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J. Math. Anal. Appl. 365 (2010) 609–618 Contents lists available at ScienceDirect Journal of Mathematical Analysis and Applications www.elsevier.com/locate/jmaa Wave interactions and stability of the Riemann solutions for the chromatography equations Chun Shen a,b,a School of Mathematics and Information, Ludong University, Yantai 264025, PR China b Laboratory of Mathematics Physics, Wuhan Institute of Physics and Mathematics, The Chinese Academy of Sciences, Wuhan 430071, PR China article info abstract Article history: Received 25 July 2009 Available online 27 November 2009 Submitted by B. Straughan Keywords: Wave interactions Riemann problem Temple class Chromatography system Hyperbolic conservation laws We prove that the Riemann solutions are stable for the chromatography system under the local small perturbations of the Riemann initial data. The proof is based on the detailed analysis of the wave interactions by applying the method of characteristic analysis. It is noteworthy that both the propagation directions of the shock wave S and rarefaction wave R are unchanged when they interact with the contact discontinuity J . Moreover, the global structures and large time asymptotic behaviors of the perturbed Riemann solutions are constructed and analyzed case by case. © 2009 Elsevier Inc. All rights reserved. 1. Introduction In this paper, we are concerned with the chromatography equations in the following conservative form u t + x u 1 + u + v = 0, v t + x v 1 + u + v = 0, (1.1) where u, v are the non-negative functions of the variables (x, t ) R × R + , which express transformations of the concentra- tions of two solutes. The system (1.1) is widely used by chemists and engineers to study the separation of two chemical components in a fluid phase. The chromatographic separation of two chemical species governed by the Langmuir isotherm can be expressed as [14]: c 1 x + t c 1 1 + c 1 + c 2 =−kc 1 + k c 2 , c 2 x + t γ c 2 1 + c 1 + c 2 = γ ( kc 1 k c 2 ) , (1.2) This work is partially supported by the National Science Foundation of China (10901077, 10871199), China Postdoctoral Science Foundation and program for innovative research term in Ludong University. * Address for correspondence: School of Mathematics and Information, Ludong University, Yantai 264025, PR China. E-mail address: [email protected]. 0022-247X/$ – see front matter © 2009 Elsevier Inc. All rights reserved. doi:10.1016/j.jmaa.2009.11.037

Wave interactions and stability of the Riemann solutions for the chromatography equations

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Page 1: Wave interactions and stability of the Riemann solutions for the chromatography equations

J. Math. Anal. Appl. 365 (2010) 609–618

Contents lists available at ScienceDirect

Journal of Mathematical Analysis andApplications

www.elsevier.com/locate/jmaa

Wave interactions and stability of the Riemann solutions forthe chromatography equations ✩

Chun Shen a,b,∗a School of Mathematics and Information, Ludong University, Yantai 264025, PR Chinab Laboratory of Mathematics Physics, Wuhan Institute of Physics and Mathematics, The Chinese Academy of Sciences, Wuhan 430071, PR China

a r t i c l e i n f o a b s t r a c t

Article history:Received 25 July 2009Available online 27 November 2009Submitted by B. Straughan

Keywords:Wave interactionsRiemann problemTemple classChromatography systemHyperbolic conservation laws

We prove that the Riemann solutions are stable for the chromatography system under thelocal small perturbations of the Riemann initial data. The proof is based on the detailedanalysis of the wave interactions by applying the method of characteristic analysis. Itis noteworthy that both the propagation directions of the shock wave S and rarefactionwave R are unchanged when they interact with the contact discontinuity J . Moreover, theglobal structures and large time asymptotic behaviors of the perturbed Riemann solutionsare constructed and analyzed case by case.

© 2009 Elsevier Inc. All rights reserved.

1. Introduction

In this paper, we are concerned with the chromatography equations in the following conservative form⎧⎪⎪⎨⎪⎪⎩

∂u

∂t+ ∂

∂x

(u

1 + u + v

)= 0,

∂v

∂t+ ∂

∂x

(v

1 + u + v

)= 0,

(1.1)

where u, v are the non-negative functions of the variables (x, t) ∈ R × R+ , which express transformations of the concentra-tions of two solutes.

