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Multiple Bets 1

Lesson 4 multiple bets

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Page 1: Lesson 4   multiple bets

Multiple Bets

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Page 2: Lesson 4   multiple bets

What are the odds of throwing three 6's in a row?

• Even if you throw three 6’s in a row, the odds of you throwing another 6 are still 5/1!

• However, the odds of you throwing 3 sixes in a row one after the other is 215/1.

(5/1 x 5/1 x 5/1) = (6 x 6 x 6 – 1) = 215/1

Now let’s do an example with horses:

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Page 3: Lesson 4   multiple bets

• Let us use a horse racing example to show the odds with a multiple throw of the dice.

• Throwing three sixes in a row are an example of what we call a multiple bet. It’s like you betting on three horses in three races, each at 5/1.

• For example:Race 1: Horse number 7 @ 5/1 = (5 + 1 = 6)Race 5: Horse number 5 @ 5/1 = (5 + 1 =6) Race 8: Horse number 3 @ 5/1 = (5 + 1 =6)

• Multiply 6 x 6 x 6 = 216 – 1 = 215. The odds are therefore 215/1.

• For R10 you will get R2150 or R4250 for R20, R6450 for R30.

• Now you must fly solo:3

Page 4: Lesson 4   multiple bets

Odds in a Multiple bet (Exercise)

• Calculate the odds you will receive if you placed a multiple bet on the following events (taken directly from the Turf Sport database):

Greyville (23/12/2011) • Race 1: HALLOWED @ 2.5 (5/2)• Race 3: BOULEVARD @ 9 (9/1)• Race 5: FLAMING AL @ 1 (1/1)• Race 6: RAGING RIVER @ 5 (5/1)

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(2.5 +1) x (9 + 1) x (1 + 1) x (5 + 1)3.5 x 10 x 2 x 6 = 420 – 1 = 419/1

Page 5: Lesson 4   multiple bets

Exercise

1 Convert the following computer odds into fractions• 0.25 _____________________

• 0.3 _____________________

• 1.5 _____________________

• 2.5 _____________________

• 1 _____________________

• 0.70 _____________________

• 0.33 _____________________

• 0.55 _____________________ 5

1/1

0.3/1 (x 10) = 3/10

0.25/1 = 25/100 (x 10) = 1 / 4 (divide by 25)

1.5/1 (x 10) = 15/10

2.5/1 (x 10) = 25/10 = 5/2 (divide by 5)

0.7/1 (x 10) 7/10

0.33/1 (x 100) = 33/100 1/3 (divide by 33)

0.55/1 (x 100) = 55/100 = 11/20 (divide by 5)

Page 6: Lesson 4   multiple bets

2. If a horse is 7/1, how much must a punter invest to win R1000?

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Training Exercise (Page 6)

7000/1000 = 1000/140 = R1000/R140 = R140

Page 7: Lesson 4   multiple bets

3 A punter takes a multiple on Vertigo Bay (horse) at 2/1 and Arsenal at 9/10. The bet is 1000/200. Vertigo Bay is scratched at the start and Arsenal win. What will the final bet read?

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Training Exercise (Page 6)

Vertigo Bay’s odds fall away and so the odds are only 9/10If the punter wants to win R1000, they will have to pay R1100 =

1000/1100or if he spends a stake of R200 then he stands to win 180 = 180/200

Page 8: Lesson 4   multiple bets

4 The Turfsport database indicates a horse at odds 0.17. A punter asks how much he stands to win for a stake of R100. What do you tell him?

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Odds are 1/6 = 17/100 = R17

Training Exercise (Page 6)

Page 9: Lesson 4   multiple bets

5. A punter asks how much his stake will be if he wants to win R1 000 on Manchester United at odds of 1.8. What do you tell him?

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1.8 = 18/10 = 1000/550 =His stake will be R550

Training Exercise (Page 6)

Page 10: Lesson 4   multiple bets

In the event of two horses dead heating for 1st place, bets on these horses will be halved (both winnings and stake).Example:• Winner no 1 bet is 1000/400. His bet, because he has backed half a

winner due to the dead heat, will become 500/200 and the payout will be R670 (R500 less 6% tax plus half his stake). He loses half his stake (R200).

• Winner no 2 bet is 1000/70. His bet, because he has also backed half a winner, will become 500/35 and the payout will be R505 (R500 less 6% tax plus R35 stake). He also loses half his stake (R35).

Dead Heats

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