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.
Chapter 7
Physical Layer and
Transmission Media
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Chapter 7: Outline
7.17.1
DATA AND SIGNAL DATA AND SIGNAL
7.27.2 DIGITAL TRANSMISSION DIGITAL TRANSMISSION
7.37.3 ANALOG TRANSMISSION ANALOG TRANSMISSION
7.47.4 BANDWIDTH UTILIZATION BANDWIDTH UTILIZATION
7.57.5TRANSMISSION MEDIATRANSMISSION MEDIA
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Chapter 7: Objective
We first discuss the relatioshi! "et#ee data ad si$als% We
the sho# ho# data ad si$als ca "e "oth aalo$ ad di$ital%
We the cocetrate o di$ital tras&issio% We sho# ho# to
co'ert di$ital ad aalo$ data to di$ital si$als%
Ne(t) #e cocetrate o aalo$ tras&issio% We sho# ho# to
co'ert di$ital ad aalo$ data to aalo$ si$als%
We the tal* a"out &ulti!le(i$ techi+ues ad ho# the, caco&"ie se'eral chaels%
-iall,) #e $o "elo# the !h,sical la,er ad discuss the
tras&issio &edia%
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7-1 DATA AND SIGNALS7-1 DATA AND SIGNALS
At the physical layer, thecommunication is node-to-node,but the nodes exchangeelectromagnetic signals. Figure7.1 uses the same scenario weshowed in four earlier chapters,
but the communication is now atthe physical layer.
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Figure 7.1: Communication at the physical layer
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.%/%/ Aalo$ ad Di$ital
Data ca "e aalo$ or di$ital% The ter& aalo$ data Data ca "e aalo$ or di$ital% The ter& aalo$ datarefers to ifor&atio that is cotiuous% Di$ital datarefers to ifor&atio that is cotiuous% Di$ital data
ta*e o discrete 'alues%ta*e o discrete 'alues%
Li*e the data the, re!reset) si$als ca "e either Li*e the data the, re!reset) si$als ca "e either
aalo$ or di$ital% A aalo$ si$al has ifiitel,aalo$ or di$ital% A aalo$ si$al has ifiitel,&a, le'els of itesit, o'er a !eriod of ti&e% A&a, le'els of itesit, o'er a !eriod of ti&e% A
di$ital si$al) o the other had) ca ha'e ol, adi$ital si$al) o the other had) ca ha'e ol, a
li&ited u&"er of defied 'alues% Althou$h eachli&ited u&"er of defied 'alues% Althou$h each
'alue ca "e a, u&"er) it is ofte as si&!le as /'alue ca "e a, u&"er) it is ofte as si&!le as /
ad 0%ad 0%
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7.7
.%/%/ 1cotiued2
Aalo$ Si$als Aalo$ Si$als Ti&e ad -re+uec, Do&aisTi&e ad -re+uec, Do&ais 3o&!osite Si$als3o&!osite Si$als Bad#idth Bad#idth
Di$ital Si$als Di$ital Si$als
Bit Rate Bit Rate Bit Le$th Bit Le$th
Di$ital Si$al as a 3o&!osite Aalo$ Si$al Di$ital Si$al as a 3o&!osite Aalo$ Si$al Tras&issio of Di$ital Si$alsTras&issio of Di$ital Si$als Base"ad Tras&issio Base"ad Tras&issio Broad"ad Tras&issio Broad"ad Tras&issio
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7.8
Figure 7.: Comparison of analog and digital signals
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7.9
Figure 7.!: A sine wa"e
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Figure 7.#: $a"elength and period
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12
The frequency domain is more compact and useful when we
are dealing with more than one sine wave. For example,
Figure 7.6 shows three sine waves, each with different
amplitude and frequency. All can be represented by three
spies in the frequency domain.
(xample 7.1
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Figure 7.): &he time domain and fre'uency domain ofthree sine wa"es
Figure 7 7: &he bandwidth of periodic and nonperiodic
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Figure 7.7: &he bandwidth of periodic and nonperiodiccomposite
signals
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.le"els and the
other with four signal le"els
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Assume we need to download text documents at the rate of
!"" pages per minute. #hat is the required bit rate of the
channel$ A page is an average of %& lines with '" characters
in each line. (f we assume that one character requires ' bits,
the bit rate is
(xample 7.