The system (1.1) is widely used by chemists and engineers to study the separation of two chemical components ina fluid phase. The chromatographic separation of two chemical species governed by the Langmuir isotherm can be expressedas [14]:⎧⎪⎪⎨

⎪⎪⎩∂c1

∂x+ ∂

∂t

(c1

1 + c1 + c2

)= −kc1 + k′c2,

∂c2

∂x+ ∂

∂t

(γ c2

1 + c1 + c2

)= γ

(kc1 − k′c2

),

(1.2)

✩ This work is partially supported by the National Science Foundation of China (10901077, 10871199), China Postdoctoral Science Foundation and programfor innovative research term in Ludong University.

* Address for correspondence: School of Mathematics and Information, Ludong University, Yantai 264025, PR China.E-mail address: [email protected].

0022-247X/$ – see front matter © 2009 Elsevier Inc. All rights reserved.doi:10.1016/j.jmaa.2009.11.037

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610 C. Shen / J. Math. Anal. Appl. 365 (2010) 609–618

in which c1 and c2 are proportional to the concentrations of two solutes in the fluid phase, k and k′ are proportional tothe rate constants in the reaction, and γ ∈ [0,1] is a known constant dependent on the nature of the Langmuir isotherm.It is noted that x and t in (1.2) are opposite to those in most hyperbolic systems. Eqs. (1.1) can be derived from (1.2) byletting γ = 1 and assuming that the chemical reaction tends to the chemical equilibrium (kc1 = k′c2). Here we consider theinfluence of the local small perturbation upon the chemical equilibrium.

Recently, Ambrosio et al. [2] have introduced the change of variables w = u + v and z = u − v and then studied Eqs. (1.1)as an example by employing new well-posedness results for continuity and transport equations. The chromatography sys-tem is split into the coupling between a scalar conservation law and a transport equation, so that the transport equationtechniques [1] can be heavily exploited. A different change of variables w = u + v and θ = v/u was adopted by Bressan andShen [8] where their attentions were mainly drawn on the study of ODEs with discontinuous vector fields.

It is easy to see that (1.1) belongs to the Temple class, i.e., the shock curves coincide with the rarefaction curves in thephase plane due to the special form [23]. It is now known that well-posed results for Temple systems are available for amuch larger class of initial data compared with general systems of conservation laws. Moreover, the Riemann problem canbe explicitly constructed in the large and wave interactions have simplified structures. Recently, Sun [21] have investigatedthe interactions of the Aw–Rascle model completely, which is another typical example of Temple class. For the relatedresults about Temple systems, we can refer to [3–5,7,12] and the references cited therein.

The main purpose of this paper is to study various possible interactions of elementary waves for the chromatographyequations (1.1). In order to cover all kinds of interactions completely, we consider the initial value problem with three piecesconstant initial data as follows:

(u, v)(x,0) =⎧⎨⎩

(u−, v−), −∞ < x < −ε,

(um, vm), −ε < x < ε,

(u+, v+), ε < x < +∞,

(1.3)

in which ε > 0 is arbitrarily small. In fact, the initial data (1.3) is a local small perturbation of the corresponding Riemanninitial data

(u, v)(x,0) = (u±, v±), ±x > 0. (1.4)

The local equilibrium theory plays an important role in studying the dynamics of chromatographic columns and canbe described by the system of hyperbolic conservation laws which has a comprehensive theoretical framework [15,16]. Inorder to analyze the behavior of chromatographic column in the extent of equilibrium theory, we should consider the initialboundary value problem consisting of the horizontal axis t = 0 with 0 � x � 1 and the vertical axis x = 0 and x = 1 for t � 0[9,13,20]. In fact, to solve this problem is similar to solve (1.1) and (1.3), namely, wave interactions should be dealt withcompletely. Thanks to the characteristics in the phase space being straights for (1.1), the initial value problem (1.1) and (1.3)can be constructed analytically by employing the method of characteristics.

By taking the initial data (1.3) instead of the Riemann initial data (1.4), we cannot only consider all kinds of waveinteractions but also study the stability of the Riemann solutions. The method of this local small perturbation has beenadopted to study the combustion problem [22], the traffic flow [21] and the delta shock problem [18] recently. For thegeneral knowledge about the wave interactions and the hyperbolic conservation laws, we can refer to the books by Changand Hsiao [10], Dafermos [11], Serre [17] and Smoller [19].

