17
Exp 14B: Determining an Equilibrium Exp 14B: Determining an Equilibrium Constant Constant Le Chatelier's Principle In 1884, the French chemist Henri Le Chatelier suggested that equilibrium systems tend to compensate for the effects of stress or changes. When a system at equilibrium is disturbed, the equilibrium position will shift in the direction which tends to minimize, or counteract, the effect of the disturbance. If the concentration of a reactant is increased, the equilibrium position shifts to use up the added reactants by producing more products. Reaction between Fe 3+ and thiocyanate(SCN - ) results in iron(III) thiocynate, Fe(SCN) 2+ , a red complex, which represents an example of Le Chatelier’s Principle Fe 3+ (aq) + SCN - (aq) Fe(SCN) 2+ (aq) (colourless) (red)

Exp 14B : Determining an Equilibrium Constant

  • Upload
    varian

  • View
    167

  • Download
    2

Embed Size (px)

DESCRIPTION

Exp 14B : Determining an Equilibrium Constant. Le Chatelier's Principle In 1884, the French chemist Henri Le Chatelier suggested that equilibrium systems tend to compensate for the effects of stress or changes. - PowerPoint PPT Presentation

Citation preview

Page 1: Exp 14B : Determining an Equilibrium Constant

Exp 14B: Determining an Equilibrium ConstantExp 14B: Determining an Equilibrium Constant

Le Chatelier's Principle

• In 1884, the French chemist Henri Le Chatelier suggested that equilibrium systems tend to compensate for the effects of stress or changes.

• When a system at equilibrium is disturbed, the equilibrium position will shift in the direction which tends to minimize, or counteract, the effect of the disturbance.

– If the concentration of a reactant is increased, the equilibrium position shifts to use up the added reactants by producing more products.

– Reaction between Fe3+ and thiocyanate(SCN-) results in iron(III) thiocynate, Fe(SCN)2+, a red complex, which represents an example of Le Chatelier’s Principle

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)(colourless) (red)

Page 2: Exp 14B : Determining an Equilibrium Constant

Determining an Equilibrium Constant Determining an Equilibrium Constant Le Chatelier's Principle

Changes in ConcentrationConsider the system at equilibrium

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)(colourless) (red)

• Increasing concentration of Fe3+(aq) or SCN-(aq)

• results in the equilibrium position moving to the right

• use up some of the additional reactants and producing more Fe(SCN)2+(aq)

• solution will become darker red (more Fe(SCN)2+).

• Decreasing concentration of Fe3+(aq) or SCN-(aq)

• results in the equilibrium position moving to the left

• produces more Fe3+(aq) and SCN-(aq).

• the solution will become less red as Fe(SCN)2+(aq) is consumed.

Page 3: Exp 14B : Determining an Equilibrium Constant

Determining an Equilibrium Constant Determining an Equilibrium Constant Le Chatelier's Principle

Equilibrium constant Keq

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)(colourless) (red)

Keq = [Fe(SCN)2+]eq

[Fe3+]eq [SCN-]eq

• How do we measure concentrations?

– Absorption of light

– Applying Beer’s Law

• absorption of light at a specific wavelength is proportional to the concentration of a solution

Page 4: Exp 14B : Determining an Equilibrium Constant

Absorption of light by atoms and moleculesAbsorption of light by atoms and molecules

Transmission = ratio of transmitted light/incident light = I/Io

Beer’s LawAbsorption = amount of light absorbed by solution = log Io/I = *l*c

Page 5: Exp 14B : Determining an Equilibrium Constant

Beer’s LawBeer’s Law

Transmission = I/Io

Absorption = -log T = log Io/I

Beer’s LawA= * l * c = k * c

A= absorption of lightl = length of light pathc = concentration

= molar absorptivity or molar absorption coefficientk = * l = absorption constant

Page 6: Exp 14B : Determining an Equilibrium Constant

Determining an Equilibrium ConstantDetermining an Equilibrium Constant

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)

(colourless) (red)

Experimental• Measure absorbance of a series of solutions with different known

concentrations of the complex ion, Fe(SCN)2+

Problem

• Changing concentration of reactants changes concentration of complex product: Fe(SCN)2+ is participant in reaction!

