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4Pengumpulandan pengolahan data
4.1 Pengumpulan data
4.1.1 Data poisson dan eksponensial
Tabel 4.1.1Data poisson dan eksponensial
N
o
Data Haidar Data Kahfi
Poisson Eksponensial Poisson Eksponensial
1 0.00 0.88 0.00 1.43
2 0.00 0.92 0.00 2.12
3 0.00 0.93 0.00 2.52
4 0.00 0.98 0.00 2.855 0.00 1.00 0.00 3.12
6 0.00 1.02 0.00 3.63
7 0.00 1.02 0.00 3.97
8 0.00 1.02 0.00 4.08
9 0.00 1.05 0.00 4.13
10 0.00 1.08 0.00 4.25
11 0.00 1.10 0.00 4.47
12 0.00 1.13 0.00 4.75
13 0.00 1.18 0.00 5.02
14 1.00 1.18 0.00 5.03
15 1.00 1.22 0.00 5.03
16 1.00 1.22 0.00 5.05
17 1.00 1.33 0.00 5.08
18 1.00 1.53 0.00 5.18
19 1.00 1.58 1.00 5.20
20 1.00 1.62 1.00 5.52
21 1.00 1.63 1.00 5.82
22 1.00 1.63 1.00 6.28
23 1.00 1.70 1.00 6.5024 1.00 1.73 1.00 6.80
25 1.00 1.78 1.00 6.92
26 1.00 1.80 1.00 6.97
27 2.00 1.85 1.00 7.05
28 2.00 1.87 1.00 7.10
29 2.00 1.97 1.00 7.17
30 2.00 1.98 1.00 7.25
Tabel 4.1.1Data poisson dan eksponensial (lanjutan)
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N
o
Data Haidar Data Kahfi
Poisson Eksponensial Poisson Eksponensial
31 2.00 2.38 2.00 7.47
32 2.00 2.57 2.00 7.82
33 2.00 2.62 2.00 7.85
34 2.00 3.08 2.00 8.02
35 2.00 3.25 2.00 10.83
4.2 Pengolahan data
4.2.1 Uji chi-square
4.2.1.1Ujichi-square satu sampel diskit (poisson !aida) n"#$
a) Uji hipotesis
H0= sampel mengikuti disti!usi poisson
H1= sampel tidak mengikuti disti!usi poisson
b) "iteia penolakan
H0ditolak jika #2hit$ #
2% & '( dimana v=kp1=311=1 )4.1*
% = 1+ = #2% & ' = #20.01 & 1 = 6.635
% = 5+ = #2% & '= #20.05 & 1 = 3.841
% = 10+ = #2% & ' = #20.1 & 1 = 2.710
c) Uji statistik
Tabel 4.1.2Distibusi %ekuensi satu sampel diskit
xi Oi = Fi Fi.xi
0 13 0
1 13 13
2 9 18
3 3!
1* ,ata-ata
=Fi.x i
Fi )4.2*
=31
35=0.89
imana& / adalah ata-ata pesentase sukses
adalah jumlah pesentase sukses
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# adalah pengamatan
2* o!a!ilitas poisson
P ( , x )=e
x
X !
)4.3*
P (0.89,0 )=2.718280.86
0.890
0 ! = 0.411
P (0.89 ,1 )=2.71828
0.860.89
0
1! = 0.365
P (0.89 ,2 )= 2.718280.86
0.892
2!
= 0.163
imana& adalah po!a!litas
/ adalah ata-ata pesentase sukses
e adalah epsilon, nilaina adalah 2.71828
adalah !anakna sukses dalam sampel ukuan n
3* ekuensi haapan
Ei=n P )4.4*
Ei(0)=350.411=14.385
Ei(1)=350.365=12.775
Ei(2)=350.163=5.705
imana& i adalah ekuensi haapan
adalah po!a!litas
n adalah !anakna sampel
4* hi-square hitung
OiEi2
X(xi )2 =
)4.5*
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1314.3852
X(0)2 =
1312.7752
X(1)2 =
95.7052
X(2)2 =
imana& #2adalah hi-square hitungi adalah ekuensi haapan
i adalah ekuensi
Tabel 4.4.#Distibusi %ekuensi chi-square satu sampel diskit
K xi Oi = Fi Pi Ei "#
1 0 13 0.411 14.385 0.133
2 1 13 0.365 12.775 0.004
3 2 9 0.163 5.705 1.903
#2hit 2.04
d) :nalisis pe!andingan
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&amba 4.4.1'ua pebandingan uji chi-square satu sampel diskit
e) "esimpulan
% = 1+ H0diteima( sampel mengikuti disti!usi poisson.
% = 5+ H0diteima( sampel mengikuti disti!usi poisson.
% = 10+ H0diteima( sampel mengikuti disti!usi poisson.