In this note, we investigate the interactions of elementary waves widely and construct the global solutions for (1.1)and (1.3) completely by employing the method of characteristic analysis. It should be noted that both the shock wave Sand rarefaction wave R do not change their propagation directions when they interact with the contact discontinuity J .Moreover, we can make a further step to prove that the solutions of the initial value problem (1.1) and (1.3) converge to thecorresponding Riemann solutions of (1.1) and (1.4) as ε tends to zero, which displays the stability of the Riemann solutionswith respect to the local small perturbation (1.3) of the Riemann initial data (1.4).

The rest of the paper is arranged as follows. In Section 2, we restate the Riemann problem (1.1) and (1.4) for readers’convenience. In Section 3, we mainly discuss the interactions for all kinds when the initial data are three pieces of constantstates (1.3), and the solutions are constructed globally and the stability of the Riemann solutions is analyzed case by casebefore our conclusion is drawn in Section 4.

2. Preliminaries

We shall now describe the Riemann solutions for (1.1) and (1.4) for completeness, which have already obtained byBressan in [6]. The eigenvalues of (1.1) are λ1(u, v) = 1

(1+u+v)2 and λ2(u, v) = 11+u+v , and the corresponding right-hand

side eigenvectors are r1(u, v) = (u, v)T and r2(u, v) = (1,−1)T respectively. The first characteristic field is genuinely non-linear and the second is linearly degenerate. The Riemann invariants along the characteristic fields are w = u

v and z = u + vrespectively. By a straightforward computation, we have the following fact that the shock wave and rarefaction wave curvesalways coincide in the phase space because they are straight lines.

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C. Shen / J. Math. Anal. Appl. 365 (2010) 609–618 611

Given a left state (u−, v−), the 1-rarefaction wave curves in the phase plane on the right are:

R(u−, v−):

⎧⎪⎪⎨⎪⎪⎩

x

t= λ1 = 1

(1 + u + v)2,

u

v= u−

v−, u + v < u− + v−,

(2.1)

and a 1-shock wave curves on the right are:

S(u−, v−):

⎧⎪⎪⎨⎪⎪⎩

x

t= σ = 1

(1 + u + v)(1 + u− + v−),

u

v= u−

v−, u + v > u− + v−.

(2.2)

From (2.1) and (2.2), we know that the shock wave curves coincide with the rarefaction wave curves in the phase plane dueto the property of Temple class.

Otherwise they can be directly connected by a contact discontinuity of the second family

J (u−, v−):

⎧⎨⎩

x

t= τ = 1

1 + u− + v−= 1

1 + u + v,

u + v = u− + v−.

(2.3)

In all, there exist two kinds of Riemann solutions for (1.1) and (1.4) in the following.(i) If u− + v− < u+ + v+ , the Riemann solution is a shock wave S followed by a contact discontinuity J

(u, v)(x, t) =⎧⎨⎩

(u−, v−), −∞ < x < σ t,

(u∗, v∗), σ t < x < τ t,

(u+, v+), τ t < x < +∞,

(2.4)

where σ = 1(1+u−+v−)(1+u++v+)

is the speed of shock wave and τ = 11+u++v+ is the speed of contact discontinuity, and the

intermediate state (u∗, v∗) can be calculated as (u∗, v∗) = (u−(u++v+)

u−+v− ,v−(u++v+)

u−+v− ).(ii) If u− + v− > u+ + v+ , the Riemann solution consists of a rarefaction wave R and a contact discontinuity J

(u, v)(x, t) =

⎧⎪⎪⎪⎨⎪⎪⎪⎩

(u−, v−), −∞ < x < λ1(u−, v−)t,

R, λ1(u−, v−)t � x � λ1(u∗, v∗)t,(u∗, v∗), λ1(u∗, v∗)t < x < τ t,

(u+, v+), τ t < x < +∞,

(2.5)

where the speed of contact discontinuity τ and the intermediate state (u∗, v∗) are the same as above, and the rarefactionwave R can be given by

(u, v)(x, t) =(

u−u− + v−

·(√

t

x− 1

),

v−u− + v−

·(√

t

x− 1

)). (2.6)

3. Wave interactions for the chromatography equations (1.1)

In order to cover all the cases completely, we divide our discussion into four cases according to the different combina-tions of the Riemann solutions starting from (−ε,0) and (ε,0) as follows:

(1) S + J and R + J ,(2) R + J and S + J ,(3) R + J and R + J ,(4) S + J and S + J .

