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CHMI 2227E Biochemistry I. Enzymes: Kinetics. X min. Product. Enzymatic reactions. Let’s set up a typical enzymatic reaction:. Enzyme (each = 1 µmol). Only concentrations we know we’re the ones who set up the experiment!. Substrate (each = 1 µmol). O. O. O. O. DEVD-pNA - PowerPoint PPT Presentation
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CHMI 2227 - E.R. Gauthier, Ph.D. 1
CHMI 2227EBiochemistry I
Enzymes:- Kinetics
CHMI 2227 - E.R. Gauthier, Ph.D. 2
Enzymatic reactions
Let’s set up a typical enzymatic reaction:
Enzyme (each = 1 µmol)
Substrate (each = 1 µmol)
Only concentrations we know we’re the ones who set up the experiment!
X min Product
CHMI 2227 - E.R. Gauthier, Ph.D. 3
Enzymatic reactionsHow do we measure enzyme activity?
1. Detection of the product(s): pNA = para-nitroaniline Absorbs at 405 nm
H3+N-CH-C-NH-CH-C-NH-CH-C-NH-CH-C-OH
O O O O
CH2
COO-
CH2
CH2
COO-
CHCH3H3C
CH2
COO-
NO2H2N
pNA (yellow)
H3+N-CH-C-NH-CH-C-NH-CH-C-NH-CH-C-NH-
O O O O
CH2
COO-
CH2
CH2
COO-
CHCH3H3C
CH2
COO-
NO2DEVD-pNA(uncolored)
DEVD(uncoloured)
Caspase 3 (proteasehydrolase)Measure increase
in A405nm
CHMI 2227 - E.R. Gauthier, Ph.D. 4
Enzymatic reactionsHow do we measure enzyme activity? 2. Accumulation/utilisation of a co-factor:
NADH = absorbs strongly at 340 nm ( = 6.3 molL-1cm-1 ) NAD+ =does not absorb at 340 nm
Measure increase in A340nm
Measure decrease in A340nm
Lactate dehydrogenase
CHMI 2227 - E.R. Gauthier, Ph.D. 5
Enzymatic reactionsHow do we measure enzyme activity? 3. Coupled reactions:
Very useful when neither substrate/product/co-factor can be (easily) detected;
Glutaminase
+ NH4+
1st reaction
Measure increase in A340nm
GlutamateDehydrogenase
+ NAD+ + NADH +H+
2nd reaction
+ NH4++ H2O
Detectable by HPLC but not practical
CHMI 2227 - E.R. Gauthier, Ph.D. 6
Enzymatic reactions
1 min
3 µmol / min VELOCITYor Rate
15 µmol S vs 1 µmol E
Time
[Pro
duct
]
Slope = Initial velocity = v0 = [P] / time
2 min
3 µmol / min
4 min
<3 µmol / min
CHMI 2227 - E.R. Gauthier, Ph.D. 7
Enzymatic reactions
Time
[Pro
duct
]
v0 is proportional to [E]
1µmol E
2µmol E
3µmol E
1 min
3 µmol / min
15 µmol S vs 1 µmol E
1 min
6 µmol / min
15 µmol S vs 2 µmol E
1 min
9 µmol / min
15 µmol S vs 3 µmol E
CHMI 2227 - E.R. Gauthier, Ph.D. 8
Enzymatic reactions
1 min
2 µmol / min
1 µmol / min
1 min
3 µmol / min
1 min
[Substrate]
v 0
Maximum velocity = Vmax
Vmax
½ Vmax
E saturated by S
CHMI 2227 - E.R. Gauthier, Ph.D. 9
Enzymatic reactions
So: 1) v0 (initial velocity) is the rate of the reaction very early on
when [P] is negligeable;
2) v0 can be obtained by taking the slope of the graph of [P] vs Time (units: concentration / time)
3) v0 varies as a function of [E];
4) v0 increases as a function of [S] UNTIL E is saturated by S.
5) When E is saturated with S v0 = Vmax
CHMI 2227 - E.R. Gauthier, Ph.D. 10
Michaelis-Menten Equation
The relationship between vo and [S] can be viewed as a 2 step reaction:
This relationship can be expressed by the Michaelis-Menten equation: [Substrate]
v 0
Maximum velocity = Vmax
Vmax
½ Vmax
E + S ES E + Pk2
k1
k-1
FAST SLOW
vo = Vmax [S] Km + [S]
CHMI 2227 - E.R. Gauthier, Ph.D. 11
Michaelis-Menten Equation
Km can be calculated as the [S] required to acheive half the Vmax;
Km is a measure of the affinity of E for S:
The lower the Km, the less S is requried by E to acheive ½ Vmax, and the greater the affinity of E for S.
[Substrate]
v 0
Vmax
½ Vmax
Km1 Km2
E2
E1
CHMI 2227 - E.R. Gauthier, Ph.D. 12
Km
CHMI 2227 - E.R. Gauthier, Ph.D. 13
Turnover number
At saturating [S] :
vo = Vmax vo is determined by [E] k2 will drive the rate; k2= kcat
So: Vmax = kcat [E]total
kcat = Vmax/[E]total
kcat = turnover number = maximum number of substrate molecules converted to product per second by each active site (units = s-1)
1/kcat = amount of time required for E to convert 1 substrate molecule to the product (i.e. time for 1 catalytic event). Units: s.
E + S ES E + Pk2
k1
K-1
FAST SLOW
CHMI 2227 - E.R. Gauthier, Ph.D. 14
Measuring Km and Vmax
Neither Km nor Vmax can be easily obtained directly from kinetic data because Vmax is rarely acheived (its an hyperbolic curve…); [Substrate]
v 0
Vmax
½ Vmax
Km
CHMI 2227 - E.R. Gauthier, Ph.D. 15
Measuring Km and Vmax However, Km and Vmax can be easily obtained if
we take the reciprocal of (and slightly rearrange) the Michaelis-Menten equation: the Lineweaver-Burk equation:
The graph of 1/vo vs 1/[S] gives a straight line with:
Intercept on the x axis = -1/Km Intercept on the y axis = 1/Vmax
This is the BEST and EASIEST way to accurately obtain Vmax and Km since:
You know [S] (you’re the one who did the experiment!!)
V0 is easily obtained in the lab (slope of [P] vs Time).
1/vo
1/[S]
1/Vmax
-1/Km
Lineweaver-Burk plot
1 vo
= Km x 1 + 1
Vmax [S] Vmax