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    INSTITUTO POLITÉCNICO NACIONALEscuela Superior de Cómputo

    “ Lista de Integrales ”

    Alumno:Yosef Israel Gutiérrez Moreno

    Grupo:1CV9

    Profesor:Alfredo Guzmán Rangel

    Materia:“Calculo”

    Semestre:14/2

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    2LISTA DE INTEGRALES1)

    =6

    2.

    (√ )

    √ =223

    22√3 3)

    3√

    √ 4

    = 3√ √ 4 = 3− /4=3− /14 /

    =3 /1/214 /5/2

    =6/ √

    4. ∫√ = =· ∫ 2 = =√ 2∫

    =2

    =√ 2+

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    3=√ 2 6. ∫√

    √ = = − =34 =43 =43

    8.∫ u=5x; du=5 dx

    = ∫ =

    9.

    5 =5

    = 5 →5=

    → 5=15 =15 = 55 11. ∫ =∫∗ ∗=∫ ∗ == =ln

    =1

    ∗ = 12.3 =3 =3

    3=

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    4= 3

    =13

    =13 =13 cot =cot33 14.

    3 7 =3 7 =3 →3=

    → 13 =

    13

    =13ln|| =13ln|3 7| 15.-

    ∫ − u=1-x= ∫ − =

    = | |

    17. ∫tan2 =2 =2 =12 tan∫u12 ∫tan2

    12 tan

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    5∫tan2 ∫ sincos2

    =cos = sin=1sin ∫sin 1sin∫ 12

    2=cos2

    2 =cos22

    . = == ||= | |

    =5 7 → =55= = → = 19. 3= tan3 =13 tan =13cos=13 1ℎ ℎ= log3= 13logcos= 13ln|cos3| . = 3 & =3 ; ℎ=c& = sin

    ɵ∗ɵ∗ ɵ u= ɵ du=

    ɵ∗ ɵ

    =2 = ɵ

    23.

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    6 454 44

    =4 =4 =4 =4 14 4 14ln| | 4ln| |

    14ln| 4 | 4ln4 24)cos = =3 =3 u=sen x =cos

    25.

    ∫ =

    =∫

    =∫ 1 = =∫ = = + = = 27. ∫ √ + √ 2 3=

    2 3=2 3

    =23 =4 4=

    − 4=14

    − =1412

    =24

    =122 3

    =12 2 3

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    728.-∫ + =∫ 1− =∫ − = ∫ − = = = 1 = √

    =3 =3 3=

    29.∫ U=sen(x), du=cos(x) dx

    =∫ = = - 30.

    = = → − = − = −2 =12 32.

    ∫ =∫ = +=∫ =

    =cot =1 =

    33. 1 = 1 =

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    8= 1− = − =12=2=2 1=2 1

    35.

    √ 2 1 =2 1 =2 →2=

    → −⁄2=12 −⁄ =121

    2=⁄

    =√ 2 1 36-∫ + = =

    =

    = = = | | 38.

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    9∫ tan 1(cos)

    =tan =sec=cos √ 1coscos √ 1 = 1 =1 =1

    √ 1

    √ +12 1=

    tan1+12 1=2 13

    .∫ + =∫ =∫− =− = +=2 3 → =3 26= 2 √

    u=arcsenx

    du= √ −

    =2 = 43)

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    10cot1 = = =2

    =

    2

    = cot =11 44.

    √1

    =arccos , = √1

    1 =3 = 2 45)

    cot1 = = 2 = 2 = cot

    =11 46. ∫ += =∫ + =∫ +2 = 1 =∫ =2 =∫ = =∫ + = | 1| 48.

    +

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    11cos 2sin 3 u=2sinx 3 =2cos

    2=cos 2=2=12 =12ln =12ln 2sin 3

    49-∫ = ∫ = ∫ = | | = |

    50.∫2 1 =2∫ 1 U= +1 , du= 2x dx

    =

    ∫du

    = + c

    = ( 1 + c51.

    = = 1 = = 1 =

    = =

    = = =

    =

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    12= =3

    =3

    52.-∫ + =tan− =1 1 = = ln= lntan− 53. ∫ +=∫ =ln =ln3 1 =3 tan1

    =3

    3=1

    54. = =

    = = =4 =4 56.

    cos22 3 2=2 3 2

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    13=6 2 →6= 2 →6=16

    =16ln|| =16ln|2 3 2| 57.-

    ∫ = ==

    = = 59)

    ∫ ∫

    ∫+

    1 1

    ∫2=2 . = = =2=12 → =12 2 =

    61.

    cos = = = . =

    U=

    Du= =

    =

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    14= = 64)

    ∫ ∫ ∫ +1 1 ∫ = =1

    4

    65.