In the same time, we will encounter the interesting question of determining whether the Riemann solutions of (1.1)and (1.4) are the limits of (uε, vε)(x, t) as ε → 0 case by case accompanying with the construction of the perturbed Riemannsolutions of (1.1) and (1.3).

Case 1. S + J and R + J .

At first, we consider the interaction between a shock wave followed by a contact discontinuity starting from (−ε,0) anda rarefaction wave followed by a contact discontinuity starting from (ε,0). When t is small enough, the solution of the

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612 C. Shen / J. Math. Anal. Appl. 365 (2010) 609–618

Fig. 1.1. u− + v− < u+ + v+ < um + vm .

Fig. 1.2. u+ + v+ < u− + v− < um + vm .

initial value problem (1.1) and (1.3) can be expressed briefly as (see Figs. 1.1 and 1.2):

(u−, v−) + S1 + (u1, v1) + J1 + (um, vm) + R2 + (u2, v2) + J2 + (u+, v+),

where “+” means “followed by”. The occurrence of this case depends on the conditions u− + v− < um + vm and u+ + v+ <

um + vm .It can be derived directly from (2.4) and (2.5) that

(u1, v1) =(

u−(um + vm)

u− + v−,

v−(um + vm)

u− + v−

), (3.1)

(u2, v2) =(

um(u+ + v+)

um + vm,

vm(u+ + v+)

um + vm

). (3.2)

The propagation speed of J1 is τ1 = 11+um+vm

and that of the wave back in the rarefaction wave R2 is ξ = 1(1+um+vm)2 . It

is clear that J1 will overtake R2 at a finite time. The intersection (x1, t1) is determined by⎧⎪⎪⎨⎪⎪⎩

x1 + ε = t1

1 + um + vm,

x1 − ε = t1

(1 + um + vm)2,

(3.3)

which yields

(x1, t1) =(

ε(2 + um + vm)

um + vm,

2ε(1 + um + vm)2

um + vm

). (3.4)

Therefore, the contact discontinuity J1 crosses the whole of the rarefaction wave R2 with a varying speed of propagation,which is determined by

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C. Shen / J. Math. Anal. Appl. 365 (2010) 609–618 613

⎧⎪⎪⎪⎪⎪⎪⎪⎪⎨⎪⎪⎪⎪⎪⎪⎪⎪⎩

dx

dt= 1

1 + u + v,

x − ε = t

(1 + u + v)2,

u

v= um

vm= u2

v2, u2 + v2 � u + v � um + vm,

x(t1) = x1.

(3.5)

Differentiating (3.5) with respect to t leads to

d2x

dt2= − 1

(1 + u + v)2·(

du

dt+ dv

dt

), (3.6)

dx

dt= 1

(1 + u + v)2− 2t

(1 + u + v)3·(

du

dt+ dv

dt

). (3.7)

Substituting dxdt = 1

1+u+v into (3.7), it yields

du

dt+ dv

dt= − (u + v)(1 + u + v)

2t< 0. (3.8)

Furthermore, we have

d2x

dt2= u + v

2(1 + u + v)t> 0, (3.9)

which means that the propagation speed of the contact discontinuity increases during the process of J1 passing through R2.On the other hand, from (3.5), we also have

dx

dt=

√x − ε

t, (3.10)

which, together with the initial condition (3.4), gives

√x − ε = √

t − √2ε(um + vm). (3.11)

It is shown that the contact discontinuity J1 will penetrate the whole of the rarefaction wave R2 completely and the endingpoint can be calculated by⎧⎨

⎩√

x2 − ε = √t2 − √

2ε(um + vm),

x2 − ε = t2

(1 + u2 + v2)2= t2

(1 + u+ + v+)2.