Solution

• Use excess of one of the reactants, so the other reactant becomes limiting

• Use excess SCN-, then Fe3+ is limiting reactant

[Fe(SCN)2+]formed = [Fe3+]initial

Page 7: Exp 14B : Determining an Equilibrium Constant

AnalysisAnalysisDetermining absorption constant Determining absorption constant kk

1. Measure samples in spectrophotometer at 450 nm (absorption maximum for Fe(SCN)2+)

2. Plot absorption vs. [Fe(SCN)2+]formed

3. Determine absorption constant k = slope of curve

4. Use A = k * c, or c = A/k

Page 8: Exp 14B : Determining an Equilibrium Constant

AnalysisAnalysisDetermining Equilibrium Constant Determining Equilibrium Constant KK

1. Measure A450 nm of samples with different concentrations of reactants

2. Calculate [Fe(SCN)2+], [Fe3+]i, [Fe3+]eq, [SCN-]i and [SCN-]eq

3. - [Fe3+]i = [SCN-]i = 0.0025 M x 1.0 mL/7.0 mL = 3.6 x 10-4 M

- [Fe(SCN)2+] = A/k

- [Fe3+]eq = [SCN-]eq= [Fe3+]i - [Fe(SCN)2+] =

3.6 x 10-4 M – A/k = X M

Keq = [Fe(SCN)2+]eq/[Fe3+]eq [SCN-]eq =

Page 9: Exp 14B : Determining an Equilibrium Constant

Exp 14B: Determining an Equilibrium ConstantExp 14B: Determining an Equilibrium Constant

Step 1: make a dilution of 0.0025 M Fe(NO3)3 to 0.0001 M [0.0025 M x (4.0 mL/100 mL)] - Use a 5-mL Mohr pipet to add 4.0 mL of 0.0025 M Fe(NO3)3 to a 100-mL volumetric

flask- Add 0.1 M HNO3 until exactly 100 mL. Mix- Rinse the pipet with this solution- Add the specified amounts from the table below to 5 numbered test tubesTest Tube No

Diluted Fe(NO3)3

(mL)

(0.0001 M)

1 M KSCN (ml)

0.1 M HNO3 (mL)

Total Volume (mL)

Concentration [Fe(SCN)2+]

1 1.0 5.0 4.0 10.0 0.0001 M × (1.0 mL/ 10 mL) =1.0× 10-5 M

2 2.0 5.0 3.0 10.0

3 3.0 5.0 2.0 10.0

4 4.0 5.0 1.0 10.0

5 5.0 5.0 0 10.0

Part 1: Experimental - Determining Part 1: Experimental - Determining kk in Beer’s Law in Beer’s Law

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)

Page 10: Exp 14B : Determining an Equilibrium Constant

Exp 14B: Determining an Equilibrium ConstantExp 14B: Determining an Equilibrium Constant

Test Tube No [Fe(SCN)2+] Absorption

1 1.0× 10-5 M

2

3

4

5

Part 1: Analysis - Determining Part 1: Analysis - Determining k (absorption constant)k (absorption constant)

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)

Page 11: Exp 14B : Determining an Equilibrium Constant

Exp 14B: Determining an Equilibrium ConstantExp 14B: Determining an Equilibrium Constant

Plot [Fe(SCN)2+] vs Absorption

• [Fe(SCN)2+] on X-axis

• Absorption on Y-axis

• Slope = k = absorption constant

Part 1: Analysis - Determining Part 1: Analysis - Determining k (absorption constant)k (absorption constant)

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)

[Fe(SCN)2+]

Abs

orpt

ion

k = slope = Abs/[Fe(SCN)2+]

