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1. 0.981 N (or 1N if you let g = 10m/s^)2. 52,000 N, need to find a force equivalent to the Normal force = mgcos (theta)3. Answers will vary. Check with classmates4. Since in equilibrium we know that Ff = mgsin(theta) AND Ff = mu*N so we can say:
Mu*N = mgsin(theta) then subst. for normal force (N=mgcos(theta))Mu* mgcos(theta) = mgsin(theta) cancel mg’s, solve for MuMu = sin(theta)/cos(theta) use trig identityMu = tan (theta) You may remember this from class—REMEMBER, this is ONLY true in equilibrium systemsSolve for theta using inverse tan.Answer: 17 degrees.
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