(3.12)

After the time t2, we denote the contact discontinuity with J3 whose propagation speed is τ3 = 11+u2+v2

= 11+u++v+ , which

implies that J3 is parallel to J2.It is noteworthy to see that

1

(1 + u1 + v1)2= 1

(1 + um + vm)2and

1

(1 + u2 + v2)2= 1

(1 + u3 + v3)2, (3.13)

which implies that the propagation direction of the rarefaction wave is unchanged during the process of penetration, butthe value of (u, v) changes. Here the state (u3, v3) is the crossing point of u

v = u−v− and u + v = u+ + v+ in the phase plane.

Now let us consider the interaction of S1 and R3. The propagation speed of S1 is σ1 = 1(1+u−+v−)(1+um+vm)

and that of

the wave back in the rarefaction wave R3 is also ξ = 1(1+um+vm)2 . Thus, it is easy to see that S1 will catch up with R3 at a

finite time and the intersection (x3, t3) can be calculated by⎧⎪⎪⎨⎪⎪⎩

x3 + ε = t3

(1 + u− + v−)(1 + um + vm),

x3 − ε = t3

(1 + um + vm)2,

(3.14)

an easy computation leads to

(x3, t3) =(

ε(2 + u− + v− + um + vm),

2ε(1 + um + vm)2(1 + u− + v−))

. (3.15)

(um + vm) − (u− + v−) (um + vm) − (u− + v−)
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614 C. Shen / J. Math. Anal. Appl. 365 (2010) 609–618

The expression for the shock wave S : x = x(t) passing through R3 is

⎧⎪⎪⎪⎪⎪⎪⎪⎪⎨⎪⎪⎪⎪⎪⎪⎪⎪⎩

dx

dt= 1

(1 + u− + v−)(1 + u + v),

x − ε = t

(1 + u + v)2,

u

v= u1

v1= u3

v3, u3 + v3 � u + v � u1 + v1,

x(t3) = x3,

(3.16)

in which u1 + v1 = um + vm and u3 + v3 = u2 + v2 = u+ + v+ .The combination of the first two equations in (3.16) gives

dx

dt= 1

1 + u− + v−·√

x − ε

t, (3.17)

which together with (3.15) yields

√x − ε =

√t

1 + u− + v−−

√2ε(um + vm − u− − v−)

1 + u− + v−. (3.18)

On the other hand, differentiating (3.16) with respect to t , we have

d2x

dt2= − 1

(1 + u− + v−)(1 + u + v)2·(

du

dt+ dv

dt

), (3.19)

dx

dt= 1

(1 + u + v)2− 2t

(1 + u + v)3·(

du

dt+ dv

dt

). (3.20)

Similarly, we can conclude that the following relations

du

dt+ dv

dt= − (u + v − u− − v−)(1 + u + v)

2(1 + u− + v−)t< 0, (3.21)

d2x

dt2= u + v − u− − v−

2(1 + u + v)(1 + u− + v−)2t> 0, (3.22)

are true for u + v > u− + v− . Hence S1 keeps accelerating during the process of penetration. Furthermore our discussionshould be divided into the following two subcases according to the ordering of u− + v− and u+ + v+ .

Subcase 1.1. u− + v− < u+ + v+ .

In this subcase, S1 will penetrate the whole rarefaction wave R3 completely and it ends at the point (x4, t4) whichsatisfies⎧⎪⎪⎪⎨

⎪⎪⎪⎩√

x4 − ε =√

t4

1 + u− + v−−

√2ε(um + vm − u− − v−)

1 + u− + v−,

x4 − ε = t4

(1 + u+ + v+)2.

(3.23)

After the penetration, we denote the shock wave by S2 whose propagation speed is σ2 = 1(1+u−+v−)(1+u++v+)

. Obviously,we have σ2 < τ3 which means that S2 cannot catch up with J3 and no interaction will happen.

When t > t4, the solution can be expressed as (see Fig. 1.1)

(u−, v−) + S2 + (u3, v3) + J3 + (u2, v2) + J2 + (u+, v+).

Passing to the limit ε → 0, one can easily see that J3 and J2 will coincide with each other and the limit of the solution of(1.1) and (1.3) is exactly the corresponding Riemann solution of (1.1) and (1.4).

