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IP ADDRESS CLASSES Task 1 : for a given IP address, determine network information. Given : Host IP Address 172.25.114.250 Network Mask 255.255.0.0 (/16) Find : Network Address 172.25.0.0 Network Broadcast Address 172.25.255.255 Total Number of Host Bits 65534 Number of Hosts 2 16 STEP 1 : TRANSLATE HOST IP ADDRESS AND NETWORK MASK INTO NOTATION. BINARY NUMBER 172 25 114 250 10101100 00011000 01110010 11111010 2 7 2 6 2 5 2 4 2 3 2 2 2 1 2 0 128 64 32 16 8 4 2 1 1 0 1 0 1 1 0 0 128 + 32 + 8 + 4 = 172

Ip Address and Subnetting

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IP ADDRESS CLASSESTask 1 : for a given IP address, determine network information.Given :Host IP Address172.25.114.250

Network Mask255.255.0.0 (/16)

Find : Network Address172.25.0.0

Network Broadcast Address172.25.255.255

Total Number of Host Bits65534

Number of Hosts216

STEP 1 :TRANSLATE HOST IP ADDRESS AND NETWORK MASK INTO NOTATION. BINARY NUMBER 172 25 114 250 10101100 00011000 01110010 111110102726252423222120

1286432168421

10101100

128 + 32 + 8 + 4 = 172

2726252423222120

1286432168421

00011001

16 + 8 + 1 = 25

2726252423222120

1286432168421

01110010

64 + 32 + 16 + 2 = 114

2726252423222120

1286432168421

11111010

128 + 64 + 32 + 16 + 8 + 2 = 250

NETWORK MASK

2726252423222120

1286432168421

11111111

2726252423222120

1286432168421

11111111

2726252423222120

1286432168421

00000000

2726252423222120

1286432168421

00000000

STEP 217225114250

IP ADDRESS10101100000110010111001011111010

SUBNET MASK11111111111111110000000000000000

NETWORK ADDRESS10101100000110010000000000000000

1722500

HOW TO CALCULATE 255.255.0.0

2726252423222120

1286432168421

25511111111

25511111111

000000000

000000000

STEP 3 DETERMINE THE BROADCAST ADDRESS FOR THE NETWORK ADDRESS.1722500

NETWORK ADD.10101100000110010000000000000000

MASK11111111111111110000000000000000

BROADCAST10101100000110011111111111111111

17225255255

By counting the number of host bits, we can determine the total number of usable hosts for this network.Hosts bits : 16Total number of hosts :216 = 65,536

65,536 2 = 65,534 (addresses that cannot use the all Os address, or the add this information to the cable :

Host IP Address 172.25.114.250

Network Mask255.255.0.0 (/16)

Network Address172.25.114.250

Network Broadcast Address172.25.255.255

Total Number Of Host Bits65,534

Number Of Hosts16

TASK 2 : Challenge.For all problems :Create a subnetting worksheet to show and record all work for each problem.Problem 1Host IP Adderss172.30.1.33

Network Mask255.255.0.0

Network Address172.30.0.0

Network Broadcast Address172.30.255.255

Total Number of Host Bost 65534

Number Of Hosts216

IP ADDRESS 172 30 1 33 10101100 00011110 00000001 001000011722726252423222120

1286432168421

10101100

128 + 32 + 8 + 4 = 172

302726252423222120

1286432168421

00011110

16 + 8 + 4 + 2 = 30

12726252423222120

1286432168421

00000001

0 + 0 + 0 + 0 + 0 + 0 + 0 + 1 = 1

332726252423222120

1286432168421

00100001

32 + 1 = 33

How to find NETWORK MASK

If 255.255.0.0

2552726252423222120

1286432168421

11111111

2552726252423222120

1286432168421

11111111

02726252423222120

1286432168421

00000000

02726252423222120

1286432168421

00000000

DETERMINE THE BROADCAST ADDRESS FOR THE NETWORK ADDRESS.17230133

NETWORK ADD.10101100000111100000000100100001

NETWORK MASK111111111111111100000000Nombor 1 ditukar kepada 0Nombor 0 ditukar kepada 1

