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Warmup Assign oxidation numbers to each element: Na NaCl Cl 2 H 2 O Ca(OH) 2 NO 3 -

Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

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Page 1: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

WarmupAssign oxidation numbers to each

element:

Na NaCl Cl2H2O Ca(OH)2 NO3

-

Page 2: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

ElectrochemistryElectrochemistry

is the basis for:is the basis for:

• Batteries and CorrosionBatteries and Corrosion• Industrial production of chemicalsIndustrial production of chemicals• Biological redox reactionsBiological redox reactions

Page 3: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

The oxidation numbers of elements in their compoundsThe oxidation numbers of elements in their compounds

4.4

Page 4: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

Reviewing Oxidation NumbersReviewing Oxidation Numbers

11

2

00

22

ClNaClNa

2

2

1

OH2(+1) + (-2) = 02(+1) + (-2) = 0 H O H O

2

122

)(

HOCa(+2) + 2(-2) + 2(+1) = 0(+2) + 2(-2) + 2(+1) = 0 Ca O H Ca O H

3

2?

ONX + 3(-2) = -1N O

X = +5X = +5

Page 5: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

LEOLEO says says GERGER::

eNaNa10

LLose ose EElectrons = lectrons = OOxidationxidation

Sodium is oxidizedSodium is oxidized

GGain ain EElectrons = lectrons = RReductioneduction

10 CleCl Chlorine is reducedChlorine is reduced

11

2

00

22

ClNaClNa

Page 6: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

Sr + 2HSr + 2H22O Sr(OH)O Sr(OH)22 + H + H22

TiClTiCl44 + 2Mg Ti + 2MgCl + 2Mg Ti + 2MgCl22

00 +1+1 +2+2 00

00+4+4 00 +2+2

Assign oxidation numbers to each Assign oxidation numbers to each species. Then identify the oxidizer species. Then identify the oxidizer

and reducer.and reducer.

Page 7: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

But how do we know who will give electrons to who and if the reaction will be spontaneous?

Some reactions are spontaneous and can generate an electric current

Redox (oxidation-reduction) reactions involve the transfer of electrons

Some are nonspontaneous and can be caused by imposing an electric current (lab)

Page 8: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

The Activity Series for Metals

LithiumLithium PotassiumPotassium CalciumCalcium SodiumSodium MagnesiuMagnesiumm AluminumAluminum ZincZinc ChromiumChromium IronIron NickelNickel LeadLead HydrogenHydrogen BismuthBismuth CopperCopper MercuryMercury SilverSilver PlatinumPlatinum GoldGold

Some standard Reduction Potentials at 25C E (volts)

F2(g) + 2e- 2F-(aq) +2.87

Au3+ + 3e- Au(s) +1.50Cl2(g) + 2e- 2Cl-(aq) +1.36

O2(g) + 4H3O+(aq) + 4e- 6H2O(l) +1.23

Br2(l) + 2e- 2Br-(aq) +1.08

Ag+(aq) + e- Ag(s) +0.80Hg2

2+(aq) + 2e- 2Hg(l) +0.79

I2(s) + 2e- 2I-(aq) +0.535

Cu2+(aq) + 2e- Cu(s) +0.337Sn4+(aq) + 2e- Sn2+(aq) +0.15Sn2+(aq) + 2e- Sn(s) -0.14Cd2+(aq) + 2e- Cd(s) -0.40Zn2+(aq) + 2e- Zn(s) -0.7632H2O(l) + 2e- H2(g) + 2OH-(aq) -0.828

Al3+(aq) + 3e- Al(s) -1.66K+(aq) + e- K(s) -2.93Li+(aq) + e- Li(s) -3.045

Page 9: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

Using data from the previous reduction potential table, predict which of the following is the best oxidizerHint: good oxidizing agents are really good at stealing electrons and “getting reduced”a)F2 b) Ag+ c) Cd2+ d) Al3+