4.2.1.2 Ujichi-square dua sampel diskit (poisson !aida dan poisson 'ah%i) n"*
a) Uji hipotesis
H0= sampel mengikuti disti!usi poisson
H1= sampel tidak mengikuti disti!usi poisson
b) "iteia penolakan
H0ditolak jika #2hit$ #
2% & '
dimana v=(R1)(kp1)=(21)(311)=1 )4.6*
% = 1+ = #2% & ' = #20.01 & 2 = 6.635
% = 5+ = #2% & '= #20.05 & 2 = 3.841
% = 10+ = #2% & ' = #20.1 & 2 = 2.710
c) Uji statistik
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Tabel 4.1.4Distibusi %ekuensi satu sampel diskit
Data Haidar Data Kahfi
xi Oi = Fi "i Oi = Fi
0 13 0 18
1 13 1 12
2 9 2 5
3 3
1* ekuensi haapan
Ei=(Oi1+Oi2 ) n1
n1+n2
)4.7*
Ei(0)=(13+18 )3535+35
=15.5
Ei(1)=(13+12 )3535+35
=12.5
Ei(2)=(9+5 )3535+35
=7
imana& i adalah ekuensi haapani1 adalah ekuensi sampel ep ;aepul ,
i2 adalah ekuensi sampel :
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1312.52
X(2)2 =
972
X(3)2 =
imana& #2adalah hi-square hitung
i adalah ekuensi haapan
i adalah ekuensi
3* hi-square hitung "ahi
OiEi2
X(xi )2 =
)4.9*
1815.52
X(1)2 =
1212.52
X(2)2
=
572
X(3)2 =
imana& #2adalah hi-square hitung
i adalah ekuensi haapan
i adalah ekuensi
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min adalah nilai paling endah atau minimum
2* ?umlah kelas
Jk=1+3.3 logn )4.11*
Jk=1+3.3 log35 = 6.10
imana& ?k adalah jumlah atau jangkauan kelas
n adalah jumlah data
3* Interval
I=R
Jk)4.12*
I=R
Jk=
2.37
6 =0.40
imana&Iadalah interval
Tabel 2.4.1#Distibusi %ekuensi eksponensial
Interval Fi $%& '%& %( fi.%(
0.88 > 1.22 16 0.875 1.275 1.075 17.200
1.28 > 1.67 6 1.275 1.675 1.475 8.850
1.68 > 2.07 8 1.675 2.075 1.875 15.000
2.08 > 2.47 1 2.075 2.475 2.275 2.275
2.48 > 2.87 2 2.475 2.875 2.675 5.350
2.88 > 3.27 2 2.875 3.275 3.075 6.150
3 .*#
4* @enentukan ata-ata
=X=fi.cm
fi )4.13*
=X=54.825
35 = 1.566
imana& adalah ata-ata
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5* @enentukan po!a!ilitas AB
P1= P(LCB) =1e
(LCB ) )4.14*
P1(1) =12.71828
(0.8751.566)= 0.428
P1(2) =12.71828
(1.2751.566)= 0.557
P1(3) =12.71828
(1.6751.566)= 0.657
P1(4) =12.71828
(2.0751.566)= 0.734
P1(5) =12.71828
(2.4751.566)= 0.794
P1(6) =12.71828
(2.8751.566)= 0.840
6* @enentukan po!a!ilitas UB
P2= P(UCB) =1e
(UCB ) )4.15*
P1(2) = 12.71828(1.2751.566)= 0.557
P1(3) =12.71828
(1.6751.566)= 0.657
P1(4) =12.71828
(2.0751.566)= 0.734
P1(5) =12.71828
(2.4751.566)= 0.794
P1(5) = 12.71828(2.875
1.566
)= 0.840P1(6) =
12.71828(3.2751.566)= 0.876
7) Menentukan Probabiita!
P = P2" P1 )4.16*
P(1)= 0.557 " 0.428 = 0.129
P(2)= 0.657 " 0.557 = 0.100
P(3)= 0.734 " 0.657 = 0.077
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P(4) = 0.794 " 0.734 = 0.060
P(5)= 0.840 " 0.794 = 0.046
P(6)= 0.876 " 0.840 = 0.036
imana& adalah adalah po!a!litas
ABadalah po!a!ilitas pada tiap kelas AB
UBadalah po!a!ilitas pada tiap kelas UBe adalah epsilon( nilaina adalah 2.17828
C adalah ata-ata
8* @enentukan ekuensi haapan
Eixi=n p )4.17*
Ei1=350.129=4.515
Ei2=350.100=3.500
Ei3=350.077=2.695
Ei4=350.060=2.100
Ei5=350.046=1.610
Ei6=350.036=1.260
imana& i adalah ekuensi haapan
n adalah !anakna sampel
p adalah po!a!ilitas
9* @enentukan hi-squarehitung
OiEi2
X(xi )2 =
)4.18*
164.5152
X(1 )
2 =
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63.5002
X(2)2 =
82.6952
X(3)2 =
12.1002
X(4)2 =
21.6102
X(5)2 =
21.2602
X(6)2 =
imana& #2adalah hi-square hitung
i adalah ekuensi haapan
i adalah ekuensi
Table 4.4.Distibusi %ekuensi chi-squaresatu sampel kontin+u
K $%& '%& Oi = Fi P! P# Pi Ei "#
10.875 1.275 16 0.428 0.557 0.129 4.515 29.215
1.275 1.675 6 0.557 0.657 0.100 3.500 1.786
2
1.675 2.075 8 0.657 0.734 0.077 2.695 10.443
2.075 2.475 1 0.734 0.794 0.060 2.100 0.576
2.475 2.875 2 0.794 0.840 0.046 1.610 0.094
3 2.875 3.275 2 0.840 0.876 0.036 1.260 0.435
"#hit #.
