

    ai

    K

    aiu

    T

    K1T f

    ai+ uT

    2f

    ai2

    (72)

    (73)

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    How to Compute The DerivativesAnalytically and Accurately

    Note that:1. These operations need only be performed on a small number of

    elements around the crack tip.

    2. The element stiffness derivatives can be computed analytically via:

    k= BTDB + BTDB + Tr( )BTDB[ ]v

    dV (74)

    2k= 2BTDB + 2BTDB+ BTD2B + 2 BTDB + 2Tr( ) BTDB + BTDB( )[ ]vdV

    where is the virtual strain-like matrix,

    = J1N

    1

    N

    2

    n1 n

    2

    =11 12

    21 22

    where 's are the geometry changes of the meshes due to virtual crack extension.

    (75)

    (76)

    145

    H C Th D i i

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    How to Compute The Derivatives

    Analytically and Accurately

    2Gi

    ai2 =

    1

    2uT

    3K

    ai3 u 2u

    T 2K

    ai2

    u

    ai uT

    K

    ai

    2u

    ai2

    (77)

    uai

    T

    Kai

    uai

    + 2

    uai

    2

    T

    fai

    + 2 uai

    T

    2

    fai

    2 + uT 3

    fai

    3

    u

    ai= K1

    f

    ai

    K

    aiu

    and

    2u

    ai 2= K1

    2f

    ai2

    2K

    ai2u 2

    K

    ai

    u

    ai

    3k= 3BTDB + 32BTDB +3BTD2B+ BTD3B[ ]

    v

    dV

    + 2 2B

    TDB + 6 B TDB + B TDB( )+ 2 Tr()B TDB[ ]

    v

    dV

    + 3 2B

    TDB + 2BTDB + B TD2B[ ]

    v

    Tr( )dV

    3

    B = 6 ( )3

    B (78)146

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    How to Compute The Derivatives

    Analytically and Accurately

    You also need the force derivatives when relevant, assembled from elementalderivatives from the virtually perturbed elements:

    fa =

    feae

    2f

    a

    2=

    2fe

    a

    2

    e

    (79)

    For example, if there is crack face pressure, p

    fe = NT

    p ds =s N

    T

    p + Tr()NT

    p[ ]dss (80)

    2fe =

    2N

    Tpds

    s

    = NT2p+ 2Tr()NTp + 2 NTp[ ]dss

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    If You Want Stress Intensity Rather ThanEnergy Release Rate Derivatives

    Then, where H = E for plane stress and H = E/(1 - 2) for plane strain:

    KI( )i = GiH

    KI( )i

    aj= 1

    2Gi

    aj

    HGi

    (81)

    2 KI( )iai

    2 =1

    2

    2Gi

    ai2

    H

    Gi

    1

    4Gi

    Gi

    ai

    2 H

    Gi(82)

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    Example: Stability of Multiple 2D Crack Systems

    Key issue: a/d ratio and its effect on crack tip interaction

    Applied Uniform Displacement = 0.5 in.

    Applied Uniform Displacement

    a

    d =2 in.

    Think:When a/d is very small

    and as a/d grows

    .and finally?

    E=29000ksi Deformed shape

    149

    C t d E R l R t d

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    Computed Energy Release Rates and

    Rates of Energy Release Rates

    150

    a Top

    Crack

    Middle

    Crack

    Bottom

    Crack

    0.5 119 42 117

    1 94 21 94

    2 16 12 19

    3 21 -3 16

    4 -27 -16 -18

    Total Rates ofG

    0

    50

    100

    150

    200

    250

    300

    0 1 2 3 4 5

    Crack Length, a

    Ene

    rgy

    Release

    Ra

    te,

    G

    Top, Bottom Cracks

    Middle Crack

    Observe: one can use the generalized VCE technique to predictsensitivity coefficients, strength of crack interaction, and

    propagation stability of multiple 2D crack systems.

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    2D, Mixed-Mode Case

    As previously discussed, we can decompose energy release rate into

    components from symmetric and anti-symmetric fields (p.86-88)

    ,

    ( ) ( )iIIiIi

    GGG +=

    ( ) ( ) ( )i

    IT

    II

    i

    T

    IiIa

    fuu

    a

    KuG

    +=2

    1

    GI( )ia

    j

    = uI( )T K

    ai

    K1 fI

    aj

    K

    aj

    uI

    +

    fI

    aj

    K

    aj

    uI

    T

    K1T fI

    ai

    GII( )iaj

    = uII( )T K

    aiK

    1 fII

    aj

    K

    ajuII

    +

    fII

    aj

    K

    ajuII

    T

    K1TfII

    ai

    For i j

    GII( )i = 1

    2uII( )

    T K

    aiuII + uII( )

    TfII

    ai(83)

    Then,

    (84)

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    2D, Mixed-Mode Case

    For i = j

    GI( )iai = u

    I

    ( )T K

    aiK

    1 fI

    ai

    K

    aiuI

    1

    2 uI

    ( )T2K

    ai2 uI

    +fI

    ai

    K

    ai

    uI

    T

    K1TfI

    ai

    + uT2fI

    ai2

    ,

    (85)

    GII( )iai = uII( )

    T K

    ai K

    1 fII

    ai

    K

    ai uII

    1

    2 uII( )

    T 2K

    ai2 uII

    +fII

    ai

    K

    ai

    uII

    T

    K1T fII

    ai

    + uT2fII

    ai

    2

    (86)

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    Crack Growth Model:Crack Growth Model:

    Principle of Minimum Potential EnergyPrinciple of Minimum Potential Energy

    Maximize = (a0) (a0 +a)w.r.t. Next Crack Extension a

    a

    (a)

    aa0 = G0 a + 1/2 G0 a

    WE NEED TO KNOW G and dG

    for Mult iple Planar/Non-Planar Crack Systemsin 2D/3D Under Arbitrary Loading

    G0

    G0

    G(a)

    a

    aa0

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    Three Dimensional Problem:Find New Crack Front Shape, a(s)

    ( ) ( ) ( ) ( )

    +=

    FrontCrack

    dssasGsasG 2

    1 Maximize

    (87)( )=FrontCrack

    dssaA w.r.t a(s) subjected to

    Piecewise Linearly Approximate G(s), a(s), G(s) along thecrack front.

    s

    Crack front

    GiGj Gk

    ai ajak

    G(s)

    a(s)154

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    Three Dimensional Problem:

    Find New Crack Front Shape, a(s)

    This problem is at the current state-of-the-art. For someinteresting insights and examples, see

    Hwang, Wawrzynek, Ingraffea, " On the virtual crack extension method for calculating thederivatives of energy release rates for a 3D planar crack of arbitrary shape under mode-I

    loading", Engineering Fracture Mechanics, 68, 7, 925-947, 2001.

    155