Line of best fit

Page 12: Exp 14B : Determining an Equilibrium Constant

Exp 14B: Determining an Equilibrium ConstantExp 14B: Determining an Equilibrium Constant

Test Tube No

0.0025 M Fe(NO3)3 (mL)

0.0025 M KSCN (mL)

0.1 M HNO3 (mL)

Total Volume (mL)

6 1.0 1.0 5.0 7.0

7 1.0 1.5 4.5 7.0

8 1.0 2.0 4.0 7.0

9 1.0 2.5 3.5 7.0

10 1.0 3.0 3.0 7.0

11 2.0 1.0 4.0 7.0

12 2.0 1.5 3.5 7.0

13 2.0 2.0 3.0 7.0

14 2.0 2.5 2.5 7.0

15 2.0 3.0 2.0 7.0

Total Vol. 5 10 20

Part 2: Experimental - Determining Part 2: Experimental - Determining equilibrium constant Kequilibrium constant Kcc

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)

Page 13: Exp 14B : Determining an Equilibrium Constant

Exp 14B: Determining an Equilibrium ConstantExp 14B: Determining an Equilibrium Constant

Test Tube No

Absorption

6

7

8

9

10

Part 2: Experimental - Determining Part 2: Experimental - Determining equilibrium constant Kequilibrium constant Kcc

Test Tube No

Absorption

11

12

13

14

15

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)

Page 14: Exp 14B : Determining an Equilibrium Constant

Exp 14B: Determining an Equilibrium ConstantExp 14B: Determining an Equilibrium Constant

Test Tube

Starting [Fe3+]

Starting [SCN-]

Equilibrium [Fe(SCN)2+]

Equilibrium [Fe3+]

Equilibrium [SCN-]

Kc

6

7

8

9

10

11

12

13

14

15

Average

Part 2: Analysis - Determining Part 2: Analysis - Determining equilibrium constant Kequilibrium constant Kcc

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)

Page 15: Exp 14B : Determining an Equilibrium Constant

Exp 14B: Determining an Equilibrium ConstantExp 14B: Determining an Equilibrium Constant

Calculation of concentration

Tube 6:

• starting [Fe3+] = [SCN-]

• [Fe(SCN)2+] = Absorption/slope = Abs/k

• Equilibrium [Fe3+] = [Fe3+]i - [Fe(SCN)2+]e =

• Equilibrium [SCN-] = equilibrium [Fe3+]

• Equilibrium constant K = [Fe(SCN)2+]e / [Fe3+]e [SCN-]e

Part 2: Analysis - Determining Part 2: Analysis - Determining equilibrium constant Kequilibrium constant Kcc

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)

Page 16: Exp 14B : Determining an Equilibrium Constant

Exp 14B: Determining an Equilibrium ConstantExp 14B: Determining an Equilibrium Constant

Calculation of concentration

Tube 7:

• starting [Fe3+]

• starting [SCN-]

• [Fe(SCN)2+] = Absorption/slope

• Equilibrium [Fe3+] = [Fe3+]i - [Fe(SCN)2+]e

• Equilibrium [SCN-] = [SCN-]i - [Fe(SCN)2+]e

• Equilibrium constant K = [Fe(SCN)2+]e / [Fe3+]e [SCN-]e

Part 2: Analysis - Determining Part 2: Analysis - Determining equilibrium constant Kequilibrium constant Kcc

Fe3+(aq) + SCN-(aq) Fe(SCN)2+(aq)

Page 17: Exp 14B : Determining an Equilibrium Constant

• Next Week Oct 29 Exp 14B: Full lab report including graph for all the results

Exp 15: The Relative Strength of Some AcidsLab preparations

– Read background and procedure– Protocol– Chemicals: HCl, H3PO4, NaH2PO4, CH3COOH, NH4NO3 , Al(NO3)3 ,

Zn(NO3)2 • Prelab assignment