00000000

BROADCAST10101100000111101111111111111111

17230255255

Host IP Address 172.30.1.33

Network Mask255.255.0.0 (/16)

Network Address172.30.0.0

Network Broadcast Address172.30.255.255

Total Number Of Host Bits65,534

Number Of Hosts216

HOW TO TOTAL NUMBER OF HOST BITS

65,536 65,536 2= 65,532

HOW TO FIND NUMBER OF HOSTSFORMULA :-Network( 1 )= tidakperlu tolak(-)Host(0) = kena tolak ( - )dengan 2

255.255.0.0255255 00

11111111 11111111 00000000 00000000

00000000 + 00000000

= 16 ZEROS

NUMBER OF HOSTS = 2^16

Problem 2Host IP Adderss 172.30.1.33

Network Mask 255.255.255.0

Network Address 172.30.1.0

Network Broadcast Address 172.30.1.255

Total Number of Host Bost 254

Number Of Hosts 28

IP ADDRESS 172 30 1 33 10101100 00011110 00000001 001000011722726252423222120

1286432168421

10101100

128 + 32 + 8 + 4 = 172

302726252423222120

1286432168421

00011110

16 + 8 + 4 + 2 = 30

12726252423222120

1286432168421

00000001

0 + 0 + 0 + 0 + 0 + 0 + 0 + 1 = 1

332726252423222120

1286432168421

00100001

32 + 1 = 33

How to find NETWORK MASK

If 255.255.255.0

2552726252423222120

1286432168421

11111111

2552726252423222120

1286432168421

11111111

2552726252423222120

1286432168421

11111111

02726252423222120

1286432168421

00000000

DETERMINE THE BROADCAST ADDRESS FOR THE NETWORK ADDRESS.17230133

NETWORK ADD.10101100000111100000000100100001

MASK11111111111111111111111100000000

BROADCAST10101100000111100000000111111111

172301255

Host IP Address 172.30.1.33

Network Mask255.255.255.0 (/16)

