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Power Transmission and Distribution
Differential Protection (7UT)Dynamic tests, Tests
PTD PA13 N. M Tests 7UT 05/03 No. 2
Method of Vector Group Determination
IL1,S1IL1,S2 = IL1 - IL2
330°(n * 30°)
Vector group is
Y d 11
Side 2: Side 1:
1L1
1L2
1L3
2L1
2L2
2L3
PTD PA13 N. M Tests 7UT 05/03 No. 3
Definitions in SIPROTEC 4 Relays
How to see the vector group Yd11?
Original Siprotec 4 (Browser) Phase angles
Side 1: 0°(reference phase)
Side 2: 210°
Please subtract 180°,than you get 30°(360° - 30° = 330°)
Vector definition to a node is positiveThe shown vectors or phase angles are transformed inthis positive definitionThe phase angle is displayed mathematics positive. The reference phase is always phase L1 on side 1
PTD PA13 N. M Tests 7UT 05/03 No. 4
Web Tool (Browser) Vector group Yd11
PTD PA13 N. M Tests 7UT 05/03 No. 5
Vector Group Determination via Fault Record
IL1;Side 1
IL1;Side 2 lags 150° or leads 210° Star point is towards the protected object
Way 1:IL1 Side: 150° + 180° = 330°
Way 2:IL1 Side: 210° - 180° = 30°leads 30° or lags 330°
Phase shift is according the vector group definition 330° 11 * 30°
PTD PA13 N. M Tests 7UT 05/03 No. 6
Test Configuration
7UT612
20 kV 110 kV2500A/1A 500A/1A
500A/1A
Dynamic calculation with NETOMAC Transient files were transplayed with a CMC-256 Test device from Omicron
80 MVAYNd11
PTD PA13 N. M Tests 7UT 05/03 No. 7
7UT612 Differential Protection Settings
PTD PA13 N. M Tests 7UT 05/03 No. 8
Test: Inrush followed by an external fault L1-L2-L3 (LV side) Infeed: HV side
7UT612 TQL 000009 17.06.2003,19:09:31
Inrush
Externalfault
PTD PA13 N. M Tests 7UT 05/03 No. 9
Test: Inrush followed by an internal fault L1-L2-L3 (LV side)Infeed: HV side
7UT612 TQL 000010 17.06.2003,19:11:37
Inrush
Internalfault
PTD PA13 N. M Tests 7UT 05/03 No. 10
Test: External fault L1-L2-L3 (LV side) with CT saturationInfeed: HV side, Saturation detector is active (Diff BL exF L1)
7UT612 TQL 000001 18.06.2003,14:16:23
Differential currentdue to CT saturation
PTD PA13 N. M Tests 7UT 05/03 No. 11
Test: Internal fault L1-E (HV side) with CT saturationInfeed: HV side
7UT612 TQL 000008 17.06.2003,19:02:00
IDiff>>
PTD PA13 N. M Tests 7UT 05/03 No. 12
Test: External Fault L1-L2-L3, evolving fault intern L1-L2-L3Infeed: HV side
7UT612 TQL 000001 17.06.2003,18:35:45
Internalevolving fault
1
3
2
4
PTD PA13 N. M Tests 7UT 05/03 No. 13
Test: Internal Fault L1-E HV side (Io Elimination)Infeed: LV side
7UT612 TQL 000002 18.06.2003,14:53:43
2/3 Idiff
1/3 Idiff
PTD PA13 N. M Tests 7UT 05/03 No. 14
Test: Internal Fault L1-E HV side (Io Correction)Infeed: LV side
7UT612 TQL 000005 18.06.2003,15:01:20
IDiff>>
3/3 Idiff
PTD PA13 N. M Tests 7UT 05/03 No. 15
Test: External Fault L1-E HV side (Io Correction)Infeed: LV side
7UT612 TQL 000008 18.06.2003,16:51:06
PTD PA13 N. M Tests 7UT 05/03 No. 16
Test: External Fault L1-E HV side (Io Elimination)Infeed: LV side
7UT612 TQL 000009 18.06.2003,16:52:34
PTD PA13 N. M Tests 7UT 05/03 No. 17
Test: External Fault L1-E HV side (without Io Elim./Correction)Infeed: LV side
7UT612 TQL 000010 18.06.2003,16:55:08
PTD PA13 N. M Tests 7UT 05/03 No. 18
7UT: Test of Add On Stabilisation with sequencer (1 of 5)
for test 1
Test:
- Through flowing current 5 InTr for minimum 10-12ms (Side 1: 18.375A , Side 2: 30.25A)
- Reducing from one current to 5A to get a differential current. (Duration less than the number of periods under parameter 1617 )
- Increasing the current again to its pre value.
Relay: 7UT5125 (5A In)
PTD PA13 N. M Tests 7UT 05/03 No. 19
7UT: Test of Add On Stabilisation with sequencer (2 of 5)
Test 1: with Io-Elimination
PTD PA13 N. M Tests 7UT 05/03 No. 20
7UT: Test of Add On Stabilisation with sequencer (3 of 5)
Add On Stabilisation
2/3 of 10
Restraining current L1 (A) : 2/325 InTr = 6.6InTrRestraining current L2/3 (B/C) : 1/325 InTr = 3.3InTrTrip L1 (A) is blocked, but L2 (B) and L3 (C) will trip.To prevent a Trip of L2/L3 , the through flowing current must be higher than 35/2(Setting 1618=5) , means 7.5 InTr.
PTD PA13 N. M Tests 7UT 05/03 No. 21
7UT: Test of Add On Stabilisation with sequencer (4 of 5)
Test 2: without Io-Elimination
PTD PA13 N. M Tests 7UT 05/03 No. 22
7UT: Test of Add On Stabilisation with sequencer (5 of 5)
Add On Stabilisation
Restraining current L1 (A) : 25 InTr = 10InTr
Restraining current L2/3 (B/C): 0 InTr = 0
There is no Trip !!
PTD PA13 N. M Tests 7UT 05/03 No. 23
7UT6: Test characteristic for YNyn0 with Io-Elimination
Slope 1: 0.25Slope 1: 0.25
PTD PA13 N. M Tests 7UT 05/03 No. 24
7UT6: Test characteristic for YNyn0 with Io-Elimination
Slope 1: 0.25
Slope 2: 0.5