Using data from the previous reduction potential table, predict which of the following is the best reducing agent.Hint: good reducers are really good at donating electrons……and really bad at STEALING them.a) I2 b) Au3+ c) Br2 e) Sn2+

Page 10: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

The Activity Series for Metals

LithiumLithium PotassiumPotassium CalciumCalcium SodiumSodium MagnesiuMagnesiumm AluminumAluminum ZincZinc ChromiumChromium IronIron NickelNickel LeadLead HydrogenHydrogen BismuthBismuth CopperCopper MercuryMercury SilverSilver PlatinumPlatinum GoldGold

Some standard Reduction Potentials at 25C E (volts)

F2(g) + 2e- 2F-(aq) +2.87

Au3+ + 3e- Au(s) +1.50Cl2(g) + 2e- 2Cl-(aq) +1.36

O2(g) + 4H3O+(aq) + 4e- 6H2O(l) +1.23

Br2(l) + 2e- 2Br-(aq) +1.08

Ag+(aq) + e- Ag(s) +0.80Hg2

2+(aq) + 2e- 2Hg(l) +0.79

I2(s) + 2e- 2I-(aq) +0.535

Cu2+(aq) + 2e- Cu(s) +0.337Sn4+(aq) + 2e- Sn2+(aq) +0.15Sn2+(aq) + 2e- Sn(s) -0.14Cd2+(aq) + 2e- Cd(s) -0.40Zn2+(aq) + 2e- Zn(s) -0.7632H2O(l) + 2e- H2(g) + 2OH-(aq) -0.828

Al3+(aq) + 3e- Al(s) -1.66K+(aq) + e- K(s) -2.93Li+(aq) + e- Li(s) -3.045

Page 11: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

Calculate E° for a voltaic cell in which the reaction is:

2Ag+(aq) + Cd(s) 2Ag(s) +Cd2+(aq)

a) split into 2 half reactions

2Ag+(aq) + 2e- 2Ag(s)

Cd2+(aq) + 2e- Cd(s)

Cd(s) Cd2+(aq) + 2e-

b) Find E° values on table

Don’t multiply potential by # moles: electric potentials are ”intensive properties” and do not depend on the amount of the substance

Et° +0.80 + +0.40 = 1.20 V

The reaction will always happen in a way where the Et

is + (spontaneous)

E° = -0.40V

reversed, = + 0.40 V

E° = + 0.80V

Page 12: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

Calculate ET° for the following reaction:2Al3+(aq) + 3Cd(s) 2Al(s) + 3Cd2+(aq)

a)-2.06 V b) -4.52 V c) +4.52 V

d) -1.26 V e) +2.06 V

Al3+(aq) + 3e- Al(s) E° = -1.66Cd2+(aq) + 2e- Cd(s E° = -0.40

E° = -1.66 + 0.40

Page 13: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

Write the cell notation:

Zn|Zn2+||Cu2+|Cu

Which reaction

occurs at the anode?

Oxidation

Zn(s) Zn2+(aq) + 2e-

Which reaction occurs at

the cathode?

Reduction

Cu2+(aq) + 2e- Cu(s)

Voltaic Cellse- are produced at the anode and travel to the cathode. This causes ions to migrate to the electrodes and undergo redox reactions. After some time, the [ ] change.

salt bridge maintains electroneutrality and allows a current to flow. Otherwise, there would be a pile-up of electrons, and the current would stop. If there were no salt bridge, the reactants would simply mix together and react directly rather than sending electrons through a wire. Consequently, no current would flow, and there would not be a cell.

Page 14: Warmup Assign oxidation numbers to each element: NaNaClCl 2 H 2 O Ca(OH) 2 NO 3 -

Reduction Potentials

Pb2+ + 2e¯ Pb -0.13 V

Al3+ + 3e¯ Al -1.68 V

Label the cathode and anode.

What voltage will be produced by the voltaic cell?

a) 2.97Vb) 1.55Vc) -1.81Vd) -2.97V

Cathode

(reduction, e- accepted here)

anode

(oxidation, e- given away here)