    3

    =3 =3ln3

    1ln3ln3 1ln3ln3 =1ln3ln3

    ∫ 1ln3 =1ln3 11ln3 1 3 +1ln3 1 ln3

    3ln3 166)

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    15− =3=13 =13 =1

    3−

    = 3 = 3 67. ∫ = ∫ ∫

    =5 =∫ ∫ =5 =∫ ∫= = ∫ =5 = ∫ =5 = ∫ = = = =

    69. ∫ − = 2

    = 2 = 2

    = 2 =lnln 2=ln lnln ln2=ln lnln ln2 =ln ln2

    70.-∫ + =∫ + =∫ =∫ = ∫ = | |

    =

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    16= =

    = 71.∫ + U= 2x, du=2dx

    = ∫ + S= 2, ds= du

    =

    =

    = log( 2 = log( 2 72.

    1 2

    =1 ; =√ 2 =√ 2 →√ 2= →1√ 2 1 =1√ 21−

    =1√ 2

    −√ 2

    73.- ∫√ − =∫√ ·√ ·√ =√ 3 =√ 3 →√ 3= √ 3√11

    = √ 3 · √1=

    13√1=1√ 3sin− C

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    1774.√16 9=13√ =13 =13 394

    √=

    =16, =4: =9, =3 75.√9 =9 ; =3 = ; = =1 =1

    3 377.9 4 =3 ; =2

    =3 →3=

    13 =13 1312arctan32 =16 arctan32 78.-

    = =

    = =

    [ ]

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    18

    | | | |

    | | | | | |

    80.

    ∫√ =asec =tansec = sec =atan =arcsec

    12∫sec sectansec tan

    s=tanu secu ds=sectansec 1∫1s =

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    2087)

    √3 5=1√ 3

    1 153

    =1√ 5

    1√1

    = 1√ 5

    = 53√ 5

    = 53 = 53 90. ∫ −√ − cos−√1 =cos−√1 √1 =cos−√1 1=cos−√1 1− =cos− , =1

    =√1, = 2

    =√1, 2= − 2 = 12 − =21212=12cos− 221 =12cos− 1

    91.-∫ −+ = ∫ − = ∫ + =∫ = ∫ = 1 =∫ = ∫ = = =

    =

    = =

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    2295 .∫ +=arctanc Se utiliza la formula += = , = = ; =, =

    96.cos √ = =cos = −cos

    = − =13 =3=3 =3√

    98.

    2√ 1 :

    2 =2 →2√ 1

    = 1 = 2 → − = 2 = 2 1 99.-

    ∫ = = ∫ =

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    23

    − −

    = 101.

    ∫2sin 3cos =? 122.

    ∫ 2√ ∫ = = 2 ∫1√

    = . = ==

    103.∫ − +=∫√ −√ + =√ ∫ + =

    √ ∫ + =√ ∫ + =√ ∫ + =√ tan− =

    √ =√ 3 √ , =√ 3 ; = , =

    6 9 9 5

    34

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    24= 3 =

    ∫ −=

    ln−+

    =12 2ln 3 232 =

    106)

    2 2 1= = =

    111. ∫ ++ − 7 16 1=7 12 1 3 1 7 12 13 1= 2 13 1 7 1=3 12 1 7 1=3 2

    7 1=3 2 3 2 =7 =1 =1 =2 7 12 13 1=12 123 1

    7 12 1 3 1=12 123 1 =2 12 3 1

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    25=2 1, =3 1 =2 , =3

    2= ,3=

    2 23=2 23=12 23 =12ln| |23ln| |=12ln 2 123ln 3 1 =23ln 3 112ln 2 1 112.-∫ −− + =∫ −− + = − +− + = ∫ − + =2∫ − + = √ √ 39√ √ =

    √ 39 √ 39√ √ = √ √ 39√ √ ) = √ 39 √ 39√ √ = ln √ 39 √ 39√ √ = ln √ √ 10 1 = ln√ √ 10 1

    117.√ 2 =ln 2 .√ = √ √ =

    = || = = = =4 13 → =4 4 , 1 ,4

    = 1 ,4 1=

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    26124.∫ −√ + − = ∫√ = 2√ = √ = √ 1166 3 129)

    = cos= cos = = = = = = cos

    132. ∫ln 1 ln1 =ln1 , = =1 , = ln1 = ln1 1 = 1 = 1

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    27= ln1 1 = ln1 1= ln1

    = ln1 = ln1 ln1= 1ln1 133.-∫ = + ∫ + =∫ + = + ln++ C = =

    =

    135.