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C. Shen / J. Math. Anal. Appl. 365 (2010) 609–618 615

Fig. 2.1. um + vm < u− + v− < u+ + v+ .

Fig. 2.2. um + vm < u+ + v+ < u− + v− .

Subcase 1.2. u− + v− � u+ + v+ .

In this subcase, S1 cannot cancel the whole rarefaction wave R3 completely and ultimately has x − ε = t(1+u−+v−)2 as its

asymptote. In the special case u− + v− = u+ + v+ , S1 has the wave front in R3 as its asymptote.When t → ∞, the solution can be expressed as (see Fig. 1.2)

(u−, v−) + R + (u3, v3) + J3 + (u2, v2) + J2 + (u+, v+).

Taking the limit ε → 0, we can see that the conclusion is obviously identical with our assertion.

Case 2. R + J and S + J .

In this case, when t is small enough, the solution of the initial value problem (1.1) and (1.3) can be expressed briefly asfollows (see Figs. 2.1 and 2.2):

(u−, v−) + R1 + (u1, v1) + J1 + (um, vm) + S2 + (u2, v2) + J2 + (u+, v+).

The occurrence of this case depends on the conditions u− + v− > um + vm and u+ + v+ > um + vm .Here and below the intermediate states (u1, v1), (u2, v2) and (u3, v3) have the same presentations as above. The prop-

agation speeds of J1 and S2 are τ1 = 11+um+vm

and σ2 = 1(1+um+vm)(1+u++v+)

respectively, so J1 will interact with S2 at thepoint (x1, t1) satisfying⎧⎪⎪⎨

⎪⎪⎩x1 + ε = t1

1 + um + vm,

x1 − ε = t1

(1 + um + vm)(1 + u+ + v+),

(3.24)

which yields

(x1, t1) =(

ε(2 + u+ + v+),

2ε(1 + um + vm)(1 + u+ + v+))

. (3.25)

u+ + v+ u+ + v+
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616 C. Shen / J. Math. Anal. Appl. 365 (2010) 609–618

The interaction of J1 and S2 generates a new shock wave S3 and a new contact discontinuity J3. After the interaction,the propagation direction of the shock wave is unchanged for the propagation speed of S3 is the same as that of S2. Andwe also have τ3 = τ2 namely J3 is parallel to J2.

The propagation speed of the wave front in the rarefaction wave R is ξ = 1(1+um+vm)2 , thus R will overtake S3 at the

point (x2, t2) which is determined by⎧⎪⎪⎨⎪⎪⎩

x2 + ε = t2

(1 + um + vm)2,

x2 − ε = t2

(1 + um + vm)(1 + u+ + v+),

(3.26)

it follows that

(x2, t2) =(

ε(2 + u− + v− + um + vm)

(um + vm) − (u− + v−),

2ε(1 + um + vm)2(1 + u− + v−)

(um + vm) − (u− + v−)

). (3.27)

The expression for the shock wave S : x = x(t) during the penetration is

⎧⎪⎪⎪⎪⎪⎪⎪⎪⎨⎪⎪⎪⎪⎪⎪⎪⎪⎩

dx

dt= 1

(1 + u3 + v3)(1 + u + v),

x + ε = t

(1 + u + v)2,

u

v= u1

v1= u−

v−, u1 + v1 � u + v � u− + v−,

x(t2) = x2.

(3.28)

From (3.28), we have

dx

dt= 1

1 + u3 + v3·√

x + ε

t, (3.29)

combining with (3.27) leads to

√x + ε =

√t

1 + u3 + v3+

√2ε(u+ + v+ − um − vm)

1 + u+ + v+. (3.30)

In the same way as before, by differentiating (3.28) with respect to t , it holds that

d2x

dt2= u + v − u+ − v+

2(1 + u + v)(1 + u+ + v+)2t< 0 (3.31)

for u + v < u+ + v+ . Thus the shock wave is found to decelerate during the penetration process. Also we have the followingtwo subcases.

Subcase 2.1. u− + v− < u+ + v+ .

