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Lecture 12: Elastic Potential Energy & Energy Conservation

Lecture 12: Elastic Potential Energy & Energy Conservation

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Lecture 12: Elastic Potential Energy & Energy Conservation. Questions of Yesterday. A 50-kg student starting from rest slides down a frictionless waterslide of height 10 m while a 100-kg student slides down a similar slide that is only 5 m high. - PowerPoint PPT Presentation

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Page 1: Lecture 12:  Elastic Potential Energy & Energy Conservation

Lecture 12: Elastic Potential

Energy &Energy Conservation

Page 2: Lecture 12:  Elastic Potential Energy & Energy Conservation

Questions of Yesterday

1) A 50-kg student starting from rest slides down a frictionless waterslide of height 10 m while a 100-kg student slides down a similar slide that is only 5 m high. Which student is going faster when they reach the bottom?a) the 50-kg studentb) the 100-kg studentc) they are going the same speed

2) A women pulls a crate up a rough (with friction) inclined plane at a constant speed. Which statement is NOT true?

a) The work done on the crate by the normal force of the inclined plane on the crate is ZEROb) The work done on the crate by gravity is ZERO c) The work done by the net force on the crate is ZEROd) The gravitational PE is increasing

Page 3: Lecture 12:  Elastic Potential Energy & Energy Conservation

Spring Potential EnergyWhen you push or pull on a spring are you doing work

on the spring?

As you displace a spring from its equilibrium position (compress or stretch it) its potential to gain kinetic

energy increases

Does an object attached to a stretched or compressed spring have the potential to gain kinetic energy?

Is mechanical energy conserved?

Elastic Potential Energyenergy stored in a spring that is compressed or

stretched from its equilibrium position

Page 4: Lecture 12:  Elastic Potential Energy & Energy Conservation

Equilibrium Position

Spring exerts no force

x = 0

Stretching vs Compressing

x = 0-x +x

x = -d x = 0

x = dx = 0

Compressedx = negativeF = positive

+F

-FStretchedx = positiveF = negative

Page 5: Lecture 12:  Elastic Potential Energy & Energy Conservation

Force Exerted by the spring ALWAYS acts in a direction OPPOSITE to displacement from equilibrium position

Restoring Force

x = -d x = 0

x = dx = 0

Compressedx = negativeF = positive

+F

-FStretchedx = positiveF = negative

RESTORING FORCE of a spring always acts to restore spring to equilibrium

(to return spring to x = 0)

Page 6: Lecture 12:  Elastic Potential Energy & Energy Conservation

Restoring Force (FS) increases with displacement from equilibrium

Restoring Force

FS (N)

x (m)

x = 0equilibrium

x = dx = 0

stretched

x = -d x = 0

compressed

equilibrium

stretched

compressed

k = spring constant (units = N/m) (measures stiffness of spring)

x = displacement from eq. Position (x = 0)

FS = -kx

SpringRestoring Force

Page 7: Lecture 12:  Elastic Potential Energy & Energy Conservation

Just like gravitational potential energy….Elastic Potential Energy = -(Work done by the spring)

Work done by a Spring

FS (N)

x (m)

equilibrium

stretched

compressed

FS = -kx

Work done by spring (WS)

is negative

Work done by a varying force = Area under F vs x curve

FS is not constant

WS = FSx

Page 8: Lecture 12:  Elastic Potential Energy & Energy Conservation

Just like gravitational potential energy….Elastic Potential Energy = -(Work done by the spring)

Work done by a Spring

FS

x

FS = -kx

WS = (1/2)FSx

Work done by a varying force = Area under F vs x curve

A = (1/2)FSx

WS = -(1/2)kx2

PES = (1/2)kx2

Page 9: Lecture 12:  Elastic Potential Energy & Energy Conservation

Energy Conservation

Wnc = KE + PE

PEGPES

when Wnc = 0

(KE + PEG + PES)i = (KE + PEG + PES)f

(1/2)mv2 mgy (1/2)kx2

Wnc = (KEf - KEi) + (PEGf - PEGi) + (PESf - PESi)

Page 10: Lecture 12:  Elastic Potential Energy & Energy Conservation

Practice Problem

An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from 0 to 250 N.

What is the equivalent spring constant of the bow?

How much work does the archer do in pulling the bow?

Page 11: Lecture 12:  Elastic Potential Energy & Energy Conservation

Practice Problem

A toy gun uses a spring to project a 10.2 g soft rubber sphere horizontally. The barrel of the gun and the

uncompressed spring are both 15 cm long, the spring constant is 10 N/m, and a constant frictional force of

0.05 N exists between the barrel and projectile.

With what speed does the projectile leave the barrel if the spring was compressed 10.0 cm for this launch?

If the gun is held 1.0 m above the ground what is the ball’s speed when it hits the ground?

Page 12: Lecture 12:  Elastic Potential Energy & Energy Conservation

Practice Problem

A block of mass 10.0 kg slides from rest down a frictionless 30.0o incline and is stopped by a spring with k = 100 N/m. The block slides 10.00 m from the point of release to the point where it comes to rest against

the spring.

When the block comes to rest, how far has the spring been compressed?

Page 13: Lecture 12:  Elastic Potential Energy & Energy Conservation

Questions of the Day1) A mass with speed v hits a horizontal spring and

compresses it a distance d. If the the speed of the mass were doubled (2v) what would the compression distance be?a) 4db) 2dc) d d) d/2

2) A mass on a spring is oscillating back and forth from x = -d to x = d? At what point in the oscillation is the speed of the mass the greatest?a) x = d

b) x = -dc) x = 0d) x = d and x = -d