325
19
553
7112
570
7515415
7016
538
21
11050
57
~ ~ ~ ~ CLUES ~ ~ ~ ~
Left\: 15= __ x __ 70= __ x __ x __165= __ x __ x __ 38= __ x __Down:570= __ x __ x __ x __154= __ x __ x __ 75= __ x __ x __Right/: 21= __ x __110= __ x __ x __ 50= __ x __ x __ 57= __ x __
MrV’s HexFactor #1
1. Factor each clue completely. Ex: 15 = 3 x 5 , etc.2. Find an intersection of 3 clues, and see if there is only one
common factor. The top cell’s clues are 15, 570, 213. 3 is common: Fill it in and cross it off in each of the clues.4. Fill in any others: 15’s missing factor is 5. 21’s is 7.5. Repeat steps 2, 3 & 4 for each remaining cell.
15 / \
3 5
21 / \
3 7
?57
570 / \
3 190 / \
2 95 / \
5 19
Now go ahead and figure out the rest of the
puzzle!
~ ~ ~ ~ CLUES ~ ~ ~ ~
Left\: 15= 3 x 5 70= 2 x 5 x 7 165= 3 x 5 x 11 38= 2 x 19 Down:570= 2 x 3 x 5 x 19154= 2 x 7 x 11 75= 3 x 5 x 5 /Right: 21= 3 x 7 110= 2 x 5 x 11 50= 2 x 5 x 5 57= 3 x 19
3
325
19
553
7112
570
7515415
7016
538
21
11050
57
325
19
553
7112
570
75154
15
7016
538
21
11050
57
MrV’s HexFactor #1Solution #1
1. Factor each clue completely. Ex: 15 = 3 x 5 , etc.2. Find an intersection where only one factor will fit:
15 = 3 x 5 and 21 = ? And 570 = ?3. Fill in the factor and cross it off in the clues.4. Then fill in any others that must fit.5. Repeat steps 2, 3 & 4 for the remaining cells.
~ ~ ~ ~ CLUES ~ ~ ~ ~ Down:570= 2 x 3 x 5 x 19154= 2 x 7 x 11 75= 3 x 5 x 5 Left: 15= 3 x 5 70= 2 x 5 x 7 165= 3 x 5 x 11 38= 2 x 19 Right: 21= 3 x 7 110= 2 x 5 x 11 50= 2 x 5 x 5 57= 3 x 19
~ ~ ~ ~ CLUES ~ ~ ~ ~ Down:
570= __ x __ x __ x __154= __ x __ x __ 75= __ x __ x __Left:
15= __ x __ 70= __ x __ x __165= __ x __ x __ 38= __ x __Right:
21= __ x __110= __ x __ x __ 50= __ x __ x __ 57= __ x __
104
11010570
364
110
42
330
910286
~ ~ ~ ~ CLUES ~ ~ ~ ~ 33= __ x __ 42= __ x __ x __ 70= __ x __ x __ 91= __ x __ 104= __ x __ x __ x __ 105= __ x __ x __ 110= __ x __ x __ 110= __ x __ x __ 286= __ x __ x __ 330= __ x __ x __ x __ 364= __ x __ x __ x __ 910= __ x __ x __ x __1287= __ x __ x __ x __
MrV’s HexFactor #2
33
1287
91
1. Factor each of the clues. Ex: 33 = 3 x 11, etc.2. Find an intersection where only one factor will fit:
33 = 3 x 11 and 42 = 2 x 3 x 73. Fill in the factor, then fill in any others that fit.4. Repeat steps 2 & 3 for the remaining cells.
131111
13
22
2
23
37
75
5
104
110105
70
364
110
42
330
910286
33
1287
91
131111
13
22
2
23
37
75
5
~ ~ ~ ~ CLUES ~ ~ ~ ~ 33= 3 x 11 42= 2 x 3 x 7 70= 3 x 5 x 7 91= 7 x 13 104= 2 x 2 x 2 x 13 105= 3 x 5 x 7 110= 2 x 5 x 11 110= 2 x 5 x 11 286= 2 x 11 x 13 330= 2 x 3 x 5 x 11 364= 2 x 2 x 7 x 13 910= 2 x 5 x 7 x 131287= 3 x 3 x 11 x 13
Solution #2
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