Quadratic Equations Quadratic Equations

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    Solving

    Equations

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    A quadratic equation is an equation equivalent to one of the form

    Where a, b, and c are real numbers and a 0

    02 cbxax

    To solve a quadratic equation we get it in the form above

    and see if it will factor.652 xx Get form above by subtracting 5x andadding 6 to both sides to get 0 on right side.

    -5x + 6 -5x + 6

    0652

    xx Factor.

    023 xx Use the Null Factor law and set eachfactor = 0 and solve.

    02or03 xx 3x 2x

    So if we have an equation inxand the highest power is 2, it is quadratic.

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    In this form we could have the case where b = 0.

    02 cbxax

    Remember standard form for a quadratic equation is:

    02 cax

    002 cxax

    When this is the case, we get the x2 alone and then square

    root both sides.

    062 2 x Getx2 alone by adding 6 to both sides and then

    dividing both sides by 2+ 6 + 6

    62

    2

    x2 2 32 x

    Now take the square root of both

    sides remembering that you must

    consider both the positive andnegative root.

    3xLet's

    check: 06322

    06322

    066 066

    Now take the square root of both

    sides remembering that you must

    consider both the positive andnegative root.

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    02 cbxax

    What if in standard form, c = 0?

    002 bxax

    We could factor by pulling

    anxout of each term.

    032 2 xx Factor out the commonx

    032 xx Use the Null Factor law and set eachfactor = 0 and solve.

    032or0 xx

    2

    3or0 xx

    If you put either of these values in forx

    in the original equation you can see it

    makes a true statement.

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    02 cbxaxWhat are we going to do if we have non-zero values for

    a, b and c but can't factor the left hand side?

    0362 xxThis will not factor so we will complete the

    square and apply the square root method.

    First get the constant term on the other side by

    subtracting 3 from both sides.36

    2 xx

    ___3___62 xx

    We are now going to add a number to the left side so it will factor

    into a perfect square. This means that it will factor into two

    identical factors. If we add a number to one side of the equation,

    we need to add it to the other to keep the equation true.

    Let's add 9. Right now we'll see that it works and then we'll look at howto find it.

    9 9 6962 xx

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    6962 xx Now factor the left hand side.

    633 xx

    two identical factors

    63 2 xThis can be written as:

    Now we'll get rid of the square by

    square rooting both sides.

    63 2 xRemember you need both the

    positive and negative root!

    63x Subtract 3 from both sides to getxalone.

    63 xThese are the answers in exact form. We

    can put them in a calculator to get two

    approximate answers.

    55.063 x 45.563 x

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    Okay---so this works to solve the equation but how did we

    know to add 9 to both sides?

    ___3___62

    xx 9 9

    633 xx We wanted the left hand side to factorinto two identical factors.

    When you FOIL, the outer terms and theinner terms need to be identical and need

    to add up to 6x.+3 x+3

    x

    6 x

    The last term in the original trinomial will then be the middleterm's coefficient divided by 2 and squared since last term

    times last term will be (3)(3) or 32.

    So to complete the square, the number to add to both sides

    is

    the middle term's coefficient divided by 2 and squared

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    By completing the square on a general quadratic equation in

    standard form we come up with what is called the quadratic formula.

    (Remember the song!! )

    a

    acbbx

    2

    42

    This formula can be used to solve any quadratic equationwhether it factors or not. If it factors, it is generally easier to

    factor---but this formula would give you the solutions as well.

    We solved this by completing the square

    but let's solve it using the quadratic formula

    a

    acbbx

    2

    42

    1

    (1)

    (1)

    6 6 (3)

    2

    12366

    Don't make a mistake with order of operations!Let's do the power and the multiplying first.

    02 cbxax

    036

    2 xx

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    2

    12366 x

    2

    246

    626424

    2

    626

    2

    632

    There's a 2 in common in

    the terms of the numerator

    63 These are the solutions wegot when we completed the

    square on this problem.

    NOTE: When using this formula if you've simplified under the

    radical and end up with a negative, there are no real solutions.

    (There are complex (imaginary) solutions, but that will be dealt

    with in year 12 Calculus).