* "iteia penolakan
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H0ditolak jika #2hit$ #
2% & '( dimana v=kp1=311=1 )4.19*
% = 1+ = #2% & ' = #20.01 & 1 = 6.635
% = 5+ = #2% & '= #20.05 & 1 = 3.841
% = 10+ = #2% & ' = #20.1 & 1= 2.710
d* :nalisis pe!andingan
&amba 4.4.#'ua pebandingan uji chi-square satu sampel kontin+ue* "esimpulan
% = 1+ H0ditolak( sampel tidak mengikuti disti!usi eksponensial.
% = 5+ H0ditolak( sampel tidak mengikuti disti!usi eksponensial.
% = 10+ H0ditolak( sampel tidak mengikuti disti!usi eksponensial.
4.2.1.4 Uji chi-square dua sampel kontin+u (eksponensial !aida daneksponensial 'ah%i) n"*
a) Uji hipotesis
H0= kedua sampel mengikuti disti!usi eksponensial
H1= kedua sampel tidak mengikuti disti!usi eksponensial
!* Uji ;tatistik
1) Range
Range= max min )4.20*
Range= 10.83 > 0.88 = 9.95
imana& Range),* adalah jaak
maxadalah nilai paling tinggi atau maksimum
min adalah nilai paling endah atau minimum
2* ?umlah kelas
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Jk=1+3.3 logn )4.21*
Jk=1+3.3 log70 = 7.09 D 6
imana& ?k adalah jumlah atau jangkauan kelas
n adalah jumlah data
3* Interval
I=R
Jk)4.22*
I=R
Jk=
9.95
6 =1.66
imana&Iadalah interval
Tabel 4.4.,Distibusi %ekuensi dua sampel kontin+u
+nter,al Fi sa-pel Haidar Fi sa-pel Kahfi 0.88 > 2.53 31 3
2.54 > 4.19 4 6
4.20 > 5.85 0 12
5.86 > 7.51 0 10
7.52 > 9.17 0 3
9.18 > 10.83 0 1
3 3
4* @enentukan ekuensi haapan
Ei=(Oi1+Oi2)n1
n1+n2
)4.23*
Ei1=(31+3 )3535+35
=17
Ei2=(4+6 )3535+35
=5
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Ei3=(0+12 )3535+35
=6
Ei4
=(0+10)35
35+35 =5
Ei5=(0+3 )3535+35
=1.5
Ei6=(0+1)3535+35
=0.5
imana& i adalah ekuensi haapani1 adalah ekuensi sampel Haida
i2 adalah ekuensi sampel "ahi
5* @enentukan hi-square hitung Haida
OiEi2
X(xi )2 =
)4.24*
3117
2
X1 (1)2 =
452
X1 (2)2 =
062
X1 (3 )2 =
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052
X1 (4)2 =
01.52
X1 (5 )2 =
00.52
X1 (6 )2 =
imana& #2adalah hi-square hitung
i adalah ekuensi haapan
i adalah ekuensi
6* @enentukan hi-square hitung "ahi
OiEi
2
X(xi )2 =
)4.25*
3172
X1 (1)2 =
652
X1 (2)2 =
1262
X1 (3 )2
=
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1052
X1 (4)
2 =
31.52
X1 (5 )2 =
10.52
X1 (6 )2 =
imana& #2adalah hi-square hitung
i adalah ekuensi haapan
i adalah ekuensi
Tabel 4.4.Distibusi %ekuensi chi-squaredua sampel kontin+u
"! "# "3 " " " "#hit
N
!
31
17
4 5 0 6 0 5 0 1.5 00.50
24.73
11.53 0.20 6.00 5.00 1.50 0.30
N
#
31
76 5
1
26
1
05 3 1.5 1
0.5
0
24.73
11.53 0.20 6.00 5.00 1.50 0.30
/.
* "iteia penolakan
H0ditolak jika #2hit$ #2% & '
dimana v=(R1)(kp1)=(21)(611)=4 )4.26*
% = 1+ = #2% & ' = #20.01 & 4 = 13.28
% = 5+ = #2% & '= #20.05 & 4 = 9.49
% = 10+ = #2% & ' = #20.1 & 4 = 7.28
d* :nalisis pe!andingan
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&amba 4.4.4'ua pebandingan chi-squaredua sampel kontin+u
e* "esimpulan
% = 1+ H0ditolak( kedua sampel tidak mengikuti disti!usi eksponensial.
% = 5+ H0ditolak( kedua sampel tidak mengikuti disti!usi eksponensial.
% = 10+ H0ditolak( kedua sampel tidak mengikuti disti!usi eksponensial.