Network Address172.30.1.0

Network Broadcast Address172.30.1.255

Total Number Of Host Bits254

Number Of Hosts28

HOW TO TOTAL NUMBER OF HOST BITS256 256 2= 254

HOW TO FIND NUMBER OF HOSTS 255.255.255.02552552550

11111111111111111111111100000000

00000000

= 8 ZEROS

NUMBER OF HOSTS = 2^8

Problem 3Host IP Adderss 192.168.10.234

Network Mask 255.255.255.0

Network Address 172.168.10.0

Network Broadcast Address 192.168.10.255

Total Number of Host Bost 254

Number Of Hosts 28

IP ADDRESS 192 168 10 234 11000000 10101000 00001010 11101010192 2726252423222120

1286432168421

11000000

128 + 64 = 192

82726252423222120

1286432168421

10101000

128 + 32 + 8 = 168

102726252423222120

1286432168421

00001010

8 + 2 = 10

2342726252423222120

1286432168421

11101010

128 + 64 + 32 + 8 + 2 = 234

How to find NETWORK MASK

If 255.255.255.0

2552726252423222120

1286432168421

11111111

2552726252423222120

1286432168421

11111111

2552726252423222120

1286432168421

11111111

02726252423222120

1286432168421

00000000

DETERMINE THE BROADCAST ADDRESS FOR THE NETWORK ADDRESS.19216810234

NETWORK ADD.110000001010100000001010 11101010

MASK11111111111111111111111100000000

BROADCAST11000000 10101000 00001010 11101010

19216810234

HOW TO TOTAL NUMBER OF HOST BITS256256 2= 254HOW TO FIND NUMBER OF HOSTS 255.255.255.02552552550

11111111111111111111111100000000

00000000

= 8 ZEROSNUMBER OF HOSTS = 2^8

Problem 4Host IP Adderss 172.17.99.71

Network Mask 255.255.0.0

Network Address 172.17.0.0

Network Broadcast Address 172.17.255.255

Total Number of Host Bost 65534

Number Of Hosts 216

IP ADDRESS 172 17 99 71 10101100 00010001 01100011 010001111722726252423222120

1286432168421

10101100

128 + 32 + 8 + 4 = 172

172726252423222120

1286432168421

00010001

16 + 1 = 17

992726252423222120

1286432168421

01100011

64 + 32 + 2 + 1 = 99

712726252423222120

1286432168421

01000111

64 + 4 + 2 + 1 = 71

How to find NETWORK MASK

If 255.255.0.0

2552726252423222120

1286432168421

11111111

2552726252423222120

1286432168421

11111111

02726252423222120

1286432168421

00000000

02726252423222120

1286432168421

00000000

DETERMINE THE BROADCAST ADDRESS FOR THE NETWORK ADDRESS.172179971

NETWORK ADD.1010110000010001 01100011 01000111

MASK11111111111111110000000000000000

BROADCAST1010110000010001 11111111 11111111

17217255255

Host IP Address 172.25.114.250

Network Mask255.255.0.0 (/16)

Network Address172.17.0.0

Network Broadcast Address172.17.255.255

Total Number Of Host Bits65,534

Number Of Hosts216

HOW TO TOTAL NUMBER OF HOST BITS 65,53665,536 2 = 65,534

HOW TO FIND NUMBER OF HOSTS255.255.0.0

25525500

11111111111111110000000000000000

00000000

= 8 ZEROS

NUMBER OF HOSTS = 2^8

Problem 5Host IP Adderss 192.168.3.219

Network Mask 255.255.0.0

Network Address 192.168.0.0

Network Broadcast Address 192.168.255.255

Total Number of Host Bost 65534

Number Of Hosts 216

IP ADDRESS 192 168 3 219 11000000 10101000 00000011 111010101922726252423222120

1286432168421

11000000

128 + 64 = 192

1682726252423222120

1286432168421

10101000

128 + 32 + 8 = 168

32726252423222120

1286432168421

00000011

2 + 1 = 3

2192726252423222120

1286432168421

11011011

128 + 64 + 16 + 8 + 2 + 1 = 219

How to find NETWORK MASK

If 255.255.0.0

2552726252423222120

1286432168421

11111111

2552726252423222120

1286432168421

11111111

02726252423222120

1286432168421

00000000

02726252423222120

1286432168421

00000000

DETERMINE THE BROADCAST ADDRESS FOR THE NETWORK ADDRESS.

1921683219

NETWORK ADD.110000001010100000000011 11101010

MASK11111111111111110000000000000000

BROADCAST11000000101010001111111111111111

192168255255

Host IP Address 172.25.114.250

Network Mask255.255.0.0 (/16)

