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A powerpoint presentation on my lesson, Quadratic Inequality
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Quadratic Inequalities
Activity 1: What Makes Me True?
Give the solution/s of each of the following mathematical sentences.1. x + 5 > 8
2. r – 3 = 10
3. 2s + 7 ≥ 21
4. 3t – 2 ≤ 13
5. 12 – 5m = - 8
Guide QuestionsHow did you find the solution/s of each
mathematical statements?
What mathematical concepts or principles did you apply to come up with the solution/s?
Which mathematical sentences has only one solution? More than one solution? Describe these sentences.
Activity 2: Which are Not Quadratic Equations?
x2 + 9z + 20 = 0
2r2 < 21 - 9t 2x2 + 2 = 10x
r2 + 10r ≤ - 16 m2 = 6m - 7 4x2 – 25 = 0
15 – 6h2 = 10 3w2 + 12w ≥ 0
2s2 + 7s + 5 > 0
Definition Is an inequality that contains a polynomial of degree
2 and can be written in any of the following forms.
ax2 + bx + c > 0 ax2 + bx + c ≥ 0
ax2 + bx + c < 0 ax2 + bx + c ≤ 0
where a, b, and c are real numbers and a ≠ 0.
To solve a quadratic inequality, find the roots of its corresponding equality.
Find the solution set of x2 + 7x + 12 > 0.The corresponding equality of x2 + 7x + 12 > 0 is x2 + 7x + 12 = 0.
Solve x2 + 7x + 12 = 0.(x + 3)(x + 4) = 0 Why?x + 3 = 0 & x + 4 = 0 Why?x = - 3 & x = - 4 Why?
Plot the points corresponding to -3 and -4 on the number line.
For - ∞ < x < - 4,Let x = - 7
For – 4 < x < - 3, Let x = 3.6
For – 3 < x < ∞,Let x = 0
x2 + 7x + 12 > 0(-7)2 + 7(-7) + 12 > 049 – 49 + 12 > 012 > 0 (true)
x2 + 7x + 12 > 0(-3.6)2 + 7(-3.6) + 12 > 012.96 – 25.2 + 12 > 0-0.24 > 0 (false)
x2 + 7x + 12 > 0(0)2 + 7(0) + 12 > 00 + 0 + 12 > 012 > 0 (true)
The three interval are: - ∞ < x < - 4, - 4 < x < - 3, - 3 < x < ∞.
Test a number from each interval against the inequality.
Also test whether the points x = - 3 and x = - 4 satisfy the equation.
x2 + 7x + 12 > 0(-3)2 + 7(-3) + 12 > 09 – 21 + 12 > 00 > 0 (false)
x2 + 7x + 12 > 0(-4)2 + 7(-4) + 12 > 016 – 28 + 12 > 00 > 0 (false)
Therefore, the inequality is true for any value of x in the interval - ∞ < x < - 4 or - 3 < x < ∞, and these intervals exclude – 3 and – 4. The solution set of the inequality is {x:x < - 4 or x > - 3}.
Quadratic Inequalities In Two Variables
There are quadratic inequalities that involves two variables. These inequalities can be written in any of the following forms.
y > ax2 + bx + c y ≥ ax2 + bx + c
y < ax2 + bx + c y ≤ ax2 + bx + c