4.2.2 Uji kolmogorov-smirnov
4.2.2.1 Uji kolmogorov-smirnov satu sampel diskit (poisson !aida) n"#$
a) Uji hipotesis
H0= sampel mengikuti disti!usi poisson
H1= sampel tidak mengikuti disti!usi poisson
b) "iteia penolakan
H0ditolak jika nhit$ n % & n
% = 1+ = n % & n = n 0.01 & 35 = 0.27
% = 5+ = n % & n= n 0.05 & 35 = 0.23
% = 10+ = n % & n = n 0.1 & 35 = 0.21
c) Uji statistik
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1* ,ata-ata
=Fi.x i
Fi )4.27*
=31
35=0.89
imana& / adalah ata-ata pesentase sukses
adalah jumlah pesentase sukses
# adalah pengamatan
2* o!a!ilitas poisson
Fe=P ( , x )= e x
X !)4.28*
P (0.89,0 )=2.71828
0.860.89
0
0 ! = 0.411
P (0.89 ,1 )=2.71828
0.860.89
0
1! = 0.365
P (0.89 ,2 )=2.71828
0.860.89
2
2! = 0.163
imana& adalah po!a!litas
/ adalah ata-ata pesentase sukses
e adalah epsilon, nilaina adalah 2.71828
adalah !anakna sukses dalam sampel ukuan n
3* ekuensi kumulati elati
Fo=Fkr= Fk Fi
)4.29*
Fkr(0)=13
35=0.37 1
Fkr(1)=26
35=0.743
Fkr(3)=35
35
=1 .000
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imana& k adalah ekuensi kumulati elati
k adalah ekuensi kumulati
i adalah ekuensi
4* n mahitung
n=|FeFo| )4.30*
n0=|0.4110.371|=0.040
n1=|0.3650.743|=0.378
n2=|0.1631.000|=0.837
imana& n adalahKolmogorov smirnov hitunge adalah po!a!ilitas
o adalah ekuensi kumulati elati'e
Tabel 4.4.1*Distibusi %ekeunsi Kolmogorov-smirnov satu sampel diskit
xi Fi Fk Fi.xi Fo = Fkr Fe = P Dn
0 13 13 0 0.371 0.411 0.040
1 13 26 13 0.743 0.365 0.378
2 9 35 18 1.000 0.163 0.837 35 31
n ma = 0.837
d* :nalisis pe!andingan
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&amba 4.4.$'ua pebandingan uji Kolmogorov-smirnov satu sampeldiskit
e* "esimpulan
% = 1+ H0ditolak( sampel tidak mengikuti disti!usi poisson.
% = 5+ H0ditolak( sampel tidak mengikuti disti!usi poisson.
% = 10+ H0ditolak( sampel tidak mengikuti disti!usi poisson.
4.2.2.2 Uji kolmogorov-smirnov dua sampel diskit (poisson !aida danPoisson 'ah%i) n"*
a) Uji hipotesis
H0= sampel mengikuti disti!usi poisson
H1= sampel tidak mengikuti disti!usi poisson
!* "iteia penolakan
H0ditolak jika nhit$ n % & n
% = 1+ = n % & n = n 0.01 & 70 = 0.19
% = 5+ = n % & n= n 0.05 & 70 = 0.16
% = 10+ = n % & n = n 0.1 & 70 = 0.15
* Uji ;tatistik
1* ekuensi kumulati elati'e Haida
Fo=Fkr= Fk
Fi
)4.31*
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Fkr(0)=13
35=0.371
Fkr(1)=2635=0.743
Fkr(2)=35
35=1
imana& k adalah ekuensi kumulati elati
k adalah ekuensi kumulati
i adalah ekuensi
2* ekuensi kumulati elati'e "ahi
Fo=Fkr= Fk
Fi
)4.32*
Fkr(0)=18
35=0.514
Fkr(1)=30
35=0.857
Fkr(2)=3535=1 .000
imana& k adalah ekuensi kumulati elati
k adalah ekuensi kumulati
i adalah ekuensi
3* n hitung
n=|Fo1Fo2| )4.33*
n0=|0.3710.514|=0.143
n1=|0.7430.857|=0.20
n2=|11|=0
Tabel 4.4.11Distibusi %ekuensi uji Kolmogorov-smirnov dua sampeldiskit
xiFi Fk Fkr = Fo Dn
n! n# n! n# n! n#
0 13 18 13 18 0.371 0.514 0.143
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1 13 12 26 30 0.743 0.857 0.114
2 9 5 35 35 1.000 1.000 0.000
3 3
n ma = 0.143
d* :nalisis pe!andingan
&amba 4.4.'ua pebandingan uji Kolmogorov-smirnov dua sampel diskit
e* "esimpulan
% = 1+ H0ditolak( kedua sampel tidak mengikuti disti!usi poisson.
% = 5+ H0ditolak( kedua sampel tidak mengikuti disti!usi poisson.
% = 10+ H0ditolak( kedua sampel tidak mengikuti disti!usi poisson.
