Download pdf - beamerAnalysis6-13

Transcript
  • 8/13/2019 beamerAnalysis6-13

    1/14

    0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.90

    50

    100X = [0,1] i.e., X compact ; f discontinuous

    0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.90

    50

    100X = (0,1] i.e., X not compact; f continuous

    0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.90

    50

    100X = [0,1] i.e., X compact; f continuous

    Figure 1. Compactness plus continuity implies boundedness

    () August 18, 2013 1 / 14

    http://find/
  • 8/13/2019 beamerAnalysis6-13

    2/14

    (

    (

    X

    Y

    W

    X

    Y

    [ )

    [

    [xx xxxn xn

    ) f(x)

    n)

    f(xn)

    S

    f1(S)

    O

    f1(O)

    if part of the proof (contra-positive)

    f continuous, f1(S) not open impliesSnot open

    only if part of the proof (contra-positive)

    fdiscontinuous,O open,f1(O) not open

    Figure 1. fis continuous iffSopen = f1(S) open

    () August 18, 2013 2 / 14

    http://find/
  • 8/13/2019 beamerAnalysis6-13

    3/14

    Continuity & Hemi-continuity defns: continuity

    1(a) Inverse image formulation of continuity.

    A functionf : X Y is calledcontinuousif for every open setO Y,f1(O)is an open set ofX.

    1(b) Neighborhood formulation of continuity.

    A functionf : X Y is calledcontinuousif for everyx Xand everyneighborhoodUoff(x)there is a neighborhoodV ofxsuch thatf(x) U foreveryx V.

    1(c) Sequential formulation of continuity.

    A functionf : XRn is calledcontinuousatx0 Xif whenever {xm}m=1convergesx0 then {f(xm)} converges tof(x0); the functionfis continuous if itis continuous atxfor everyx X.

    () August 18, 2013 3 / 14

    http://find/
  • 8/13/2019 beamerAnalysis6-13

    4/14

    Continuity & Hemi-continuity defns: upper hemi-continuity

    2(a) Inverse image formulation of upper hemicontinuity.A correspondence : S T is calledupper hemicontinuousif for every open

    setO T, the upper inverse image ofOunder,1

    (O) S, is an open set.Explosions allowed;implosions are not

    2(b) Neighborhood formulation of upper hemicontinuity.A correspondence : S T is calledupper hemicontinuousif for everys Sand every neighborhoodUof(s)there is a neighborhoodV ofssuch that(s) Ufor everys V.

    2(c) Sequential formulation of upper hemicontinuity.

    A compact-valued correspondence : S T is calledupper hemicontinuousif for everys S, every sequence {sn} converging tosand every sequence{tn} withtn (sn), there is a convergent subsequence {tnk} of {tn} such thatlim

    ntnk=

    t (

    s)

    .

    () August 18, 2013 4 / 14

    http://find/
  • 8/13/2019 beamerAnalysis6-13

    5/14

    Continuity & Hemi-continuity defns: lower hemi-continuity

    3(a) Inverse image formulation of lower hemicontinuity.A correspondence : S T is calledlower hemicontinuousif for every opensetO T, the lower inverse image ofOunder,1(O) S, is an open set.Implosions allowed;explosions are not

    3(b) Neighborhood formulation of lower hemicontinuity.

    A correspondence : S T is calledlower hemicontinuousif for everys S,and every open setU T withU

    (s) = /0, there exists a neighborhoodV of

    ssuch thatU(z) = /0, for everyz V.

    3(c) Sequential formulation of lower hemicontinuity.

    A correspondence : S T is calledlower hemicontinuousif for everys S,anyt (s), and any sequence {sn} converging tos, there exists a sequence{tn} such thattn (sn)and lim

    ntn= t.

    () August 18, 2013 5 / 14

    http://find/
  • 8/13/2019 beamerAnalysis6-13

    6/14

    Explosions, Implosions and Hemi-continuity

    Thegraphof a correspondence:

    Graph() = {(s, t) ST :t (s)}

    Theouter accumulationof a correspondence.

    OAc

    (s) = {t T : (s,

    t)is an accumulation point of Graph()}Theinner accumulationof a correspondence.

    IAc(s) = {t T : {sn} s,{tn} s.t.n, tn (sn)and {tn} t}

    Definition: explodesat sif(s) IAc(s).

    Definition: implodesat sifOAc(s) (s).

