Upload
nka63
View
16
Download
2
Embed Size (px)
Citation preview
ASSESMENT OF LUNG PARENCHYMAL DAMAGE WITH ARTERIAL BLOOD GAS ANALYSIS (ABG)
PROF.N.K.AGRAWAL
OBJECTIVE
The objective of the study was to assess the lung damage at alveoli level with arterial blood gas analysis (ABG)
The major task of the lung is to oxygenate the blood and remove carbon dioxide, this happens by exchange
of gas between alveoli and blood capillary. Oxygen diffuses passively from the alveoli to plasma. The
diffusion is affected by-
Surface area
available
Thickness of
membrane
Pressure difference of the gas across the
barrier
Molecular weight of the gas
Solubility of gas.
The alveoli are main respiratory surface in human being, they are small sacs of branching of bronchioles, and they are one cell thick and provide large area for gas exchange
If all other factors are kept constant the main factor are surface area and thickness of alveoli. The gas exchange is hence inversely proportionate to thickness, the more is the thickness less will be diffusion. Patients with chronic bronchitis, COPD, fibrosis pneumonia, ARDS etc have changes in thickness and surface area.2
RESPIRATORY EQUATIONS
PATM = PN 2+Po2+Pco2+PH2O
P760 = P514 + P159 + P40 + P47
PI02 = FIO2 X ( PB - -- H2 0 )
PAO2 = FiO2 x ( Pb- 47 ) - 1.25 x PCO2
The normal P ( A-a) O2 difference at patient breathing air is 5 to 20 mm of Hg while at Fio2 of 1 it may go up to 110 mm of Hg. The A-a gradient increases by5-7 mm of Hg with every 10% rise of FIO2
Expected Pao2 = PAo2 X ( 1- k ) (k = 0.05 at 20-40 %, 0.1 at 41-60%,0.15 at 61-80%,0.2 at 81-100 % FIO2 )
• The expected Pao2 will be EPao2 = PAO2 X (1-k)
(Below equation is copyright of author)
Epa02– Pa02 Lung Damage = ------------------- x100 EPao2
Case No. 1 A patient in ICU had Pao2 78 mm of hg with Fio2 =1 PAo2 = 1x (760 - 47) – 1.25x32
= 1x 713 - 40 = 673 mm of Hg EPao2= PAo2x 1-0.2 = 0.8 x 673 = 536 mm Hg
536 - 78 LD = -------------------
536 = 0.85x 100 = 85 %
CASE NO.2 A patient posted for thoracotomy the ABG showed Pao2=57
PAo2 = 0.2 x (760-47) – 1.25x32
=147-40 =107 EPao2 = 0.95x PAo2 = 0.95 x 107 =101mm of Hg
101 - 57 LD = ----------------- x 100
101 = 44 %
CONCLUSION
Here we conclude that whenever the ABG reports are read in one must take in account the Fio2 and atmospheric pressure. Using the above equation we will be able to assess the lung damage correctly to manage the patients who are appearing normal as per Pao2 available.