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ower Transmission and Distribution Differential Protection (7UT) Dynamic tests, Tests

Differential Protection

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Page 1: Differential Protection

Power Transmission and Distribution

Differential Protection (7UT)Dynamic tests, Tests

Page 2: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 2

Method of Vector Group Determination

IL1,S1IL1,S2 = IL1 - IL2

330°(n * 30°)

Vector group is

Y d 11

Side 2: Side 1:

1L1

1L2

1L3

2L1

2L2

2L3

Page 3: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 3

Definitions in SIPROTEC 4 Relays

How to see the vector group Yd11?

Original Siprotec 4 (Browser) Phase angles

Side 1: 0°(reference phase)

Side 2: 210°

Please subtract 180°,than you get 30°(360° - 30° = 330°)

Vector definition to a node is positiveThe shown vectors or phase angles are transformed inthis positive definitionThe phase angle is displayed mathematics positive. The reference phase is always phase L1 on side 1

Page 4: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 4

Web Tool (Browser) Vector group Yd11

Page 5: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 5

Vector Group Determination via Fault Record

IL1;Side 1

IL1;Side 2 lags 150° or leads 210° Star point is towards the protected object

Way 1:IL1 Side: 150° + 180° = 330°

Way 2:IL1 Side: 210° - 180° = 30°leads 30° or lags 330°

Phase shift is according the vector group definition 330° 11 * 30°

Page 6: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 6

Test Configuration

7UT612

20 kV 110 kV2500A/1A 500A/1A

500A/1A

Dynamic calculation with NETOMAC Transient files were transplayed with a CMC-256 Test device from Omicron

80 MVAYNd11

Page 7: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 7

7UT612 Differential Protection Settings

Page 8: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 8

Test: Inrush followed by an external fault L1-L2-L3 (LV side) Infeed: HV side

7UT612 TQL 000009 17.06.2003,19:09:31

Inrush

Externalfault

Page 9: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 9

Test: Inrush followed by an internal fault L1-L2-L3 (LV side)Infeed: HV side

7UT612 TQL 000010 17.06.2003,19:11:37

Inrush

Internalfault

Page 10: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 10

Test: External fault L1-L2-L3 (LV side) with CT saturationInfeed: HV side, Saturation detector is active (Diff BL exF L1)

7UT612 TQL 000001 18.06.2003,14:16:23

Differential currentdue to CT saturation

Page 11: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 11

Test: Internal fault L1-E (HV side) with CT saturationInfeed: HV side

7UT612 TQL 000008 17.06.2003,19:02:00

IDiff>>

Page 12: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 12

Test: External Fault L1-L2-L3, evolving fault intern L1-L2-L3Infeed: HV side

7UT612 TQL 000001 17.06.2003,18:35:45

Internalevolving fault

1

3

2

4

Page 13: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 13

Test: Internal Fault L1-E HV side (Io Elimination)Infeed: LV side

7UT612 TQL 000002 18.06.2003,14:53:43

2/3 Idiff

1/3 Idiff

Page 14: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 14

Test: Internal Fault L1-E HV side (Io Correction)Infeed: LV side

7UT612 TQL 000005 18.06.2003,15:01:20

IDiff>>

3/3 Idiff

Page 15: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 15

Test: External Fault L1-E HV side (Io Correction)Infeed: LV side

7UT612 TQL 000008 18.06.2003,16:51:06

Page 16: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 16

Test: External Fault L1-E HV side (Io Elimination)Infeed: LV side

7UT612 TQL 000009 18.06.2003,16:52:34

Page 17: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 17

Test: External Fault L1-E HV side (without Io Elim./Correction)Infeed: LV side

7UT612 TQL 000010 18.06.2003,16:55:08

Page 18: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 18

7UT: Test of Add On Stabilisation with sequencer (1 of 5)

for test 1

Test:

- Through flowing current 5 InTr for minimum 10-12ms (Side 1: 18.375A , Side 2: 30.25A)

- Reducing from one current to 5A to get a differential current. (Duration less than the number of periods under parameter 1617 )

- Increasing the current again to its pre value.

Relay: 7UT5125 (5A In)

Page 19: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 19

7UT: Test of Add On Stabilisation with sequencer (2 of 5)

Test 1: with Io-Elimination

Page 20: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 20

7UT: Test of Add On Stabilisation with sequencer (3 of 5)

Add On Stabilisation

2/3 of 10

Restraining current L1 (A) : 2/325 InTr = 6.6InTrRestraining current L2/3 (B/C) : 1/325 InTr = 3.3InTrTrip L1 (A) is blocked, but L2 (B) and L3 (C) will trip.To prevent a Trip of L2/L3 , the through flowing current must be higher than 35/2(Setting 1618=5) , means 7.5 InTr.

Page 21: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 21

7UT: Test of Add On Stabilisation with sequencer (4 of 5)

Test 2: without Io-Elimination

Page 22: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 22

7UT: Test of Add On Stabilisation with sequencer (5 of 5)

Add On Stabilisation

Restraining current L1 (A) : 25 InTr = 10InTr

Restraining current L2/3 (B/C): 0 InTr = 0

There is no Trip !!

Page 23: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 23

7UT6: Test characteristic for YNyn0 with Io-Elimination

Slope 1: 0.25Slope 1: 0.25

Page 24: Differential Protection

PTD PA13 N. M Tests 7UT 05/03 No. 24

7UT6: Test characteristic for YNyn0 with Io-Elimination

Slope 1: 0.25

Slope 2: 0.5