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. periodic and
nonperiodic digital signals
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Figure 7.1: aseband transmission
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An example of a dedicated channel where the entire
bandwidth of the medium is used as one single channel is a
)A*. Almost every wired )A* today uses a dedicated
channel for two stations communicating with each other.
(xample 7.!
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Figure 7.11: andwidth of a band-pass channel
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.transmission on a
band-pass channel
( l 7 #
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An example of broadband transmission using modulation is
the sending of computer data through a telephone subscriber
line, the line connecting a resident to the central telephone
office. Although this channel can be used as a low+pass
channel, it is normally considered a band+pass channel. ne
reason is that the bandwidth is so narrow -& /0 that if wetreat the channel as low+pass and use it for baseband
transmission, the maximum bit rate can be only ' bps
-explained later0. The solution is to consider the channel a
band+pass channel, convert the digital signal from thecomputer to an analog signal, and send the analog signal.
(xample 7.#
( l 7 %
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A second example is the digital cellular telephone. For better
reception, digital cellular phones digiti/e analog voice.
Although the bandwidth allocated to a company providing
digital cellular phone service is very wide, we still cannot
send the digiti/ed signal without conversion. The reason is
that we have only a band+pass channel available betweencaller and callee. For example, if the available bandwidth is
# and we allow !""" couples to tal simultaneously, this
means the available channel is #1!""", 2ust part of the
entire bandwidth. #e need to convert the digiti/ed voice to acomposite analog signal before transmission.
(xample 7.%
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.%/%4 Tras&issio I&!air&et
Si$als tra'el throu$h tras&issio &edia) #hich Si$als tra'el throu$h tras&issio &edia) #hichare ot !erfect% The i&!erfectio causes si$alare ot !erfect% The i&!erfectio causes si$al
i&!air&et% This &eas that the si$al at thei&!air&et% This &eas that the si$al at the
"e$ii$ of the &ediu& is ot the sa&e as the"e$ii$ of the &ediu& is ot the sa&e as the
si$al at the ed of the &ediu&% What is set is otsi$al at the ed of the &ediu&% What is set is ot#hat is recei'ed% Three causes of i&!air&et are#hat is recei'ed% Three causes of i&!air&et are
atteuatio) distortio) ad oise%atteuatio) distortio) ad oise%
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.%/%4 1cotiued2
Atteuatio Atteuatio
Distortio Distortio
Si$al5to5Noise Ratio 1SNR2 Si$al5to5Noise Ratio 1SNR2
Noise Noise
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Figure 7.1%: oise
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. / 6 D t R t Li it
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.%/%6 Data Rate Li&its
A 'er, i&!ortat cosideratio i data A 'er, i&!ortat cosideratio i data
co&&uicatios is ho# fast #e ca sed data) ico&&uicatios is ho# fast #e ca sed data) i
"its !er secod) o'er a chael% Data rate de!eds"its !er secod) o'er a chael% Data rate de!eds
o three factors7o three factors7
/%/% The "ad#idth a'aila"leThe "ad#idth a'aila"le
4%4% The le'el of the si$als #e useThe le'el of the si$als #e use
6%6% The +ualit, of the chael 1the le'el of oise2The +ualit, of the chael 1the le'el of oise2
T#o theoretical for&ulas #ere de'elo!ed toT#o theoretical for&ulas #ere de'elo!ed to
calculate the data rate7 oe ", N,+uist for acalculate the data rate7 oe ", N,+uist for a
oiseless chael) aother ", Shao for a ois,oiseless chael) aother ", Shao for a ois,
chael%chael%
. / 6 1 ti d2
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.%/%6 1cotiued2
Noiseless 3hael7 N,+uist Bit Rate Noiseless 3hael7 N,+uist Bit Rate
Nois, 3hael7 Shao 3a!acit, Nois, 3hael7 Shao 3a!acit,
Usi$ Both Li&itsUsi$ Both Li&its
(xample 7 7
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#e need to send %6 bps over a noiseless -ideal0 channel
with a bandwidth of %" /. ow many signal levels do we
need$ #e can use the *yquist formula as shown:
(xample 7.7
3ince this result is not a power of %, we need to either
increase the number of levels or reduce the bit rate. (f we
have !%' levels, the bit rate is %'" bps. (f we have 6&levels, the bit rate is %&" bps.