Network Address192.168.0.0

Network Broadcast Address255.255

Total Number Of Host Bits65,534

Number Of Hosts216

HOW TO TOTAL NUMBER OF HOST BITS65,536655,36 2= 655,34 HOW TO FIND NUMBER OF HOSTS255.255.0.025525500

11111111111111110000000000000000

00000000 + 00000000

= 16 ZEROS

NUMBER OF HOSTS = 2^16

Problem 6 Host IP Adderss 192.168.3.219

Network Mask 255.255.255.224

Network Address 192.168.3.223

Network Broadcast Address 192.168.3.223

Total Number of Host Bost 30

Number Of Hosts 216

IP ADDRESS 192 168 3 219 11000000 10101000 00000011 111010101922726252423222120

1286432168421

11000000

128 + 64 = 192

1682726252423222120

1286432168421

10101000

128 + 32 + 8 = 168

32726252423222120

1286432168421

00000011

2 + 1 = 3

2192726252423222120

1286432168421

11011011

128 + 64 + 16 + 8 + 2 + 1 = 219

How to find NETWORK MASK

If 255.255.255.224

2552726252423222120

1286432168421

11111111

2552726252423222120

1286432168421

11111111

2552726252423222120

1286432168421

11111111

2242726252423222120

1286432168421

11100000

DETERMINE THE BROADCAST ADDRESS FOR THE NETWORK ADDRESS.1921683219

NETWORK ADD.110000001010100000000011 11101010

MASK11111111111111110000000000000000

BROADCAST1111111111111111

255255

Host IP Address 172.25.114.250

Network Mask255.255.0.0 (/16)

Network Address192.168.3.192

Network Broadcast Address192.168.3.223

Total Number Of Host Bits30

Number Of Hosts25

HOW TO TOTAL NUMBER OF HOST BITS 32 32 2= 30

HOW TO FIND NUMBER OF HOSTS 255.255.255.224255255255224

11111111111111111111111111100000

00000

= 5 ZEROS

NUMBER OF HOSTS = 2^5GIVEN:HOST IP ADDRESS 172.25.114.250

NETWORK MASK255.255.0.0 (/16)

SUBNET MASK255.255.255.192 (/26)

FIND :NUMBER OF SUBNET BITS10

NUMBER OF SUBNETS210 = 1024 subnet

NUMBER OF HOSTS BITS PER SUBNET6

NUMBER OF USABLE HOSTS PER SUBNET26 = 64 2 = 62 bit per subnet

SUBNET ADDRESS FOR THIS IP ADDRESS 172.25.114.192

IP ADDRESS OF FIRST HOSTS ON THIS SUBNET172.25.114.193

IP ADDRESS OF LAST HOSTS ON THIS SUBNET172.25.114.254

BROADCAST ADDRESS FOR ON THIS SUBNET172.25.114.255

STEP 1 : TRANSLATE HOSTS IP ADDRESS AND SUBNET MASK INTO BINARY NOTATION.IP ADDRESS

17225114250

000110010111001011111010

11111111111111111111111111000000SUBNET MASK

10101100 0001100101110010 11000000

17225114192

Subnet address = 172.25.114.192

DETERMINE THE BIT RANGERS FOR SUBNETS AND HOSTS17225114250

10101110000110010111001011111010

111111111111111110000000000000000

25525500

TOTAL NUMBERSUBNET MUSK = 11111111.11111111.00000000.00000000

= network : 2^8 = 256Number of Host Bits per Subnet = 16 bitsNumber of Usable Hosts per Subnet= host: 2^16 = 65536 2 = 65534

TASK 2 : FOR A SUBNETTING WORKSHEET TO SHOW AND RECORD ALL WORK FOR EACH PROBLEM.PROBLEM 1HOSTS IP ADDRESS 172.30.1.33

SUBNET MASK255.255.255.0

IP ADDRESS17230133

10101110000111100000000100100001

SUBNET MASK111111111111111111111111100000000

2552552550

Total number of Subnet Mask= 11111111.11111111.11111111.00000000= network = 2^8 = 256Number of Hosts Bits per Subnet = 8 bitsNumber of Usable Hosts per Subnet= hosts = 2^8 = 256 2 = 254

NETWORK 17230133IP ADDRESS

10101110000111100000000100100001

111111111111111111111111100000000SUBNET MUSK

2552552550

10101110000111100000000100000000NETWORK

1723010

NETWORK = IP ADDRESS + SUBNET MASK172= 1010111030=000111101= 0000000133= 00100001 11111111 1111111 11111111 00000000 10101110 00011001 00000001 00000000NETWORK = 10101110.00011001. 00000001.00000000 =172.30.1.0

FIRST HOSTS

17230133

10101110000111100000000100100001

111111111111111111111111111111100

255255255252

10101110000111100000000100000000

1723010

10101110000110010000000111111111

172301255

1723011

10101110000111100000000100000001

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast 10101110000111100000000111111111