4.2.2.# Uji kolmogorov-smirnov satu sampel kontin+u
a) Uji hipotesis
H0= sampel mengikuti disti!usi eksponensial
H1= sampel tidak mengikuti disti!usi eksponensialb) "iteia penolakan
H0ditolak jika nhit$ n % & n
% = 1+ = n % & n = n 0.01 & 35 = 0.27
% = 5+ = n % & n= n 0.05 & 35 = 0.23
% = 10+ = n % & n = n 0.1 & 35 = 0.21
c) Uji statistik
Tabel 4.4.12Distibusi %ekuensi Kolmogorov-smirnov satu sampel kontin+u
xi Fi Fk fi.xi fkr p Dn -ax
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0.88 1 1 0.88 0.03 0.43 0.40
0.92 1 2 0.92 0.06 0.44 0.38
0.93 1 3 0.93 0.09 0.45 0.36
0.98 1 4 0.98 0.11 0.46 0.35
1.00 1 5 1.00 0.14 0.47 0.331.02 3 8 3.06 0.23 0.86 0.63
1.05 1 9 1.05 0.26 0.49 0.23
1.08 1 10 1.08 0.29 0.50 0.21
1.10 1 11 1.10 0.31 0.50 0.19
1.13 1 12 1.13 0.34 0.51 0.17
1.18 2 14 2.36 0.40 0.78 0.38
1.22 2 16 2.44 0.46 0.79 0.33
1.33 1 17 1.33 0.49 0.57 0.08
1.53 1 18 1.53 0.51 0.62 0.11
1.58 1 19 1.58 0.54 0.63 0.09
1.62 1 20 1.62 0.57 0.63 0.07
1.63 2 22 3.26 0.63 0.87 0.241.70 1 23 1.70 0.66 0.66 0.00
1.73 1 24 1.73 0.69 0.67 0.02
1.78 1 25 1.78 0.71 0.68 0.03
1.80 1 26 1.80 0.74 0.68 0.06
1.85 1 27 1.85 0.77 0.69 0.08
1.87 1 28 1.87 0.80 0.70 0.10
1.97 1 29 1.97 0.83 0.71 0.12
1.98 1 30 1.98 0.86 0.72 0.14
2.38 1 31 2.38 0.89 0.78 0.11
2.57 1 32 2.57 0.91 0.80 0.11
2.62 1 33 2.62 0.94 0.81 0.13
3.08 1 34 3.08 0.97 0.86 0.11
3.25 1 35 3.25 1.00 0.87 0.13
n ma = 0.495
!) @enentukan ata-ata
=X= f i . x i
fi
)4.34*
=X=54.8335
= 1.57
imana& adalah ata-ata
#) @enentukan ekuensi elati'e
Fo=Fkr= Fk
Fi
)4.35*
Fkr (0.88 )=1
35=0.03
Fkr (1.53 )=19
35=0.54
Fkr (1.58 )=20
35=0.57
Fkr (1.62 )=22
35=0.63
Fkr (1.63 )=22
35=0.63
Fkr (1.70 )=23
35=0.66
Fkr (1.73 )=24
35=0.69
Fkr (1.78)=2535
=0.71
Fkr (1.80 )=26
35
=0.74
Fkr (1.85 )=27
35=0.77
Fkr (1.87 )=28
35=0.80
Fkr (1.97 )=29
35=0.83
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Fkr (0.92 )=2
35=0.06
Fkr (0.93 )=3
35=0.09
Fkr (0.98 )= 435
=0.11
Fkr (1.00 )=5
35=0.14
Fkr (1.02 )= 8
35=0.23
Fkr (1.02 )= 9
35=0.26
Fkr (1.05 )=10
35=0.29
Fkr (1.08 )=11
35=0.31
Fkr (1.10 )=12
35=0.34
Fkr (1.13 )=14
35=0.40
Fkr (1.18 )=16
35=0.46
Fkr (1.22 )=17
35=0.49
Fkr (1.33 )=17
35=0.49
Fkr (1.43 )=18
35=0.51
imana& k adalah ekuensi kumulati elati
k adalah ekuensi kumulati
i adalah ekuensi
3) @enentukan po!a!ilitas
P(#i) = 1e(xi) )4.36*
P(0.88)=12.71828
(0.881.57) = 0.03 P(1.62)=12.71828
( 1.621.57 ) =0.57
P(0.92)=12.71828
(0.921.57) = 0.06 P(1.63)=12.71828
( 1.631.57 ) =0.63
P(0.93)=12.71828
(0.931.57) = 0.09 P(1.70)=12.71828
( 1.701.57 ) =0.66
7/26/2019 Bab 4 Goodtest
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P(0.98)=12.71828
(0.981.57) = 0.11 P(1.73)=12.71828
( 1.731.57 ) =0.69
P(1.00)=12.71828(
1.001.57 ) = 0.14 P(1.78)=
12.71828(1.781.57 ) = 0.71
P(1.02)=12.71828
( 1.021.57 ) = 0.23 P(1.80)=
12.71828(1.801.57 ) = 0.74
P(1.05)=12.71828
( 1.051.57 ) = 0.26 P(1.85)=
12.71828(1.851.57 ) = 0.77
P(1.08)=12.71828
( 1.081.57 ) = 0.29 P(1.87)=
12.71828(1.871.57 ) = 0.80
