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Aim: What do slope, tangent and the derivative have to do with each other?. Do Now: What is the equation of the line tangent to the circle at point (7, 8)? . A secant of a circle is a line that intersects the circle in two points. Tangents & Secants. - PowerPoint PPT Presentation
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Aim: The Tangent Problem & the Derivative Course: Calculus
Do Now: What is the equation of the line tangent to the circle at point (7, 8)?
Aim: What do slope, tangent and the derivative have to do with each other?
5 10
10
8
6
4
2
-2
Aim: The Tangent Problem & the Derivative Course: Calculus
Tangents & Secants
A tangent to a circle is a line in the plane of the circle that intersects the circle in exactlyone point.
O
A
A secant of a circle is a line that intersects thecircle in two points.
B
C
Aim: The Tangent Problem & the Derivative Course: Calculus
-1
Tan y
x1-1
1radius = 1center at (0,0)
(x,y)cos , sin
cos
sin
tan length of the leg opposite
length of the leg adjacent to
xy
cossintan
1
slope
Aim: The Tangent Problem & the Derivative Course: Calculus
slope is steep!
slope is level: m = 0
Tangents to a Graph
(x1, y1)
(x2, y2)
(x3, y3)
(x4, y4)slope is falling: m is (-)
3
2
1
-1
2A
Unlike a tangent to a circle, tangent lines of curves can intersect the graph at more than one point.
3
2
1
-1
2A
Aim: The Tangent Problem & the Derivative Course: Calculus
Finding the Slope (tangent) of a Graph at a Point10
8
6
4
2
5
h x = x2
12
212
xy
mslope
This is an approximation. How can we be sure this line is really tangent to f(x) at (1, 1)?
(1, 1)
Aim: The Tangent Problem & the Derivative Course: Calculus
Slope and the Limit Process
3
2.5
2
1.5
1
0.5
1
3
2.5
2
1.5
1
0.5
1
(x + h, f(x + h))
A more precise method for finding the slope of the tangent through (x, f(x)) employs use of the secant line.
xy
mslope
sec
h
h is the change in x
f(x + h) – f(x)
f(x + h) – f(x) is the change in y
hxfhxfmslope )()(
sec
This is a very rough approximation of the slope of the tangent at the point (x, f(x)).
x, f(x)
Aim: The Tangent Problem & the Derivative Course: Calculus
3
2.5
2
1.5
1
0.5
1
Slope and the Limit Process
x, f(x)
h
f(x + h) – f(x)
xy
mslope
sec
(x + h, f(x + h))
h is the change in xf(x + h) – f(x) is the change in y
As (x + h, f(x + h)) moves down the curve and gets closer to (x, f(x)), the slope of the secant more approximates the slope of the tangent at (x, f(x).
Aim: The Tangent Problem & the Derivative Course: Calculus
3
2.5
2
1.5
1
0.5
1
Slope and the Limit Process
x, f(x)
h
f(x + h) – f(x)(x + h, f(x + h))
What is happening to h, the change in x?It’s approaching 0,or its limit at x as h approaches 0.
xy
mslope
sec
h is the change in xf(x + h) – f(x) is the change in y
Aim: The Tangent Problem & the Derivative Course: Calculus
Slope and the Limit Process
3
2.5
2
1.5
1
0.5
1
As h 0, the slope of the secant, which approximates the slope of the tangent at (x, f(x)) more closely as (x + h, f(x + h)) moved down the curve. At reaching its limit, the slope of the secant equaled the slope of the tangent at (x, f(x)).
sec0tan lim mmslopeh
hxfhxf
mslope)()(
sec
Aim: The Tangent Problem & the Derivative Course: Calculus
Definition of slope of a Graph3
2.5
2
1.5
1
0.5
1
The slope m of the graph of f at the point (x, f(x)) , is equal to the slope of its tangent line at (x, f(x)), and is given by
provided this limit exists.
sec0tan lim mmslopeh
hxfhxf
mh
)()(lim0
difference quotient
Aim: The Tangent Problem & the Derivative Course: Calculus
Model Problem
Find the slope of the graph f(x) = x2 at the point (-2, 4).
hxfhxf
mh
)()(lim0
hfhf
mh
)2()2(lim0
set up difference quotient
hh
mh
22
0
)2()2(lim
Use f(x) = x2
hhh
mh
444lim2
0
Expand
hhh
mh
2
0
4lim
Simplify
hhh
mh
)4(lim0
Factor and divide out
Simplify)4(lim0
hmh
4)4(lim0
hmh
Evaluate the limit
8
6
4
2
Slope ED = -4.00
D: (-2.00, 4.00)
q x = x2
E
D
Aim: The Tangent Problem & the Derivative Course: Calculus
Slope at Specific Point vs. Formula
hxfhxf
mh
)()(lim)1(0
hcfhcf
mh
)()(lim)2(0
What is the difference between the following two versions of the difference quotient?