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    SUMMARY OF SOLVING QUADRATIC EQUATIONS

    Get the equation in standard form: 02 cbxax

    If there is no middle term (b = 0) then get thex2 alone and square

    root both sides (if you get a negative under the square root there are

    no real solutions).

    If there is no constant term (c = 0) then factor out the commonxand use the null factor law to solve (set each factor = 0).

    Ifa, band care non-zero, see if you can factor and use the null

    factor law to solve.

    If it doesn't factor or is hard to factor, use the quadratic formula

    to solve (if you get a negative under the square root there are no real

    solutions).

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    a

    acbbxcbxax

    2

    40

    22

    If we have a quadratic equation and are considering solutions

    from the real number system, using the quadratic formula, one of

    three things can happen.

    3. The "stuff" under the square root can be negative and we'd get

    no real solutions.

    The "stuff" under the square root is called the discriminant.

    This "discriminates" or tells us what type of solutions we'll have.

    1. The "stuff" under the square root can be positive and we'd gettwo unequal real solutions 04if 2 acb

    2. The "stuff" under the square root can be zero and we'd get one

    solution (called a repeated or double root because it would factor

    into two equal factors, each giving us the same solution).04if

    2

    acb

    04if2

    acb

    The Discriminant acb 42

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    13

    5-2 Two-Way Selection

    The decision is described to the computer as aconditional statement that can be answered either true

    or false. If the answer is true, one or more action

    statements are executed. If the answer is false, then a

    different action or set of actions is executed.

    ifelse andNull else Statement

    Nested ifStatements and Dangling else Problem

    Simplifying ifStatements

    Conditional Expressions

    Topics discussed in this section:

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    Computer Science: AStructured

    14

    FIGURE 5-6 Two-way Decision Logic

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    Computer Science: AStructured

    15

    FIGURE 5-7 if...else Logic Flow

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    Computer Science: AStructured

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    Table 5-2 Syntactical Rules forifelse Statements

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    Computer Science: AStructured

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    FIGURE 5-8 A Simple if...else Statement

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    Computer Science: AStructured

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    FIGURE 5-9 Compound Statements in an if...else

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    19

    5-3 Multiway Selection

    In addition to two-way selection, most programming

    languages provide another selection concept known as

    multiway selection. Multiway selection chooses among

    several alternatives. C has two different ways toimplement multiway selection: the switch statement and

    else-if construct.

    Theswitch Statement

    The else-if

    Topics discussed in this section:

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    Computer Science: AStructured

    20

    FIGURE 5-19switch Decision Logic

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    Computer Science: AStructured

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    FIGURE 5-24 The else-ifLogic Design for Program 5-9

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    Computer Science: AStructured

    22

    The else-ifis an artificial C construct that is only used when

    1. The selection variable is not an integral, and

    2. The same variable is being tested in the expressions.

    Note

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    General Syntax of else-if

    constructif (expression-1)

    statement-1;

    else if (expression-2)statement-2;

    ..

    ..else

    statement-n;

    #i l d < tdi h>

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    #include

    #include

    #include

    #include

    void main()

    {float a,b,c,x1,x2,disc;

    clrscr();

    printf("Enter the co-efficients\n");

    scanf("%f%f%f",&a,&b,&c);

    if(a==0)

    {printf( equation is not quadratic \n);

    exit(0);

    }

    disc=b*b-4*a*c;/*to find discriminant*/

    if(disc>0) /*distinct roots*/

    {x1=(-b+sqrt(disc))/(2*a);

    x2=(-b-sqrt(disc))/(2*a);

    printf("The roots are distinct\n");

    }

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    else

    {

    x1=-b/(2*a);/*complex roots*/

    x2=sqrt(fabs(disc))/(2*a);

    printf("The roots are complex\n");

    printf("The first root=%f+i%f\n",x1,x2);printf("The second root=%f-i%f\n",x1,x2);

    getch();

    }

    } /* end of main function */

    else if(disc==0)/*Equal roots*/{

    x1=x2=-b/(2*a);

    printf("The roots are equal\n");

    printf("x1=%f\nx2=%f\n",x1,x2);

    }

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