    Theorem: If:S T,Tis compact and is compact-valued, then is u.h.c atsiff does not implode ats

    Theorem: is l.h.c atsiff does not explode at s() August 18, 2013 6 / 14

    http://find/
  • 8/13/2019 beamerAnalysis6-13

    7/14

    O)

    (

    ( )( )1(O)

    1(O)

    Figure 3. Upper and Lower inverse images of

    () August 18, 2013 7 / 14

    http://find/
  • 8/13/2019 beamerAnalysis6-13

    8/14

    (1,

    2)

    (0,0)

    x

    u

    is

    uhsb

    ut

    not

    lhc

    u1((1, 2)) = {0} closed

    u1

    ((1, 2)) =

    (1

    ,1)

    (0,0)

    is

    lhc

    but

    not

    uhc

    1

    ((1, 1)) = {0} closed

    1((1, 1)) = R

    Figure 4. u and

    () August 18, 2013 8 / 14

    http://find/http://goback/
  • 8/13/2019 beamerAnalysis6-13

    9/14

    0 1

    U

    O

    yz w

    (

    (

    )

    )

    x

    Figure 5. : [0, 1] R() August 18, 2013 9 / 14

    http://find/
  • 8/13/2019 beamerAnalysis6-13

    10/14

    0 1

    U

    O

    yz w

    (

    (

    )

    )

    v x

    Figure 6. : [0, 1] R() August 18, 2013 10 / 14

    http://find/
  • 8/13/2019 beamerAnalysis6-13

    11/14

    Berges Theorem

    Berges Theorem of the Maximum: If :X Yis a continuous

    correspondence with nonempty and compact values and:YR is acontinuous function, theny :X Ydefined byy(x) =argmaxy(x)(y)isu.h.c. and :XR defined by(x) =maxy(x)(y)is a continuousfunction.

    For our purposes, think of:Xas a space of price vectors

    Yas a space of commodity vectors

    as a budget correspondence, continuous, compact-valued

    as a utility function, continuousy as a demand correspondence. Result: its u.h.c.

    as an indirect utility function. Result: its continuous

    (Ill adduto the pics, its a direct utility function)

    () August 18, 2013 11 / 14

    http://find/
  • 8/13/2019 beamerAnalysis6-13

    12/14

    Berges theorem: Introduction

    0 0 0 0 0 0 00 0 0 0 0 0 00 0 0 0 0 0 00 0 0 0 0 0 00 0 0 0 0 0 00 0 0 0 0 0 00 0 0 0 0 0 00 0 0 0 0 0 00 0 0 0 0 0 00 0 0 0 0 0 01 1 1 1 1 1 11 1 1 1 1 1 11 1 1 1 1 1 11 1 1 1 1 1 11 1 1 1 1 1 11 1 1 1 1 1 11 1 1 1 1 1 11 1 1 1 1 1 11 1 1 1 1 1 11 1 1 1 1 1 1 0 0 0 0 00 0 0 0 00 0 0 0 00 0 0 0 00 0 0 0 00 0 0 0 00 0 0 0 00 0 0 0 00 0 0 0 00 0 0 0 00 0 0 0 00 0 0 0 01 1 1 1 11 1 1 1 11 1 1 1 11 1 1 1 11 1 1 1 11 1 1 1 11 1 1 1 11 1 1 1 11 1 1 1 11 1 1 1 11 1 1 1 11 1 1 1 10 0 0 0 0 0 0 0 0 00 0 0 0 0 0 0 0 0 00 0 0 0 0 0 0 0 0 00 0 0 0 0 0 0 0 0 00 0 0 0 0 0 0 0 0 00 0 0 0 0 0 0 0 0 00 0 0 0 0 0 0 0 0 00 0 0 0 0 0 0 0 0 01 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 2.5

    * **

    y1y1y1

    y2y2y2

    y(1)

    y(2)

    y(0.5) (1) (2)(0.5)

    P = x1x2

    Figure 7. The demand correspondence is u.h.c

    () August 18, 2013 12 / 14

    http://find/http://goback/
  • 8/13/2019 beamerAnalysis6-13

    13/14

    Berges theorem: Role of upper-hemi-continuity

    (

    (

    }(y) = (x)y O (nbd of(x))inf(O)

    U =1(O)

    (x)

    (x)

    x

    x

    V = 1(U)

    RX Y

    Figure 1. Lower hemi-continuity of implies that (x)>inf(O).

    () August 18, 2013 13 / 14

    http://find/
  • 8/13/2019 beamerAnalysis6-13

    14/14

    Berges theorem: Role of upper-hemi-continuity

    Y

    (

    (

    (

    (

    }

    }(y) = (x) O (nbd of(x))

    Uh =1(O)

    O (nbd of((x))

    O

    =O O

    sup(O)

    (x)

    x

    Vh =1(Uh)

    RX

    Figure 2. Upper hemi-continuity of implies that (x)< sup(O).

    () August 18, 2013 14 / 14

    http://find/

Recommended