In this subcase, the shock wave will penetrate the whole rarefaction wave R completely and the ending point can becalculated by

⎧⎪⎪⎪⎨⎪⎪⎪⎩

√x3 + ε =

√t3

1 + u3 + v3+

√2ε(u+ + v+ − um − vm)

1 + u+ + v+,

x3 + ε = t3

(1 + u− + v−)2.

(3.32)

When t > t3, the solution can be expressed as (see Fig. 2.1)

(u−, v−) + S3 + (u3, v3) + J3 + (u2, v2) + J2 + (u+, v+),

which is identical with Subcase 1.1.

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C. Shen / J. Math. Anal. Appl. 365 (2010) 609–618 617

Fig. 3. u− + v− > um + vm > u+ + v+ .

Fig. 4. u− + v− < um + vm < u+ + v+ .

Subcase 2.2. u− + v− � u+ + v+ .

In this subcase, S1 cannot penetrate the whole rarefaction wave R3 completely and ultimately has x + ε = t(1+u++v+)2 as

its asymptote (see Fig. 2.2). In the special case u− + v− = u+ + v+ , S2 has the wave back in R as its asymptote. The limitsituation is like as Subcase 1.2.

Case 3. R + J and R + J .

In this case, we consider the situation that a rarefaction wave plus a contact discontinuity emits from (−ε,0) and (ε,0)

respectively (see Fig. 3). This case arises when u− + v− > um + vm > u+ + v+ is satisfied.Like as the first part of Case 1, J1 will accelerate to penetrate over R2 and the propagation direction of R2 is unchanged.

After the penetration, we denote J1 with J3 which is parallel to J2. It is noticed that the wave front in R1 and the waveback in R3 have the same propagation speed ξ = 1

(1+u1+v1)2 .

As ε → 0, J3 and J2 will coincide with each other and the two rarefaction waves R1 and R3 will coalesce into one. Thusthe limit situation is also a rarefaction wave plus a contact discontinuity which is the corresponding Riemann solution.

Case 4. S + J and S + J .

Finally, we consider the interaction of a shock wave followed by a contact discontinuity starting from (−ε,0) and (ε,0)

respectively (see Fig. 4). This case happens if and only if u− + v− < um + vm < u+ + v+ .Similarly to the first part of Case 2, the interaction of J1 and S2 results in a new shock wave S3 and a new contact

discontinuity J3. The shock wave S3 has the same propagation direction as S2 and J3 is parallel to J2.The propagation speeds of S1 and S3 are σ1 = 1

(1+u−+v−)(1+um+vm)and σ3 = 1

(1+um+vm)(1+u++v+)respectively, so S1 will

overtake S3 in finite time. Then (u−, v−) and (u3, v3) can be connected directly by a shock wave, which implies that S1and S3 coalesce into a new shock wave S4. As ε → 0, the limit situation is a shock wave plus a contact discontinuity andthe conclusion is obviously true.

4. Conclusions

So far, we have finished the discussion for all kinds of interactions and we can see that wave interactions have a moresimple structure for Temple class than general systems of conservation laws. This is due to the fact that interaction of

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waves of the same family does not generate wave of other family for Temple systems. By letting ε → 0, through the aboveanalysis and computation, we can see that the limits of the perturbed Riemann solutions of (1.1) and (1.3) are exactlythe corresponding Riemann solutions of (1.1) and (1.4) by passing to the limit ε → 0 and the asymptotic behavior of theperturbed Riemann solutions is governed completely by the states (u±, v±).

It is important to study the interactions of elementary waves for (1.1) not only because of their significance in practicalapplications in the chromatography systems such as comparison with the numerical and experimental results, but alsobecause of their basic role as building blocks for the general mathematical theory of the chromatography systems. And theresults obtained here can be also used in a procedure similar to the wave-front tracking approximation for general initialdata.

It is noticed that (1.1) is the simplest chromatography system by assuming it satisfies the Langmuir isotherm andchemical equilibrium. However, real systems are more complicate than (1.1) due to other types of isotherms, such as theanti-Langmuir isotherm and the isotherm with inflection points etc. [13]. We can see that the result obtained here can beextended to the more general chromatography systems provided that they belong to the Temple type. On the other hand,the technique of wave interactions used here is very effective to study the behavior of the chromatographic column.

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