P(1.10)=12.71828
( 1.101.57 ) = 0.31 P(1.97)=
12.71828(1.971.57 ) = 0.83
P(1.13)=12.71828
( 1.131.57 ) = 0.34 P(1.98)=
12.71828(1.981.57 ) = 0.86
P(1.18)=12.71828
( 1.181.57 ) = 0.40 P(2.38)=
12.71828(2.381.57 ) = 0.89
P(1.22)=
12.71828( 1.221.57 ) = 0.46 P(2.57)=
12.71828(2.571.57 ) = 0.91
P(1.33)=12.71828
( 1.331.57 ) = 0.49 P(2.62)=
12.71828(2.621.57 ) = 0.94
P(1.53)=12.71828
( 1.531.57 ) = 0.51 P(3.08)=
12.71828(3.081.57 ) = 0.97
7/26/2019 Bab 4 Goodtest
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P(1.58)=12.71828
( 1.581.57 ) = 0.54 P(3.25)=
12.71828(3.251.57 ) = 1.00
) n hitung
n=|FeFo| )4.37*
Dn (0.88 )=|0.43-0.03|=0.40Dn (0.92 )=|0.44-0.06|=0.38Dn (0.93 )=|0.45-0.09|=0.36
Dn (0.98)=|0.46-0.11|=0.35Dn (1.00 )=|0.47-0.14|=0.33Dn (3.06)=|0.86-0.23|=0.63Dn (1.05 )=|0.49-0.26|=0.23Dn (1.08)=|0.50-0.29|=0.21Dn (1.10 )=|0.50-0.31|=0.19Dn (1.13 )=|0.50-0.34|=0.17Dn (2.36 )=|0.51-0.40|=0.38Dn (2.44 )=|0.78-0.46|=0.33Dn (1.33 )=|0.79-0.49|=0.08
Dn (1.53 )=|0.57-0.51|=0.11Dn (1.58 )=|0.62-0.54|=0.09Dn (1.62 )=|0.63-0.57|=0.07Dn (3.26 )=|0.64-0.63|=0.24
imana& n adalahKolmogorov smirnov hitunge adalah po!a!ilitas
o adalah ekuensi kumulati elati'e
d) :nalisis pe!andingan
n (1.70 )=|0.870.66|=0.00n (1.73)=|0.660.69|=0.02n (1.78 )=|0.670.71|=0.03
n (1.80 )=|0.680.74|=0.06n (1.85 )=|0.680.77|=0.08n (1.87 )=|0.690.80|=0.10n (1.97 )=|0.700.83|=0.12n (1.98 )=|0.710.86|=0.14n (2.38 )=|0.720.89|=011n (2.57 )=|0.780.91|=0.11n (2.62 )=|0.800.94|=0.13n (3.08 )=|0.810.97|=0.11n (3.25 )=|0.861.00|=0.13
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x ifi Fk Fkr=Fo
Dnn1 n2 n1 n2 n1 n2
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0.88 0 1 0 1 0 0.03 0.03
0.92 0 1 0 2 0 0.06 0.06
0.93 0 1 0 3 0 0.09 0.09
0.98 0 1 0 4 0 0.11 0.11
1 0 1 0 5 0 0.14 0.14
1.02 0 3 0 8 0 0.23 0.23
1.05 0 1 0 9 0 0.26 0.26
1.08 0 1 0 10 0 0.29 0.29
1.1 0 1 0 11 0 0.31 0.31
1.13 0 1 0 12 0 0.34 0.34
1.18 0 2 0 14 0 0.40 0.40
1.22 0 2 0 16 0 0.46 0.46
1.33 0 1 0 17 0 0.49 0.49
1.43 1 0 1 17 0.03 0.49 0.46
1.53 0 1 1 18 0.03 0.51 0.49
1.58 0 1 1 19 0.03 0.54 0.51
1.62 0 1 1 20 0.03 0.57 0.54
1.63 0 2 1 22 0.03 0.63 0.60
1.7 0 1 1 23 0.03 0.66 0.63
1.73 0 1 1 24 0.03 0.69 0.66
1.78 0 1 1 25 0.03 0.71 0.69
1.8 0 1 1 26 0.03 0.74 0.71
1.85 0 1 1 27 0.03 0.77 0.74
1.87 0 1 1 28 0.03 0.80 0.77
1.97 0 1 1 29 0.03 0.83 0.80
1.98 0 1 1 30 0.03 0.86 0.83
2.12 1 0 2 30 0.06 0.86 0.80
2.38 0 1 2 31 0.06 0.89 0.83
2.52 1 0 3 31 0.09 0.89 0.80
2.57 0 1 3 32 0.09 0.91 0.83
2.62 0 1 3 33 0.09 0.94 0.86
2.85 1 0 4 33 0.11 0.94 0.83
3.08 0 1 4 34 0.11 0.97 0.86
3.12 1 0 5 34 0.14 0.97 0.83
3.25 0 1 5 35 0.14 1.00 0.86
3.63 1 0 6 35 0.17 1.00 0.83
3.97 1 0 7 35 0.20 1.00 0.80
4.08 1 0 8 35 0.23 1.00 0.77
4.13 1 0 9 35 0.26 1.00 0.74
4.25 1 0 10 35 0.29 1.00 0.71
4.47 1 0 11 35 0.31 1.00 0.69
4.75 1 0 12 35 0.34 1.00 0.66
5.02 1 0 13 35 0.37 1.00 0.63
5.03 2 0 15 35 0.43 1.00 0.57
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5.05 1 0 16 35 0.46 1.00 0.54