(1) Produces a formula for finding the slope of any point on the function.(2) Finds the slope of the graph for the specific coordinate (c, f(c)).
Aim: The Tangent Problem & the Derivative Course: Calculus
Definition of the Derivative
The derivative of f at x is
hxfhxf
xfh
)()(lim)('0
provided this limit exists.
The derivative f’(x) is a formula for the slope of the tangent line to the graph of f at the point (x,f(x)).
The function found by evaluating the limit of the difference quotient is called the derivative of f at x. It is denoted by f ’(x), which is read “f prime of x”.
Aim: The Tangent Problem & the Derivative Course: Calculus
Finding a Derivative
Find the derivative of f(x) = 3x2 – 2x.
0
( ) ( )'( ) limh
f x h f xf x
h
hxxhxhx
xfh
)23()](2)(3[lim)('22
0
hxxhxhxhx
xfh
2322363lim)('222
0
hhhxh
xfh
236lim)('2
0
hhxh
xfh
)236(lim)('0
factor out h
)236(lim)('0
hxxfh
26 x
Aim: The Tangent Problem & the Derivative Course: Calculus
Do Now: Find the equation of the line tangent to
Aim: What is the connection between differentiability and continuity?
( ) 2Find the slope of tangent at = 9f x x
x
Aim: The Tangent Problem & the Derivative Course: Calculus
7
6
5
4
3
2
1
0.5 1 1.5 2 2.5
f(x) is a continuous function
Differentiability and Continuity
What is the relationship, if any, between differentiability and continuity?
(c, f(c))
(x, f(x))
f(x) – f(c)
x – c
x c
Is there a limit as x approaches c? YES
x c
f x f cf c
x c( ) ( )'( ) lim
alternative form of derivative
Aim: The Tangent Problem & the Derivative Course: Calculus
Differentiability and Continuity3.5
3
2.5
2
1.5
1
0.5
-0.5
-1
-1 1 2 3 4
f x x( ) [[ ]]
Does this step function, the greatest integer function, have a limit at 1?
NO: f(x) approaches a different number from the right side of 1 than it does from the left side.
By definition the derivative is a limit. If there is no limit at x = c, then the function is not differentiable at x = c.
Is this step function differentiable at x = 1?
Aim: The Tangent Problem & the Derivative Course: Calculus
Differentiability and Continuity
If f is differentiable at x = c, then f is continuous at x = c.
Is the Converse true?
If f is continuous at x = c, then f is differentiable at x = c.
NO
Aim: The Tangent Problem & the Derivative Course: Calculus
Graphs with Sharp Turns – Differentiable?2.5
2
1.5
1
0.5
-0.5
1 2 3 4 5
f(x) = |x – 2|
Is this function continuous at 2?
m = 1m = -1
xx
2lim | 2 | ?
xx
2lim | 2 | ?
YES
One-sided limits are not equal, f is therefore not differentiable at 2. There is no tangent line at (2, 0)
2 2
2 0( ) (2)lim lim 12 2x x
xf x fx x
x c
f x f cf c
x c( ) ( )'( ) lim
alternative form of derivative
2 2
2 0( ) (2)lim lim 12 2x x
xf x fx x
Is this function differentiable at 2?
Aim: The Tangent Problem & the Derivative Course: Calculus
Graph with a Vertical Tangent Line1.2
1
0.8
0.6
0.4
0.2
-0.2
-0.4
-0.6
-0.8
-1
-1 1
f(x) = x1/3
Is f continuous at 0?YES
x
f x fx0
( ) (0)lim0
x
xx
13
0
0lim
x x
20 3
1lim
UND
xx
13
0lim ?
Does a limit exist at 0?
NO
f is not differentiable at 0; slope of vertical line is undefined.
Aim: The Tangent Problem & the Derivative Course: Calculus
Differentiability Implies Continuity
a b c d
f is not continuous at a therefore not differentiable
f is continuous at b & c, but not differentiable
cornervertical tangent
f is continuous at d and
differentiable
Aim: The Tangent Problem & the Derivative Course: Calculus
Summary