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Graphing parabola using methods of squares What you need to do is that you just draw six squares with sides four times the focus then you can visualize the graph of a parabola provided you already locate the vertex of the parabola. Here are the steps you will follow: Translate the equation to form x 2 = 4py for the parabola with vertex at the origin. And (x-h) 2 = 4p(y-k) for the parabola with vertex at (h,k)

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  • 1. Graphing parabola using methods of squares What you need to do is that you just draw six squares with sides four times the focus then you can visualize the graph of a parabola provided you already locate the vertex of the parabola. Here are the steps you will follow: Translate the equation to form x2= 4py for the parabola with vertex at the origin. And (x-h)2= 4p(y-k) for the parabola with vertex at (h,k)

2. Sample : Plot the graph of x2 = 12y. Solution: transform the equation to x2 =4py 4py=12y : if we divide both sides by 4y we will get p= 3 With these data we can now graph the parabola in which our the focus is at (0,p) or (0,3), the directrix is y=-p or y=-3. What we need is now to construct the six squares with sides 2p or 6 units 3. The line in violet is the length of latus rectum, while the left-right arrow in blue is the directrix, and the circles in red are the ordered pairs of the parabola foud at the edges of the squares. 4. Thank you for viewing Virgilio rollon paragele Teacher at Tomas cabili national high school