(xample 7 *
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;onsider an extremely noisy channel in which the value of
the signal+to+noise ratio is almost /ero. (n other words, the
noise is so strong that the signal is faint. For this channel the
capacity ; is calculated as shown below.
(xample 7.*
This means that the capacity of this channel is /ero
regardless of the bandwidth. (n other words, the data is socorrupted in this channel that it is useless when received.
(xample 7 +
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#e can calculate the theoretical highest bit rate of a regular
telephone line. A telephone line normally has a bandwidth of
""" / -"" to "" /0 assigned for data
communications. The signal+to+noise ratio is usually !6%.
For this channel the capacity is calculated as shown below.
(xample 7.+
This means that the highest bit rate for a telephone line is
&.''! bps. (f we want to send data faster than this, we caneither increase the bandwidth of the line or improve the
signal+to noise ratio.
(xample 7 1
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#e have a channel with a !+</ bandwidth. The 3*= for
this channel is 6. #hat are the appropriate bit rate and
signal level$
(xample 7.1
. / 8 9 f
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.%/%8 9erfor&ace
U! to o#) #e ha'e discussed the tools ofU! to o#) #e ha'e discussed the tools oftras&itti$ data 1si$als2 o'er a et#or* ad ho#tras&itti$ data 1si$als2 o'er a et#or* ad ho#
the data "eha'e% Oe i&!ortat issue i et#or*i$the data "eha'e% Oe i&!ortat issue i et#or*i$
is the !erfor&ace of the et#or*:ho# $ood is it;is the !erfor&ace of the et#or*:ho# $ood is it;
We discuss +ualit, of ser'ice) a o'erallWe discuss +ualit, of ser'ice) a o'erall&easure&et of et#or* !erfor&ace) i detail i&easure&et of et#or* !erfor&ace) i detail i
3ha!ter <%3ha!ter <%
. / 8 1cotiued2
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.%/%8 1cotiued2
Bad#idth Bad#idth Bad#idth i Hert= Bad#idth i Hert= Bad#idth i Bits !er Secods Bad#idth i Bits !er Secods Relatioshi! Relatioshi!
Throu$h!ut Throu$h!ut
Latec, 1Dela,2 Latec, 1Dela,2
Bad#idth5Dela, 9roduct Bad#idth5Dela, 9roduct
>itter >itter
(xample 7 11
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The bandwidth of a subscriber line is & / for voice or
data. The bandwidth of this line for data transmission can be
up to 6 bps, using a sophisticated modem to change the
digital signal to analog. (f the telephone company improves
the quality of the line and increases the bandwidth to ' /,
we can send !!% bps.
(xample 7.11
Figure 7 17: Filling the lin4 with bits for cases 1 and
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Figure 7.17: Filling the lin4 with bits for cases 1 and
(xample 7 1
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#e can thin about the lin between two points as a pipe.
The cross section of the pipe represents the bandwidth, and
the length of the pipe represents the delay. #e can say the
volume of the pipe defines the bandwidth+delay product, as
shown in Figure 7.!'.
(xample 7.1
Figure 7 1*: Concept of bandwidth delay product
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Figure 7.1*: Concept of bandwidth-delay product
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7-2 DIGITAL TRANSMISSION7-2 DIGITAL TRANSMISSION
A computer networ4 is designed tosend information from one point toanother. &his information needs tobe con"erted to either a digitalsignal or an analog signal fortransmission. 5n this section, we
discuss the /rst choice, con"ersionto digital signals6 in the next section,we discuss the second choice,
con"ersion to analog signals.
