Che 201 Hand Out 4 Chapter 10

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    Computer Aided Balance

    Calculations

    Dr M. A. A. Shoukat Choudhury

    Department o hemical EngineeringBUET, Dhaka 1000

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    Motivation

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    = . .

    DOF = 0 A Unique Solution

    ,

    solutions

    < , , ,

    made some mistake and wrote more equations

    than that you are entitled to. However, in some

    other areas, you may find DOF>0 where there isno unique solution

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    should be independently specified todefine the roblem com letel . Theseexternally specified variables are called

    design variables Once design variables are specified, the

    other variables can be calculated from the

    re a ons equa ons, w c are ca e s a evariables.

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    -.

    Mixer

    n1 g 2

    40 oCn4 kg O2n k N

    n2 g 2n3 kg N2

    25o

    C

    Q, kJ

    50 oC

    1 ,- 3 relations ( 2 MB, 1 EB)

    DOF = 3

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    -A liquid mixture of n-hexane (HX) and n-heptane

    HP at a hi h ressure is abru tl ex osed to a

    lower pressure. A portion of the mixture evaporates,yielding a vapor mixture relatively rich in hexane

    rich in heptane. The two product streams are in

    e uilibrium at tem erature T and ressure P; theircompositions are related by Raoults Law. PerformDOF analysis. Specify variables so that you get a

    s ra g - orwar so u on2) trial-error solution

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    Example 10.1-1 (contd)

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    Example 10.1-1 (contd)

    10 variables - n1, n2, n3, x1, x2, x3, T, P, p*HX , p

    *HP

    2 Raoults Law

    2 Antoine Equation

    6 E uations

    x2 P = x3 p*HX(1 - x2 ) P = (1 - x3 ) p

    *HP

    DOF = 4

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    1. Straight-Forward Solution:

    Specify Design Variables - n1, x1, x3, T

    - * * ,

    calculated from Antoine Equation

    - 2

    Raoults Law

    - a cu a e n2 an n3 rom componen

    balance

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    1. Straight-Forward Solution (contd):

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    2. Trial and Error Solution

    3. Impossible Solution - n1, n2, n3 and T

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    A process that contains two or more interconnected unitshas fewer degrees of freedom than the sum of thedegrees of freedom of the individual units

    1. Draw and completely label the flow-chart

    2. Determine the local degrees of freedom for eachprocess un , m x ng po n an s ream sp ng po n s

    3. Calculate number of tie variables

    4. Determine the overall de rees of freedom. This isequal to the sum of all local dofs minus number of tievariables.

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    Example 10.1-2 DOF Analysis of a Multiple-Unit Process

    reaction

    CO+2H2CH3OH

    T e res ee , w c conta ns CO an H2 n sto c ometr c proport on,

    enters the process at a rate of 2.2 m3/s at 250C and 6.0 MPa and combinesadiabatically with a recycle stream. The combined stream is heated to 2500C

    and fed to the reactor. The reactor effluent emerges at the same temperature

    and is cooled to 00C at P= 6.0 MPa, partially condensing the methanol

    product. The gas leaving the condenser is saturated with methanol: 1% istaken off for process monitoring purposes and the remainder is recycled. An

    overall CO conversion of 98% is achieved. The ratio of H2 to CO is 2 mol

    H2/1 mol CO everywhere in the process system. Ideal gas behavior may be

    assumed.

    - -

    the given information is sufficient to allow the calculation of the component

    flow rates for all streams, the required heat duties for all process units, and

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    Example 10.1-2 (contd)

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    Purge point:

    ,

    0 balance

    2 dof

    Overall Process DOF: 12 ( Sum of Local DOF)

    11 tie variables

    1 additional relation

    0

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    Two Approaches of Computer Aided Simulation

    Sequential Modular

    - break-down flow chart in terms of modules- write the algorithm/subroutine for the module

    - use the modules as needed to solve the whole problemsequentially

    - Commercial softwares: ASPEN Plus, HYSIS, CHEMCAD, ICAS,Design II

    Equation Based- Equations of all units are collected and solved simultaneously

    - simultaneous solution of a large number of equations (some ofthem may be nonlinear) can be cumbersome and time consuming

    - powerful equation solving commercial packages Maple, Matlab,Mathcad, E-Z solve

    Recently, a combination of the above two approaches are also being used.

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    The following two reactions occur in an ethylene oxide

    2 C2H4 + O2 = 2 C2H4OC2H4 + 3 O2 = 2 CO2 + 2 H2O

    A stream containing equimolar amounts of ethylene and oxygen isjoined by a recycle stream containing pure ethylene, and the

    combined stream is fed to the reactor. The reactor effluent goes to a.

    first stream, which is sold, is pure ethylene oxide; and the second,which is discarded, contains all the carbon dioxide, oxygen, waterand 5% of the unreacted ethylene leaving the reactor; and the third

    , ,unreacted ethylene. Perform a degrees of freedom analysis for theprocess and specify the design variables that must be known tosolve the problem completely.