172301255

1723011

10101110000111100000000100000001

LAST HOSTS17230133

10101110000111100000000100100001

111111111111111111111111100000000

2552552550

10101110000111100000000100000000

1723010

10101110000111100000000111111111

172301255

1723011

10101110000111100000000100000001

172301254

10101110000111100000000111111110

Last Host = replace the number 0 be the number 1 at 17-31 bits in the Broadcast

1723011

10101110000111100000000100000001

172301254

10101110000111100000000111111110

BROADCAST17230133

10101110000111100000000100100001

111111111111111111111111100000000

2552552550

10101110000111100000000100000000

1723010

10101110000111100000000111111111

172301255

BROADCAST = replace the number 0 to number 1 appearing on network address

10101110000111100000000100000000

1723010

10101110000111100000000111111111

172301255

RESULT HOSTS IP ADDRESS 172.30.1.33

SUBNET MASK255.255.255.0

NUMBER OF SUBNET BITS8 BITS

NUMBER OF SUBNETS2^8 = 256

NUMBER OF HOST BITS PER SUBNET256

NUMBER OF USABLE HOSTS PER SUBNET2^8 2 = 256 2 = 254

SUBNET ADDRESS FOR THIS IP ADDRESS172.30.1.0

IP ADDRESS OF FIRST HOST ON THIS SUBNET172.30.1.1

IP ADDRESS OF LAST HOST ON THIS SUBNET172.30.1.254

BROADCAST ADDRESS FOR THIS SUBNET172.30.1.255

PROBLEM 2IP ADDRESS172.30.1.33

SUBNET MASK255.255.255.252

IP ADDRESS17230133

10101110000110010000000100100001

SUBNET MASK111111111111111111111111111111100

255255255252

Total number of Subnet Mask = 11111111.11111111.11111111.11111100Network = 2^14 = 16384

Number of Hosts Bits per Subnet = 2 bits

Number of Usable Hosts per Subnet= hosts = 2^2 = 4 2 = 2

NETWORK 17230133IP ADDRESS

10101110000111100000000100100001

111111111111111111111111111111100SUBNET MUSK

255255255252

10101110000111100000000100100000NETWORK

17230132

NETWORK = IP ADDRESS + SUBNET MASK172= 1010111030=000111101= 0000000133= 00100001 11111111 11111111 11111111 11111100 10101110 00011001 00000001 00100000NETWORK = 10101110.00011001. 00000001.00100000 =172.30.1.32

FIRST HOSTS 17230133

10101110000111100000000100100001

111111111111111111111111100000000

2552552550

10101110000111100000000100100000

17230132

1723011

10101110000111100000000100000001

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast 10101110000111100000000100100000

17230132

17230133

10101110000111100000000100100001

LAST HOSTS17230133

10101110000111100000000100100001

111111111111111111111111111111100

255255255252

10101110000111100000000100100000

17230132

17230134

10101110000111100000000100100010

Last host = replace a number from 0 to 1 on the host range subnet add except on the last bit remains 0.17230132

