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II II - 1 Lines Planes FV ‘’PULUNG’’ FV ‘’PULUNG’’ DATA KAPAL Nama Kapal : FV ”PULUNG” Jenis Kapal : FISHING BOAT Ukuran Utama : LPP = 43,40 M LWL = 44,268 M LOA = 46,2 M B = 8,6 M H = 3,6 M T = 2,8 M Cb = 0,59 M Vs = 11,5 M a = 6000SeaMiles BHP = 1400 HP BRT = 530Ton NRT = 200 Ton Program Studi Diploma III Teknik Perkapalan Program Studi Diploma III Teknik Perkapalan Universitas Diponegoro Semarang Universitas Diponegoro Semarang TULUS PULUNG KURNIA PURWATAMA TULUS PULUNG KURNIA PURWATAMA NIM :21090113060045 NIM :21090113060045

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Lines Planes

FV PULUNG

DATA KAPAL

Nama Kapal : FV PULUNGJenis Kapal : FISHING BOATUkuran Utama :

LPP = 43,40 M

LWL = 44,268 M

LOA = 46,2 M

B = 8,6 M

H = 3,6 M

T = 2,8 M

Cb = 0,59 M

Vs = 11,5 M

a = 6000SeaMiles

BHP = 1400 HP

BRT = 530Ton

NRT = 200 Ton

PERHITUNGAN RENCANA GARIS

(LINES PLAN)

A PERHITUNGAN DASAR1.Panjang Garis Air Muat (Lwl)

Lwl= Lpp + 2 % x Lpp

(Ref : ITS Th.1982 Diktat Rencana Garis)= 43,40+ 2 % x 43,40= 44,40 m 2.Panjang Displacement (L Displ)

L Displ= 0,5 x (Lwl+ Lpp )(Ref : ITS Th.1982 Diktat Rencana Garis)

= 0,5 x (44,268 + 43,40)

= 43,834 m

3.Coefisien Midship (Cm) Formula Arkent Bont Shocker.

Cm=0,9+ (0,1x Cb )

=0,9+ (0,1x0,72 )

=0,823Memenuhi Syarat(0,73 ~ 0,88)

4.Coefisien Prismatik (Cp) Formula Troast

Cp=Cb/ Cm

=0,59/0,823

=0,717Memenuhi Syarat(0,61 0,70)

5.Coefisien Garis Air (Cw) Formula Troast

Cw=

=0,59-0,025

=0,752

Memenuhi syarat (0.73- 0.81)6.Luas Garis Air (Awl) (Ref : ITS Th.1982 Diktat Rencana Garis)Awl=Lwlx BxCw

=44,268x8,60x0,752

=286,162 m27.Luas Midship (Am)(Ref : ITS Th.1982 Diktat Rencana Garis)Am=Bx Tx Cm

=8,60x2,80x0,823

=19,822 m28.Volume Displacement (C Displ)(Ref : ITS Th.1982 Diktat Rencana Garis)V Displ= Lppx Bx Tx Cb

=43,40x8,60x2,80x0,59

=616,592 m29.Coefisien Prismatik Displacement (Cp Displ)(Ref : ITS Th.1982 Diktat Rencana Garis)Cp Displ=Lpp/L Displx Cp

=43,40/43,834

x0,717

=0,71010.Displacement (D)(Ref : ITS Th.1982 Diktat Rencana Garis)D=Vol Displx x c

=616,592x1,025x1,004

=634,535 TonB MENENTUKAN LETAK LCBB.1. Dengan menggunakan Cp Displacement pada grafik NSP pada Cp Displacement = 0,45 Didapat letak titik LCB (Longitudinal Centre Bouyancy = 0,5 % x L Displ, dimana L Displ = 69,539 m

Cp Displ=Lpp/L DisplxCp

=43,40/43,834x0,72

=0,710a. Letak LCB Displ menurut grafik NSP

LCB Displ

=1,025%xL Displ

=1,024 %x43,834

=0,449 m( Dibelakang midship Lpp)

b. Jarak midship ( ( ) L Displ ke FP

( Displ

=0,5xL Displ

=0,5x43,834

=21,917 m

c. Jarak midship (( ) Lpp ke FP

( Lpp

=0,5x Lpp

=0,5x43,40

=21,7 m

d. Jarak antara midship (( ) L Displ dengan midship (( ) Lpp

=( Displ-( Lpp

=21,917-21,7

=0,217 m

e. Jarak antara LCB terhadap midship (( ) Lpp

=0,449-0,217

=0,232 m( Di depan ( Lpp)

2. Menurut diagram NSP dengan luas tiap section (Am) = 107,84 m2No. Ord%% Terhadap AmFsHasilFmHasil

AP00,0001 - -10 -

10,11,9824 7,929 -9 -71,361

20,35,9472 11,893 -8 -95,147

30,5110,1094 40,438 -7 -283,064

40,713,8762 27,751 -6 -166,508

50,8416,6514 66,603 -5 -333,016

60,92518,3362 36,671 -4 -146,686

70,97519,3274 77,307 -3 -231,922

80,9919,6242 39,248 -2 -78,497

9119,8224 79,290 -1 -79,290

2 -1.485,489

101 39,645 2 39,645 0 -

111 79,290 4 79,290 1 79,290

121 39,645 2 39,645 2 79,290

130,99 78,497 4 78,497 3 235,490

140,96 38,059 2 38,059 4 152,236

150,92 72,946 4 72,946 5 364,732

160,81 32,112 2 32,112 6 192,674

170,625 49,556 4 49,556 7 346,892

180,38 15,065 2 15,065 8 120,520

190,1 7,929 4 7,929 9 71,361

FP0 - 1 - 10 -

1839,873

31,642,482

a. h

= L Displ / 20

= 43,834 / 20

= 2,192 m

b. Volume Displacement

V Displ= 1/3x h x

= 1/3x 2,192 x 839,874= 613,584 m3c. Letak LCB NSP

LCB NSP = x h

=

x2,192

= 0,410 md. Koreksi prosentase penyimpangan LCB

=

x100 %

=

x100 %

= 0,00090x100 %

= 0,090 %