5.08 1 0 17 35 0.49 1.00 0.51
5.18 1 0 18 35 0.51 1.00 0.49
5.20 1 0 19 35 0.54 1.00 0.46
5.52 1 0 20 35 0.57 1.00 0.43
5.82 1 0 21 35 0.60 1.00 0.40
6.28 1 0 22 35 0.63 1.00 0.37
6.50 1 0 23 35 0.66 1.00 0.34
6.80 1 0 24 35 0.69 1.00 0.31
6.92 1 0 25 35 0.71 1.00 0.29
6.97 1 0 26 35 0.74 1.00 0.26
7.05 1 0 27 35 0.77 1.00 0.23
7.10 1 0 28 35 0.80 1.00 0.20
7.17 1 0 29 35 0.83 1.00 0.17
7.25 1 0 30 35 0.86 1.00 0.14
7.47 1 0 31 35 0.89 1.00 0.11
7.82 1 0 32 35 0.91 1.00 0.09
7.85 1 0 33 35 0.94 1.00 0.06
8.02 1 0 34 35 0.97 1.00 0.03
10.83 1 0 35 35 1.00 1.00 0.00
1) Men$ari niai %kr&iai ini 'itentukan 'enan er!a*aan 4.4.12 berikut+
Fo=Fkr (x i)= Fk
fi
n1!Fkr (0.88 )= 0
35=0
Fkr (0.92 )=0
35=0
Fkr (0.93 )=0
35=0
Fkr (0.98 )=0
35=0
Fkr (1.00 )=0
35=0
Fkr (1.02 )= 0
35=0
Fkr (1.02 )= 0
35=0
Fkr (1.05 )=0
35=0
Fkr (1.08 )=0
35=0
n2 Fkr (0.88 )= 1
35=0.03
Fkr (0.92 )=2
35=0.06
Fkr (0.93 )=3
35=0.09
Fkr (0.98 )=4
35=0.11
Fkr (1.00 )=5
35=0.14
Fkr (1.02 )= 8
35=0.23
Fkr (1.02 )= 9
35=0.26
Fkr (1.05 )=10
35=0.29
Fkr (1.08 )=11
35=0.31
)4.4.1
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Fkr (1.10 )=0
35=0
Fkr (1.13 )=0
35=0
Fkr (1.18 )= 035
=0
Fkr (1.22 )= 0
35=0
Fkr (1.33 )=0
35=0
Fkr (1.43 )=1
35=0.03
Fkr (1.53 )=1
35=0.03
Fkr (1.58 )=1
35=0.03
Fkr (1.62 )= 1
35=0.03
Fkr (1.63 )=1
35=0.03
Fkr (1.70 )=1
35=0.03
Fkr (1.73 )=1
35=0.03
n1 Fkr (1.78 )=1
35=0.03
Fkr (1.80 )=1
35=0.03
Fkr (1.85 )=1
35=0.03
Fkr (1.87 )=1
35=0.03
Fkr (1.97 )=1
35=0.03
Fkr (1.98 )=1
35=0.03
Fkr (2.12 )= 2
35=0.06
Fkr (2.38 )=2
35=0.06
Fkr (2.52 )= 3
35=0.09
Fkr (2.57 )=3
35=0.09
Fkr (2.62 )= 3
35=0.09
Fkr (1.10 )=12
35=0.34
Fkr (1.13 )=14
35=0.40
Fkr (1.18 )=1635
=0.46
Fkr (1.22 )=17
35=0.49
Fkr (1.33 )=17
35=0.49
Fkr (1.43 )=18
35=0.51
Fkr (1.53 )=19
35=0.54
Fkr (1.58 )=20
35=0.57
Fkr (1.62 )=22
35=0.63
Fkr (1.63 )=22
35=0.63
Fkr (1.70 )=23
35=0.66
Fkr (1.73 )=24
35=0.69
n2 Fkr (1.78 )=25
35=0.71
Fkr (1.80 )=26
35=0.74
Fkr (1.85 )=27
35=0.77
Fkr (1.87 )=28
35=0.80
Fkr (1.97 )=29
35=0.83
Fkr (1.98 )=30
35=0.86
Fkr (2.12 )=30
35=0.86
Fkr (2.38 )=31
35=0.89
Fkr (2.52 )=31
35=0.89
Fkr (2.57 )=32
35=0.91
Fkr (2.62 )=33
35=0.94
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Fkr (2.85 )=4
35=0.11
Fkr (3.08 )=4
35=0.11
Fkr (3.12 )= 535
=0.14
Fkr (3.25 )=5
35=0.14
Fkr (3.63 )=6
35=0.17
Fkr (3.97 )=7
35=0.20
Fkr (4.08 )= 8
35=0.23
Fkr (4.13 )= 9
35=0.26
Fkr (4.25 )=10
35=0.29
Fkr (4.47 )=11
35=0.31
Fkr (4.75 )=12
35=0.34
Fkr (5.02 )=13
35=0.37
Fkr (5.03 )=15
35=0.43
Fkr (5.05 )=16
35=0.46
Fkr (5.08 )=17
35=0.49
Fkr (5.18 )=18
35=0.51
Fkr (5.20 )=19
35=0.54
Fkr (5.52 )=20
35=0.57
n1 Fkr (5.82 )=21
35=0.60
Fkr (6.28 )=22
35=0.63
Fkr (6.50 )=23
35=0.66
Fkr (6.80 )=24
35=0.69
Fkr (6.92 )=25
35=0.71
Fkr (2.85 )=33
35=0.94
Fkr (3.08 )=34
35=0.97
Fkr (3.12 )=3435
=0.97
Fkr (3.25 )=35
35=1.00
Fkr (3.63 )=35
35=1.00
Fkr (3.97 )=35
35=1.00
Fkr (4.08 )=35
35=1.00
Fkr (4.13 )=35
35=1.00
Fkr (4.25 )=35
35=1.00