10101110000111100000000100100000

17230133

10101110000111100000000100100001

BROADCAST17230133

10101110000111100000000100100001

111111111111111111111111111111100

255255255252

10101110000111100000000100100000

17230132

10101110000111100000000100100011

17230135

BROADCAST = replace the number 0 to number 1 appearing on network address

10101110000111100000000100000000

1723010

k10101110000111100000000100000011

17230135

RESULTHOST IP ADDRESS172.30.1.33

SUBNET MASK255.255.255.252

NUMBER OF SUBNET BITS14 BITS

NUMBER OF SUBNET2^14 = 16384

NUMBER OF HOST BITS PER SUBNET4

NUMBER OF USABLE HOSTS PER SUBNET2^4 2 =4 2 = 2 host per subnet

SUBNET ADDRESS FOR THIS IP ADDRESS172.30.1.32

IP ADDRESS OF FIRST HOST ON THIS SUBNET172.30.1.33

IP ADDRESS OF LAST HOST ON THIS SUBNET172.30.1.34

BROADCAST ADDRESS FOR THIS SUBNET172.30.1.35

PROBLEM 3

IP ADDRESS192.192.10.234

SUBNET MASK255.255.255.0

IP ADDRESS19219210234

11000000110000000000101011101010

SUBNET MASK111111111111111111111111100000000

2552552550

Total number of Subnet Mask = 11111111.11111111.11111111.00000000Network = 2^8 = 256

Number of Hosts Bits per Subnet = 8 bitsNumber of Usable Hosts per Subnet= hosts = 2^8 = 256 2 = 254

NETWORK

19219210234IP ADDRESS

1100000011000000 00001010 11101010

111111111111111111111111100000000SUBNET MUSK

2552552550

11000000 11000000 00001010 00000000NETWORK

19219210 0

NETWORK = IP ADDRESS + SUBNET MASK192= 11000000192=1100000010= 00001010234= 11101010 11111111 11111111 11111111 11111100 11000000 11000000 00001010 00000000NETWORK = 110000001100000000001010 00000000 =192.192.10.234

FIRST HOSTS

17230133

10101110000111100000000100100001

111111111111111111111111100000000

2552552550

10101110000111100000000100100000

17230132

1723011

10101110000111100000000100000001

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast 11000000 11000000 00001010 00000000

192192100

192 192 101

1100000011000000 00001010 00000001

LAST HOSTS19219210234

11000000 1100000000001010 11101010

111111111111111111111111100000000

2552552550

1100000011000000 00001010 00000000

192192100

19219210254

11000000 11000000 00001010 11111110

Last host = replace a number from 0 to 1 on the host range subnet add except on the last bit remains 0.

192192100

11000000 11000000 00001010 00000000

19219210254

1100000011000000 0000101011111110

BROADCAST19219210234

1100000011000000 0000101011101010

111111111111111111111111100000000

2552552550

11000000 11000000 00001010 00000000

192192100

11000000 11000000 00001010 11111111

19219210255

BROADCAST = replace the number 0 to number 1 appearing on network address 1100000011000000 00001010 00000000

192192100

1100000011000000 0000101011111111

19219210255

RESULTHOST IP ADDRESS192.192.10.234

SUBNET MASK255.255.255.0

NUMBER OF SUBNET BITS8 BITS

NUMBER OF SUBNET2^8 = 256

NUMBER OF HOST BITS PER SUBNET8 BITS

NUMBER OF USABLE HOSTS PER SUBNET2^8 2 =256 2 = 254 host per subnet

SUBNET ADDRESS FOR THIS IP ADDRESS192.192.10.0

IP ADDRESS OF FIRST HOST ON THIS SUBNET192.192.10.1

IP ADDRESS OF LAST HOST ON THIS SUBNET192.192.10.254

BROADCAST ADDRESS FOR THIS SUBNET192.192.10.255

PROBLEM 4

IP ADDRESS172.17.99.71

SUBNET MASK255.255.0.0

IP ADDRESS172179971

10101100000100010110001101000111

SUBNET MASK111111111111111110000000000000000

25525500

Total number of Subnet Mask = 11111111.11111111.00000000.00000000Network = 2^0 = 1

Number of Hosts Bits per Subnet = 16 bitsNumber of Usable Hosts per Subnet= hosts = 2^16 = 65536 2 = 65534

NETWORK 172179971IP ADDRESS

10101100 00010001 01100011 01000111

111111111111111110000000000000000SUBNET MUSK

25525500

10101100 00010001 00000000 00000000NETWORK

172170 0

NETWORK = IP ADDRESS + SUBNET MASK172= 1010110017=00010001 99= 01100011234= 01000111 11111111 11111111 00000000 00000000 10101100 00010001 00000000 00000000NETWORK = 10101100 00010001 00000000 00000000 =172.17.0.0