. 4 / Di$ital to Di$ital 3o'ersio
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.%4%/ Di$ital5to5Di$ital 3o'ersio
I this sectio) #e see ho# #e ca re!reset I this sectio) #e see ho# #e ca re!resetdi$ital data ", usi$ di$ital si$als% Thedi$ital data ", usi$ di$ital si$als% The
co'ersio i'ol'es three techi+ues7 lieco'ersio i'ol'es three techi+ues7 lie
codi$) "loc* codi$) ad scra&"li$% Liecodi$) "loc* codi$) ad scra&"li$% Lie
codi$ is al#a,s eeded? "loc* codi$ adcodi$ is al#a,s eeded? "loc* codi$ ad
scra&"li$ &a, or &a, ot "e eeded%scra&"li$ &a, or &a, ot "e eeded%
. 4 / 1cotiued2
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.%4%/ 1cotiued2
Lie 3odi$ Lie 3odi$ 9olar Sche&es 9olar Sche&es Bi!olar Sche&es Bi!olar Sche&es Multile'el Sche&es Multile'el Sche&es
Bloc* 3odi$ Bloc* 3odi$ 8B@B 3odi$ 8B@B 3odi$ <B@/0B 3odi$ <B@/0B 3odi$
Scra&"li$ Scra&"li$
B<ZS 3odi$ B<ZS 3odi$ HDB6 3odi$ HDB6 3odi$
Figure 7 1+: ine coding and decoding
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Figure 7.1+: ine coding and decoding
Figure 7 : 8olar schemes 98art 5: 3;
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Figure 7.: 8olar schemes 98art 5: 3;
Figure 7.: 8olar schemes 98art 55: 3;
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Figure 7.: 8olar schemes 98art 55: 3;
Figure 7.: 8olar schemes 98art 555: anchesters;
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Figure 7.: 8olar schemes 98art 555: anchesters;
Figure 7.1: ipolar schemes: A5 and pseudoternary
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Figure 7.1: ipolar schemes: A5 and pseudoternary
Figure 7.: ultile"el: 1< and *)&
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Figure 7.: ultile"el: 1< and *)&
Figure 7.!: loc4 coding concept
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Figure 7.!: loc4 coding concept
Figure 7.#: =sing bloc4 coding #>% with 3-5 linedi h
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coding scheme
Figure 7.%: *>1 bloc4 encoding
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g > g
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Figure 7.7: &wo cases of *2 scrambling techni'ue
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g g '
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Figure 7.+: Components of 8C encoder
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Figure 7.!: y'uist sampling rate for low-pass andbandpass signals
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bandpass signals
Figure 7.!: <uantiation and encoding of a sampledsignal
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signal
(xample 7.1!
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64
#e want to digiti/e the human voice. #hat is the bit rate,
assuming ' bits per sample$
Solution
The human voice normally contains frequencies from " to
&""" /. 3o the sampling rate and bit rate are calculated as
follows.
p
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Figure 7.!#: &he process of delta modulation
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.%6%/ Di$ital5to5Aalo$ 3o'ersio
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$ $
Di$ital5to5aalo$ co'ersio is the !rocess of Di$ital5to5aalo$ co'ersio is the !rocess of
cha$i$ oe of the characteristics of a aalo$cha$i$ oe of the characteristics of a aalo$
si$al "ased o the ifor&atio i di$ital data%si$al "ased o the ifor&atio i di$ital data%
-i$ure .%6 sho#s the relatioshi! "et#ee the-i$ure .%6 sho#s the relatioshi! "et#ee the
di$ital ifor&atio) the di$ital5to5aalo$di$ital ifor&atio) the di$ital5to5aalo$&odulati$ !rocess) ad the resultat aalo$&odulati$ !rocess) ad the resultat aalo$
si$al%si$al%
.%6%/ 1cotiued2
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1 2
A&!litude Shift Ce,i$ A&!litude Shift Ce,i$
Biar, ASC 1BASC2 Biar, ASC 1BASC2 Multile'el ASC Multile'el ASC Biar, -SC 1B-SC2 Biar, -SC 1B-SC2
Multile'el -SC Multile'el -SC 9hase Shift Ce,i$ 9hase Shift Ce,i$
Biar, 9SC 1B9SC2 Biar, 9SC 1B9SC2 uadrature 9SC 19SC2uadrature 9SC 19SC2
3ostellatio Dia$ra&3ostellatio Dia$ra&
uadrature A&!litude Modulatiouadrature A&!litude Modulatio
Bad#idth for AM Bad#idth for AM
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Figure 7.!): inary amplitude shift 4eying
