34
15/01/2011 1 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

Embed Size (px)

Citation preview

Page 1: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

15/01/2011 1

On Using Thermo-Calc

Sourav Das,Researcher,

Product Research Group,Research and Development Division,

Tata Steel

Page 2: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

2

What is thermodynamics???

Science of flow of heat.

1. It is universal. We can find it in both organic (mitochondria, ATP etc) and inorganic (black holes, mechanical systems, chemical reactions) objects.

2. It is based on macroscopic properties of matter.

3. Entirely empirical.

15/01/2011

Page 3: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

3

Zeroth law : Defines temperature, T.If A and C are both in thermal equilibrium with a third body B, then they are also in thermal equilibrium with each other.

1st law : Defines energy, UEnergy can be transformed (changed from one form to another), but can not created or destroyed.

2nd law : Defines entropy, SThe entropy of an isolated system which is not in equilibrium will tend to increase with time.

3rd law : Gives a numerical value to the entropyAs a system approaches to absolute zero, all the processes cease and the entropy of the system approaches a minimum value

15/01/2011

Page 4: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

4

Symbols Full namesU Internal energy

q Quantity of heat

w Work done by the system

V Volume of the system

P Pressure

T Temperature in absolute scale

CP Specific heat capacity at constant pressure

CV Specific heat capacity at constant volume

H Enthalpy

G Gibbs free energy

15/01/2011

Page 5: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

5

Internal Energy, U

ΔU = q – w

ordU = dq – dw, where, dw = PdV if P =

constant

q

AA

A

15/01/2011

Page 6: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

6

Enthalpy, H

V

H = U + PV

15/01/2011

Page 7: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

7

Specific heat capacities

Heat absorbed per unit change in temperature (dq/dT).

Since, dq = dU + dw = dU + PdV (at constant pressure)

So, specific heat at constant volume, CV = VT

U

Cp = , at constant pressurePT

H

H = U + PV dH = d(U + PV) = dU + d(PV) = dU + PdV + VdP = (dq – PdV) + (PdV + VdP) = dq + VdP

Specific heat at constant volume

15/01/2011

Page 8: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

8

dTCHT

T

P2

1

assuming CP is constant

When the reaction A + B = C will be possible?

ΔH = Hfinal – Hinitial = -ve

But, why is it only possible? Why will it not necessarily happen?

15/01/2011

Page 9: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

9

Entropy, S

P P/2

Why the reaction will happen in the direction of the arrow?Why not in the opposite direction?

So, even if ΔH = 0, a reaction may spontaneously happen if the ΔS > 0

2

1

T

T

P dTT

CSFor a reversible process, or

T

dqdS rev

15/01/2011

Entropy is a capacity property. Different entropies can be added together S1 + S2 + S3 = S4

Page 10: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

10

Entropy, S (again)

How does Entropy fit with the probability picture?

Through Boltzman’s law: S = k ln(w)

P

Possible arrangement, W = 1, Possible arrangement, W = very very large

15/01/2011

Probability of getting all the n mlecules at one side = 4 / [n(n-1)]

Page 11: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

11

Gibbs Free Energy, G

G = H – TS or ΔG = ΔH - TΔS

Note: This is probably the most important parameter in all thermodynamical calculations

15/01/2011

Page 12: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

12

Equilibrium

15/01/2011

Page 13: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

13

Allotropic Transition in Pure Iron

D. R. Gaskell, Thermodynamics of Materials

15/01/2011

Page 14: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

14

Mechanical Mixture

A B

(1-x) x

15/01/2011

free energy of mechanical mixture

A B

Gib

bs

free e

nerg

y p

er

mole

Concentration x of B

G*

1-xx

0AG

0BG

Page 15: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

15

A B+

atomic solution

Solution

15/01/2011

free energy of solution

MG

free energy of mechanical mixture

A B

Gib

bs

free e

nerg

y p

er

mole

Concentration x of B

G*

x

0AG

0BG

G{x}

Page 16: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

16

Chemical potential

15/01/2011

.),,(.' constPTdndG AA

.),(.' constPTdndndG BBAA

xxdG BA )1(.

Page 17: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

17

Chemical potential

15/01/2011

A BxGib

bs f

ree e

nerg

y p

er

mole

Composition

G{x}

0AG

0BG

)1( xA

)(xB

Page 18: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

18

BA xxxG )1(}{

Conditions:

1.Under standard conditions (T = 298 K and P = 101.3 kPa)2.Without intermolecular interactions3.Natural isotope composition of elements

15/01/2011

Page 19: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

19

AA BB ,

Equilibrium between two solutions

15/01/2011

Page 20: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

20

Equilibrium between two solutions(contd……..)

wt% C

T = T1 (constant)

α

15/01/2011

Page 21: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

21

Equilibrium between two solutions(contd……..)

wt% C

T = T2 (constant), T2 >T1

α

Xα Xα

15/01/2011

Page 22: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

22

Equilibrium between two solutions(contd……..)

wt% C

α

T = T3 (constant), T3 > T2

15/01/2011

Page 23: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

23

Phase diagram between two phases

T = T3

T = T2

T = T1

C

15/01/2011

γ

γ + α

α

Page 24: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

24

α

2x

2x

M1

M

M2

α

)(2

x )(2

x )(2

x )(2

x

α α +

+

Phase diagram among three phases

15/01/2011

Page 25: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

2515/01/2011

We have considered:

1. Ideal solution (random distribution of solute atoms) and no change in binding energy when we mix the atoms together

2. Binary solution

1. In regular solution, there will be excess free energy of mixing and there may be liking or disliking among the atoms(back up slide for enthalpy of mixing)

2. There can be 8-10 elements in a commercial alloy

Page 26: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

2615/01/2011

dTCHT

T

P2

1

assuming CP is constant

2

1

T

T

P dTT

CS

For a reversible process, or T

dqdS rev

Heat capacity is a function of: 1. vibration of atoms 2. magnetic property of the atoms3. Electronic heat capacity due to electronic configuration4. Curling up of molecules etc etc……….

Page 27: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

2715/01/2011

CP = b1 + b2T + b3T2 + b4/T2

Page 28: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

2815/01/2011wt% C

α

Xα Xα

Page 29: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

2915/01/2011

Page 30: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

12/07/2010 30

References:

1. Introduction to the Thermodynamics of Materials, 3rd edition, D. R. Gaskell

2. Online available course materials from Georgia State University, USA3. http://en.wikipedia.org4. Classroom video lectures on Thermodynamics from MIT, USA 5. Class room video lectures from University of Cambridge, UK6. Online course material from University of Texas at Austin, USA7. Thermodynamics in Materials Science, International Edition1993, R. T. DeHoff8. An Introduction to Metallurgy, 2nd edition, A. H. Cottrell9. Chemical Thermodynamics of Materials, C. H. P. Lupis

Page 31: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

3115/01/2011

Thank you for

kind attention

Page 32: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

3215/01/2011

Free energy of mixing

If we consider an ideal solution, the entropy of mixing will be:

If we consider a regular solution, there will be always a change in bond energy and there will be excess free energy

Page 33: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

3315/01/2011

Page 34: 15/01/20111 On Using Thermo-Calc Sourav Das, Researcher, Product Research Group, Research and Development Division, Tata Steel

3415/01/2011