172.168.4.2/16

Class = B

Total Network=8

Subnet Bit=4

Slash Bit=16+4=20

Total Subnet=24=16

Host Bit=16-4=12

Total Host=212 =4096

Useable Host= 212 -2 =4096-2=4094

Subnet Mask=255.255.240.0

Network Address Broadcast Address

S1 172.168.0.0 172.168.15.255

S2 172.168.16.0 172.168.31. 255

S3 172.168.32.0 172.168.47. 255

S4 172.168.48. 0 172.168.63. 255

S5 172.168.64. 0 172.168.79. 255

S6 172.168.80. 0 172.168.95. 255

S7 172.168.96. 0 172.168.111. 255

S8 172.168.122.0 172.168.127. 255

S9 172.168.128.0 172.168.143. 255

S10 172.168.144.0 172.168.159. 255

S11 172.168.160.0 172.168.175. 255

S12 172.168.176.0 172.168.191. 255

S13 172.168.192.0 172.168.207. 255

S14 172.168.208.0 172.168.223. 255

S15 172.168.224.0 172.168.239. 255

S16 172.168.240.0 172.168.255. 255

10.12.5.2/8

1. This network Class A

2. Number network =8

3. Subnet bits = 4

4. Slash bit = DNB + SB =16+4=20

Then 10.12.5.2/20

5. Total subnet =2subnet bit =24 =16

6. Host bit = DNB – SB

1. =20-16 = 4

7. Total Host =24 = 16

8. Total Host = 2subnet bit -2 =216-2 = 14

9. Subnet mask = 255.255.255.240

Network Address Broadcast Address

S1 10.12.5.0 10.12.5.15

S2 10.12.5.16 110.12.5.31

S3 10.12.5.32 10.12.5.47

S4 10.12.5.48 10.12.5.63

S5 10.12.5.64 10.12.5.79

S6 10.12.5.80 10.12.5.95

S7 10.12.5.96 10.12.5.111

S8 10.12.5.112 10.12.5.127

S9 10.12.5.128 10.12.5.143

S10 10.12.5.144 10.12.5.159

S11 10.12.5.60 10.12.5.175

S12 10.12.5.176 10.12.5.191

S13 10.12.5.192 10.12.5.207

S14 10.12.5.280 10.12.5.223

S15 10.12.5.224 10.12.5.239

S16 10.12.5.240 10.12.5.255