    = =√1

    = =2 →2 2√1 =2 2√1 =2 =12 = √1 = 1 →2 [2 1 1 2] =2 [2 1 12 1 ] ó = 1 =

    =

    1 :

    = =

    = 1

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    28= =1 22 =212 2 =214 2=12 12 2

    =12 :=→ = √1= ℎ :

    2 [2 11212 1 ]=2 2 1 14 14 1 =2 4 1 14 142 1 1

    136.-

    ∫log 1 =∫ =∫

    = ln1 = =+ = = ln1∫ + = ln1 2 1

    = ln1 2 11

    1

    = ln1 21 1 2 1 = ln1 2tan− 2 1 = ln1 2tan− 2 137. ∫arctan√ =arctan√ ∫√ + = √ =

    =12√ 1 =

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    29√ = =, =2 arctan√ 12 2 1 = arctan√ 1

    = arctan√ 111 =

    arctan√ 1 = arctan√ arctan= arctan√ √ arctan√ 138.√ √

    = √ =√

    =1 1√ =−

    =1√ 1 =2√ =2√ √ 2√ √ 1 =2√ √ 2√ √ 1 =2√ √ 2(√ 1 ) 140.

    = = = =

    → = 1 22 =12⌈ 2 =12[ 12 2 ]=12[ 22 ] =12

    →2 12

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    30=2 12 12 2 122 =2 2 4 2 =42 4 2 =4 24 2 143.∫x tan− 1

    =√1 =√ − ∫u tan−u =tan−u = =1 1 =2

    12tan−u12∫1 12∫ 1 1

    12tan−uu212tan−u =12tan− 1 1 . = = =√

    = √ = || = → =1√1 , =− → =

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    32 csc = cos/ ℎ= ℎ=cos 1ℎ ℎ =1ℎcsc=√ 1

    151. ∫√ + = ∫ =∫ =| |

    √ = =√ + = = =√ + =

    153. ∫ + + + 1 3 5= 1 3 5

    = 3 5 1 5 1 3

    = 8 156 54 3 = 8 156 54 3 = 8 6 4 =0 8 6 4 =1

    15 5 3 =0

    =18, =34, =58

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    3318 134 358 5 =18 134 358 5=

    18 1

    34 3

    58 5==18ln 134ln 358ln 5=18 ln16ln 35ln 5=18ln 35 1

    156.

    1 2

    11 2= 1 1 2 1= 1 2 2 1 =1 = 1 =2 =1 3 2 22 =1 2 2 =1 2 2 1=1

    2 = 2 = 1 1 1 2= ln| 1| 1 1ln| 2| =1 1ln 12

    157.-∫ −− + =∫ −−

    =22

    23

    2 = 31 2 21 2 21 =21 31 2 21 =2ln 3∫ 2∫ … 3∫ = 3= …=2ln2ln = − ln

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    34

    161.

    2 3 312 5

    2 3 312 5= 1 2 5 2 3 3=2 5 1 2 5 =23 3 → =2 2 = 3 5 = 3 = 1

    =3 = 213 22 5

    ln| 1| 2 22 512

    =ln2 5

    1 12

    164.

    ∫ 3 74 4

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    35

    =

    42 1

    12

    −2

    196.-∫ =∫ = ∫ 1 =∫ ∗ = ∫ ∗∫ =∫ ∗∫ = ∫ = ∫ =+ = = = = =

    = = =

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    36

    198.

    = = 1 = =

    5 7

    199.- ∫ =∫ = ∫ 1 = = = 1 = 1

    = 13

    = 3 =csc3 = 13 200.∫ =∫ +=∫ ∫ =∫ ∫ =

    =414 2 = =1 cos22 201.

    = = [1212cos2 ]=

    1412cos2

    14 2

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    37=4 cos22 8 cos4 8 =14

    12

    cos218

    18

    cos4 =2 =4 =2 =4

    2= 4= 14 12 cos218 18 cos4 14

    1212 cos

    18

    1814 cos

    =14 14 218 132 4 =38 14 2132 4 203.

    = 1 22 1 22 116218 2 116 1162 =116 2

    2 =1 44 = 1 2 4 44 14 4 =14 4 4 =1 cos82

    12cos8 12 =12 cos8 2

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    3818 cos =18 = 1418 82 =132 816

    12 =2 12 4 =12 4 =18 4 14 =4 18 2 =

    18 2 2 =1 42 12 4 =18 4 12 =2 116 =16

    →31281128 411024 8 →11283 4sin88

    206.

    ∫cot− cot x ( cos² x /sen² x )cot x ( (1 – sen² x)/sen² x )((cot x/sen² x) – cot x)

    ∫ cot³ (x) dx = ∫ ((cot x/sen² x) – cot x) dx =∫ (cot x/sen² x) dx – ∫ cot x dx =

    (-1/2) cot² x – In(sen x) + C

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    40=6 = =∫ · ∫=∫ ∫ = ∫

    =− ∫ =2 =2 = =− ∫ · =− ∫ =− =− 220.-∫ + =∫ + = 1 = =− = 1 1 = 1 1 =1 1