Fkr (4.47 )=35
35=1.00
Fkr (4.75 )=35
35=1.00
Fkr (5.02 )=35
35=1.00
Fkr (5.03 )=35
35=1.00
Fkr (5.05 )=35
35=1.00
Fkr (5.08 )=35
35=1.00
Fkr (5.18 )=35
35=1.00
Fkr (5.20 )=35
35=1.00
Fkr (5.52 )=35
35=1.00
n2 Fkr (5.82 )=35
35=1.00
Fkr (6.28 )=35
35=1.00
Fkr (6.50 )=35
35=1.00
Fkr (6.80 )=35
35=1.00
Fkr (6.92 )=35
35=1.00
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Fkr (6.97 )=26
35=0.74
Fkr (7.05 )=27
35=0.77
Fkr (7.10 )=2835
=0.80
Fkr (7.17 )=29
35=0.83
Fkr (7.25 )=30
35=0.86
Fkr (7.47 )=31
35=0.89
Fkr (7.82 )=32
35=0.91
Fkr (7.85 )=33
35=0.94
Fkr (8.02 )=34
35=0.97
Fkr (10.83 )=35
35=1.00
Fkr (6.97 )=35
35=1.00
Fkr (7.05 )=35
35=1.00
Fkr (7.10 )=3535
=1.00
Fkr (7.17 )=35
35=1.00
Fkr (7.25 )=35
35=1.00
Fkr (7.47 )=35
35=1.00
Fkr (7.82 )=35
35=1.00
Fkr (7.85 )=35
35=1.00
Fkr (8.02 )=35
35=1.00
Fkr (10.83 )=35
35=1.00
2) Men$ari niai ,n
&iai ini 'i$ari 'enan er!a*aan 4.4.14 berikut+
n=|Fkr (1)Fkr (2)|
Dn (0.88 )=|0-0.03|=0.03Dn (0.92 )=|0-0.06|=0.06Dn (0.93 )=|0-0.09|=0.09Dn (0.98 )=|0-0.11|=0.11Dn (1.00 )=|0-0.14|=0.14Dn (1.02 )=|0-0.23|=0.23Dn (1.05 )=|0-0.26|=0.26Dn (1.08 )=|0-0.29|=0.29
Dn (1.10 )=|0-0.31|=0.31Dn (1.13 )=|0-0.34|=0.34Dn (1.18 )=|0-0.40|=0.40Dn (1.22 )=|0-0.46|=0.46Dn (1.33 )=|0-0.49|=0.49Dn (1.43 )=|0.03-0.49|=0.46Dn (1.53 )=|0.03-0.51|=0.49Dn (1.58 )=|0.03-0.54|=0.51Dn (1.62 )=|0.03-0.57|=0.54Dn (1.63 )=|0.03-0.63|=0.60
Dn (1.70 )=|0.03-0.66|=0.63
Dn (1.80 )=|0.03-0.74|=0.71Dn (1.85 )=|0.03-0.77|=0.74Dn (1.87 )=|0.03-0.80|=0.77Dn (1.97 )=|0.03-0.83|=0.80Dn (1.98 )=|0.03-0.86|=0.83Dn (2.12 )=|0.06-0.86|=0.80Dn (2.38 )=|0.06-0.89|=0.83Dn (2.52 )=|0.09-0.89|=0.80
Dn (2.57 )=|0.09-0.91|=0.83Dn (2.62 )=|0.09-0.94|=0.86Dn (2.85 )=|0.11-0.94|=0.83Dn (3.08 )=|0.11-0.97|=0.86Dn (3.12 )=|0.14-0.97|=0.83Dn (3,25 )=|0.14-1.00|=0.86Dn (3.63 )=|0.17-1.00|=0.83Dn (3.97 )=|0.20-1.00|=0.80Dn (4.08 )=|0.23-1.00|=0.77Dn (4.13 )=|0.26-1.00|=0.74
Dn (4.25 )=|0.29-1.00|=0.71
)4.4.1
,n *a#
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Dn (1.73 )=|0.03-0.69|=0.66Dn (1.78 )=|0.03-0.71|=0.69Dn (5.02 )=|0.37-1.00|=0.69Dn (5.03 )=|0.43-1.00|=0.57Dn (5.05 )=|0.46-1.00|=0.54Dn (5.08 )=|0.49-1.00|=0.51Dn (5.18 )=|0.51-1.00|=0.49Dn (5.20 )=|0.54-1.00|=0.46Dn (5.52 )=|0.57-1.00|=0.43Dn (5.82 )=|0.60-1.00|=0.40Dn (6.28 )=|0.63-1.00|=0.37Dn (6.50 )=|0.66-1.00|=0.34Dn (6.80 )=|0.69-1.00|=0.31
Dn (4.47 )=|0.31-1.00|=0.69Dn (4.75 )=|0.34-1.00|=0.66Dn (6.92 )=|0.71-1.00|=0.29Dn (6.97 )=|0.74-1.00|=0.26Dn (7.05 )=|0.77-1.00|=0.23Dn (7.10 )=|0.80-1.00|=0.20Dn (7.17 )=|0.83-1.00|=0.17Dn (7.25 )=|0.86-1.00|=0.14Dn (7.47 )=|0.89-1.00|=0.11Dn (7.82 )=|0.91-1.00|=0.09Dn (7.85 )=|0.94-1.00|=0.06Dn (8.02 )=|0.97-1.00|=0.03Dn (10.83)=|1.00-1.003|=0
b) -nai!a erban'inan
&amba 4.4.,'ua uji 'olmogoo-smino dua sampel kontin+u$) e!i*uan
"=1, /0'itoak ke'ua !a*e ti'ak *enikuti 'i!tribu!i exponential"=5, /0'itoak ke'ua !a*e ti'ak *enikuti 'i!tribu!i exponential"=10, /0'itoak ke'ua !a*e ti'ak *enikuti 'i!tribu!i exponential