Calculation of Kcal

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    PdillonFall 2011

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    The patient is getting 125ml/h ofThe patient is getting 125ml/h of

    D5%RL or 1000ml per 8 hours. HowD5%RL or 1000ml per 8 hours. How

    many alories is she getting in 2!many alories is she getting in 2!

    hours"hours" #f 1000 ml is 8 hours$ then 000 ml#f 1000 ml is 8 hours$ then 000 ml

    in 2!.in 2!.

    &on'ersion fator (&on'ersion fator (

    1 )ram D5%RL ( .! alories1 )ram D5%RL ( .! alories

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    1 )ram of #* De+trose ( .! ,al/)ram1 )ram of #* De+trose ( .! ,al/)ram

    How many )rams of De+trose in D5-How many )rams of De+trose in D5-solution"solution"

    D5- means De+trose inD5- means De+trose in 5% solution5% solution((

    5/100 gi'es you the5/100 gi'es you the amount of )rams in 1mlamount of )rams in 1ml..#n this ase it woul ( 0.05 )rams 50mg.#n this ase it woul ( 0.05 )rams 50mg.Then 1000ml ( 50 )rams of De+troseThen 1000ml ( 50 )rams of De+trose

    1000 ml +.05 )rams ( 50 )rams1000 ml +.05 )rams ( 50 )rams

    Therefore$ in 8 hours$ sine she is getting Therefore$ in 8 hours$ sine she is getting the amount or 000 ml$ it woul e thethe amount or 000 ml$ it woul e thenumer of grams (150 )rams of De+trosenumer of grams (150 )rams of De+trose

    R34LT6 150 )rams .! ,al (R34LT6 150 )rams .! ,al ( 510 ,al510 ,al

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    The 2,g infant is orere to eThe 2,g infant is orere to e

    plae on T7 .plae on T7 .

    20% De+trose at 10.8/hr.De+trose620% De+trose at 10.8/hr.De+trose6

    20%e+trose re9uires a entral20%e+trose re9uires a entral

    line. :or infants an hilren$line. :or infants an hilren$

    rug osages are eterminerug osages are eterminease on weight in mg/;g 7

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    ====:irst rememer 20 % e+trose ( 20 grams/100ml ( 0.2:irst rememer 20 % e+trose ( 20 grams/100ml ( 0.2grams e+trose/mlgrams e+trose/ml

    THR33 4T374THR33 4T374

    4T37 164T37 16You need how much (mg or gm) in theYou need how much (mg or gm) in the

    solution you will be giving: 10.8solution you will be giving: 10.8

    mlhour ! 0.2 gramsml " 2.1#mlhour ! 0.2 gramsml " 2.1#

    gramshourgramshour

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    To get this in minutes rather than theTo get this in minutes rather than thehours$ on'ert from hours to minutes 1hours$ on'ert from hours to minutes 1hr ( >0 min.6hr ( >0 min.6

    2.1> gm/hour i'ie y >0 min/hour (2.1> gm/hour i'ie y >0 min/hour (

    0.0> grams/min ( > mg/min 4ine you0.0> grams/min ( > mg/min 4ine younee mg/min$ multiply the grams ynee mg/min$ multiply the grams y1000 to on'ert to milligrams6 1 gram (1000 to on'ert to milligrams6 1 gram (1000 mg.1000 mg.

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    ow Di'ie y the weight of the infant toow Di'ie y the weight of the infant to

    see how muh this 2;g infant willsee how muh this 2;g infant willreei'e6reei'e6

    > mg/min i'ie y 2 ;g (> mg/min i'ie y 2 ;g (

    18 mg/;g/minute.18 mg/;g/minute.

    ==?==?@ou always he;

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    1 . #: TH3 AD

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    2. 25G.2 ml/ay + 0.02 grams/ml (2. 25G.2 ml/ay + 0.02 grams/ml (

    5.G> grams/ay5.G> grams/ay

    4tep .4tep .5.G> grams/ay i'ie y 2 ;g ( 2.G85.G> grams/ay i'ie y 2 ;g ( 2.G8((

    grams/;g/ay of protein grams/;g/ay of protein

    Rememer6Rememer6 :irst he; the norms an here forpremature an term infants. The re9uire aily amount ofprotein neee to promote nitrogen retention is 2.5 C grams/;g/ay$ so this aition to the hyperal orer woul

    pro'ie an appropriate amount re9uire..

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    4T3746 4T3746

    4tep 1.4tep 1.20 % ( 20 grams/100 ml (20 % ( 20 grams/100 ml (

    0.20.2grams/mlgrams/ml

    4tep 2.4tep 2.28.8 ml/ay + 0.2 grams/ml (28.8 ml/ay + 0.2 grams/ml (

    5.> grams/ay of fat5.> grams/ay of fat

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    5.> grams/ay i'ie y 2 ;g (5.> grams/ay i'ie y 2 ;g (

    2.88 grams/;g/ay of fat2.88 grams/;g/ay of fat

    ==== :or premature infants or infants 4)E the:or premature infants or infants 4)E the

    ma+imum reommene amount of fat/ayma+imum reommene amount of fat/aywoul e grams/;g/ay$ so thiswoul e grams/;g/ay$ so thishyperalimentation orer woulhyperalimentation orer woul

    pro'ie an appropriate amount.pro'ie an appropriate amount.

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    2 -HET #4 TH3

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    $%&P 2.$%&P 2.

    2. 25G.2 ml/ay + 0.22. 25G.2 ml/ay + 0.2grams e+trose/ml ( 51.8! grams/aygrams e+trose/ml ( 51.8! grams/ay

    e+trose.e+trose.

    4tep .4tep .

    De+trose has .! ,al/gramDe+trose has .! ,al/gram$ so$ so

    .! al/gram + 51.8! gram (.! al/gram + 51.8! gram (

    1>. ,al from1>. ,al from

    e+trosee+trose