FIRST HOSTS

172179971

1010111000010001 01100011 01000111

1111111111111111100000000 00000000

25525500

1010111000010001 0000000000000000

1721700

1721701

1010111000010001 0000000000000001

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast 1010110000010001 00000000 00000000

1721700

172 17 01

10101100 00010001 00000000 00000001

LAST HOSTS172179971

10101100 00010001 01100011 01000111

1111111111111111100000000 00000000

25525500

10101100 00010001 00000000 00000000

1721700

172 17255254

10101100 00010001 111111111 11111110

Last host = replace a number from 0 to 1 on the host range subnet add except on the last bit remains 0.

1721700

10101100 00010001 00000000 00000000

17217255254

10101100 00010001 11111111 11111110

BROADCAST172179971

10101100 00010001 01100011 01000111

1111111111111111100000000 00000000

25525500

10101100 00010001 00000000 00000000

1721700

10101100 00010001 11111111 11111111

17217255255

BROADCAST = replace the number 0 to number 1 appearing on network address

10101100 00010001 00000000 00000000

1721700

10101100 00010001 11111111 11111111

17217255 255

RESULTHOST IP ADDRESS172.17.99.71

SUBNET MASK255.255.0.0

NUMBER OF SUBNET BITS0 BITS

NUMBER OF SUBNET2^0 = 1

NUMBER OF HOST BITS PER SUBNET16 BITS

NUMBER OF USABLE HOSTS PER SUBNET2^16 2 =65536 2 = 65534 host per subnet

SUBNET ADDRESS FOR THIS IP ADDRESS172.17.0.0

IP ADDRESS OF FIRST HOST ON THIS SUBNET172.17.0.1

IP ADDRESS OF LAST HOST ON THIS SUBNET172.17.255.254

BROADCAST ADDRESS FOR THIS SUBNET172.17.255.255

PROBLEM 5

IP ADDRESS192.168.3.219

SUBNET MASK255.255.255.0

IP ADDRESS1921683219

11000000101010000000001111011011

SUBNET MASK111111111111111111111111100000000

2552552550

Total number of Subnet Mask = 11111111.11111111. 11111111.00000000Network = 2^8 = 256

Number of Hosts Bits per Subnet = 8 bitsNumber of Usable Hosts per Subnet= hosts = 2^8 = 256 2 = 254

NETWORK 1921683219IP ADDRESS

11000000 10101000 00000011 11011011

11111111111111111111111111 00000000SUBNET MUSK

2552552550

111111111 10101000 00000011 00000000NETWORK

19216830

NETWORK = IP ADDRESS + SUBNET MASK192= 11000000168=101010003= 00000011219= 11011011 11111111 11111111 00000000 00000000 11000000 10101000 00000011 00000000

NETWORK = 11000000.10101000.00000011.00000000 =192.168.3.0 FIRST HOSTS 1921683219

11000000 10101000 00000011 11011011

11111111111111111111111111 00000000

2552552550

11000000 10101000 00000011 00000000

19216830

17216831

11000000 10101000 00000011 00000001

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast 11000000 10101000 00000011 00000000

19216830

192 16831

11000000 10101000 00000011 00000001

LAST HOSTS1921683219

11000000 10101000 00000011 11011011

1111111111111111100000000 00000000

25525500

11000000 10101000 00000011 00000000

19216830

192 1683254

11000000 10101000 00000011 11111110

Last host = replace a number from 0 to 1 on the host range subnet add except on the last bit remains 0.19216830

