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     Wood Stack – Where is the Limit? Discovering the Harmonic Series Aron Brunner, Johann Rubatscher Intention The question on how far equal wooden cuboids (e.g. dominoes, CD‐covers) with the dimensions l, b, and h in a stack can be moved without the stack collapsing has been asked for centuries. The maximal overhang s of the cuboid on top should be discovered here. New developments can be found in the bibliography. https://de.wikipedia.org/wiki/Harmonische_Reihe Background of Subject Matter A stack of cuboids does not collapse if the foot of the common centre of mass of the cuboids does not leave the cuboid below. The maximal shift distance s can be discovered by finding the centre of mass which is just barely located on the surface of the cuboid below. Through adding new cuboids, s can be described through the series: /2 /4 /6 /8 /10 /12 /14 ⋯, division by l/2 leads to: /2 ⋅ ൬1 1 2 1 3 1 4 1 5 1 6 1 7 ⋯൰ The brackets contain the harmonic series, which does not converge. Thus, adding more cuboids leads to a larger shift distance. Working out the Results The first cuboid on top can be shifted by ݏ/2 as then the centre of mass rests over the edge of the cuboid below. Two cuboids together can be shifted by ݏ/4 as due to symmetry, the centre of mass is in the middle of the two independent centres of mass. The shift distance for three cuboids is best solved with an equation. The common centre of mass is located directly above the edge of the fourth cuboid below. Thus, the mass‐share of the three cuboids and therefore of the individual cuboids left of the centre of mass equal those on the right. Be x the location of the centre of mass in relation to the left edge of the third. As a result, x equals ݏ. As the cuboids are shifted longitudinally, the lengths replace the masses:

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Page 1: Wood Stack – Where is the Limit? - Uni Bayreuth

 

 

 

 

 

Wood Stack – Where is the Limit?

Discovering the Harmonic Series

Aron Brunner, Johann Rubatscher Intention The question on how far equal wooden cuboids (e.g.dominoes, CD‐covers) with the dimensions l, b, and h in astack can bemoved without the stack collapsing has beenasked for centuries. Themaximal overhang s of the cuboidontopshouldbediscoveredhere.Newdevelopmentscanbefoundinthebibliography.

https://de.wikipedia.org/wiki/Harmonische_Reihe

Background of Subject Matter Astackofcuboidsdoesnotcollapseifthefootofthecommoncentreofmassofthecuboidsdoesnotleavethecuboidbelow.Themaximalshiftdistancescanbediscoveredbyfindingthecentreofmasswhichisjustbarelylocatedonthesurfaceofthecuboidbelow.Throughaddingnewcuboids,scanbedescribedthroughtheseries:

/2 /4 /6 /8 /10 /12 /14 ⋯,

divisionbyl/2leadsto:

/2 ⋅ 112

13

14

15

16

17

Thebracketscontaintheharmonicseries,whichdoesnotconverge.Thus,addingmorecuboidsleadstoalargershiftdistance. Working out the Results Thefirstcuboidontopcanbeshiftedby /2asthenthecentreofmassrestsovertheedgeofthecuboidbelow.Twocuboidstogethercanbeshiftedby /4asduetosymmetry,thecentreofmassisinthemiddleofthetwoindependentcentresofmass.Theshiftdistanceforthreecuboidsisbestsolvedwithanequation.Thecommoncentreofmassislocateddirectlyabovetheedgeofthefourth cuboid below. Thus, the mass‐share of the three cuboids and therefore of the individualcuboidsleftofthecentreofmassequalthoseontheright.Bexthelocationofthecentreofmassinrelationtotheleftedgeofthethird.Asaresult,xequals .Asthecuboidsareshiftedlongitudinally,thelengthsreplacethemasses:

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Totalofindividualmassesleft Totalofindividualmassesright Totalofindividuallengthsleft Totalofindividuallengthsright

/4 /4 /2 /4 /4 /2 Solvingtheequationleadsto: /6Fourcuboidsbeget :

/6 /6 /4 /6 /4 /2 /6 /6 /4 /6 /4 /2

Solvingtheequationleadsto: /8Continuationfor , , ,…generates:

⋯ /2 /4 /6 /8 /10 /12 ⋯AnAlternativeDerivation:Thecentreofmassoftwocuboidsislocatedinthemiddleofthecentresofmassoftwocuboidsontheirown(symmetry).Thecentreofmassofthreecuboids,however,isnotlocatedinthemiddleofthecentreofmassof the twocuboidsand the thirdbut is shifted in thedirectionof thecentreofmassofthetwocuboidsasthetwopossessmoremass.Duetothis,thecentreofmassisshiftedintheratio2:1,whichisequivalenttoathirdofl/2.Itisvalidthat:

1/3 ⋅ /2 /6Thecentreofmassoffourcuboidsisshiftedaccordingtotheratio3:1,whichleadsto:

1/4 ⋅ /2 /8Thecentreofmassoffivecuboidsisshiftedaccordingtotheratio4:1,whichleadsto:

1/5 ⋅ /2 /10

Thecontinuationoftheharmonicseriesshouldbepointedouttothepupils.Aspreadsheetprogramcancalculatetheharmonicseriesuptoabout 200.000.Bibliography Pöppe, C. (2010):TürmeausBauklötzen –MathematischeUnterhaltungen, SpektrumderWissen‐

schaft,September2010,S.64Paterson, M., Peres, Y., Thorup, M., Winkler, P., Zwick, U. (2008): Maximum Overhang, arXiv.org,

CornellUniversityLibrary,http://arxiv.org/pdf/0707.0093v1.pdf

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Pupils‘ Results

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Page 5: Wood Stack – Where is the Limit? - Uni Bayreuth

 

Wood Stack – Where is the Limit?

https://de.wikipedia.org/wiki/Harmonische_Reihe

1 Description of the Task and First Experiments Taketwoequalwoodencuboids(dominoesorCD‐covers)oflengthl,widthb,andheighth(withhalot smaller than l and b), stack them on top of each other andmove the cuboid on top so far inlongitudinaldirection that it sticksoutas faraspossible.Puta thirdequalcuboidunderneath thetwofirstonesandmovethetwouppercuboidsagainasfaraspossible.Continuethisprocess.2 Calculation Considerwithpen,paper,pocketcalculator,etc.,howfaryoucanmovethecuboidssuccessively ifthetotalnumberofblocksis 2, 3, 4, 5, …?Howfaristhetotalshiftdistancesineachcase? 3 How far? Which is thenumber ofwoodenblocks,withwhicha stackof thismannercanbebuilt thatdoesnotcollapse?4 With Help from the Computer Calculate withaspreadsheetprogram. 5 Further Considerations Howbigiss,ifeachcuboidismovedbyl/3orl/4?Whatwouldhappenwithwoodendisks?Whatwouldchangeifyouwereallowedtousecounterweightsoranyotheradditions? Readthefollowingarticles:Pöppe, C. (2010):TürmeausBauklötzen–MathematischeUnterhaltungen, SpektrumderWissen‐

schaft,September2010,S.64Paterson, M., Peres, Y., Thorup, M., Winkler, P., Zwick, U. (2008): Maximum Overhang, arXiv.org,

CornellUniversityLibrary,http://arxiv.org/pdf/0707.0093v1.pdf