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Figure 7.!+: Concept of a constellation diagram
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Figure 7.#: Constellation diagrams for some <As
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.%6%4 Aalo$5to5Aalo$ 3o'ersio
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Aalo$5to5aalo$ co'ersio) or aalo$ Aalo$5to5aalo$ co'ersio) or aalo$
&odulatio) is the re!resetatio of aalo$&odulatio) is the re!resetatio of aalo$ifor&atio ", a aalo$ si$al% Oe &a, as*ifor&atio ", a aalo$ si$al% Oe &a, as*
#h, #e eed to &odulate a aalo$ si$al? it is#h, #e eed to &odulate a aalo$ si$al? it is
alread, aalo$% Modulatio is eeded if thealread, aalo$% Modulatio is eeded if the&ediu& is "ad!ass i ature or if ol, a&ediu& is "ad!ass i ature or if ol, a
"ad!ass chael is a'aila"le to us%"ad!ass chael is a'aila"le to us%
A&!litude Modulatio A&!litude Modulatio -re+uec, Modulatio-re+uec, Modulatio
9hase Modulatio 9hase Modulatio
Figure 7.#1: Amplitude modulation
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Figure 7.#: Fre'uency modulation
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7 4 BANDWIDTH UTILIZATION7 4 BANDWIDTH UTILIZATION
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7-4 BANDWIDTH UTILIZATION7-4 BANDWIDTH UTILIZATION
5n real life, we ha"e lin4s withlimited bandwidths. 2ometimeswe need to combine se"eral low-bandwidth channels to ma4e useof one channel with a largerbandwidth. 2ometimes we need to
expand the bandwidth of achannel to achie"e goals such as
pri"acy and anti-Bamming.
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.%8%/ 1cotiued2
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-re+uec,5Di'isio Multi!le(i$ -re+uec,5Di'isio Multi!le(i$
Wa'ele$th5Di'isio Multi!le(i$ Wa'ele$th5Di'isio Multi!le(i$
S,chroous TDM S,chroous TDM Statistical Ti&e5Di'isio Multi!le(i$ Statistical Ti&e5Di'isio Multi!le(i$
Ti&e5Di'isio Multi!le(i$ Ti&e5Di'isio Multi!le(i$
Figure 7.##: 0i"iding a lin4 into channels
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Figure 7.#%: Fre'uency-di"ision multiplexing
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(xample 7.1#
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Assume that a voice channel occupies a bandwidth of & /.
#e need to combine three voice channels into a lin with a
bandwidth of !% /, from %" to % /. 3how theconfiguration, using the frequency domain. Assume there
are no guard bands.
Figure 7.#): (xample 7.1#
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Figure 7.#7: $a"elength-di"ision multiplexing
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Figure 7.#+: 2ynchronous time-di"ision multiplexing
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(xample 7.1)
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Telephone companies implement T@< through a hierarchy
of digital signals, called digital signal -@30 service or digital
hierarchy. Figure 7.! shows the data rates supported byeach level. The commercial implementations of these
services are referred to as T lines.
❑ DS-0 service is a single digital channel of 64 kbps.
❑ DS-1 is a 1.544-Mbps service.
❑ DS-2 is a 6.12-Mbps service.
❑ DS- is a 44.!6-Mbps service.
❑ DS-4 is a 2!4.1!6-Mbps service.
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Figure 7.%#: Fre'uency hopping spread spectrum9F@22;
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Figure 7.%%: F@22 cycles
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Figure 7.%7: 0222
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7-5 TRANSMISSION MEDIA7-5 TRANSMISSION MEDIA
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7 5 TRANSMISSION MEDIA7 5 TRANSMISSION MEDIA
$e discussed many issues relatedto the physical layer in thischapter. 5n this section, we discuss
transmission media. &ransmissionmedia are actually located belowthe physical layer and are directly
controlled by the physical layer.$e could say that transmissionmedia belong to layer ero.
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Figure 7.%+: &wisted-pair cable
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Figure 7.)!: odes
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Figure 7.)#: (lectromagnetic spectrum for wirelesscommunication
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