11000000 10101000 00000011 00000000

192168 3254

11000000 10101000 00000011 11111110

BROADCAST1921683219

11000000 10101000 0000001111011011

11111111111111111111111111 00000000

2552552550

11000000 10101000 00000011 00000000

19216830

11000000 10101000 00000011 11111111

1921683255

BROADCAST = replace the number 0 to number 1 appearing on network address

11000000 10101000 00000011 00000000

19216830

11000000 10101000 00000011 11111111

172168 3255

RESULTHOST IP ADDRESS192.168.3.219

SUBNET MASK255.255.255.0

NUMBER OF SUBNET BITS8 BITS

NUMBER OF SUBNET2^8 = 256

NUMBER OF HOST BITS PER SUBNET8 BITS

NUMBER OF USABLE HOSTS PER SUBNET2^8 2 =256 2 = 254 host per subnet

SUBNET ADDRESS FOR THIS IP ADDRESS192.168.3.0

IP ADDRESS OF FIRST HOST ON THIS SUBNET192.168.3.1

IP ADDRESS OF LAST HOST ON THIS SUBNET192.168.3.254

BROADCAST ADDRESS FOR THIS SUBNET192.168.3.255

PROBLEM 6IP ADDRESS192.168.3.219

SUBNET MASK255.255.255.252

IP ADDRESS1921683219

11000000101010000000001111011011

SUBNET MASK111111111111111111111111111111100

255255255252

Total number of Subnet Mask NUMBER OF SUBNET BITS2 BITS

NUMBER OF SUBNETS2^2 = 4

255.255.255.0255 255 255 0

111111111111111111111111.11111100

11111111.111111 = 14

= 11111111.11111111. 11111111.11111100Network = 2^14 = 16384

Number of Hosts Bits per Subnet = 2 bitsNumber of Usable Hosts per Subnet= hosts = 2^2 = 4 2 = 2 NETWORK 1921683219IP ADDRESS

11000000 10101000 00000011 11011011

11111111111111111111111111 11111100 SUBNET MUSK

255255255252

111111111 10101000 00000011 11011000 NETWORK

19216830

NETWORK = IP ADDRESS + SUBNET MASK192= 11000000168=101010003= 00000011216= 11011000 11111111 11111111 00000000 11111100 11000000 10101000 00000011 11011000NETWORK = 11000000101010000000001111011000 =192.168.3.216

FIRST HOSTS 1921683219

11000000 10101000 00000011 11011011

11111111111111111111111111 11111100

255255255252

11000000 10101000 00000011 11011000

1921683216

1921683217

11000000 10101000 00000011 11011001

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast 11000000 10101000 00000011 11011000

1921683216

192 16831

11000000 10101000 00000011 00000001

LAST HOSTS1921683219

11000000 10101000 00000011 11011011

11111111111111111111111111 11111100

255255255252

11000000 10101000 00000011 11011000

1921683216

192 1683218

11000000 10101000 00000011 11011010

Last host = replace a number from 0 to 1 on the host range subnet add except on the last bit remains 0.

1921683216

11000000 10101000 00000011 11011000

192168 3218

11000000 10101000 00000011 11011010

BROADCAST1921683219

11000000 10101000 0000001111011011

11111111111111111111111111 11111100

255255255252

11000000 10101000 00000011 11011000

1921683216

11000000 10101000 00000011 11011011

1921683219

BROADCAST = replace the number 0 to number 1 appearing on network address

11000000 10101000 00000011 11011000

1921683216

11000000 10101000 00000011 11011011

172168 3219

RESULTHOST IP ADDRESS192.168.3.219

SUBNET MASK255.255.255.252

NUMBER OF SUBNET BITS14 BITS

NUMBER OF SUBNET2^14 = 16384

NUMBER OF HOST BITS PER SUBNET2 BITS

NUMBER OF USABLE HOSTS PER SUBNET2^2 2 =4 2 = 2 host per subnet

SUBNET ADDRESS FOR THIS IP ADDRESS192.168.3.216

IP ADDRESS OF FIRST HOST ON THIS SUBNET192.168.3.217

IP ADDRESS OF LAST HOST ON THIS SUBNET192.168.3.218

BROADCAST ADDRESS FOR THIS SUBNET192.168.3.219